Answers
Applying the power rules, it was found that the equivalent expressions are: [tex]6^{(x+7)}*(2)^{5x}[/tex] and [tex](2)^{5x+1}*6^{(x+6)}*3[/tex].
Power RulesThe main power rules are presented below.
Multiplication with the same base: you should repeat the base and add the exponents.Division with the same base: you should repeat the base and subtract the exponents.Power. For this rule, you should repeat the base and multiply the exponents.Exponent negative - For this rule, you should write the reciprocal number with the exponent positive.Zero Exponent. When you have an exponent equal to zero, the result must be 1.For solving this question, you should apply the power rules and check the options are equivalent to the given expression [tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}[/tex].
From the power rules, you can simplify the given expression, as shown below.
[tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}=6*(6^2)^{\frac{x}{2}+3}*(2)^{5x}\\ \\ 6*(36)^{\frac{x}{2}+3}*(2)^{5x}=6*(6)^{x+6}*(2)^{5x}\\ \\ 6*(36)^{\frac{x}{2}+3}*(2)^{5x}=6*6^x*6^6*(2)^{5x}\\ \\ 6*(36)^{\frac{x}{2}+3}*(2)^{5x}=6^{(x+7)}*(2)^{5x}[/tex]
Then, you should find an expression equivalent to [tex]6^{(x+7)}*(2)^{5x}[/tex].
Option 1 - [tex]6^{(x+7)}*(2)^{5x}[/tex]This expression is exactly the result of the simplification done in the expression given [tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}[/tex].
It is equivalent to [tex]6^{(x+7)}*(2)^{5x}[/tex].
Option 2- [tex]6^{(2x+6)}*(2)^{5x}[/tex]The expression [tex]6^{(2x+6)}*(2)^{5x}[/tex] is not equivalent to [tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}[/tex].
Option 3- [tex](2)^{5x+1}*6^{(x+6)}*3[/tex][tex](2)^{5x+1}*6^{(x+6)}*3= 2^{5x}*2^1*6^x*6^6*3\\ \\ (2)^{5x+1}*6^{(x+6)}*3= 2^{5x}*6^x*6^6*6\\ \\ (2)^{5x+1}*6^{(x+6)}*3= 2^{5x}*6^x*6^7\\ \\ (2)^{5x+1}*6^{(x+6)}*3= 2^{5x}*6^{x+7}[/tex]
The expression [tex](2)^{5x+1}*6^{(x+6)}*3[/tex] is equivalent to [tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}[/tex].
Option 4- [tex]32^x*(216)^{\frac{x}{2}+3}[/tex][tex]32^x*(216)^{\frac{x}{2}+3} =2^{5x}*(6^3)^{\frac{x}{2}+3}\\ \\ 32^x*(216)^{\frac{x}{2}+3} =2^{5x}*(6^\frac{3x}{2} )*6^9}\\ \\[/tex]
The expression [tex]32^x*(216)^{\frac{x}{2}+3}[/tex] is not equivalent to [tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}[/tex].
Option 5- [tex]32^x*(6)^{\frac{x}{2}+4}[/tex][tex]32^x*(6)^{\frac{x}{2}+4}=2^{5x}*6^{\frac{x}{2} }*6^4[/tex]
The expression [tex]32^x*(6)^{\frac{x}{2}+4}[/tex] is not equivalent to [tex]6*(36)^{\frac{x}{2}+3}*(2)^{5x}[/tex].
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Related Questions
*See image *The number of foxes in a forest increases
by 20% each year.
This year, there are 500 foxes in the
forest.
Calculate the number of foxes that there
will be in the forest
a) after 1 year.
b) after 2 years.
Answers
Answer:
a) 600 foxes
b) 720 foxes
Step-by-step explanation:
See attached spreadsheet.
The rate of population increase is 20% each year. To find a new year's population, multiply the previous year's population by 0.20 (20%) and add that to the previous year. Year 1 would be (500)*(0.20) = 100 new foxes which are added to the year 0 population of 500, which means there are (500+100) or 600 foxes in year 1.
Year 2: (0.20)*(600) = 120 new foxes
Add 120 to the existing 600 to find 720 foxes in year 2,
============
A formula that can be used to predict the fox population for any year, n, would be:
P(n) = 500*(1+0.20)^n
where P(n) is the popluation at year n. The 500 is the population at year 0 (the starting population). (1+0.20) is the growth for each year (120%, which means the original population plus 20%). That is raised to the year of interest, n. [When n=0, (1+0.20)^0 = 1]
Graph f(x) = -x. Click on the graph until the graph of f(x) = -x appears.
Answers
The graph of f(x) = -x is attached.
What is the x-intercept?The intersection of a function or equation's graph with the x axis is known as the x intercept. This can be compared to a point having a value of 0.
For any given curve, the x-intercept is a coordinate that is plotted on the x-axis. To put it another way, the x-intercept is the value of the x coordinate at the point where the graph crosses the x-axis, or we can say that it is the value of the x coordinate at a point where the value of the y coordinate equals zero.
f(x) = -x ----------(1)
Equation (1) can be written as f(x) = -x+0
This is in the form of f(x)=mx+b,
where , m= -1, b=0
this represents a line
Find the x and y-intercepts: ( consider f(x)=y)
Find x-intercept when y=0
=> 0=-x
=> x=0
Thus, x-intercept is (0,0)
Find y-intercept when x=0
=> y=-0 = 0
Thus, y-intercept is (0,0)
We need another point, because both intercepts are same
When x= 1, y= -1
The point is (1,-1)
Plot these points and join them with a line.
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Complete Question:
Which of the following is the graph of f(x) = x2?
Click on the graph until the correct graph appears.
Q27) A retailer receives some products from three suppliers - $1, S2 and S3. The probability of successfully delivering the products in time by the suppliers are 0.85 for S1, 0.82 for S2 and 0.91 for S3. No supplier's delivery is impacted by any other supplier's delivery. The manufacturer orders 500 units of a raw material from $1, 120 units from S2 and 156 units from S3. What is the expected loss for the retailer given that failure to receive the materials in time will cost the manufacturer $20 per unit for the product supplied by $1, $30 for the product supplied by 52 and $10 for the product supplied by S3.
Answers
Expected loss for the retailer is $2288.4
There are three suppliers named S1, S2, and S3 who provide raw materials to a retailer. The probability of supplying the raw materials on time for S1, S2, and S3 are 0.85, 0.82, and 0.91 respectively. Let’s suppose that the retailer orders 500 units of raw material from S1, 120 units from S2, and 156 units from S3. The loss for the retailer is $20, $30, and $10 respectively for S1, S2, and S3. To find out the expected loss for the retailer, we can use the formula given below:Expected loss = (probability of loss) × (value of loss) + (probability of no loss) × (value of no loss)Let’s calculate the expected loss for each supplier separately.Supplier S1: The probability of not receiving raw material on time from S1 is 1 - 0.85 = 0.15. The expected loss due to S1 can be calculated as follows:Expected loss for S1 = (0.15) × (500 units) × ($20 per unit) = $1500Supplier S2: The probability of not receiving raw material on time from S2 is 1 - 0.82 = 0.18. The expected loss due to S2 can be calculated as follows:Expected loss for S2 = (0.18) × (120 units) × ($30 per unit) = $648Supplier S3: The probability of not receiving raw material on time from S3 is 1 - 0.91 = 0.09. The expected loss due to S3 can be calculated as follows:Expected loss for S3 = (0.09) × (156 units) × ($10 per unit) = $140.4Therefore, the total expected loss for the retailer can be calculated by adding the losses from all three suppliers.Total expected loss = $1500 + $648 + $140.4 = $2288.4Thus, the expected loss for the retailer is $2288.4.
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(09.02 MC)
What step is needed when constructing a circle circumscribed about a triangle? (1 point)
Group of answer choices
Construct the angle bisectors of each angle in the triangle.
Construct the perpendicular bisectors of each side of the triangle.
Construct the midpoints of each side of the triangle.
Construct the altitude of each angle in the triangle.
Answers
The step needed when constructing a circle circumscribed about a triangle is option B: Construct the perpendicular bisectors of each side of the triangle.
What is the triangle construction about?When constructing a circle circumscribed about a triangle, the center of the circle must lie at the intersection of the perpendicular bisectors of the sides of the triangle.
To construct the perpendicular bisector of a side, you need to find its midpoint and then draw a line perpendicular to the side passing through that midpoint.
By constructing the perpendicular bisectors of all three sides, you can find their point of intersection, which will be the center of the circle. Then, the radius of the circle can be found by measuring the distance from the center to any of the vertices of the triangle.
Therefore, Once you have the center and radius, you can draw the circle circumscribed about the triangle.
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AD and EC are diameters of 0. OB is a radius. Classify each statement as true or false. AOC = 100
Answers
Therefore , the solution of the given problem of circle comes out to be this statement is true ∠AOC = 100° .
Circle – what is it?Each area of a plane with a specific distance from this additional spot forms a circle (center). Thus, it comprises of curved spots that are separated from one another and separated by the surface. Additionally, it rotates evenly around the centre from all sides. Every set of endpoints in a circular, constrained double sphere is uniformly spaced apart from the "centre."
Here,
Given :
AD and EC are diameters as we can see they are passing through centre .
So , there are diameter.
=> ∠AOC = ∠A0B + ∠BOC
=> ∠AOC = 100°
thus , this statement is true ∠AOC = 100° .
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Let X be a geometric random variable with so that P(X=k)=(1=p)^k-1 p over k=1,2,…and p is the probability of success taking a value between 0 and 1. a) Let
P(A) be the event that X assumes an even number. Compute P(A) . b) Compute the expectation and variance of e^X. c) Compute P(e^x >10)
Answers
0.0472 (approx.)
Anwer:
a) P(A) = P(X is even) = P(X = 2) + P(X = 4) + P(X = 6) + ...Let us take p = 1/3, thus P(X = k) = (1 - p)^(k - 1)p, for k = 1, 2, 3, .... Therefore, P(X = 2) = (2 - 1)p(1-p), P(X = 4) = (4 - 1)p(1 - p)^3, P(X = 6) = (6 - 1)p(1 - p)^5, ...So, we haveP(A) = [(2-1)p(1-p)] + [(4-1)p(1-p)^3] + [(6-1)p(1-p)^5] + ...= p(1-p)[1 + 3(1-p)^2 + 5(1-p)^4 + ...]= p(1-p)/(1-(1-p)^2)= 2p(1-p) = 2/9.b) For a geometric random variable, we have E(X) = 1/p and Var(X) = (1 - p)/p^2.The expected value of e^X is:E(e^X) = Σ e^k (1-p)^(k-1) p= p Σ [e^(ln(1-p))]^(k-1) = p Σ (1-p)^(k-1)= p/(1-(1-p)) = 1/pAnd the variance of e^X is:Var(e^X) = E((e^X)^2) - [E(e^X)]^2= E(e^(2X)) - (1/p)^2= Σ e^(2k) (1-p)^(k-1) p - 1/p^2= p Σ [e^(2ln(1-p))]^(k-1) - 1/p^2= p Σ (1-p)^(2(k-1)) - 1/p^2= p/[1-(1-p)^2] - 1/p^2= (2-p)/(p(1-p)^2).c) P(e^X > 10) = P(X > ln(10)) = (1-p)^[ln(10)] = 0.0472 (approx.)
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Find the probability of obtaining exactly four tails when flipping four coins. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth
Answers
The probability of obtaining exactly four tails {( T,T,T,T)}, when flipping four coins is equals to the 1/16 = 0.0625.
Independent Events : If the result of one event does not influence the result of another event, then the events are referred to as independent. In other words, it can be said that both events can happen simultaneously without interference. Probability is defined as a chance of occurrence of an event. Let E be the event that exactly four tails when flipping four coins. As we know that, when One coin is flip, total outcomes = 2 = { H,T}
So, 4 coins flipped, total possible outcomes = 16
Probability of getting tail on flipping one coin = 1/2
That is exactly four tails when flipping four coins are independent events. Therefore, the probability of obtaining four tails in a row in 4 flips of a coin is the product of probability in 4 flips. Since each flipping of a coin is independent, so
the probability of obtaining exactly four tails when flipping four coins = P(X = 4)
=( 1/2)(1/2)(1/2)(1/2) = (1/2)⁴
= 0.0625
Hence, required probability is 0.0625.
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Hi. I need to know the answer because one of my friends wanted to know the answer and I knew the answer, but not how to explain it well enough: Adrienne and Evelyn have a pet cat. When they got it as a kitten, as much as it it weighed 0.6 kilograms. Now it weighs 7.3 times did when it was a kitten. How much does their cat weigh now?
Answers
So their cat weighs 4.38 kilograms now.
What is an algebraic expression?
An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations. It may also include exponents and/or roots. Algebraic expressions are used to represent quantities and relationships between quantities in mathematical situations, often in the context of problem-solving.
Algebraic expressions can take many different forms, but some common examples include:
3x + 7
2a^2 + 5ab - 3b^2
(x + 2)(x - 5)
4x^2 - 9.
Let's start by figuring out how much the cat weighs now. We know that the cat weighs 7.3 times what it did when it was a kitten, and it weighed 0.6 kilograms when it was a kitten.
To find out how much the cat weighs now, we can multiply its original weight by 7.3:
0.6 kilograms x 7.3 = 4.38 kilograms
Therefore, So their cat weighs 4.38 kilograms now.
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−
2
x
+
2
y
=
8
6
x
+
y
=
11
If
(
x
,
y
)
is the solution to the system of equations above, what is the value of
7
y
?
Answers
Answer:
7y=-91
Step-by-step explanation:
-2x + 2y = 8 (multiply the second equation by 2)
12x + 2y = 22
Adding the two equations, we get:
10x = 30
Therefore, x = 3.
Substituting x = 3 into the second equation, we get:
6(3) + y = 11
Simplifying, we get:
y = -13
Finally, we can find the value of 7y:
7y = 7(-13) = -91
enter your answer and show all the steps that you use to solve this in the space provided.
find the surface area of the cone. Use 3.14 for π height 7in diameter 8in and below it says drawing not to scale??
Answers
The surface area of the cone is 305.30 inches squared.
How to find the surface area of a cone?The height of the cone is 7 inches and the diameter of the cone is 8 inches. Therefore, let's find the surface area of the cone as follows:
surface area of the cone = πr(r + l)
where
r = radiusl = slant heightHence,
r = 8 / 2 = 4 inches
l² = 7² + 4²
l = √49 + 16
l = √65
l = 8.0622577483
l = 8.06 inches
Therefore,
surface area of the cone = 3.14 × 8.06(4 + 8.06)
surface area of the cone = 25.3154893297(12.06)
surface area of the cone = 305.304801316
surface area of the cone = 305.30 inches squared
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MNPQ is a rectangle. Find the value of x.
*
Answers
Explanation:
All angles in a rectangle are right angles. That means we can make an equation of 3x + 2x + 20 + 90 = 180
( 180 because half of a rectangle)
To solve:
Combine like terms -
5x + 110 = 180
Subtract -
5x = 70
Divide -
x = 14 degrees
help please i really appreciate it
Answers
Answer:
B
Step-by-step explanation:
The system of linear equations below has the solution (3, 3), where F, G, H, P. Q, and R are non-zero real numbers.
Fr+ Gy=H
Pr+Qy= R
Which system must also have the solution (3,3) ?
3Fx - 3Gy= H
Pr + Qy = R
[ 3Fx + 3Gy = H
13Px +3Qy = R
((F+3P) x + (G+ 3Q) y = H + 3R
Pr+Qy = R
((F+3G) x + (P+3Q) y = H + 3R
Pr+Qy = R
Answers
Answer:
3Fx - 3Gy= H
Step-by-step explanation:
A bank offers two interest account plans. Plan A gives you 6% interest compounded annually. Plan B gives you 13% annual simple interest. You plan to invest $2,000 for the next 4 years. Which account earns you the most interest (in dollars) after 4 years? How much will you have earned?
Answers
Answer:
Plan A
The formula is
A=p (1+r)^t
A=2,000×(1+0.06)^(4)
A=2,524.95 ( future value )
Interest earned=A-p
Interest earned=2524.95-2000
Interest earned=524.95
Plan B
Use the simple interest formula
I=prt
I interest earned?
P principle 2000
R interest rate 0.13
T time 4years
I=2,000×0.13×4
I=1,040
The Answer is
Plan B; $1,040
Step-by-step explanation:
When women were allowed to become pilots of fighter jets, engineers needed to redesign the ejection seats because they had been originally designed for men only. The ACES-II ejection seats were designed for men weighing between 140LB and 211LB. Weights of women are now normally distributed with a mean of 165LB and a standard deviation of 45.6LB
a. If 1 woman is randomly selected, find the probability that her weight is between 140LB and 211LB
b. If 36 different women are randomly selected, find the probability that their mean weight is between 140LB and 211LB
Answers
The probability that the mean weight of 36 different women is between 140LB and 211LB is approximately 0.9874.
Is it possible for a random variable to have 0 probability across the board?There can only be one value for a random variable. A random variable's value could be zero with a probability of zero. A probability distribution's total probabilities are always equal to one.
a. We must convert the weight to a typical normal distribution using the following formula in order to determine the likelihood that a randomly chosen woman weighs between 140LB and 211LB.
z = (x - μ) / σ
If the weight x, the mean weight, and the standard deviation are all given. The probability can then be determined using a calculator or a typical normal table.
When x=140LB, we get:
z = (140 - 165) / 45.6 = -0.5461
x = 211LB results in:
z = (211 - 165) / 45.6 = 1.0096
The area under the standard normal curve between z = -0.5461 and z = 1.0096 is found to be roughly 0.6267 using a typical normal table or calculator.
Hence, the likelihood that a lady chosen at random weighs between 140LB and 211LB is roughly 0.6267.
b. We must normalise the sample mean to a standard normal distribution using the following method in order to determine the likelihood that the mean weight of 36 individual women is between 140LB and 211LB.
z is equal to (x - ) / (n / sqrt(n)).
When n is the sample size, x is the sample mean weight, is the mean weight, and is the standard deviation. The probability can then be determined using a calculator or a typical normal table.
To solve this issue, we have:
μ = 165LB
σ = 45.6LB
n = 36
If x = 140 LB, we get:
z = (140 - 165) / (45.6 / sqrt(36)) = -2.4994
With x = 211LB, we get:
z = (211 - 165) / (45.6 / sqrt(36)) = 2.4994
The area under the standard normal curve between z = -2.4994 and z = 2.4994 is found to be around 0.9874 using a standard normal table or calculator.
Hence, there is a roughly 0.9874 percent chance that the average weight of 36 individual women falls between 140LB and 211LB.
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ALGEBRA 2 HELP
(Please show work!)
A student wrote the arithmetic series 8 + 11 + ... + 29 in summation notation as (picture below)
a. Describe and correct the error in the notation.
b. Evaluate the corrected summation of the arithmetic series above.
[tex]S_8=[/tex]
c. Write the explicit and recursive formulas for the arithmetic series above,
Explicit:
[tex]a_n=[/tex]
Recursive:
If [tex]a_1=[/tex]
Then for n > 1
[tex]a_n=[/tex]
Answers
Step-by-step explanation:
ALGEBRA 2 HELP
(Please show work!)
A student wrote the arithmetic series 8 + 11 + ... + 29 in summation notation as (picture below)
a. Describe and correct the error in the notation.
b. Evaluate the corrected summation of the arithmetic series above.
�
8
=
S
8
=
c. Write the explicit and recursive formulas for the arithmetic series above,
Explicit:
�
�
=
a
n
=
Recursive:
If
�
1
=
a
1
=
Then for n > 1
�
�
=
a
n
=
HEELLPPPP!!!! quickly im being timed.
Answers
need help with part A part B and part c
Answers
Answer:
4,20,C
Step-by-step explanation:
1/7 of 28 is 4
5/7 of 28 is 20
and if you multiply 4 times 5 you get 20
hope this helped
Find the Primeter and area
Answers
For rectangle type books, the difference in the heights of their stacks of books is 15 3/4 inches.
What exactly is a rectangle?
A rectangle is a type of quadrilateral (a four-sided polygon) that has four straight sides and four right angles. It is a two-dimensional shape, meaning it lies flat in a plane, and is defined by its two sets of parallel sides, each pair of which are equal in length.
In a rectangle, opposite sides are parallel and congruent (equal in length), and adjacent sides are perpendicular (meet at a right angle). The diagonals of a rectangle bisect each other (divide each other into two equal parts) and are congruent.
The area of a rectangle is calculated by multiplying its length and width, while its perimeter is found by adding the lengths of all its sides. The area of a rectangle is A = l x w, where A is the area, l is the length, and w is the width.
Now,
To solve this problem, we need to first find out the height of Rick's stack of books. We know that his stack is 3 times as tall as Trevor's stack, so:
Rick's stack = 3 x Trevor's stack
Rick's stack = 3 x 7 7/8 inches
Rick's stack = 23 5/8 inches
Now that we know the height of both stacks, we can find the difference between them:
Difference = Rick's stack - Trevor's stack
Difference = 23 5/8 inches - 7 7/8 inches
Difference = 15 6/8 inches
Difference = 15 3/4 inches
Therefore, the difference in the heights of their stacks of books is 15 3/4 inches.
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for the next olympic winter games, the organizers wish to expand the number of teams competing in curling. they wish to have teams enter, divided into two pools of seven teams each. right now, they're thinking of requiring that in preliminary play each team will play seven games against distinct opponents. five of the opponents will come from their own pool and two of the opponents will come from the other pool. they're having trouble setting up such a schedule, so they've come to you. by using an appropriate graph-theoretic model, either argue that they cannot use their current plan or devise a way for them to do so.
Answers
The organizers can use their current plan and have each team play 7 games against distinct opponents, with 5 of the opponents from their own pool and 2 of the opponents from the other pool.
To answer this question, we can use a bipartite graph as a model. A bipartite graph is a graph that has two sets of vertices, X and Y, with edges only between vertices from different sets. In this case, we can have one set of vertices representing the teams in one pool and the other set of vertices representing the teams in the other pool.
We can start by drawing a bipartite graph with 14 vertices, 7 in each set. Each vertex represents a team, and we can label them as T1, T2, ..., T14. Now, we need to add edges to represent the games that each team will play.
For each team in one pool, we can add 5 edges to connect it to 5 different teams in the same pool, and 2 edges to connect it to 2 different teams in the other pool.
After adding all the edges, we can see that each team has 7 edges connected to it, representing the 7 games that it will play. However, we also need to make sure that each team plays against distinct opponents. To do this, we can check if there are any duplicate edges in the graph.
If there are no duplicate edges, then the schedule can be used as it is. But if there are duplicate edges, then the schedule cannot be used and the organizers need to come up with a different plan.
In this case, we can see that there are no duplicate edges in the graph, which means that the schedule can be used as it is. Therefore, the organizers can use their current plan and have each team play 7 games against distinct opponents, with 5 of the opponents from their own pool and 2 of the opponents from the other pool.
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(x + 2y ) 2 some one answer this please I need help
Answers
Answer:
x² + 4xy + 4y²
Step-by-step explanation:
(x + 2y )²
= (x + 2y) (x + 2y)
= x² + 2xy + 2xy + 4y²
= x² + 4xy + 4y²
So, the answer is x² + 4xy + 4y²
Which is better? 8"A" students out of 40, or 9 "A" student out of 50
Answers
The first group has a higher proportion of "A" students 0.2
To determine which is better, we need to compare the proportions of "A" students in each group.
For the first group, the proportion of "A" students is:
8/40 = 0.2
For the second group, the proportion of "A" students is:
9/50 = 0.18
Therefore, the first group has a higher proportion of "A" students, and we can say that it is "better" in terms of producing "A" students. However, it is important to note that this is just one aspect of performance and there may be other factors to consider as well.
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These triangles are similar. I need to know what x is.
Answers
The value of x as per the similarity of triangles is = 7.1.
What is similarity of triangles?If two triangles' sides have the same ratio or proportion and their angles are the same (corresponding angles), then the triangles will resemble one another (corresponding sides).
Similar triangles may have varied side lengths when compared individually, but they must all have the same ratio of their side lengths and equal angles.
Now in the figure, the triangles are similar.
So, sides of the triangles will be proportional to each other.
Now, 9/15 = 4.3/x
⇒ x = (4.3 × 15)/ 9
⇒ x = 7.1
Therefore, the value of x as per the similarity of triangles is = 7.1.
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2p - 5q= 8
3p - 7q = 11
Solve the simultaneous equation using elimination method
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Step-by-step explanation:
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URGENT!!
3. Suppose ABC=EFG, and EG=7x-11, AB 5x -9. GF=3x-1 and AC=2x+4 . Find the value of x and the lengths of the sides of EFG.
Part I: Sketch the triangles below.
Part II: Use measures for AC and EG to find the value of x. Show your work.
Part III: Find the lengths of the sides of EFG. Show your work.
Part IV: Explain how to find the lengths of the sides of ABC.
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Part II: Value of x=0
Part III: the lengths of the sides of EFG as EF = G = 11 and EG = -11.
Part IV: the lengths of the sides of ABC as AB = -9, GF = -1, and AC = 4.
What is value?Value can be used to find the solution to an equation or to compare two or more values.
Part II: To find the value of x, we need to use measures for AC and EG. We can use the equation AC = 2x + 4 to solve for x.
We can rearrange the equation to 2x = AC - 4, and then substitute in the value of AC, which is 2x + 4.
This gives us 2x = 2x + 4 - 4, or 0 = 0
x = 0.
Part III: To find the lengths of the sides of EFG, we can use the equation EF = G + 7x - 11.
Substituting in the value of x, which is 0, we get
EF = G + 7 * 0 - 11,
or EF = G - 11.
Since EG = 7x - 11, substituting in the value of x gives us
EG = 7 * 0 - 11,
or EG = -11.
So EF = G and EG = -11
Part IV: To find the lengths of the sides of ABC, we can use the equation AB = 5x - 9, substituting in the value of x as 0.
This gives us AB = 5 * 0 - 9,
or AB = -9.
Since GF = 3x - 1 and AC = 2x + 4, substituting in the value of x gives us GF = 3 * 0 - 1,
or GF = -1,
and AC = 2 * 0 + 4
or AC = 4.
So AB = -9, GF = -1, and AC = 4, giving us the lengths of the sides of ABC as AB = -9, GF = -1, and AC = 4.
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to decrease a number by 37% you multiply by 0.63
to decrease a number by 16% what do you multiply it by
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To decrease a number by 16%, you should multiply it by 0.84.(1 - 0.16 = 0.84).
When you reduce a number by a percentage, you are subtracting that percentage from it. For example, if you were to decrease 100 by 16%, you would subtract 16 from 100 to get 84.
This is also known as a percentage decrease, which is the opposite of a percentage increase.
Using the formula for percentage decrease, we get:
Percentage decrease = (Decrease in value / Original value) × 100
We're told that to decrease a number by 37%, you multiply it by 0.63.
Therefore, we can write:
0.63 = (Decrease in value / Original value) × 1000.63 × Original value = Decrease in value
We want to find what you multiply a number by to decrease it by 16%, so let's call that value x.
So: x = (Decrease in value / Original value) × 100%
So, we can substitute in the values we know to solve for x:
x = (0.16 × Original value / Original value) × 100%x = 0.16 × 100%x = 16%
Therefore, to decrease a number by 16%, you should multiply it by 0.84.
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Trey and matt each have a rectangular prism the base if treys is 4 by 7 by 12 the base of matts prism is 6 by 10 by 3 whose rectangular prism will require more material to construct
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Trey's rectangular prism will require more material to be constructed.
To determine which rectangular prism will require more material to construct, we need to calculate the surface area of each prism.
The surface area of a rectangular prism is given by the formula,
SA = 2×l×w + 2×l×h + 2×w×h
where l, w, and h are the length, width, and height of the prism, respectively.
For Trey's prism, the length is 12, the width is 7, and the height is 4. Therefore, the surface area of Trey's prism is:
SA of Trey = 2(12 x 7) + 2(12 x 4) + 2(7 x 4) = 336
For Matt's prism, the length is 10, the width is 6, and the height is 3. Therefore, the surface area of Matt's prism is,
SA of Matt = 2(10 x 6) + 2(10 x 3) + 2(6 x 3) = 192
Comparing the surface areas, we see that Trey's prism requires more material to construct since its surface area is larger than Matt's prism. Therefore, Trey's rectangular prism requires more material to construct than Matt's rectangular prism.
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What is the x-coordinate of the midpoint of line segment AB with points A(21, 5) and B(-9, -13).
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Answer:
6
Step-by-step explanation:
You want the x-coordinate of the midpoint of segment AB with endpoint coordinates A(21, 5) and B(-9, -13).
MidpointThe midpoint of a line segment has coordinates that are the average of the endpoint coordinates:
M = (A +B)/2
M = ((21, 5) +(-9, -13))/2 = (12, -8)/2
M = (6, -4)
The midpoint of AB is (6, -4).
The x-coordinate of the midpoint is 6.
Mrs. Smitherman is coordinating the third- and fourth-grade program. She wishes to arrange the children to the fewest number of rows that contain the same number of children. She also does not wish to mix be classes within a row. If there are 60 third graders and 48 fourth graders, how many children should be aced in each row? How many rows will be needed?
Answers
Answer:
Number of students in each row = 12
Total number of rows = 9
Step-by-step explanation:
We have to assume that each row can seat the same number of students
Find the GCF(greatest common factor) of 60 and 48 to find the number of students in each row
60 = 12 x 5
48 = 12 x 4
The GCF = 12
So there are 12 students per row
If there are 60 third-grade students they will occupy 60/12 = 5 rows
48 fourth grade students will occupy 48/12 = 4 rows
Therefore the total number of rows = 5 + 4 = 9 rows
Eighteen individuals are scheduled to take a driving test at a particular DMV office on a certain day, eight of whom will be taking the test for the first time. Suppose that six of these individuals are randomly assigned to a particular examiner, and let X be the number among the six who are taking the test for the first time. a. What kind of a distribution does X have (name and values of all parameters)?
b. Compute c. Calculate the mean value and standard deviation of X.
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The distribution of X is a hypergeometric distribution, he probability that exactly 2 of the 6 individuals assigned to the examiner are taking the test for the first time is 0.317 and the mean value of hypergeometric distribution is 1.187.
a. The distribution of X is a hypergeometric distribution with the following parameters:
N = 18 (total number of individuals)
K = 8 (number of individuals taking the test for the first time)
n = 6 (number of individuals randomly assigned to a particular examiner)
b. The probability mass function of a hypergeometric distribution is given by:
P(X = x) = (K choose x) * ((N-K) choose (n-x)) / (N choose n)
So, for example, the probability that exactly 2 of the 6 individuals assigned to the examiner are taking the test for the first time is:
P(X = 2) = (8 choose 2) * (10 choose 4) / (18 choose 6) = 28 * 210 / 18564 = 0.317
c. The mean value of a hypergeometric distribution is given by:
E(X) = n * (K/N) = 6 * (8/18) = 2.667
The standard deviation of a hypergeometric distribution is given by:
SD(X) = sqrt(n * (K/N) * ((N-K)/N) * ((N-n)/(N-1))) = sqrt(6 * (8/18) * (10/18) * (12/17)) = 1.187
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