Answer:
MN = 10
Step-by-step explanation:
There is a scale factor of 2 [This means that the lengths of triangle ∆MPN are exactly 2 times larger than ∆SRQ], so 5 × 2 = 10.
Notice that each corresponding line is marked by a black mark perpendicular to the side. Since 2 corresponds to 4, and 3 corresponds to 6, 5 must correspond to 10. These triangles are similar as indicated by the marks so there is just a size difference. Because these two triangles are similar, the sides must be proportional.
∆MPN ~ ∆SRQ.
It can also be thought of as completing a set of proportional fractions:
4/2 = 6/3 = ?/5
4/2 = 2 → 6/3 = 2 → ?/5 = 2.
?/5 = 2, ? = 5 × 2 = 10.
1. A relation contains the ordered pairs shown. One of the ordered pairs is missing an x-coordinate. {(-1,4),(0,4),(2,5),(3,-6),(?,7)} What could be the missing x-coordinate if the relation is not a function?
Answer:
There are 4 possible scenarios where given relation could not be a function:
i) [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]
ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]
iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]
iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]
Step-by-step explanation:
From Function Theory, we remember that a relation is not a function when at least one element from domain (x-coordinate) is related to one or more elements from range (y-coordinate). Hence, there are four possibilities of making the relation not a function:
i) [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]
ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]
iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]
iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]
cal d gradient B(4,-7), c(-6-5) and d two point find d gradient
Answer:
d = - 1/5
Step-by-step explanation:
slope form: m= y2-y1/x2-x1
m= -5-(-7)/-6-4
m= 2/-10
m= - 1/5
Which expression is equivalent to StartFraction negative 18 a Superscript negative 2 Baseline b Superscript 5 Baseline Over Negative 12 a Superscript negative 4 Baseline b Superscript negative 6 Baseline EndFraction? Assume a not-equals 0, b not-equals 0.
A. StartFraction 2 a squared b Superscript 11 Baseline Over 3 EndFraction
B. StartFraction 2 a squared b Superscript 30 Baseline Over 3 EndFraction
C. StartFraction 3 a squared b Superscript 11 Baseline Over 2 EndFraction
D. StartFraction 3 a squared b Superscript 30 Baseline Over 2 EndFraction
Answer:
B
Step-by-step explanation:
I just took the test
Answer:
A.
Step-by-step explanation:
Giving brainiest explain answer
Answer:
A.) -5
Step-by-step explanation:
Slope Formula ---> [tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex] m = slope
[tex]m = \frac{2 - (-3)}{-2 - (-1)}[/tex]
Eliminate negatives:
[tex]m = \frac{2 + 3}{ -2 + 1}[/tex]
Solve:
[tex]m = \frac{5}{-1}[/tex]
Simplify:
[tex]m = -5[/tex]
Central City High's basketball team will be entering the playoffs at the end of their regular season. There will be 3 other teams in the playoffs, with season average scores of 87, 92, and 119. Central City High has played 7 games with an average score of 91. What score range could they have in their eighth and last regular season game to have the second highest season average score in the tournament?
Answer:
99<x<315
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
edg. 2021
rationalise the denominator of (6+root3)(6-root3) over root33
Answer:
√33
Step-by-step explanation:
In the image .
The expression (6 + √3) (6 - √3) / √33 upon rationalizing the denominator gives √33.
What is Square Root?Square root of a number is the value such that upon multiplying the value by itself twice gives the original number.
The given expression is (6 + √3) (6 - √3) / √33
We have the identity,
(a + b) (a - b) = a² - b²
∴ (6 + √3) (6 - √3) / 33 = 6² - (√3)² / √33
= (36 - 3) / √33
= 33 /√33
Multiplying numerator and denominator by √33,
(6 + √3) (6 - √3) / 33 = (33 × √33) / (√33 × √33)
= 33√33 / 33
= √33
Hence upon rationalizing the denominator in the expression (6 + √3) (6 - √3) / 33 yields √33.
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—16t^2 + 64t + 3
Please help as soon as possible 33 points if you do it!!
Answer:
51t^3
Step-by-step explanation:
64+3=67
67 +(-16)=51
t^2 +t= t^3
now you just add them up but they cant be combined because one is a number and the other a variable w an exponent so we just get 51t^3
True or false, f(x) is a function
Answer:
Step-by-step explanation:
True!!
Is this true or false? Ill give brainliest
i think true because 0,4 on there is correct and so is 2,0
y-9= 2(x - 5)
Solve for y
Answer:
y=2x-1
Step-by-step explanation:
y-9=2x-10
y=2x -10+9
y=2x-1
A rope is 225 centimeters long.
You need the rope to be 1 1/2 meters long.
How many centimeters should you cut off?
Rope = 225 cm
Needed rope = 11/2m = (11/2) × 100 cm = 550cm
So, rope needed to be cut
= 550cm - 225cm
= 225cm
=225/100m
=2.25 m
the answer would be (12)
thank you.............................
The perimeter of a football field is 920 feet. The width is 60 feet more than one-third of the length. What are the dimensions of a football field?
Given:
Perimeter of a football field = 920 feet.
The width is 60 feet more than one-third of the length.
To find:
The dimensions of a football field.
Solution:
Let the length of the field be x.
Then, width = [tex]\dfrac{1}{3}x+60[/tex]
We know that,
[tex]Perimeter = 2( length + width)[/tex]
[tex]920 = 2(x+\dfrac{1}{3}x+60)[/tex]
[tex]920 = 2(\dfrac{4}{3}x+60)[/tex]
[tex]920 =\dfrac{8}{3}x+120[/tex]
Subtract both sides by 120.
[tex]920-120 =\dfrac{8}{3}x+120-120[/tex]
[tex]800 =\dfrac{8}{3}x[/tex]
Multiply both sides by 3.
[tex]2400 =8x[/tex]
Divide both sides by 8.
[tex]300 =x[/tex]
Now,
[tex]Length = 300\text{ feet}[/tex]
[tex]Width=\dfrac{1}{3}(300)+60[/tex]
[tex]Width=100+60[/tex]
[tex]Width=160\text{ feet}[/tex]
Therefore, the length and width of the football field are 300 feet and 160 feet respectively.
work out area of this semi circle with diameter 10
Area of a circle is pi x r^2
R is the radius which is have the diameter: r = 10/2 = 5
Area of the full circle would be 3.14 x 5^2 = 3.14 x 25 = 78.5 square units.
A semi circle is half a full circle
Area of the semi circle = 78.5/2 = 39.25 square units.
number of boys and girls are in the class are in the ratio of 7 : 5 the number of boys is 8 more than the number of girls what is a total class strength?
Answer:
Step-by-step explanation:
Given ratio of boys and girls in the class =7:5
No of boys is 8more than the girls
So
Let no of boys in the class =7x
No of girls in the class=5x
7x=5x+8
2x=8
X=8/2
X=4.
Total strength =no of boys + no of girls
=7x+5x
=7×4+5×4
= 28+20
=48.
Total strength in the class is 48.
Answer:
Total class strength = 48
Step-by-step explanation:
Boys : Girls = 7 : 5
Number of boys = 7x
Number of girls = 5x
7x - 5x = 8
2x = 8
x = 8/2
x = 4
Total strength = 7x + 5x = 12x = 12*4 = 48
3x + 12 – 6x ≤ -9 Solve, graph, and express the following inequalities in interval notation.
The solution of inequality 3x + 12 – 6x ≤ –9 will be greater than or equal to 7.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The inequality is given below.
3x + 12 – 6x ≤ –9
Simplify the equation, then the value of 'x' is calculated as,
3x + 12 – 6x ≤ –9
6x – 3x ≥ 12 + 9
3x ≥ 21
x ≥ 21 / 3
x ≥ 7
The solution of inequality 3x + 12 – 6x ≤ –9 will be greater than or equal to 7.
The solution is shown on the number line.
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what is the equation of the line with slope -3 and y-intercept 6? Express your answer in slope-intercept form.
Answer:
y=-3x+6
Step-by-step explanation:
Answer:
y = -3x + 6
Step-by-step explanation:
y = mx + b
m = slope
b = y-intercept
SO
m = -3
b = 6
Thus,
y = -3x + 6
2b+ 9r use b=2 and r=7
Answer:
67
Step-by-step explanation:
2b+9r
2(2)+9(7)
4+63
67
Answer:
67
Step-by-step explanation:
2(2)+9(7)
4+63=67
Have a great day
The percentage of sprouted seeds for a single crop can be modeled by a logistic function that is represented by y=100/1+99e^-0.89x. Which statements about the scenario are true? Check all that apply.
Answer:
A, B, and C
Step-by-step explanation:
Subtract 7b(2a 2 +5a-7) from (7a 2 -a+3 )-3b(6a 2 -b+3)
Answer:
[tex]\huge\boxed{-32a^2b+7a^2+3b^2-35ab-a+40b+3}[/tex]
Step-by-step explanation:
[tex]7b(2a^2+5a-7)\qquad|\text{use the distributive property}\\\\=(7b)(2a^2)+(7b)(5a)+(7b)(-7)=14a^2b+35ab-49b\\\\\\(7a^2-a+3)-3b(6a^2-b+3)\qquad|\text{use the distributive property}\\\\=7a^2-a+3+(-3b)(6a^2)+(-3b)(-b)+(-3b)(3)\\\\=7a^2-a+3-18a^2b+3b^2-9b[/tex]
Substraction
[tex](7a^2-a+3-18a^2b+3b^2-9b)-(14a^2b+35ab-49b)\\\\=7a^2-a+3-18a^2b+3b^2-9b-14a^2b-35ab+49b\\\\\text{combine like terms}\\\\=(-18a^2b-14a^2b)+7a^2+3b^2-35ab-a+(-9b+49b)+3\\\\=-32a^2b+7a^2+3b^2-35ab-a+40b+3[/tex]
(4w+32)(-w-5)=0 solution set
Answer:
W=5 w=8
Step-by-step explanation:
A zookeeper is preparing to care for snakes in an exhibit. For every 2 snakes, she needs 1 bowl of water. How many bowls of water are needed if the number of snakes is x? *
Answer:
k
Step-by-step explanation:
The graph of a function f is shown. Use the graph to estimate the average rate of change from x=-2 to x=0
Answer:
2
Step-by-step explanation:
Given:
The interval, x = -2 to x = 0.
Required:
Average rate of change from x = -2 to x = 0.
SOLUTION:
From the graph,
If x = -2, f(-2) = 0.
If x = 0, f(0) = 4
Average rate of change = [tex] \frac{f(b) - f(a)}{b - a} [/tex]
Where,
[tex] a = -2, f(a) = 0 [/tex]
[tex] b = 0, f(b) = 4 [/tex]
Plug in the values into the formula:
[tex] = \frac{4 - 0}{0 -(-2)} [/tex]
[tex] = \frac{4}{2} = 2 [/tex]
Average rate of change from x = -2 to x = 0 is 2.
The ratio of boys to girls in a class is 5:3. There are 32 students in the class. How many students are boys?
Answer:
5x+3x=8x
8x = 32
x=32/8 = 4
boys are 4 x 5 = 20
girls are 4 x 3 = 12
Step-by-step explanation:
Add the ratios together: 5 + 3 = 8
Divide total students by 8:
32 / 8 = 4
Multiply each ratio by 4 to find the number of each:
Boys = 4 x 5 = 20
Girls = 3 x 4 = 12
There are 20 boys.
Is 12 even or odd? Pick you choice
Answer:
Even
Step-by-step explanation:
Please help with the attatched!
Answer: a + b = 40
[tex](3+\sqrt{5})(7-6\sqrt{5})=3.7+7\sqrt{5}-3.6\sqrt{5}-6\sqrt{5}.\sqrt{5}\\\\=21+6.5-11\sqrt{5}\\\\=51-11\sqrt{5}[/tex]
because [tex](3+\sqrt{5})(7-6\sqrt{5})=a+b\sqrt{5}[/tex]
=> a = 51
b = -11
=> a + b = 51 -11 =40
Step-by-step explanation:
Answer:
[tex]a = -9 - 11\sqrt{5} - \sqrt{5}b[/tex]
a = 51
b= -11
Mariana drinks 2 pints of milk each day. How many days does it take her to drink 1 gallon of milk?
Answer:
4 days
Step-by-step explanation:
because Mariana drank 2 pints a day 8 pints are in a gallon so 8 ÷ 2 = 4
Hi! I have trouble with these type of questions, what is 3.478 divided by 37?
Answer:
0.094
Step-by-step explanation:
3.478 ÷ 37 = 0.094I hope this helps!
Solve the following system of equations graphically on the set of axes below. y=3x−3 , x+y=5
Answer:
x=2, y=3
Step-by-step explanation:
First, graph both equations on a rectangular coordinate system (see attached screenshot). Then, simply figure out where these two lines intersect. Since they intersect at (2,3), x=2 and y=3.
Plugging these values in the equations for x and y, you can see if these are the correct answers:
(3)=3(2)-3, (2)+(3)=5
Since both of these are true, you have the right answer.
Hope this helps!
Two linear equation has their solutions on the points where they intersect each other.
The solution of the given system of equations is:
x = 2, y = 3.
How to determine the solution of system of linear equations graphically?Each linear equation represents a straight line.
If both the given lines intersect at one point, then that point's coordinate is the solution of the given system of the equations.
If both the given lines are parallel, then there is no intersection and thus no solution.
If both the lines are coincident(that is, lying over each other fully), then there are infinite points of intersection, as they touch each other on infinite points, and thus infinite solutions to the given system of equations exist.
Using method of substitution to solve the system of equations:[tex]y = 3x-3\\ x+y = 5 [/tex]
Substituting the value of y from first equation in the second equation, we get:
[tex]x + y = 5\\ x + (3x-3) = 5\\ x+3x = 5+3\\ 4x = 8 \\ x = 2\\ [/tex]
Thus, putting this value of x in first equation, we get:
[tex]y = 3x - 3\\ y = 3 \times 2 - 3\\ y = 6-3\\ y = 3[/tex]
Thus, the system has one solution and it is x = 2, y = 3.
Using graphing, we can see that point of intersection is (x,y) = (2,3)
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Quadrilateral ABCD has coordinates A(-2,0), B(0,4), C(4,6), and D(2,2). If it is
reflected over the x-axis, what are the coordinates of C'? (Answer as an ordered
pair without spaces)
Answer:
C' (4,-6)
Step-by-step explanation:
Any point being reflected over the x-axis will undergo the following transformation:
(x, y) --> (x, -y)
(4, 6) --> (4, -6)
The coordinates of C',
C(4,6) → C'(4, -6).
What is a reflection?A reflection is a type of transformation that involves flipping a shape, known as the preimage, over a line, known as the line of reflection, to produce a new shape (called the image). You can picture what would happen if you flipped the form over the line in order to graph a reflection.
Given:
Quadrilateral ABCD has coordinates A(-2,0), B(0,4), C(4,6), and D(2,2).
If it is reflected over the x-axis,
The reflection rule:
(x, y) → (x, -y)
The coordinates of C',
C(4,6) → C'(4, -6).
Therefore, the image point of C is C'(4, -6).
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