Point M is in the exterior of an angle AOB, ray OC is a bisector of this angle. Prove, that the measure of angle MOC is equal to one-half the sum of the measures of angles AOM and BOM.

Answers

Answer 1

Answer:

see the prove below

Step-by-step explanation:

We have to prove that MOC=(AOM+BOM)/2

Let Angle AOM=x and AOC=y .  => AOB=2y ( because OC is the bisector of AOB)

So MOC= AOM+AOC=x+y

BOM=AOB+AOM=2y +x

AOM+BOM= x+2y+x=2y+2x

(AOM+BOM)/2= (2y+2x)/2=x+y=MOC

The statement is proved


Related Questions

The prize in a raffle is a flat-screen TV valued at $350, and 1,000 tickets are sold for a dollar each. Let’s find the expected value if you buy 1 ticket. Find the expected value. Round your answer to two decimal places. Remember a gain would be posit

Answers

Answer:

the expected value EV = −$0.65

Step-by-step explanation:

Expected value EV = expected gain - expected loss

Given;

Cost of a ticket L = $1

Probability of losing the ticket P(L)= 999/1000 = 0.999

Cost of a flat screen TV = $350

Expected gain G = $350 - $1 = $349

Probability of winning the TV P(G) = 1/1000 = 0.001

EV = G × P(G) - L × P(L)

Substituting the values;

EV = $349 × 0.001 - $1 × 0.999

EV = −$0.65

the expected value EV = −$0.65

John multiplied 400,000 by 7,800 on his calculator. He got the result shown on his calculator display. What is this number in standard form? A calculator screen that shows 3 point 1 2 E 9. A 0.00000000312 B 0.000000312 C 312,000,000 D 3,120,000,000

Answers

Answer:

D

Step-by-step explanation:

jtrsytexjgfcgvhjbkjnhgfdsasdfghjhgrertyu

Answer:

Correct answer is D

Step-by-step explanation:

Manueala scored -4 \dfrac12−4 2 1 ​ minus, 4, start fraction, 1, divided by, 2, end fraction points relative to her season average against the China Dragons. She scored 1 \dfrac121 2 1 ​ 1, start fraction, 1, divided by, 2, end fraction points relative to her season average against the Canada Moose. Drag the white cards onto the gray rectangle to write an inequality that correctly compares Manueala's relative numbers of points. Which one of the following descriptions is correct? Choose 1 answer: Choose 1 answer: (Choice A) A Manueala scored more points against the China Dragons than against the Canada Moose. (Choice B) B Manueala scored more points against the Canada Moose than against the China Dragons.

Answers

Answer:

1 1/2 > - 4 1/2  and                                                                                                      Manuela scored more points against the Canada Moose than against the China Dragons.

Find the value of x. Please help! Thanks.

Answers

Answer:

[tex]\huge\boxed{x=\sqrt{30}}[/tex]

Step-by-step explanation:

ΔABC and ΔBDC are similar (AAA).

Therefore the corresponding sides are in proportion:

[tex]\dfrac{AC}{BC}=\dfrac{BC}{CD}[/tex]

substitute

[tex]AC=7+3=10\\{BC}=x\\CD=3[/tex]

[tex]\dfrac{10}{x}=\dfrac{x}{3}[/tex]           cross multiply

[tex](10)(3)=(x)(x)\\\\30=x^2\\\\x^2=30\to x=\sqrt{30}[/tex]

Please help me!!!!!!!!

Answers

Step-by-step explanation:

might be option c is a correct answer of your given question

Given that IG is perpendicular to FT, which of the following statements is true?

Answers

Answer:

B ). IF = IT

Step-by-step explanation:

IG is perpendicular to FT, means that the line IG divides the line FT into two equal parts without remainder.

Line IG does not only divide line FT, it also bisect the arc FT into two equally parts also.

It also divide the segment of the circle FIT into two equal parts.

So to the correct answer to the question, IF = IT

What is the greatest common factor of the polynomial below 12x^2-9x

Answers

Answer:

the greatest common factor of this is 3

The World Issues club has decided to donate 60% of all their fundraising activities this year to Stephen Lewis
Foundation. This foundation was created to help ease the pain of HIV/AIDS in Africa Lewis, a Canadian
works for the United Nations trying to determine ways to stop the spread of this deadly disease from crippling
an entire continent
a. Choose a variable to represent the money earned during fundraising activities and the revenue generated
for the foundation
b. Use these variables to create an equation that will determine the amount of money the foundation will
receive
c. In their latest bake sale, the club raised $72. Calculate the amount the foundation will receive
d. At the end of the year, the World Issues Club mailed a cheque to the foundation for $850. How much
money did they fundraise in total?​

Answers

Answer:

a. Let the variable be [tex]x[/tex] for the fundraising activities and [tex]M[/tex] as the revenue for foundation.

b. [tex]M =0.60x[/tex]

c. $43.2

d. $1416.67

Step-by-step explanation:

Given that:

The World Issues club donates 60% of the total of their fundraising activities.

Answer a.

Let us choose the variable [tex]x[/tex] to represent the money earned during fundraising activities and [tex]M[/tex] for the revenue generated for foundation.

Answer b.

Foundation will receive 60% of the total of the fundraising activities.

Equation to determine the money that will be received by foundation:

[tex]M = 60\%\ of\ x\\OR\\M = 0.6x[/tex]

Answer c.

Given that x = $72, M = ?

Putting the value of x in the equation above:

[tex]M = 0.6 \times 72\\\Rightarrow \$43.2[/tex]

Answer d.

Given that M = $850, x = ?

Putting the value of M in the equation above to find x:

[tex]850= 0.6 \times x\\\Rightarrow x = \dfrac{850}{0.6}\\\Rightarrow x = \$ 1416.67[/tex]

So, the answers are:

a. Let the variable be [tex]x[/tex] for the fundraising activities and [tex]M[/tex] as the revenue for foundation.

b. [tex]M =0.60x[/tex]

c. $43.2

d. $1416.67

(1 point) A vendor sells ice cream from a cart on the boardwalk. He offers vanilla, chocolate, strawberry, blueberry, and pistachio ice cream, served on either a waffle, sugar, or plain cone. How many different single-scoop ice-cream cones can you buy from this vendor

Answers

Answer:

six single scoops icecream cones

Consider the following hypothesis test:
H0:
≤ 50
Ha: > 50
A sample of 55 is used and the population standard deviation is 6. Use the critical value approach to state your conclusion for each of the following sample results. Use = .05.
a. With = 52.5, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
b. With = 51, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
c. With = 51.8, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No

Answers

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

[tex]H_0: \mu\leq50\\\\H_a:\mu> 50[/tex]

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809[/tex]

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09[/tex]

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24[/tex]

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22[/tex]

The null hypothesis is rejected, as z>zc and falls in the rejection region.

The average annual cost (including tuition, room, board, books and fees) to attend a public college takes nearly a third of the annual income of a typical family with college-age children (Money, April 2012). At private colleges, the average annual cost is equal to about 60% of the typical family's income. The following random samples show the annual cost of attending private and public colleges. Data are in thousands of dollars.Private Colleges 52.8 30.6 43.2 45.8 45.0 37.8 33.3 50.5 44.0 42.0 Public Colleges 20.3 22.8 22.0 25.8 28.2 18.5 15.6 25.6 24.1 14.4 28.5 21.8 a. Compute the sample mean and sample standard deviation for private and public colleges. Round your answers to two decimal places.
S1 =
S2 =
b. What is the point estimate of the difference between the two population means? Round your answer to one decimal place.
Interpret this value in terms of the annual cost of attending private and public colleges.$
c. Develop a 95% confidence interval of the difference between the annual cost of attending private and pubic colleges.
95% confidence interval, private colleges have a population mean annual cost $ to $ more expensive than public colleges.

Answers

Answer:

Step-by-step explanation:

a) For private colleges,

Mean = (52.8 + 30.6 + 43.2 + 45.8 + 45.0 + 37.8 + 33.3 + 50.5 + 44.0 + 42.0)/10 = 42.5

x1 = 42.5 × 1000 = 42500

Standard deviation = √(summation(x - mean)²/n

n = 10

Summation(x - mean)² = (52.8 - 42.5)^2 + (30.6 - 42.5)^2 + (43.2 - 42.5)^2 + (45.8 - 42.5)^2 + (45.0 - 52.5)^2 + (37.8 - 42.5)^2 + (33.3 - 42.5)^2 + (50.5 - 42.5)^2 + (44.0 - 42.5)^2 + (42.0 - 52.5)^2 = 598.56

standard deviation = √(598.56/10 = 7.74

s1 = 7.74 × 1000 = 7740

For public colleges,

Mean = (20.3 + 22.8 + 22.0 + 25.8 + 28.2 + 18.5 + 15.6 + 25.6 + 24.1 + 14.4 28.5 + 21.8)/12 = 22.3

x2 = 22.3 × 1000 = 22300

n2 = 12

Summation(x - mean)² = (20.3 - 22.3)^2 + (22.8 - 22.3)^2 + (22 - 22.3)^2 + (25.8 - 22.3)^2 + (28.2 - 22.3)^2 + (18.5 - 22.3)^2 + (15.6 - 22.3)^2 + (25.6 - 22.3)^2 + (24.1 - 22.3)^2 + (14.4 - 22.3)^2 + (28.5 - 22.3)^2 + (21.8 - 22.3)^2 = 225.96

standard deviation = √(225.96/12 = 4.34

s2 = 4.34 × 1000 = 4340

b) The point estimate is the difference between the sample means

Point estimate = 42500 - 22300 = 20200

The best guess for the difference in population mean annual cost of attending private and public colleges is $20200. The range of the value is determined by the margin of error.

c) Confidence interval = point estimate ± margin of error

Margin of error = z√(s²/n1 + s2²/n2)

Where z is the test score for 95% confidence level from the t distribution table. To find the test score, we would first find degree of freedom, df

df = (n1 - 1) + (n2 - 1) = (10 - 1) + (12 - 1) = 20

From the t distribution table,

z = 2.086

Margin of error = 2.086√(7.74²/10 + 4.34²/12) = 4.84

4.84 × 1000 = 4840

Confidence interval = 20200 ± 4840

If 10 is added to the maximum value and 10 is subtracted from the minimum value of a set of ages of citizens waiting in line to vote, which of the following is true? a-The mean age and median age are unchanged. b-The mean age changes but the median age does not change. c- The median age changes but the mean age does not change. d-The effect on the mean and median cannot be determined without knowing the other ages. e-None of these.

Answers

Answer:

a-The mean age and median age are unchanged.

Step-by-step explanation:

By adding the same you are subtracting, the sum of the ages remains the same. Therefore, the mean remains the same since you are dividing the same total of ages by the same number of people.

The middle number continues to be the middle number, so the median also does not change.

Try an example.

The ages are 30, 40, 50, 60, 70

Mean = (30 + 40 + 50 + 60 + 70)/5 = 250/5 = 50

Median: 50

Now add 10 to the greatest value and subtract 10 from the least value.

The ages now are 20, 40, 50, 60, 80

Mean = (20 + 40 + 50 + 60 + 80)/5 = 250/5 = 50

Median: 50

As you can see, both the mean and the median did not change.

Answer: a-The mean age and median age are unchanged.

Answer:

The mean age and median age are unchanged

Step-by-step explanation:

The median will not change when we alter the lowest and highest values so we can eliminate the answers that say the median changes

The mean is found by adding the values together and dividing by the number of values

If we add 10 and subtract 10, we have not changed the total value before dividing, so the mean does not change

A Norman window has the shape of a rectangle surmounted by a semicircle. (Thus the diameter of the semicircle is equal to the width of the rectangle.) If the perimeter of the window is 30 ft, find the dimensions of the window so that the greatest possible amount of light is admitted.

Answers

The dimensions of the Norman window that admit the greatest possible amount of light are approximately:

Width (w) ≈ 11.72 ft

Height (h) ≈ 2.91 ft

To find the dimensions of the Norman window that admit the greatest possible amount of light, we need to maximize the area of the window. The window consists of a rectangle and a semicircle, so the area is the sum of the areas of both shapes.

Let's assume the width of the rectangle is "w" and the radius of the semicircle is "r".

Since the diameter of the semicircle is equal to the width of the rectangle, the radius "r" is half of "w".

Area of the rectangle = w * h, where h is the height of the rectangle.

Area of the semicircle = (1/2) * π * r²

The perimeter of the window is given as 30 ft, which can be written as:

Perimeter = 2 * (w + h) + π * r + w

Since r = w/2, we can rewrite the perimeter equation as:

Perimeter = 2 * (w + h) + (π/2) * w + w

Perimeter = 2w + 2h + (π/2 + 1) * w

Given that the perimeter is 30 ft, we have:

30 = 2w + 2h + (π/2 + 1) * w

Now, we can express "h" in terms of "w" using the perimeter equation:

h = (30 - 2w - (π/2 + 1) * w) / 2

Next, let's express the area "A" of the window in terms of "w" using the formulas for the area of the rectangle and the semicircle:

Area (A) = Area of rectangle + Area of semicircle

A = w * h + (1/2) * π * r²

A = w * ((30 - 2w - (π/2 + 1) * w) / 2) + (1/2) * π * (w/2)²

A = w * ((30 - 2w - (π/2 + 1) * w) / 2) + (1/2) * π * (w² / 4)

Now, we want to maximize the area "A."

To find the maximum value, we take the derivative of "A" with respect to "w" and set it equal to zero:

dA/dw = (30 - 2w - (π/2 + 1) * w) / 2 + (π/4) * w = 0

Solving for "w":

(30 - 2w - (π/2 + 1) * w) / 2 + (π/4) * w = 0

(30 - 2w - (π/2 + 1) * w) + (π/2) * w = 0

(30 - (2 + π/2) * w) + (π/2) * w = 0

30 - (2 + π/2) * w + (π/2) * w = 0

(30 - 2w) + (π/2 - π/4) * w = 0

30 - 2w + (π/4) * w = 0

(π/4) * w - 2w = -30

w ((π/4) - 2) = -30

w = -30 / ((π/4) - 2)

w ≈ 11.72 ft

Now that we have the value of "w," we can find the value of "h" using the perimeter equation:

Perimeter = 2w + 2h + (π/2 + 1) * w

30 = 2(11.72) + 2h + (π/2 + 1) * (11.72)

30 = 23.44 + 2h + (π/2 + 1) * 11.72

2h = 30 - 23.44 - (π/2 + 1) * 11.72

2h = 6.56 - (π/2 + 1) * 11.72

h = (6.56 - (π/2 + 1) * 11.72) / 2

h ≈ 2.91 ft

So, the dimensions of the Norman window that admit the greatest possible amount of light are approximately:

Width (w) ≈ 11.72 ft

Height (h) ≈ 2.91 ft.

To learn more on derivative click:

brainly.com/question/12445967

#SPJ4

Emily and George had a farm with a new barn.
True
False

Answers

Answer:

true

Step-by-step explanation:

it is so because they are brother and sister

And in the chapter there is that they had farm with a new barn

if in your book lesson there is that they had no farm with a new barn then there will be false

Now did you understood?

Answer:

True

Step-by-step explanation:

two cards are drawn without replacement from a standard deck of 52 playing cards. what is the probability of choosing a diamond and then without replacement another diamond? express your answer as a fraction or decimal number rounded to four decimal places.

Answers

Answer:

1/17

Step-by-step explanation:

There are 13 diamond cards in a standard 52-card deck.

First drawing:

13 diamonds

52 total cards

After the first drawing you already took a diamond, so there are 12 diamonds left out of 51 total cards.

p(diamond and diamond) = 13/52 * 12/51 = 1/4 * 4/17 = 1/17

If you can help with the explanation I will mark brainpower

Answers

Answer:

It is 90º

Step-by-step explanation:

Looking at the picture, we realize that the angle direcly beside it, EGD, is 90º. Now, both angles form a straight line, which equals 180º. 180-90= 90º.

Answer: A 40 B 50 C 90 D 130

where they go: B goes under A, D goes under the whole thing, just like E (although that doesn't want to be answered) and C goes under B

hope this helped

What is the circumference of the circle below? (Round your answer to the nearest tenth.)

Answers

Hey there! :)

Answer:

75.4 cm.

Step-by-step explanation:

Formula for the circumference of a circle:

C = 2rπ

Given:

r = 12 cm

Plug this value of r into the equation:

C = 2(12)π

C = 24π

Multiply by π (3.14)

24 × 3.14 = 75.36 cm

Round to nearest tenth:

75.36 ≈ 75.4 cm.

Answer: B

Step-by Step: C=2n

r= 2•n•12= 75.39822

You round it to the nearest tenth, it would be 75.4

In a random sample of 964 young adults aged 18-29, it was found that 196 of them were married. Construct a 99% confidence interval for the proportion of married young adults aged 18-29.

Answers

Answer:

99% confidence interval for the proportion of married young adults aged 18-29.

(0.1779 , 0.2287)

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 964

Given data a random sample of 964 young adults aged 18-29, it was found that 196 of them were married

sample proportion

                           [tex]p^{-} = \frac{196}{964} = 0.2033[/tex]

Step(ii):-

99% confidence interval for the proportion of married young adults aged 18-29.

[tex](p^{-} - Z_{0.05} \sqrt{\frac{p^{-}(1-p^{-} ) }{n} } ,p^{-} +Z_{0.05} \sqrt{\frac{p^{-}(1-p^{-} ) }{n} })[/tex]

[tex](0.2033 -1.96 \sqrt{\frac{0.2033(1-0.2033 ) }{964} } ,0.2033 +1.96\sqrt{\frac{0.2033(1-0.2033 ) }{964} })[/tex]

(0.2033 -  0.02540 , 0.2033 +0.02540)

(0.1779 , 0.2287)

Conclusion:-

99% confidence interval for the proportion of married young adults aged 18-29.

(0.1779 , 0.2287)

Given an objective function value of 150 and a shadow price for resource 1 of 5, if 10 more units of resource 1 are added (assuming the allowable increase is greater than 10), what is the impact on the objective function value?

Answers

Answer:

The impact on the objective function is that it is increased by 50.

Step-by-step explanation:

In this case we have that the value of the objective function is 150, and they tell us that 10 more units of resource one are added, but they tell us that the shadow price ranges from 1 to 5, therefore:

10 * 5 = 50

Which means that the impact on the objective function is that it is increased by 50.

Please answer this correctly

Answers

Answer:

9/49

Step-by-step explanation:

The probability of landing on an even number is 3/7.

Because there are only 3 numbers even out of 7 total numbers.

[tex]3/7 \times 3/7[/tex]

[tex]= 9/49[/tex]

At an international conference, flags from 8 different countries will be displayed. Of these flags, 4 are from the continent of Africa and 4 flags are from the continent of Europe. The flags will be displayed in a row, alternating between continents. A flag from Africa will be in the first position. In how many ways can the flags be displayed?

Answers

Answer:

96 ways

Step-by-step explanation:

Let´s call flags of countries from Africa as  A₁,  A₂, A₃, A₄, and from Europe as  E₁, E₂, E₃ and E₄

We have to display the flags always beginning with one flag from Africa let´s take A₁

For that flag, we have 4! possibilities Then 4! is:

4*3*2*1  = 24

As we have 4 different Flags from Africa, we will have

4*24 = 96  possibilities

In 1968, vehicle emission standards allowed
6.3 hydrocarbons released per mile driven. By 1980, the
standards allowed only 0.41 hydrocarbons per mile driven.
What was the rate of change from 1968 to 1980?​

Answers

Answer:

Step-by-step explanation:

In 1968, vehicle emission standards allowed 6.3 hydrocarbons released per mile driven and by 1980, the

standards allowed only 0.41 hydrocarbons per mile driven. This means that the change in the amount of hydrocarbons released per mile driven as allowed by the vehicle emission standards between 1968 and 1980 is

6.3 - 0.41 = 5.89

Therefore, the percentage rate of change in the amount of hydrocarbons released per mile driven as allowed by the vehicle emission standards between 1968 and 1980 would be

5.89/6.3 × 100 = 93.49%

what is Divide −240 by 8

Answers

Answer:

-30

Explanation:

1. A negative divided by a positive = a negative

2. 8•-30=-240

I hope this helps you!!

The division -240 by 8 gives the quotient is -30.

What is Division?

The division is one of the four introductory fine operations, the other three being addition, deduction, and addition. In simple words, division can be defined as the splitting of a large group into lower groups similar that every group will have an equal number of particulars. It's an operation used for equal grouping and equal sharing in calculation.

We have to divide -240 by 8.

So, the division is

                              8 | -240 | 30

                                     24

                                    ____

                                      00

Thus, the quotient is -30.

Learn more about Division here:

https://brainly.com/question/21416852

#SPJ2

What is the solution of the system? {2x+y=15x−y=3 Enter your answer in the boxes. ( , )

Answers

(13x=3).

Step-by-step explanation:

2x+y=15x-y=3

then u group like terms

2x-15x= -y+y=3

then ur answer

13x=3

Of the following points, name all that lie on the same horizontal line? (7,-1) (2,-1) (-3,9) (-3,-1)

Answers

Hey there!

If everything is on the same horizontal level, it is at the same elevation, or height. On a graph, the elevation is the y-value. So, if we want the points to on the same horizontal line, they have to have the same y-value.

The points that all share the y-value of -1 are (7,-1), (2,-1), and (-3,-1). Since (-3,9) is at a different y-value it is not on the horizontal line of y=-1.

Have a wonderful day!

Answer:

A (7,-1)

B (2,-1)

D (-3,-1)

Step-by-step explanation:

Well lets plot the following points on a graph first,

A (7,-1)

B (2,-1)

C (-3,9)

D (-3,-1)

Look at the image below ↓

By looking at the graph we can tell that points,

A, B, and D lie on the same horizontal line.

Thus,

points A, B, and D lie on the same horizontal line.

Hope this helps :)

Priya was busy studying this week and ran 7 fewer miles than last week. She ran 3 times as far as Elena ran this week. Elena only had time to run 4 miles this week. How many miles did Priya run last week?

Answers

Answer:Priya ran 19 miles last week

Step-by-step explanation:

4 x 3 = 12

12 + 7 = 19

a bag contains 6 cherry 3 orange and 2 lemon candies. You reach in and take 3 pieces of candy at random. Find the probability of all lemons

Answers

Answer:

0.181818

Step-by-step explanation:

There are total 11 candies. The possibility of combinations is 165 which is found by using computation technique 11C3. It is assumed that order does not matter. There are 3 pieces of candy are selected at random. There are 6C2 which is 15 different ways to select cherry and lemon. There are 30 ways to choose 2 cherry and a lemon combination. The probability is [tex]\frac{30}{165}[/tex] = 0.181818

Which graph represents the function?

Answers

the answer is the bottom left option

How long will it take 3800 to grow into 5700 if it’s invested at 6% interest compounded continuously?

Answers

Answer:

1234567891234567890

Answer: 25 years

Step-by-step explanation:

t = I / Pr

t = 5700 / ( 3800 × 0.06 ) = 25

t = 25 years

Someone help me please pls pls pls ​

Answers

Answer:

There is 9 on each pace and 3 on a row

Step-by-step explanation:

54/6=9

if there is 9 on each side and the same on each side, then it has to be 3 in each row and column. Also, this is a Rubix cube

Please give me brainliest, it really helps! :)

Have a good day!

Other Questions
use calculator to work out: (1dp) 28/2.8 Why did Euroepan governents face so much political insatbility after the Hundred Years War in England (Parliment) If 50 ml of 1.00 M of H2SO4 and 50 ml of 2.0 M KOH are mixed what is the concentration of the resulting solutes? Bradley's Miniature Golf and Driving Range Inc. was opened on March 1 by Bob Dean. These selected events and transactions occurred during March.Mar. 1 Stockholder invested $59,000 cash in the business in exchange for common stock of the corporation3 Purchased Snead's Golf Land for $41,200 cash. The price consists of land $22,900, building $8,310, and equipment $9,990. (Record this in a single entry.)5 Advertised the opening of the driving range and miniature golf course, paying advertising expenses of $1,560 cash6 Paid cash $3,500 for a 1-year insurance policy.10 Purchased golf clubs and other equipment for $4,800 from Tahoe Company, payable in 30 days18 Received golf fees of $1,550 in cash from customers for golf services performed19 Sold 105 coupon books for $10 each in cash. Each book contains 10 coupons that enable the holder to play one round of miniature golf or to hit one bucket of golf balls. (Hint: The revenue should not be recognized until the customers use the coupons.)25 Paid a $420 cash dividend. 30 Paid salaries of $810.30 Paid Tahoe Company in full for equipment purchased on March 10.31 Received $800 in cash from customers for golf services performedJournalize the March transactions. Bradley's records golf fees as service revenue. (Record journal entries in the order presented in the problem.) Chemical synthesis of peptides by the Merrifield method:_______. a. has a practical upper limit of a polymer of about 500 amino acid residues. b. involves synthesizing the peptide and then attaching it to a solid support. c. is nearly as efficient as peptide bond synthesis in biochemical systems. d. proceeds from the carboxyl terminus to the amino terminus. WILL GIVE BRAINLEIST!!! Please answer this correctly SWAN85 help me baby please help me BABY!!!!!!! Each block on the grid is 1 unit by 1 unit. We wish to walk from A to B via 7 unit path but we have to stay on the grid. How many different paths can we take? pls pls help me help me Red beads cost $1 an ounce and gold beads cost $3an ounce. Juanita wants to purchase a 12-ouncemixture of red and gold beads that she can sell for $2an ounce. The solution of the system shows thenumber of beads needed for Juanita to break even.x + y = 12x + 3y = 24How many ounces of red beads will Juanita buy tobreak even?How many ounces of gold beads will she buy? Suppose that Larimer Company sells a product for $24. Unit costs are as follows: Direct materials $4.98 Direct labor 2.10 Variable factory overhead 1.00 Variable selling and administrative expense 2.00 Total fixed factory overhead is $26,500 per year, and total fixed selling and administrative expense is $15,260.Requried:a. Calculate the variable cost per unit and the contribution margin per unit. b. Calculate the contribution margin ratio and the variable cost ratio. c. Calculate the break-even units. A gear motor can develop 2 hp when it turns at 450rpm. If the motor turns a solid shaft with a diameter of 1 in., determine the maximum shear stress developed in the shaft. (30 pts) Paine challenged people who considered themselves as what A parent Abolitionist Loyalist Some studies done by economists have found that the original inventor receives _________________________________________________ from innovations, while other businesses and new product users receive the rest of the benefit. True or False? Circle the correct answer for each statement. If a statement is false, explain why under thestatement1. The type of chemical bond within the water molecule is the ionic bond. True False Escribe una historia, verdad o imaginaria, de el primer tiempo que volaste. Qu cosas tuviste contigo? Con quin hablaste en el aeropuerto, durante el vuelo, y despus del vuelo? Pas algo interesante or inesperado? which of the following are Greeks The water was pumped out of a backyard pond. What is the domain of this graph? The walls of bronchioles lacka. elastic tissueb. columnar epitheliumc. smooth muscled. hyaline cartilagee. ciliated cells