plsss help with these 2 questions

Answer:

$42.50

Step-by-step explanation:

discount reduces the price of the good

discount value = 15% x 50 = 0.15 x 50 = 7.5

sales price = 50 - 7.5 = 42.50

Answer:

post the entire question

Answer:

11.5 years

Step-by-step explanation:

Given data

Principal= $400

Rate= 6%

For the compound interest at time t, the expression is given as

A= P(1+r)^t

Substitute

A= 400(1+0.06)^t

A=400(1.06)^t

B. How much money is in Jennifer's account after 5 years

put t= 5

A=400(1.06)^5

A=400*1.338

A=$535.2

C. Approximately when will Jennifer have $800 in her account

A=$800

P=$400

r=6%

t= ln(A/P)/r

t= ln(800/400)/0.06

t= ln(2)/0.06

t= 0.6931/0.06

t=11.551

Hence the time is about 11.5 years

Answer:

6

Step-by-step explanation:

4 – (3 – 5) =

PEMDAS says parentheses first

4 – (-2) =

Subtracting a negative is like adding

4 +2

6

Answer:

2-

Step-by-step explanation:

.....................................................................

Answer:

the answer is D

Step-by-step explanation:

Got it wrong on the A*pex test D is the correct answer

1+(1/30)30

Answer

Equation: m - 12 = 20

Answer:

It’s 12.48 but if it is only a number and no decimals it will be 12.

Step-by-step explanation:

Answer:

y - x= - 13   -------(1)

- 4x + 3y = -51 -------(2)

(1) => y = - 13 + x

Substitute y in (2)

- 4x + 3( - 13 + x) = -51

- 4x - 39 + 3x = -51

- x = -51 + 39

- x = -12

x = 12

Substitute x in (1)

y = - 13 + x = -13 + 12 = - 1

x = 12, y = -1

Answer:

see explanation

Step-by-step explanation:

(a)

[tex]\frac{3}{7}[/tex] a × - [tex]\frac{21}{15}[/tex] b ( cancel 3 and 15 and 7 and 21 )

= a × - [tex]\frac{3}{5}[/tex] b

= - [tex]\frac{3}{5}[/tex] ab

(b)

3xy(5x²y² - 4yz) ← multiply each term in the parenthesis by 3xy

= 15x³y³ - 12xy²z

Answer:

$2,263.63

Step-by-step explanation:

You start with "if" but don't end with what your goal is.  I will assume that you want to know how much you'll have to pay after 5 years to pay off this $1,000 loan.  

Use the compound amount formula A = P(1 + r)^5.  Replacing P with $1,000, r with 0.1775 and t with 5 years, we get the payoff balance

A = $1,000(1 + 0.1775)^5 = $2,263.63

Answer:

9514 1404 393

Answer:

  Identity Property

Step-by-step explanation:

The identity property of addition is illustrated.

The identity element is 0. It is the additive identity element because the original value retains its identity when 0 is added.

Answer:

68.47

Step-by-step explanation:

30%=0.3

20.54/0.3=68.4666……

Answer:

A. We cannot calculate this value.

Step-by-step explanation:

Had it on my test c:

We cannot calculate this value because the width is not given so we cannot find the area of the region option (A) is correct.

It is defined as the ratio of the population to the total area. The population density represents the average number of people living on each square unit.

We have:

If you live in a rectangular city that is 1 mile along the southern border and contains 1000 people,

As we know,

population density = number of people/area of the region

As we have a rectangular city,

The area of the city = length×width

Width is not given so we cannot find the area of the region.

Thus, we cannot calculate this value because the width is not given so we cannot find the area of the region option (A) is correct.

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0.04

jndjnwjnc jwnfjnjwfjn jn jnwjnj njnfjbfwhijfkwb jnj nwjnjfjwkf n

Answer:

[tex]Students = 340[/tex]

Step-by-step explanation:

Given

[tex]2008 \to 83\%[/tex]

[tex]2009 \to 85\%[/tex]

[tex]2010 \to 89\%[/tex]

[tex]2011 \to 84\%[/tex]

[tex]2012 \to 88\%[/tex]

[tex]2013 \to 81\%[/tex]

[tex]n = 400[/tex]

Required

The expected number of students

First, calculate the average attendance in the 6 years of the talent show.

[tex]\bar x = \frac{83\% + 85\% + 89\% + 84\% + 88\% + 81\%}{6}[/tex]

[tex]\bar x = \frac{510\%}{6}[/tex]

[tex]\bar x = 85\%[/tex]

The expected number of students is:

[tex]Students =n * \bar x[/tex]

[tex]Students = 400 * 85\%[/tex]

[tex]Students = 340[/tex]

Answer:

[tex]x=0.1 ~ft[/tex]

Step-by-step explanation:

[tex]cot30=\frac{B}{H} =\frac{B}{H}[/tex]

[tex]\frac{\sqrt{3} }{2} =\frac{B}{H}=H=\frac{16}{\sqrt{3} }[/tex]

[tex]sin70=\frac{X}{H} =\frac{P}{H}[/tex]

[tex]sin70=\frac{x}{\frac{16}{\sqrt{3} } }[/tex]

[tex]x=\frac{\sqrt{3} }{16 ~sin70}[/tex]

[tex]=0.1152[/tex]

[tex]x=0.1[/tex]

----------------------

hope it helps

have a great day!!

Answer: 9.7

Step-by-step explanation: I got this question right

70+30 = 100

B = 180 - 100 - 20

B = 60°

80+20 = 100

C = 180 - 100 - 30

C = 50

DB/sin100 = 8/sin(60)

8*sin(100)/sin(60)

DB = 9.0973

DC/sin(30) = 8/sin(50)

8*sin(30)/sin(50)

DC = 5.22163

x = [tex]\sqrt{5.22163^{2} +9.0973^{2} -2*5.22163*9.0973*cos(80)[/tex]

x = 9.7

Answer:

10[tex]\pi[/tex]

Step-by-step explanation:

Length of arc = [tex]\frac{theta }{360} * 2\pi r[/tex]

= [tex]\frac{150}{360} * 2 \pi * 12\\[/tex]

= [tex]10\pi[/tex]

Answer:

10^x=1/100

10^x=10^-10

x=-10

Step-by-step explanation:

Answer:

The answer is option B.

Step-by-step explanation:

Answer: D

Step-by-step explanation:

The histogram shows driving to work so A even though it looks like it may fit there is no way to assume they don’t drive at all

Hope this helps

Answer:

Step-by-step explanation:

Sp of an article= Rs 2300

profit%=15%

let Cost Price of an article be X

SP=CP+PROFIT %*CP

2300=X+15/100*X

2300=100X+15X/100

2300*100=115X

230000/115=X

2000=X

Therefore cost price of an article is Rs 2000.

Answer:

D is a binomial random variable with [tex]p = 0.65, n = 15[/tex]

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they have dogs, or they do not. The probability of a customer having a dog is independent of any other customer. This means that D is a binomial random variable.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

65% of the customers have dogs:

This means that [tex]p = 0.65[/tex]

15 customers:

This means that [tex]n = 15[/tex]

What type of variable is D?

D is a binomial random variable with [tex]p = 0.65, n = 15[/tex]

Answer:

binomial

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

========================================================

Explanation:

She saved 10 shots out of 18 total, so that means 18-10 = 8 shots went in.

That forms the ratio 8:10 where we list the amount of shots that went in, followed by a colon, then the amount of shots that were saved. The order is important. From here, we divide both parts of the ratio by 2. The ratio 8:10 fully reduces to 4:5

Effectively, this means that for every 4 shots that went in, there were 5 shots that were blocked.

Answer:

y=2

Step-by-step explanation:

-2y+1=y-5

Add 2y to each side

-2y+2y+1=y+2y-5

1 = 3y -5

Add 5 to each side

1+5 = 3y-5+5

6 = 3y

Divide each side by 3

6/3 = 3y/3

2 =y

Answer:

y=2

Step-by-step explanation:

Move y to the other side by subtracting by y on both sides:

-y-2y+1=y-y-5

-3y+1=-5

Move the 1 to the other side by subtracting by 1 on both sides:

-3y+1-1=-5-1

-3y=-6

Divide -3 on both sides to eliminate the -3 on y

-3y/-3=-6/-3

y=2

Answer:

about 4.1 miles per hour

Answer:

zⁿ = z³

Step-by-step explanation:

We have the expression:

√(z/ z^⅓)

Hence

= z^½/ (z^⅓)^½

= z^½/ (z^⅙)

= z^(½ ÷⅙)

= z ^(1/2 × 6/1)

= z³

Therefore: zⁿ = z³

Answer:

10

Step-by-step explanation:

Determinant = ad - bc

[tex]\det\begin{pmatrix} 2 & 0 \\-2 & 5\end{pmatrix} =\begin{vmatrix} 2 & 0 \\-2 & 5\end{vmatrix} = 2\times5 + 0\times2 = 10[/tex]

Probability  that the two numbers are multiples of 3 after replacing first

It is a branch of mathematics that deals with the occurrence of a random event.

The odd integers from11 to 22 are

11,13,15,17,19,21

So there are 6 events

Out of these 6 numbers, 2 numbers (15,21) are multiples of 3.

One number out of these 2 numbers can be chosen in 2 ways.

Therefore, favourable number of elementary events = 2.

Required probability =2/6=1/3

Hence 1/3 is the probability  that the two numbers are multiples of 3 after replacing first

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