PLZZZ HELP ME ASAP FOR BRAINLIEST AND 20 POINTS
I am desperate and these are my last points.
:'(

Answer:

Joules/second^2=(Newton×meter)/second^2.

Solving for mass: Kg= (second^3/ meter^2).

Answer:

Is to add all forces, for example either the gf = gravitational force

Ff= force fiction

Fn= normal force

Thus, fg + ff + fn = y will give you results

Well then the forces you use in your exercises or questions.

The equation for net force is: ΣF = ma

or, ΣF = Δp/Δt.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

A spring balance can be used to calculate the Force. Newton is the SI unit of force.

Hence, net force applied on the object = mass × acceleration

ΣF = ma

It can be written in another from as:

net force applied on the object = change in momentum ÷ time interval

ΣF = Δp/Δt

So, the equation for net force is: ΣF = ma

or, ΣF = Δp/Δt.

Learn more about force here:

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Answer:

the rocks have the same amount of thermal energy

The chemical secreted by glands that regulates the activities of different body cells is HORMONE.

Answer:

206

Explanation:

The axial skeleton, comprising the spine, chest and head, contains 80 bones. The appendicular skeleton, comprising the arms and legs, including the shoulder and pelvic girdles, contains 126 bones, bringing the total for the entire skeleton to 206 bones.

A fully grown adult features 26 bones in the spine, whereas a child can have 34.

Answer:

The human body is made up of 206 bones

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Where

q₁ and q₂ are charges

r is the distance between charges

When  each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]

Apply new values,

[tex]F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F[/tex]

So, the new force becomes 64 times the initial force.

Answer:

option A

Explanation:

the diameter is twice the length of the radius

hope it helps

Answer:

A. The angle with which the light passes from glass into water is approximately 31.97°

B. The image formed is, real, inverted, and smaller than the object

C. The image distance is 53.2[tex]\overline 6[/tex] cm

The image is real

D. The magnification is approximately 0.182

E. The type of lens required is a concave lens which corrects the focus of a powerful eye lens or a long eyeball

Explanation:

The given parameters for the light wave are;

The refractive index of the glass medium, n₁ = 1.5

The angle of incidence of the light, θ₁ = 28°

The refractive index of water, n₂ = 1.33

A. Let θ₂ represent the angle with which the light passes from glass into water

Snell's law is mathematically stated as follows;

n₁·sin(θ₁) = n₂·sin(θ₂)

According to Snell's law, we have;

1.5 × sin(28°) = 1.33 × sin(θ₂)

sin(θ) = (1.5 × sin(28°))/1.33 = 0.52947920615

∴ θ₂ = arcsin(0.52947920615) ≈ 31.97°

The angle with which the light passes from glass into water, θ₂ ≈ 31.97°

B. Please find attached the drawing of the image created with Microsoft Visio

From the drawing, we have that the image formed is real inverted smaller than the object and between the focus and radius of curvature

C. The location of the object from the mirror, u = 94.0 cm

The focal length of the mirror, f = +34.0 cm

The mirror formula for a concave mirror is given as follows;

[tex]\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}[/tex]

Therefore, we have;

[tex]\dfrac{1}{34.0} = \dfrac{1}{94.0} + \dfrac{1}{v}[/tex]

[tex]\dfrac{1}{v} = \dfrac{1}{34.0} - \dfrac{1}{94.0} = \dfrac{15}{799}[/tex]

[tex]\therefore \dfrac{v}{1} = v =\dfrac{799}{15} = 56.2\overline 6[/tex]

The image distance, v = 799/15 = 53.2[tex]\overline 6[/tex] cm

Therefore the image is in front of the mirror, which is a real image

The image is real

D. The given parameters of the object and lens are;

The distance of the object from the lens, u = 65.0 cm

The distance of the image formed from the lens, i = -18 cm

The magnification, M, is given as follows;

[tex]M = \dfrac{-v}{u}[/tex]

Therefore;

[tex]M = \dfrac{-(-11.8)}{65.0} = \dfrac{59}{325} \approx 0.18153846153[/tex]

The magnification, M ≈ 0.182

E. For a person who is near sighted, the light from objects from distant location are almost parallel and are brought to a focus in front of the retina and therefore, they appear blurred

The use of a concave lens is required to correct nearsightedness as it causes the light to appear come from a point before the focus such that the divergent rays of the object refracted through the concave lens comes to a focus at the.

Answer:

P = 3 Pa

Explanation:

Given that,

Force exerted by the car, F = 9 N

The area of the car, A = 3 m²

We need to find the pressure exerted by the car. We know that pressure is equal to the force per unit area such that,

[tex]P=\dfrac{F}{A}\\\\P=\dfrac{9\ N}{3\ m^2}\\\\P=3\ Pa[/tex]

So, the pressure exerted by the car is equal to 3 Pa.

Answer:

Hope this helps you out if you could please leave 5 stars or brainiest thank you

Answer:

(b) 2

Explanation:

Answer:

40g

Explanation:

Solubility of Copper sulfate at 90°=60g

Solubility of potassium bromide at 90°=100g

100g-60g=40g

Answer:

c because you see with your eyes and c rhymes with eyes

Answer: force is 0.42 N

Explanation: F = l·v·B

Answer:

to heat spaces in buildingss

Explanation:

(60 W) x (336 hrs) = 20,160 W-hr

That's 20.16 KWh .

Answer:

The anwser is C, Garreth and Elisa ran together, Luigi and Jasmine went the same distance, and Logan and Jasmine have the same displacement in the opposite direction.

Explanation:

i just took the test and got 100%

Answer:

C or Garreth and Elisa ran together, Luigi and Jasmine went the same distance, and Logan and Jasmine have the same displacement in the opposite direction.

Explanation:

Answer:

500 N

Explanation:

Since the work done on the spring W = Fx where F = force applied and x = compression length = 0.170 m (since the spring will be compressed its full length when the force is applied)

Since W = 85.0 J and we need to find F,

F = W/x

= 85.0 J/0.170 m

= 500 N

So, the  magnitude of force must you apply to hold the platform stationary at the final distance given above is 500 N.

Answer: 4875 N

Explanation:

Given

Stuntman weight is [tex]W=650\ N[/tex]

His center of gravity is located at [tex]x=0.75\ m[/tex] away from pole

If he applies an upwards force at 0.10 m away from the pole

Suppose  F is the applied force

To remain vertical, the torque of weight must be canceled by the vertical force

[tex]\Rightarrow 650\times 0.75-F\times 0.10=0\\\\\Rightarrow 650\times 0.75=F\times 0.10\\\\\Rightarrow F=\dfrac{487.5}{0.10}=4875\ N[/tex]

Answer:

A) s=1/2at^2

t=√(2s/a)=√(2x400)/10.0)=9.0s

B) v=at

v=10.0x9=90m/s

Answer:

19.2 m/s

Explanation:

From the question,

Velocity = displacement/time = d/t

V = d/t.................................. Equation 1

Average velocity = Total displacement/ total time

Total dispalcement = √(30²+60²) = √4500 = 67.08 m

Total time = 1.5+2 = 3.5 s.

Substitute these value into equation 1

V = 67.08/3.5

V = 19.2 m/s.

Hence the average velocity is 19.2 m/s

The parameter given for the car during transit is 30 m north in 1.5 seconds and drives 60 east in 2 seconds, we want to find the average velocity.

average velocity is 19.2 m/s

Solution

The expression for Average velocity is

Average velocity = Total Displacement/ Total time Taken...............Eqn 1

Total Displacement = √(30²+60²) = √4500 = 67.08 m

Total time = 1.5+2 = 3.5 s.

From the Equation 1

Average Velocity = 67.08/3.5

V = 19.2 m/s.

Therefore, the average velocity is 19.2 m/s

Learn more about average velocity :

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Answer:

296.01 J

Explanation:

From the question,

Q = cm(t₂-t₁)....................... Equation 1

Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature

Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k

Substitute these values into equation 1

Q = 897×0.01×(55-22)

Q = 897×0.01×33

Q = 296.01 J

Hence 296.01 Joules of heat is required.

Answer:

cola forms so slowly that we could use up the supply that exists now

Answer: c and d

Explanation:

Answer:

4.02 s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 35°

Initial velocity (u) = 50 m/s

Acceleration due to gravity (g) = 10 m/s²

Time of flight (T) =?

The time of flight of the arrow can be obtained as follow:

T = 2uSineθ / g

T = 2 × 35 × Sine 35 / 10

T = 70 × 0.5736 / 10

T = 7 × 0.5736

T = 4.02 s

Therefore, the time taken for the arrow to return is 4.02 s

Answer:

B on EDGE

Explanation:

Answer:

[tex]124.62\ \text{rad/s}[/tex]

[tex]3.71\ \text{m/s}[/tex]

[tex]1.23\ \text{km/s}^2[/tex]

[tex]20.28\ \text{m}[/tex]

Explanation:

r = Radius of disk = 7.9 cm

N = Number of revolution per minute = 1190 rev/minute

Angular speed is given by

[tex]\omega=N\dfrac{2\pi}{60}\\\Rightarrow \omega=1190\times \dfrac{2\pi}{60}\\\Rightarrow \omega=124.62\ \text{rad/s}[/tex]

The angular speed is [tex]124.62\ \text{rad/s}[/tex]

r = 2.98 cm

Tangential speed is given by

[tex]v=r\omega\\\Rightarrow v=2.98\times 10^{-2}\times 124.62\\\Rightarrow v=3.71\ \text{m/s}[/tex]

Tangential speed at the required point is [tex]3.71\ \text{m/s}[/tex]

Radial acceleration is given by

[tex]a=\omega^2r\\\Rightarrow a=124.62^2\times 7.9\times 10^{-2}\\\Rightarrow a=1226.88\approx 1.23\ \text{km/s}^2[/tex]

The radial acceleration is [tex]1.23\ \text{km/s}^2[/tex].

t = Time = 2.06 s

Distance traveled is given by

[tex]d=vt\\\Rightarrow d=\omega rt\\\Rightarrow d=124.62\times 7.9\times 10^{-2}\times 2.06\\\Rightarrow d=20.28\ \text{m}[/tex]

The total distance a point on the rim moves in the required time is [tex]20.28\ \text{m}[/tex].