Police body cameras: A survey of New York State residents asked about police officers having to wear video cameras on duty. The question stated, "Do you agree or disagree that police officers should carry video cameras for the purposes of filming their activities while on duty?" Most (88%) respondents agreed with this statement. Do Californians share the same opinion? A California-based civil rights group conducted a similar survey by randomly selecting 500 California residents, and 425 agreed that police officers should carry video cameras for the purposes of filming their activities while on duty. Conduct a hypothesis test to determine if the proportion of California residents who agree is different from New York residents. Use a 5% significance level to make your decision. Use the applet (at the top of this Checkpoint) to determine the P-value. Which of the following is an appropriate conclusion based on the results?

a. The survey provides strong evidence that the proportion of California residents who agree that police officers should carry video cameras for the purposes of filming their activities while on duty is significantly different from the proportion of New York residents.

b. The survey suggests that the proportion of California residents who agree that police officers should carry video cameras for the purposes of filming their activities while on duty is 85%.

c. Of the California residents surveyed, 85% agree that police officers should carry video cameras for the purposes of filming their activities while on duty, but this is not strong enough evidence to conclude that the proportion of California residents who agree is significantly different from the proportion of New York residents.

d. This survey suggests that 88% of California residents surveyed agree that police officers should carry video cameras for the purposes of filming their activities while on duty.​

Answer:

[tex](-5,-4)[/tex]

Step-by-step explanation:

Given

[tex]P = (5,4)[/tex]

Rotation: 180 degrees counterclockwise

Required

P'

Rotation: 180 degrees counterclockwise

The rule is:

[tex](x,y) \to (-x,-y)[/tex]

So: [tex]P = (5,4)[/tex] becomes

[tex](5,4) \to (-5,-4)[/tex]

Answer:

The answer is 181

Step-by-step explanation:

PEDMAS

1 x 1 + 9 x 20

1 x 1 = 1

1 + 9 x 20

9 x 20= 180

1+180

which equals 181

Answer:

181

Step-by-step explanation:1x1=1 9x20=180+1=181

Thats your answer my fellow brains

9514 1404 393

Answer:

Step-by-step explanation:

The law of sines tells you the ratio of sides is the same as the ratio of sines of their opposite angles.

This post has 2 kinds of problems.

1) 2 angles and the side between them are given.

2) 2 sides and the angle opposite the longest is given.

For the first type, you need to determine the missing angle (opposite the given side). That comes from the sum of angles of a triangle being 180°. Then you find the remaining sides using the ratio of sines.

For the second type, the angle opposite the shorter side is found using the ratio of sides to find the sine of that angle. Then the third side and third angle can be found using the ratio of sides to find the sine of the angle, and using the ratio of sines to find the missing side.

Straightforward, and tedious. For more than one, I like to use a spreadsheet to crunch the numbers.

_____

1) BC = 24.0

2) AC = 26.0

3) m∠B = 73.4°

4) m∠B = 30.0°

__

In the spreadsheet, the given values are in the first 3 columns. The 4th column is the first one calculated. As indicated above, the angle calculation for problems 1 and 2 uses the sum of angles relation. For problems 1 and 2, this is the angle opposite the given side. The "first side" is the side opposite the "first angle". c = b·sin(C)/sin(B), for example.

For problems 3 and 4, the first unknown angle is the one opposite the "short side", which is the shorter of the given sides. As it happens, this is the side that is asked for in the question. B = arcsin(c·sin(B)/sin(C))

_____

Additional comment

In a spreadsheet, angles are presumed to be in radians for all of the trig functions. We use the DEGREES( ) and RADIANS( ) functions to convert as appropriate.

Answer:

a. 3/4

Step-by-step explanation:

6:8

=6/8

=3/4

Hope it Helps

Answer:

a-16 and a half c-12

Step-by-step explanation:

Answer: 14

Step-by-step explanation:

1/16x = 7/8

x = 7/8*16/1 = 14

He can sell his candy

Give away to people.

Answer:

80

Step-by-step explanation:

18^2 + 80^2 = 82

324 + 160 = c^2

Answer:

80 cm

Step-by-step explanation:

To solve this problem, you can use the pythagorean theorem which is a^2 + b^2 = c^2. We are given that a = 18, and c as the hypotenuse equals to 82. We can plug these numbers into the theorem:

18^2 + b^2 = 82^2

324 + b^2 = 6724

b^2 = 6400

b = 80 cm

Answer:

20 questions

Step-by-step explanation:

There is 15% of the test left and 3 questions

15/3 = 5

85/5 = 17

17+ 3 = 20

Answer:

In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume.

Step-by-step explanation:

In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume.

Answer:

Y values will stay the same

Step-by-step explanation:

Reflecting over the Y axis will alter the distance left and right but not up and down. so only Y remains unchanged

Answer:

I hope this helps you hehehe :)

Step-by-step explanation:

=√256

=√4×4×4×4

=√4^4

=44/2

=4^2

=16

Answer:

[tex]Worth = \$284258.1[/tex]

Step-by-step explanation:

Given

[tex]Dimension: 7in\ * 3in\ * 1in[/tex]

[tex]Value = \$1214/oz[/tex] ---- value of Gold

Required

The worth of 1 gold bar

First, calculate the volume (n) of the gold bar

[tex]n = 7in * 3in * 1in[/tex]

[tex]n = 21in^3[/tex]

Next, calculate the weight of the gold bar using:

[tex]w = 11.15n[/tex]

[tex]w = 11.15 * 21[/tex]

[tex]w = 234.15oz[/tex]

Multiply the value of Gold by the weight of the gold bar to get the worth of the gold bar.

[tex]Worth =Value * w[/tex]

This gives:

[tex]Worth = \$1214/oz * 234.15oz[/tex]

[tex]Worth = \$1214 * 234.15[/tex]

[tex]Worth = \$284258.1[/tex]

Answer:

0.088

Step-by-step explanation:

Given two cylinders

Volume of one = 64cm^3

Volume of the other = 729cm^2

Scale factor = Volume of the small/Volume of the large

Scale factor = 64:729

Scale factor = 0.087

Answer:

b = 7.56

C = 9.24

Step-by-step explanation:

Find the last angle of the triangle.

The sum of all the angles in a triangle is  

180 degrees.

A+

90+55=180

A=35

Then find c

The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.

cos(B)=adj/hyp or Cos(55) = 5.3 / c

re write as

C = 5.3 / cos55

This gives you c = 9.24

Then use the Pythagorean theorem to find the unknown side.

[tex]a^{2} +b^{2} = c^{2} \\rewrite as\\ b^{2} = c^{2} - a^{2} \\b^{2} = 9.2^{2} - 5.3^{2} \\b^{2} = 57.29\\b = 7.56[/tex]

Answer:

D

Step-by-step explanation:

When you are raising something to a fractional power, you are raising it to the power of the numerator and finding the root denoted by the denominator. The explanation above is kinda confusing, so here is an example:

x^(3/5)

This would be written as:

[tex]\sqrt[5]{x^3}[/tex]

Now for the actual problem. Since the numerator is 4, we start by raising x to the 4th power, x^4.

Because the denominator is 5, we find the 5th root:

[tex]\sqrt[5]{x^4}[/tex]

This matches none of the answers shown, so the answer is none of the above or D.

Answer:

D

Step-by-step explanation:

The answer would be 5 square root x^4

See Image Below:)

Answer:

The area of the given figure is 87.55 cm square.

Answer:

10

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

Plug in 6 to x, since this is the x-value in the ordered pair.

[tex]3(6)+2y=36\\18+2y=36\\2y=18\\y=9[/tex]

Answer:

(6, 9)

Step-by-step explanation:

3x + 2y = 36

Substitute 6 into the equation to get the output.

3(6) + 2y = 36

Multiply 3 and 6.

18 + 2y = 36

Subtract 18 from both sides.

2y = 18

Divide both sides by 2.

y = 9

The ordered pair when x = 6 is

(6, 9)

Answer:

Step-by-step explanation:

Area = height × side

21   = 3 * side

side = 7 cm

The side of a rhombus is half the longer diagonal

longer diagonal = 2*side =2*7=14cm

Answer:

x = 14 for the first one, x = 60 for the second one

Step-by-step explanation:

Step-by-step explanation:

We know the measure of a straight line is 180° . So that ,

> 5x - 10 + 120 = 180

> 5x = 60 + 10

> 5x = 70

> x = 70/5

> x = 14

Solution 2 :-

> x + 50 + 70 = 180

> x = 180 - 120

> x = 60

Answer:

a) Acceleration = 2.4 m per seconds²

b) Distance traveled = 132 m

Step-by-step explanation:

a). Acceleration of an object is defined by the equation,

v = u + at

Here, v = Final speed

u = Initial speed

a = Acceleration

t = Duration Or time

From the graph attached,

Between t = 0 and t = 5 seconds,

v = 12 meter per second

u = 0

t = 5 seconds

B substituting values in the equation,

12 = 0 + a(5)

a = [tex]\frac{12}{5}[/tex]

a = 2.4 m per seconds²

b). Equation representing distance traveled by an object,

v² = u² + 2as

Here, v = Final speed

u = Initial speed

a = Acceleration

s = Distance traveled

By substituting these values in the given equation,

1). Between t = 0 to t = 5 seconds,

(12)² = 0 + 2(2.4)s

s = [tex]\frac{144}{4.8}[/tex]

s = 30 m

2). Between t = 5 to t = 12 sec

Car moved with a constant speed (Acceleration = 0)

Distance traveled = Speed × Time

                             = 12 × 7

                             = 84 m

3). Acceleration of the car between t = 12 sec to t = 15 sec

By substituting the values in the equation,

v = u - at

0 = 12 - a(3)

a = 4 meter per seconds²

Distance traveled in this duration,

v² = u² - 2as

0 = (12)² - 2(4)s

144 = 8s

s = [tex]\frac{144}{8}[/tex]

s = 18 m

Therefore, total distance covered by the car = 30 + 84 + 18

= 132 meters

Answer:

7,000,000

Step-by-step explanation:

Limit of a function:

The limit of a function is finding looking at it's lateral limits.

If the lateral limits are equal:

The limit exists.

[tex]\lim_{x \rightarrow a} f(x) = \lim_{x \rightarrow a^{+}} f(x) = \lim_{x \rightarrow a^{-}} f(x)[/tex]

If lateral limits are different:

That is:

[tex]\lim_{x \rightarrow a^{+}} f(x) \neq \lim_{x \rightarrow a^{-}} f(x)[/tex], then the limit does not exist.

In this question:

To the left of 1, that is, 0.9999....

[tex]\lim_{x \rightarrow 1^{-}} g(x) = 7,000,000[/tex]

To the right of 1, that is, 1.0001...

[tex]\lim_{x \rightarrow 1^{+}} g(x) = 7,000,000[/tex]

Since the both limits are the same, the limits exists and it's value is of  7,000,000.

Answer:

D

Step-by-step explanation:

It shows it in the quwestions image

Answer:

(D) The passenger's height aloe the ground is increasing by 15.708 meters per minute 7.5 minutes after the ride begins.

Step-by-step explanation:

Here, H(t) is the height after the t minutes of time.

Given :

H'(7.5) = 15.708 meters / minute

H'(t) = [tex]$\frac{d(H(t))}{dt}$[/tex]

     = rate of change of the height

So, here, H'(t) = rate of change of height

Therefore, H'(7.5) = 15.708 meters / minute

It shows that the passenger's height is increasing at rate 15.708 meters per minute at time t = 7.5 minutes after the ride begins.

9514 1404 393

Answer:

  -1 is in the domain of fºg

Step-by-step explanation:

Both functions are odd-degree polynomials (as written here), so both functions have a domain and range of "all real numbers."

  -1 is in the domain of f(g(x))

Answer:

Yes, it is a right triangle.

Step-by-step explanation:

8²+15²=17²

64+225=289

289=289 YES, it is a right triangle