PLZ HELP!!!!!! What is the equation of the line graphed below?

Answer:

5*(s+12) = $105

Step-by-step explanation:

5 snacks + 5 tickets makes the total 105 so the equation

5*(s+12) = $105 is the answer to the question.

Answer:

55

Step-by-step explanation:

x - 9 = 1/2(x + 37) according to inscribed angles theorem

2x - 18 = x + 37

x = 55

Answer:

[tex]x = \frac{22}{3}[/tex]

Step-by-step explanation:

Since both CB and ED intersect AD perpendicularly, we can say they are parallel and that ΔACB is similar to ΔAED from Thales intercept theorem. Now, we can set up a proportion from the definition of similar triangles:

[tex]\frac{AB}{AD} = \frac{BC}{DE}[/tex]

We can say that AD = AB + BD(segment addition postulate) and substitute to get AD = 11. Now we can plug in the numbers we have to the proportion:

[tex]\frac{6}{11} =\frac{4}{x}[/tex]

We can cross-multiply to get:

[tex]6x = 44[/tex]

and divide by 6 to get

[tex]x = \frac{22}{3}[/tex]

Answer:

Hello! answer: x = 68

Step-by-step explanation:

This is a complementary angle meaning it will add up to 90 degrees 90 - 22 = 68 therefore x = 68 HOPE THAT HELPS!

Answer:

1,440

Step-by-step explanation:

if first two digits must be odd, then there are 4x3 or 12 combinations for that

if the next three digits can be even or odd but not repeats then there can be 6 (two odds remaining plus four evens) x 5 x 4 = 120

120 x 12 = 1,440

Answer:

5 2/5

Step-by-step explanation:

4/10 - /5. 10 is divided by 2 to get to 5. 4 should also be divided by 2 which gets you 2. This is why your answer should be 5 2/5.

Answer:

[tex]x^2 -5x +3 = 0\\\\ x= \frac{-b \pm \sqrt{b^2-4*a*c} }{2a} \\\\b = -5, a = 1 , c = 3\\\\x= \frac{-b + \sqrt{b^2-4*a*c} }{2a} , x= \frac{-b -\sqrt{b^2-4*a*c} }{2a}\\\\x= \frac{5 + \sqrt{25-12} }{2}, x= \frac{5-\sqrt{25-12} }{2}\\\\x= \frac{5+\sqrt{13} }{2}, x= \frac{5- \sqrt{13} }{2}[/tex]

Step-by-step explanation:

1. C:arithmetic, 34, 39, 44

2. B: geometric, -64, 128, -256

3. C: geometric, 1, 1/3, 1/9

Answer:

(3,9)

Step-by-step explanation:

9-6 = 3

Answer:

2(-2,4) + 2(-1,8)=-8.4

Step-by-step explanation:

2x-2

2x4

2x-1

2x8

-8.4

Answer:

A. 244.93 ft sq

Step-by-step explanation: radius= 7 pi= 3.14 area for triangle= 168 area for semi-circle = 76.93.

how i got it:

area of semicircle 7 x 7 =49  49 x 3.14 = 153.86  153.86 divded by 2 = 76.93

 area of triangle: 14 x 24 = 336 336 divded by 2 = 168  168 + 76.93 = 244.93

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

[tex]t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}[/tex]

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

You hit the water 1.075 seconds after you jump.

The maximum height is 12.56.

Given that,

You are jumping off the 12-foot diving board at the municipal pool.

You bounce up at 6 feet per second and drop to the water your height h (in feet) above the water in terms of t seconds is given by,

[tex]\rm h(t)=-16t^2+6t+12[/tex]

We have to determine,

When do you hit the water?

What is your maximum height?

According to the question,

You bounce up at 6 feet per second and drop to the water your height h (in feet) above the water in terms of t seconds is given by,

[tex]\rm h(t)=-16t^2+6t+12[/tex]

1. The initial height is the height when t = 0 second,

[tex]\\\rm h(t)=-16t^2+6t+12\\\\\rm h(0)=-16(0)^2+6(0)+12\\\\ h(0) = 12[/tex]

And the diving board is 12 feet tall.

Then the zero in h(t)

h(t) = 0

When h(t) = 0 represent the surface of the water,

[tex]\rm h(t)=-16t^2+6t+12\\\\\rm -16t^2+6t+12 =0\\\\8t^2-3t-6=0\\\\x = \dfrac{-(-3)\pm \sqrt{(-3)^2-4\times8\times(-6)}}{2\times 8}}\\\\x = \dfrac{3\pm \sqrt{9+192}}{16}}\\\\x = \dfrac{3\pm \sqrt{201}}{16}}\\\\x = \dfrac{3\pm 14.77}{16}}\\\\ x = \dfrac{3+14.77}{16} \ and \ x = \dfrac{3-14.77}{16} \\\\x = \dfrac{17.77}{16} \ and \ x = \dfrac{-11.77}{16} \ \\\\ x = 1.075 \ and \ x = -0.855[/tex]

The value of x can not be negative then the value of x is 1.075.

Therefore, you hit the water 1.075 seconds after you jump.

2. The maximum height is reached by you, you first derivative the function h(t) with respect to t:

[tex]\rm \dfrac{dh(t)}{dt} = \dfrac{d(-16t^2+6t+12)}{dt}\\\\\rm \dfrac{dh(t)}{dt} = \dfrac{d(-16t^2)}{dt} +\dfrac{d(6t)}{dt}+\dfrac{d(12)}{dt}\\\\\rm \dfrac{dh(t)}{dt} = 2\times (-16t) + 6\times 1+0\\\\ \dfrac{dh(t)}{dt} = -32t+6\\\\[/tex]

To find the maximum height the value first derivative is equal to zero.

[tex]\rm \dfrac{dh(t)}{dt} = 0\\\\-32t+6=0\\\\-32t=-6\\\\t = \dfrac{6}{32}\\\\t = \dfrac{3}{16}\\[/tex]

Substitute the value of t in the equation to find the maximum height,

[tex]\rm h(\dfrac{3}{16})=-16(\dfrac{3}{16})^2+6(\dfrac{3}{16})+12\\\\ h(\dfrac{3}{16})=-(\dfrac{9}{16})+6(\dfrac{3}{16})+12\\\\ h(\dfrac{3}{16})=-\dfrac{-9}{16}+\dfrac{18}{16}+12\\\\ h(\dfrac{3}{16})= \dfrac{-9+18+192}{16} \\\\ h(\dfrac{3}{16}) = \dfrac{201}{16}\\\\h(\dfrac{3}{16}) = 12.56[/tex]

Hence, The maximum height is 12.56.

For more details refer to the link given below.

https://brainly.com/question/20120328

Answer:

See explanation

Step-by-step explanation:

Given

[tex]3x = 6[/tex]

Solving (a): What the expression means

3 when multiplied by x, gives 6

Solving (b): Why 2 is the solution

We have:

[tex]3x = 6[/tex]

Divide both sides by 3

[tex]\frac{3x}{3} = \frac{6}{3}[/tex]

[tex]x = \frac{6}{3}[/tex]

[tex]x = 2[/tex]

Answer:

Lateral Area: 120                                                                                    

Surface Area: 163.3

Answer:

r = √A/4π

Step-by-step explanation:

[tex]A=4\pi r^2\\\frac{A}{4\pi }=r^2\\\sqrt{\frac{A}{4\pi } }=r[/tex]

Answer:

r = √(A/4π)

Step-by-step explanation:

A =  4πr^2

Divide both sides by 4π

r^2 = A/4π

Take square root of both sides.

r = √(A/4π)

We take the positive square root only as r must be positive.

Answer:

15000000000000000000000000000000000000000000

Step-by-step explanation:

Answer:

150 centimeters

Step-by-step explanation:

just multiply!

hope this helps :)

Answer:8.5km

Step-by-step explanation:

Answer:

288 cubic feet

Step-by-step explanation:

6x6= 36 that is for one base now multiply by 8 and get 288

Answer:

Kite because it has two pairs of opposite sides and opposite angles that are equal .

Answer- 0.48

Hope this Helped :T

Answer: 6 times

Step-by-step explanation: 2.50 divided by 15 is 6.

Answer: 103,000

Step-by-step explanation:

Step-by-step explanation:

a) for the first part, you take your compass and stretch it more than halfway on to line UV. Place the fixed point at V and draw a curve. make sure you keep your compass the same size, put the fixed part of your compass on point U and draw a curve again. both curves should go both upward and downward. Now, your curves should meet at two points. use your straight edge to draw the line that meets at both points. I have drawn an example of what it should approximately look like. for the second part you are simply using your straight edge to draw a line from T down to the median M you previously found. I have drawn a second picture to show you.

b) now to check if they are perpendicular, we must find the slope of each line. I will not be able to do this accurately since I didn't use an exact method to find M, so you must follow my steps.

Step 1: find the slope of UV. To do so, we must take two points from the line. I will take points U and V because they are easiest to see. To find the slope, we can use the equation:

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

where m is the slope.

so, let's define our points.

Point V is (4,4), let's call this point one.

Point U is (14,6), let's call this point two.

So,

x1= 4

y1= 4

and

x2= 14

y2= 6

now, we can plug these into our slope equation.

[tex]m = \frac{6 - 4}{14 - 4} = \frac{2}{10} = \frac{1}{5} [/tex]

You must then use the points T and M in order to solve the second slope. Where T is (2,12). I will keep M as (x1, y1) for now.

The equation should then look like:

[tex]m = \frac{2 - y1}{12 - x1} [/tex]

now, in order for it to be perpendicular to our original slope, it must be the opposite reciprocal, which is the number flipped and made negative. The opposite reciprocal of 1/5 will be -5.

It should NOT be, as we have been told. So, we can state:

"I know that TM is not perpendicular to UV because the UV has a slope of 1/5 and TM has a slope of x, which is NOT the opposite reciprocal on 1/5."

Hope this helps! :)

Answer:

Yes

Step-by-step explanation:

Like terms are terms that have the same variables.

-c and 4c have the same variables. If it helps, -c can also be written as -1c. Both terms have the variable c.

I hope this helps!

Answer:

2 · x² - 20

Step-by-step explanation:

2x - 5 · x + 4

2x · x - 20

2x² - 20

2 · x² - 20

Answer:

[tex] {x}^{3} + {x}^{2} −24x+36[/tex]

Step-by-step explanation:

[tex](x + 6)(x - 2)(x - 3)[/tex]

[tex][x(x−2)+6(x−2)](x−3)[/tex]

[tex]( {x}^{2} −2x+6x−12)(x−3)[/tex]

[tex]( {x}^{2} +4x−12)(x−3)[/tex]

[tex] {x}^{3} + {x}^{2} −24x+36[/tex]

Answer:

Step-by-step explanation:

Rectangle 4 sides, 4 right angles, and opposite Parallel sides

Rhombus 4 sides, all sides equal length, and 4 acute angles.

I am 100% positive this answer is correct plz mark as brainliest