Answer:
jnfal4u4ryhfsbjls5
Explanation:
duehdakjweyedufkbshegygfr
a glass beaker has a mass of 50g. a liquid of density 1.8g/cm3 is poured into the beaker until it reaches the 200cm3 mark. calculate the total mass of the beaker and its contents
Answer:
total mass = 410 g
Explanation:
density = 1.8 g/cm³
volume = 200 cm³
density = mass / volume
mass (of liquid) = density x volume
= 1.8 x 200
= 360 g
total mass (beaker + liquid) = 50 + 360 = 410 g [Ans]
Hope this helps!
Someone please help me answer these questions
1. What is the walking
Aquarium to the Key West Cemetery?
A
2. What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
3. If you were walking 4 miles per hour how long would it take you
to get from the Aquarium to the Cemetery? (Speed= D/T)
4. If you were to take off in a helicopter from Ft. Zachary State
Historic Site and fly directly to the US Naval Air Station at a constant
speed of 20 miles per hour how long would it take?
Answer:
house away far from
Explanation:
I dont know tbh
Which of the following proves that electric fields can convert potential energy into kinetic energy?
a) Two electric charges produce fields. When those fields interact, the charges either attract or repel from each other
b) An electric charge is held stationary in an electric field
c)Two charges are affected by gravity, causing them to attract towards each other
d)Multiple charges are arranged in such a way to ensure that there are no net forces acting upon each other
i think its a or c?....
Answer: a
Explanation:
Is inertia a force (will give brainleist for first answer)
Answer:
Yes.
Explanation:
Answer:
I do believe it is. (more characters for character limit)
Consider the following three concentric systems two thick shells and a solid sphere all conductors The radii in the increasing order are a b c d and e The small sphere is given an excess charge of 3 C and the smaller shell is given an excess charge of 7 C The larger shell is electrically neutral The system quickly comes to electrostatic equilibrium state a Note that there are 5 conducting surfaces What are the electric charges values and signs on the each of them Are these charges distributed uniformly
Answer:
Explanation:
From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.
So, in light of that, to determine the electric charges values & signs on each of them, we have:
on a = +3 C
on b = -7 C
on c = -7 C
on d = +3 C
on e = -7 C
Olive and her friend Wellington are playing down by Captain Don's docks when they find an old chain. The old chain has only three links. By measuring with an old fish scale which is a permanent feature of the dock area, they determine that the total mass of the chain is 3.12 kg (the scale reads in newtons, but Olive knows how to calculate the mass of the chain from its weight). While playing with the scale and the chain (the chain is hanging vertically from the end of the scale, and Olive is holding on to the top of the scale with both hands, either moving the entire system upwards or downwards), Olive notices that if she is accelerating the chain either upwards or downwards, the scale no longer accurately reads the weight of the chain. When the Scale Reading is Larger than the Weight of the Chain At one point in their experiments with the chain and the scale, Wellington observes that the scale reads 47.00 N . Part A When the scale reads 47.00 N , what is the tension in the chain at the point where the lowest two links connect
Answer:
T₁ = 15.66 N
Explanation:
From the given information:
Using the free body system in the chain.
T - mg = ma
47 - 3.12 × 9.8 = 3.12a
47 - 30.576 = 3.12a
16.424 = 3.12a
a = 16.424/3.12
a = 5.26 m/s²
Now, by the free body diagram of the lowest link; the tension (T₁ ) in the chain is:
T₁ - (3.12/3) × 9.8 = (3.12/3) × 5.26
T₁ - 1.04 × 9.8 = 1.04 × 5.26
T₁ - 10.192 = 5.4704
T₁ = 5.4704 + 10.192
T₁ = 15.6624
T₁ = 15.66 N
A spring with a spring constant of 80 N/m is at rest and is attached to a block. If the block (attached to the end of the spring) is moved from 0.6 m to 0.4 m and then let go, what will be the spring force exerted on the block? Rightward is positive.
Answer:
–I6 N
Explanation:
From the question given above, the following data were obtained:
Spring constant (K) = 80 N/m
Initial position = 0.6 m
Final position = 0.4 m
Force (F) =?
Next, we shall determine the compression of the spring. This can be obtained as follow:
Initial position = 0.6 m
Final position = 0.4 m
Compression (x) =?
Compression = Final position – Initial position
Compression (x) = 0.4 – 0.6
Compression (x) = – 0.2 m
Finally, we shall determine the force. This can be obtained as follow:
Spring constant (K) = 80 N/m
Compression (x) = – 0.2 m
Force (F) =?
F = Kx
F = 80 × –0.2
F = –I6 N
For Water, determine the missing property and determine the state. 1) P = 300 kPA, v = 0.5 m3/kg. Find T 2) P = 28 MPa, T = 200oC. Find v 3) P = 1 MPa, T = 405 oC. Find v 4) T = 100oC, x = 60%. Find v
Answer:
1) LIQUID, 2) LIQUID, 3) GASEOU, 4) GASEOUS, v = 0.76 m³ / kg
Explanation:
In this exercise it is asked to determine the state of the water, that is, if it is solid, liquid or gas. For this we must use a phase diagram of water which is a graph of Pressure versus Temperature. Let's describe the water diagram
* Below 0ºC and normal pressure the water is in a solid state
* Below this temperature and at low pressure it becomes a gaseous state
* Above 0.01ºC and normal pressure is in liquid state
* Above 0.01ºC and low pressure is in a gaseous state
there are two important points
* The triple point at t + 0.01ºC and P = 0.006 atm where the three states coexist
* The critical point T = 374ºC and P = 218 atm where water decomposes into hydrogen and oxygen
Specific volume is related to density
v = 1 / ρ
ρ = 1 / v
the density of water is approximately 1000 kg / m³ in the liquid state at t = 4ºC and decreases with increasing pressure 960 kg / m³ at T = 100ºC (but without changing to the gaseous state
With the above considerations we can answer the questions
1) P = 300 kPa = 3 105 Pa
v = 0.5 m³ / kg
atmospheric pressure is Patm = 1.01 105 Pa
P = 3 105 Pa (1 atm / 1.01 105 Pa) = 3 atm
From the phase diagram described, the water can be in two liquid or gaseous states, depending on the temperature, as indicated by the speed of the same state, the water must be LIQUID
the parameter v that you indicate is the
with the other parameter we can calculate the density
rho = 1 / 0.5
rho = 2.0 kg / m³
in a thermodynamic system the three basic properties are: pressure, volume and temperature,
we can calculate the body temperature
The body must be at a temperature between 0 <T <100ºC
2) P = 28 Mpa = 28 106 Pa
P = 28 106 Mpa (1 atm / 1.01 105 Pa) = 280 atm
T = 200ºC
When examining the diagram it can be seen that the water is in the range of the LIQUID state
3) P = 1MPa
P = 1 106 Pa (1atm / 1.01 105Pa) = 10 atm
T = 405ºC
In this case, the only accessible state is the GASEOUS
4) T = 100ºC
x = 60%
Examining the phase diagram at this temperature depending on the pressure the possible states are Vapor and liquid, for pressures below 1 atm the state is GASEOUS
for the gaseous state we can use the ideal gas equation
PV = nR T
let us perform the calculation for a mole of gas n = 1, the ideal gas constant is R = 8,206 10-2 atm / mol K
V = nRT / p
V = 1 8,206 10-2 100/1
V = 8,206 m³
v = V / m
The mass of the water is 18 Kg / mol, which indicates that 60% is in the gaseous state, so the mass in this state is
m = 0.60 18
m = 10.8 kg
v = 8.206 / 10.8
v = 0.76 m³ / kg
5. Atoms may emit light energy when
O A electrons move to a lower energy level
OB protons move to a lower energy level
C electrons move to a higher energy level
OD protons move to a higher energy level
Hi
How are you all
Please I need help from anyone who know physics.
In these lessons the questions will be friction,vectors, forces in two dimensions.
So, Please to anyone who can help Write a comment,And I'll be in touch with him, thanks everyone
Answer:
umm it says he but I'm a she :p
A 1.3-kg book rests on a table. A downward force of 15 N is exerted on the top of the book by a hand pushing down on the
book
What is the net force on the book?
Answer:
The net force will be:
[tex] F_{net} = 142.53\: N[/tex]
Explanation:
The net force is given by:
[tex] F_{net} = W_{b}+F[/tex]
[tex] F_{net} = m_{b}g+15[/tex]
[tex] F_{net} = 142.53\: N[/tex]
I hope it helps you!
0.55 kg mouse moving E at 60m s or a 900 kg elephant moving E at 0.03m Which has the most momentum?
Answer:
the mouse
Explanation:
the mouse has a momentum of 33 m kg/s
while the elephant has a momentum of 27 m kg/s
i found this out using p=mv
can a body have an east velocity while expressing westward acceleration
Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.
Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.
Hope this helped!
all of the following elements will form ions by losing electrons except
aluminum
iron
sodium
oxygen
Which of the following best defines effective listening?
Answer:
The following seems to be the summary including its given phrase.
Explanation:
The willingness to adequately consider the knowledge another speaker provides as well as show interest throughout the subject covered constitutes skills of effective listening. Truly wonderful hearing skills require an individual just to listen fully to the information such that a relevant reading of the information or a piece of evidence can be done.g Consider a (12.5 A) cm long metal bar moving horizontally across a vertical magnetic field at a speed of (2.40 B) m/s. The magnetic field strength is 2.45 T. If the ends of the bar are connected to a (1.20 C) ohm resistor, find the power dissipated in the resistor while the bar is moving. Calculate the answer in watts (W) and rounded to three significant figures.
Answer:
Explanation:
emf due to movement of a rod of length L in a perpendicular to magnetic field B with velocity v is given as
emf = BLv
Putting in the given values ,
E = 2.45 x 12.5 x 10⁻² x 2.4
= .735 V
This emf produces current in resistance . Power consumed by resistance
V² / R where R is resistance , V is emf induced .
Power = .735² / 1.2
= .45 W .
I need help on how to start my essay on the 3 laws of motion
Answer:
for the first paragraph introduce the definition. for the second paragraph write about the first law, for the third paragraph write about the 2nd for the fourth paragraph write about the 3rd law. for the last paragraph do a brief summary of what you wrote and a conclusion about the laws.
i hope this helps a bit
Answer:
You can start off with the first law of motion (newtons first law), talk about what it is or what it does, give examples.
Explain how magnets have an attractive force and repulsive force
.) What will be the unit of time in that system in
which unit of length is m, unit of mass is kg and
unit of force is kg wt?
(a) [1/V(9.8) second (b) (9.8)2 second
(c) V(9.8) second
(d) 9.8 second
Answer:
yes it is a great question. Thank you .
How far can you get away from your little
brother with the squirt gun filled with
paint if you can travel at 3 m/s and you
have 15s before he sees you?
Know
Find
Equation
Solve
spray him in the eyes and you have until he washes it put
Calculate the momentum of a 6 kg ball thrown at 20 m/s by a 3 newton
force. *
Answer:
momentum = mass × velocity = 6× 20 =120 kg.ms-1
Explanation:
not sure if this is right
URGENT HELP !! The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively. How much horizontal force would you need to apply to a 34.4 kg object to start it moving from rest?
Answer:
43.83 N
Explanation:
Given that,
The mass of an object, m = 34.4 kg
The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.
The force of static friction,
[tex]F_s=\mu_smg\\\\F_s=0.53\times 34.4\times 9.8\\\\F_s=178.67\ N[/tex]
The force of kinetic friction,
[tex]F_k=\mu_kmg\\\\F_k=0.40\times 34.4\times 9.8\\\\F_k=134.84\ N[/tex]
Net force acting on the object is :
F = 178.67-134.84
= 43.83 N
Hence, this is the required solution.
can someone please answer this for me ❤️
Answer:
I don't understand the question
Explanation:
sorry I cant help because I am just a first former
What is the difference between inertia and momentum?
State the four factors the magnetic force moving in magnetic field depends on
Explanation:
It depends upon the magnitude of the charge, the velocity of the particle and its strength .
HELP ASAP PLS ILL GIVE YOU BRAINLIEST
Select the correct answer.
Which civilization was the first to record a solar eclipse?
A.
Greek
B.
Chinese
C.
Aztec
D.
Polynesian
Answer:
chinese
Explanation:
Answer:
B chinese
hope this helps you
The starter motor of a car engine draws an electric current of 110 A from the battery. The copper wire to the motor is 4.20 mm in diameter and 1.73 m long. The starter motor runs for 0.95 s before the car engine starts up.
How much electric charge passes through the starter motor?
________
What is the current density in the wire?
_________
How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)
________
Answer:
a. 104.5 C b. 7.94 × 10⁶ A/m² c. 5.83 × 10⁻⁴ m/s
Explanation:
a. How much electric charge passes through the starter motor?
Using Q = It where Q = electric charge passing through the starter motor, I = current = 110 A and t = time = 0.95 s
So, Q = It = 110 A × 0.95 s = 104.5 C
b. What is the current density in the wire?
The current density, J = I/A where I = current = 110 A and A = cross-sectional area = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m
So, J = I/A
= I/πd²/4
= 4I/πd²
= 4 × 110 A/π(4.20 × 10⁻³ m)²
= 440 A/55.42 × 10⁻⁶ m²
= 7.94 × 10⁶ A/m²
c. How far does an electron travel along the wire while the starter motor is on? (The density of conduction electrons in copper is n = 8.50×1028 1/m3.)
To find how far the electron travels, we need to find the electron drift velocity from
J = nev where J = current density = 7.94 × 10⁶ A/m², n = electron density = 8.50 × 10²⁸ m⁻³, e = electron charge = 1.602 × 10⁻¹⁹ C, v = drift velocity of electrons and A = cross-sectional area of wire = πd²/4 where d = diameter of copper wire = 4.20 mm = 4.20 × 10⁻³ m
So, v = J/ne
Substituting the values of the variables into the equation, we have
v = 7.94 × 10⁶ A/m² ÷ (8.50 × 10²⁸ m⁻³ × 1.602 × 10⁻¹⁹ C)
v = 7.94 × 10⁶ A/m² ÷ (13.617 × 10⁹ Cm⁻³)
v = 0.583 × 10⁻³ m/s
v = 5.83 × 10⁻⁴ m/s
What is the subject Physic about
Explanation:
Physics is the branch of science concerned with the study of the properties and interactions of space, time, matter and energy.
Answer:
if you are very excited to know why ball doesn't go up
Question 7 of 10
What is cos(22")?
O A. 0.93
B. 0.22
C. 0.37
O D. 0.40
Answer:
A. 0.93
Explanation:
As the mass of object increased it is density increased
Answer:
True.
Explanation:
The density of an object is given by its mass divided by its volume. It can be given as follows :
[tex]d=\dfrac{m}{V}[/tex]
It can be seen that the density of an object is directly proportional to its mass. It means if the mass of an object increase, its density will also increase. Hence, the given statement is true.