Answers
Answer:
Explanation:
#2 and for 2 i think that its the first one which says that there have to be a potential difference
#3 the answer is not at all
Related Questions
tlo
A Cu rod whose length at 80 degree is 10.0 metres is heated at 50 degree find the new length take x-for cu as 0.000 to 17 k - 1
Answers
Answer:
9.949 m
Explanation:
From the question,
L' = L+LαΔT................. Equation 1
Where L' = New length, L = Original length, α = linear expansivity of Cu, ΔT = change in temperature
Given: L = 10 m, α = 0.00017 K⁻¹, ΔT = 50-80
L' = 10+10(0.00017)(50-80)
L' = 10-0.051
L' = 9.949 m
Hence the new legth of Cu is 9.949 m
A man with a weight of 450 N climbs a ladder to a height of 5.2 meters. How much work did he do?
Answers
Answer:
the work done by him is 2,340 joules
Explanation:
The computation of the work done by him is shown below:
= Weight of man × height
= 450 N × 5.2 meters
= 2,340 joules
Hence, the work done by him is 2,340 joules
We simply multiply the man weight with the height
An electric dipole is formed from ± 5.0 nC point charges spaced 3.0 mm apart. The dipole is centered at the origin, oriented along the y-axis. What is the electric field strength at point (x,y) = ( 20 mm ,0cm)? What is the electric field strength at point (x,y) = (0cm, 20 mm )?
Answers
Answer:
The electric field strength at point (x,y) = ( 20 mm ,0cm) is =16321.0769 N/C
The electric field strength at point (x,y) = (0cm, 20 mm) is =35321.58999 N/C
Explanation:
Question: What is the electric field strength at point (x,y) = ( 20 mm ,0cm)?
Answer:
The electric field at any given point of the dipole is given as:
E= (KP) ÷ (r^2 + a^2)^3/2
Where:
K = 9x10^9 Nm^2/c^2 (coloumb constant)
P = (0.003) (5x10^-9c) which is the movement of the dipole
(0.003) is arrived at when mm is converted to m. 3.0 mm space apart was converted to a meter.
r= the point, in the question above is 20mm = 0.02m
Now, the electric field, E can be calculated by putting the values in the formula above:
E = (KP) ÷ (r^2 + a^2)^3/2
= (9x10^9 Nm^2/c^2) (0.003 m) (5x10^-9c) ÷ [ (0.02m)^2 + (0.003)^2]^3/2
= 0.135 ÷ (8.271513x10^-6)
=16321.0769 N/C
Question: What is the electric field strength at point (x,y) = (0cm, 20 mm )?
Answer:
Here, the electric field, E= 2krp ÷ (r^2 - a^2)^2
E= 2 (9x10^9 Nm^2/c^2) (0.02m) (0.003 m) (5x10^-9c) ÷ [(0.02m)^2 - (0.003)^2]^2
= 0.0054 ÷ 0.000000152881
=35321.58999 N/C
The filament in the bulb is moving back and forth, first pushed one way and then the other. What does this imply about the current in the filament? Select the best answer from the choices provided. View Available Hint(s) Select the best answer from the choices provided. The current is turning on and off. The magnitude of the current is varying with time. The current switches direction, going one way and then the other.
Answers
Answer:
the correct answer is: The magnitude of the current varies with time.
Explanation:
The movement of a filament by a current is due to the electric force when electrons accumulate on one side attract positively charged nuclei.
In this case the voters in a period of time are on one side, let's call it forward and in another period of time it accumulates on the other side, let's call it back, this explains the very small movement of the filament, therefore we have a current that varies over time.
The other two options are not correct because turning off the current the filament goes to the central position and does not go back, the other explanation the current goes in one direction or another, the voters are always on the same side therefore the filament only goes in a sense.
Consequently the correct answer is: The magnitude of the current varies with time.
Where do animals such as snakes and frogs, which do not make their own body heat, usually get their heat?
fuel
the sun
hot lava
friction
plssssssss answer correctly
Answers
The answer to this question is the Sun.
As im writing this, 12,826 people vote the Sun.
animals such as snakes and frogs, which do not make their own body heat. They usually get their heat from the sun. Hence option B is correct.
What is Cold-blooded animals ?A body temperature that is only slightly higher than the ambient temperature. This condition differentiates cold-blooded, or homoiothermic, animals from fishes, amphibians, reptiles, and invertebrates (birds and mammals). Due of their reliance on external warmth for metabolic activity, terrestrial cold-blooded species are restricted to locations with temperatures ranging from 5-10° to 35-40° C (41-50° to 95-104° F).
Cold-blooded creatures cannot create their own body heat, but they may control it by modifying their surroundings. Alligators and other reptiles frequently lay in the sun to warm up. They, on the other hand, cool off by swimming, going into a burrow in the earth, or moving inside the sade of a rock.
Hence option B is correct.
To know more about Cold-blooded animals :
https://brainly.com/question/30914929
#SPJ2.
Which three terms are needed to describe the energy a BASE Jumper has as
she falls toward the ground?
A. Potential
B. Kinetic
C. Gravitational
D. Electromagnetic
Answers
B kinetic (because she’s moving down)
and
C gravitational (as gravity is pulling her back down)
Answer:
A.Potential
B.Kinetic
C.Gravitational
Explanation:
I took the test
what happens to the loudness of the sound as the amplitude increases
Answers
it increases and gets louder
and it amplifies the noise
The teacher asked the children to turn the scales sideways and adjust the scales to zero. Jason pushes on the top of the scales and Kerry pushes on the base. They hold the scales still. Jason’s push measures 80 N. What is the size of Kerry’s push? *
Answers
Answer: J
Explanation:
Jason pushes on the top of the scales and Kerry pushes on the base. They hold the scales still. Jason's push measures 80N. What is the size of Kerry's push?
he pushes zero
What is the weight of a 3000g girl who is swimming in the Pacific Ocean?
Answers
Answer: 3000g ;-;
she feels lighter in the water but the water doesn't actually take away her weight
Explanation:
A sphere of uniform density with mass 15 kg and radius 0.6 m is spinning, making one complete revolution every 0.3 s. The center of mass of the sphere has a speed of 3 m/s. (a) What is the rotational kinetic energy of the sphere
Answers
Answer:
[tex]473.56\ \text{J}[/tex]
Explanation:
T = Time taken to complete one revolution = 0.3 s
m = Mass of sphere = 15 kg
r = Radius of sphere = 0.6 m
I = Moment of inertia of sphere = [tex]\dfrac{2}{5}mr^2[/tex]
Angular speed of the sphere is
[tex]\omega=\dfrac{2\pi}{T}=\dfrac{2\pi}{0.3}\\\Rightarrow \omega=20.94\ \text{rad/s}[/tex]
Rotational kinetic energy is given by
[tex]K_r=\dfrac{1}{2}I\omega^2=\dfrac{1}{2}\times \dfrac{2}{5}mr^2\omega^2\\\Rightarrow K_r=\dfrac{1}{2}\times \dfrac{2}{5}\times 15\times 0.6^2\times 20.94^2\\\Rightarrow K_r=473.56\ \text{J}[/tex]
The rotational kinetic energy of the sphere is [tex]473.56\ \text{J}[/tex].
1) How much work is done when a force of 50N
pulls a wagon 20 meters?
Answers
Answer:
100J
Explanation:
50N*20m=100J
N*m=J(joule)
An object with mass 100 kg moved in outer space. When it was at location <8, -30, -4> its speed was 5.5 m/s. A single constant force <220, 460, -200> N acted on the object while the object moved from location <8, -30, -4> m to location <14, -21, -7> m. Then a different single constant force <100, 260, 210> N acted on the object while the object moved from location <14, -21, -7> m to location <17, -27, -3> m. What is the speed of the object at this final location
Answers
Answer:
v = ( 6.41 i^ + 8.43 j^ + 2.63 k^ ) m/s
Explanation:
We can solve this problem using the kinematic relations, we have a three-dimensional movement, but we can work as three one-dimensional movements where the only parameter in common is time (a scalar).
X axis.
They indicate the initial position x = 8 m, its initial velocity v₀ = 5.5 m / s, the force Fx₁ = 220 N x₁ = 14 m, now the force changes to Fx₂ = 100 N up to the point xf = 17 m. The final speed is wondered.
As this movement is in three dimensions we must find the projection of the initial velocity in each axis, for this we can use trigonometry
the angle fi is with respect to the in z and the angle theta with respect to the x axis.
sin φ = z / r
Cos φ = r_p / r
z = r sin φ
r_p = r cos φ
the modulus of the vector r can be found with the Pythagorean theorem
r² = (x-x₀) ² + (y-y₀) ² + (z-z₀) ²
r² = (14-8) 2 + (-21 + 30) 2+ (-7 +4) 2
r = √126
r = 11.23 m
Let's find the angle with respect to the z axis (φfi)
φ = sin⁻¹ z / r
φ = sin⁻¹ ( [tex]\frac{-7+4}{11.23}[/tex] )
φ = 15.5º
Let's find the projection of the position vector (r_p)
r_p = r cos φ
r_p = 11.23 cos 15.5
r_p = 10.82 m
This vector is in the xy plane, so we can use trigonometry to find the angle with respect to the x axis.
cos θ = x / r_p
θ = cos⁻¹ x / r_p
θ = cos⁻¹ ( [tex]\frac{14-8}{10.82}[/tex])
θ = 56.3º
taking the angles we can decompose the initial velocity.
sin φ = v_z / v₀
cos φ = v_p / v₀
v_z = v₀ sin φ
v_z = 5.5 sin 15.5 = 1.47 m / z
v_p = vo cos φ
v_p = 5.5 cos 15.5 = 5.30 m / s
cos θ = vₓ / v_p
sin θ = v_y / v_p
vₓ = v_p cos θ
v_y = v_p sin θ
vₓ = 5.30 cos 56.3 = 2.94 m / s
v_y = 5.30 sin 56.3 = 4.41 m / s
we already have the components of the initial velocity
v₀ = (2.94 i ^ + 4.41 j ^ + 1.47 k ^) m / s
let's find the acceleration on this axis (ax1) using Newton's second law
Fₓx = m aₓ₁
aₓ₁ = Fₓ / m
aₓ₁ = 220/100
aₓ₁ = 2.20 m / s²
Let's look for the velocity at the end of this interval (vx1)
Let's be careful if the initial velocity and they relate it has the same sense it must be added, but if the velocity and acceleration have the opposite direction it must be subtracted.
vₓ₁² = v₀ₓ² + 2 aₓ₁ (x₁-x₀)
let's calculate
vₓ₁² = 2.94² + 2 2.20 (14-8)
vₓ₁ = √35.04
vₓ₁ = 5.92 m / s
to the second interval
they relate it to xf
aₓ₂ = Fₓ₂ / m
aₓ₂ = 100/100
aₓ₂ = 1 m / s²
final speed
v_{xf}² = vₓ₁² + 2 aₓ₂ (x_f- x₁)
v_{xf}² = 5.92² + 2 1 (17-14)
v_{xf} =√41.05
v_{xf} = 6.41 m / s
We carry out the same calculation for each of the other axes.
Axis y
acceleration (a_{y1})
a_{y1} = F_y / m
a_{y1} = 460/100
a_[y1} = 4.60 m / s²
the velocity at the end of the interval (v_{y1})
v_{y1}² = v_{oy}² + 2 a_{y1{ (y₁ -y₀)
v_{y1}2 = 4.41² + 2 4.60 (-21 + 30)
v_{y1} = √102.25
v_{y1} = 10.11 m / s
second interval
acceleration (a_{y2})
a_{y2} = F_{y2} / m
a_{y2} = 260/100
a_{y2} = 2.60 m / s2
final speed
v_{yf}² = v_{y1}² + 2 a_{y2} (y₂ -y₁)
v_{yf}² = 10.11² + 2 2.60 (-27 + 21)
v_{yf} = √ 71.01
v_{yf} = 8.43 m / s
here there is an inconsistency in the problem if the body is at y₁ = -27m and passes the position y_f = -21 m with the relationship it must be contrary to the velocity
z axis
first interval, relate (a_{z1})
a_{z1} = F_{z1} / m
a_{z1} = -200/100
a_{z1} = -2 m / s
the negative sign indicates that the acceleration is the negative direction of the z axis
the speed at the end of the interval
v_{z1}² = v_{zo)² + 2 a_{z1} (z₁-z₀)
v_{z1}² = 1.47² + 2 (-2) (-7 + 4)
v_{z1} = √14.16
v_{z1} = -3.76 m / s
second interval, acceleration (a_{z2})
a_{z2} = F_{z2} / m
a_{z2} = 210/100
a_{z2} = 2.10 m / s2
final speed
v_{fz}² = v_{z1}² - 2 a_{z2} | z_f-z₁)
v_{fz}² = 3.14² - 2 2.10 (-3 + 7)
v_{fz} = √6.94
v_{fz} = 2.63 m / s
speed is v = ( 6.41 i^ + 8.43 j^ + 2.63 k^ ) m/s
A 21 kg mountain lion carries a 3kg cub in it's mouth as it jumps from rest on the ground to the top of a 2 m talk rock. It takes 1 seconds for the mountain lion to jump and reach the top. How much power did the mountain lion exert? I need help to solve for power
Answers
Answer:
The power exerted by the mountain lion is 1,472.35 W.
Explanation:
Given;
mass of mountain, m₁ = 21 kg
mass of the cub, m₂ = 3 kg
height jumped by the mountain lion, h = 2 m
time taken for the mountain lion to jump, t = 1 s
Determine the weight of the lions on the top rock;
W = F = (m₁ + m₂)g
F = (21 + 3) x 9.8
F = (24) x 9.8
F = 235.2 N
Determine the final velocity of the mountain rock as it jumped to the top;
v² = u² + 2gh
where;
u is the initial velocity = 0
h is the height jumped = 2 m
v² = 0 + 2 x 9.8 x 2
v² = 39.2
v = √39.2
v = 6.26 m/s
The power exerted by the mountain lion is calculated as;
P = Fv
P = 235.2 x 6.26
P = 1,472.35 W
Therefore, the power exerted by the mountain lion is 1,472.35 W.
Light undergoes refraction as it travels from water to glass. The refractive index of water = 1.33 and refractive index of glass = 1.5. Calculate the angle of refraction inside glass if angle of incidence in the water is 32 degrees
Answers
Answer:
28°
Explanation:
Snell's Law and equation
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 ×102 T, what is the number of turns per meter for this solenoid?
Answers
Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;
[tex]B =\mu_o I(\frac{N}{L} )\\\\B = \mu_o I(n)\\\\n = \frac{B}{\mu_o I} \\\\n = \frac{2.8 \times 10^{-2}}{4 \pi \times 10^{-7} \times 5.0} \\\\n = 4.5 \times 10^3 \ turns/m[/tex]
Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
3.5 Temperature sensing in a light bulb. Incandescent light bulbs use a tungsten wire as the light-radiating filament by heating it to a temperature at which it is bright enough to produce light. The temperature of the wire can be estimated directly from the power rating and the resistance of the wire when it is cold. Given a 120 V, 100 W light bulb with a resistance of 22 W at room temperature (20 C): (a) Calculate the temperature of the filament when the light bulb is lit. (b) What are the possible sources of error in this type of indirect sensing
Answers
Answer:
Following are the solution to the given points:
Explanation:
In point a:
Given:
[tex]Temperature =20^{\circ } \ C, \\\\Resistance (R_o) = 22 \Omega[/tex]
However, the resistance of the bulb is 120 V or 100 W.
[tex]R= \frac{v^2}{P}=\frac{120^2}{100} =144 \Omega[/tex]
Let Tungsten's standard temperature coefficient be = 0.0045 [tex]20^{\circ} \ C[/tex]
Calculating temperature:
[tex]\to R=R_0(1+ \alpha (T-T_0))[/tex]
[tex]\to 144=22(1+0.0045(T-20))\\\\\to 144=22+0099(T-20)\\\\\to T -20 1232.32\\\\\to T =1252.32^{\circ } \ C \\[/tex]
In point b:
Potential consequences for indirect failures on iridescent bulb power device atmosphere does have a minor impact on defects, humidity, pressure, and surface that light bulb within the glass as well as the sensor attributable to the mercury.
12. If the distance an object travels and the time it takes to travel the distance are known, which of the following can be calculated? А Average speed B Average acceleration С Instantaneous speed Instantaneous acceleration
Answers
Answer:
A
Explanation:
Average speed
An organ pipe is 1.6 m long and open at both ends. What are the first three harmonic frequencies of this pipe?
Answers
Answer:
first harmonic = 56.7 Hz
Third harmonic = 170 Hz
Fifth harmonic = 283.3 Hz
Explanation:
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of 29.5 m. The runner starts the race at a constant speed. If she completes the 200-m dash in 24.4 s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track
Answers
Answer: [tex]2.27\ m/s^2[/tex]
Explanation:
Given
Length of the race track [tex]L=200\ m[/tex]
the radius of curvature of the track [tex]r=29.5\ m[/tex]
time taken to run on track is [tex]t=24.4\ s[/tex]
Speed of runner is
[tex]\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s[/tex]
Centripetal acceleration is
[tex]\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2[/tex]
3. The car's mass is 400 kg. It moves at a velocity of 20 m/s. Calculate the car's momentum. *
(10 Points)
0.05 kg.m/s
8000 kg.m/s
80,000 kg.m/s
20 kg.m/s
Answers
Answer:
momentum=mass×velocity
momentum =400kg×20m/s=8000kg.m/s
why do fishermen like fishing during a full moon?
Answers
Answer:
The full moon attracts more fish towards the surface of the water.
Explanation:
It is a proven fact that fish are attracted to shiny/glowing items. for example, a metal fishing lure. Or, an angler fish light-bulb.
In an electrical circuit, the amperage is 10A. It is supplied in a circuit with a voltage of 110V.
A. Calculate the resistance in the circuit.
B. Calculate the amount of electric charge passing through the circuit in 15 minutes
Answers
Answer:
11 ohm,,, 9kilo Columb
Explanation:
V=IR,,, Q =IT
Which two options are forms of kinetic energy?
A. Thermal energy
OO
O B. Nuclear energy
c. Sound energy
O D. Gravitational energy
O E. Chemical energy
Answers
Answer:
Themal energy is the best answer from you
Sound energy travels through matter in waves. Do sound waves travel faster through air or water? Explain your answer.
Answers
I uploaded the answer to a file hosting. Here's link:
tinyurl.com/wpazsebu
When an object is moving on a surface with a lot of texture, how does this affect the amount of friction created?
A. The friction is stopped.
B. Less friction is created.
C. More friction is created.
D. The amount of friction is the same
Answers
Answer:
b) less friction is created
Answer:
B
Explanation:
How much Work is done when a 5 kg object is picked up a distance of 8 m.
Answers
Answer:
392J?
Explanation:
Score
A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break, also the track can be stoped
in 7.6 m\s if the driver hit the wall.
a. What is the Impulse Excerted on the Vehicle?
b. Whta is the Averge force is exeted on the Track in each stops ?
Answers
Answer:
(a) J = 10560 kg-m/s (b) 251.42 N
Explanation:
Given that,
Mass, m = 4400 kg
Initial speed, u = 5.2 m/s
Final speed, v = 7.6 m/s
Time, t = 42 s
(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :
J = m(v-u)
J = 4400 (7.6-5.2)
J = 10560 kg-m/s
(b) Impulse = Force × t
[tex]F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N[/tex]
Hence, this is the required solution.
Which type of biological molecule would contain fats?
A) Amino Acids.
C) Nucleic Acids.
B) Lipids.
D) Carbohydrates.
Answers
B
Explanation:
lipids contains fat
hope it helps
Most modern vehicles have padded dashboards. This reduces collision injuries by...
1: reducing the driver's change in momentum
2:increasing the driver's change in momentum
3:increasing the force of impact
4:increasing the time of impact
Answers
Answer:
Option 4. is correct
Explanation:
A dashboard refers to a control panel that lies in front of the driver of the vehicle. Padded dashboards are designed to reduce injuries including face injuries and chest injuries to the driver as well as the front passenger on collisions.
Most modern vehicles have padded dashboards. This reduces collision injuries by increasing the time of impact.
Therefore,
Option 4. is correct
d. Two point charges, q1 = +25 nC and q2 = -75 nC, are separated by a distance of 3.0 cm. Find the magnitude and direction of; i. the electric force q1 exerts on q2 [5] ii. the force that q2 exerts on q1 [4] (take k = 9.0 x 109 N.m2 /C2 )
Answers
Answer:
a) F₂₁ = 0.02 N, attracting.
b) F₁₂ = 0.02 N, attracting.
Explanation:
a)
The magnitude of the force that q₁ exerts on q₂ (F₂₁) is given by Coulomb's Law, as follows:[tex]F_{21} = k * \frac{q_{1} *q_{2}}{r_{12}^{2} } = 9e9 N.m2/C2 * \frac{(25e-9C)*(75e-9C)}{(0.03m)^{2}} = 0.02 N (1)[/tex]
Since q₁ and q₂ have opposite signs, the force between them will be always attractive, i.e., from q₂ towards q₁, along the line that joins both charges.b)
The magnitude of the force on q₁ due to q₂ can be obtained applying Newton's 3rd Law, or using (1), because all parameters are the same, so F₁₂ (in magnitude) = F₂₁ = 0.02 NAs we have already said, it must be opposite to the one found in a) so it must go from q₁ towards q₂, it is an attracting force also.