Pls tell me what goes in each box

Answer:

2/5

Step-by-step explanation:

3/8 = 375/1000

1/2 = 500/1000

2/5 = 400/1000

Answer:

1) y = 17

2) w = 20

Step-by-step explanation:

Answer:

y= 17

w= 20

Step-by-step explanation:

the answer is 2

Solution:

32⅕

(2⁵)⅕

Answer is 2

Answer:

125+9x-8=180

6x+13+6y+29=180

Step-by-step explanation:

Answer:

Step-by-step explanation:

2x+10x=12x

12x=-21

x=-1.75

Answer:

x=-7,-3

Step-by-step explanation:

x2+10x+21

(x+7)(x+3)

x=-7,-3

9514 1404 393

Answer:

  1,570,000

Step-by-step explanation:

The sum is approximately ...

  1,260,000 +310,000 = 1,570,000

_____

Additional comment

It is a good idea to estimate the error associated with an estimate. Here, both numbers are rounded up by about 4000 each, so the estimate is around 8000 high.

Answer:

Use trigonometry

Choice A

Choice D

Answer:

the person above me is correct i said that because i did the math and solved it

Step-by-step explanation:

Answer:

It is 603 units greater

Step-by-step explanation:

Given

See attachment for table

Average rate of change over (a,b) is calculated as:

[tex]Rate = \frac{f(b) - f(a)}{b-a}[/tex]

For interval [7,9], we have:

[tex][a,b] = [7,9][/tex]

So, we have:

[tex]Rate = \frac{f(9) - f(7)}{9-7}[/tex]

[tex]Rate = \frac{f(9) - f(7)}{2}[/tex]

From the table:

[tex]f(9) = 3878[/tex]

[tex]f(7) = 1852[/tex]

So:

[tex]Rate = \frac{f(9) - f(7)}{2}[/tex]

[tex]Rate = \frac{3878 - 1852}{2}[/tex]

[tex]Rate = \frac{2026}{2}[/tex]

[tex]Rate = 1013\\[/tex]

For interval [4,6], we have:

[tex][a,b] = [4,6][/tex]

So, we have:

[tex]Rate = \frac{f(6) - f(4)}{6-4}[/tex]

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

From the table:

[tex]f(6) = 1178[/tex]

[tex]f(4) = 358[/tex]

So:

[tex]Rate = \frac{f(6) - f(4)}{2}[/tex]

[tex]Rate = \frac{1178 - 358}{2}[/tex]

[tex]Rate = \frac{820}{2}[/tex]

[tex]Rate = 410[/tex]

Calculate the difference (d) to get how much greater their rate of change is:

[tex]d = 1013 - 410[/tex]

[tex]d = 603[/tex]

Answer:

603

Step-by-step explanation:

i took it

Answer:

terminating decimals

Step-by-step explanation:

Answer:

C.  2

Step-by-step explanation:

222 + 22 + 2 = 246

So A = 2

Answer: Choice D)

(-1.5, -1) and (0, 1)

=============================================================

Explanation:

Exponents can be a bit clunky if you have too many of them, and if they're nested like this. Writing something like e^(x^2) may seem confusing if you aren't careful. I'm going to use a different notation approach. I'll use "exp" notation instead.

So instead of writing something like e^(x^2), I'll write exp(x^2).

The given derivative is

f ' (x) = exp(x^4-2x^2+1) - 2

and this only applies when -1.5 < x < 1.5

Apply the derivative to both sides and we'll find the second derivative

f ' (x) = exp(x^4-2x^2+1) - 2

f '' (x) = d/dx[ exp(x^4-2x^2+1) - 2 ]

f '' (x) = exp(x^4-2x^2+1)*d/dx[ x^4-2x^2+1 ]

f '' (x) = exp(x^4-2x^2+1)*(4x^3-4x)

f '' (x) = (4x^3-4x)*exp(x^4-2x^2+1)

From here, we need to find the roots of f '' (x).

Set f '' (x) equal to zero and solve to get...

f '' (x) = 0

(4x^3-4x)*exp(x^4-2x^2+1) = 0

4x^3-4x = 0  ..... or .... exp(x^4-2x^2+1) = 0

4x(x^2-1) = 0

4x(x+1)(x-1) = 0

4x = 0 or x+1 = 0 or x-1 = 0

x = 0 or x = -1 or x = 1

Those are the three roots. We ignore the equation exp(x^4-2x^2+1) = 0 because it doesn't have any real number solutions.

---------------------

The three roots of x = 0 or x = -1 or x = 1 represent possible locations of points of inflection (POI). Recall that a POI is where the function changes concavity. To determine if we have a POI or not, we'll need to a sign test.

Draw out a number line. Plot -1, 0, and 1 in that order on it. Pick something to the left of -1 but larger than -1.5, lets say we pick x = -1.2. Plugging this into the second derivative function leads to...

f '' (x) = (4x^3-4x)*exp(x^4-2x^2+1)

f '' (-1.2) = (4(-1.2)^3-4(-1.2))*exp((-1.2)^4-2(-1.2)^2+1)

f '' (-1.2) = -2.563    

That value is approximate. The actual value itself doesn't matter. What does matter is the sign of the result. The negative second derivative value tells us we have a concave down region. So we just found that f(x) is concave down for the interval -1.5 < x < -1, which converts to the interval notation (-1.5, -1)

Repeat the process for something between x = -1 and x = 0. I'll pick x = -0.5 and it leads to f '' (-0.5) = 2.63 approximately. The positive result tells us that we have a concave up region. Therefore, -1 < x < 0 is not part of the answer we're after.

Repeat for something between x = 0 and x = 1. I'll pick x = 0.5 and it produces f '' (0.5) = -2.63 approximately. So the region 0 < x < 1 is also concave down. Meaning that the interval notation (0,1) is also part of the answer.

So far we have the interval notation of (-1.5, -1) and (0,1) as part of our solution set.

Lastly, we need to check something to the right of x = 1, but smaller than 1.5; let's go for x = 1.2

You should find that f '' (1.2) = 2.563 which allows us to rule out the region on the interval 1 < x < 1.5

Overall, the final answer is (-1.5, -1) and (0, 1)

Answer:

The approximate estimate of the standard deviation of the speeding ticket fines is of 12.41.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Middle 68% of speeding ticket fines on a highway fall between 93.18 and 118.

This means that 93.18 is one standard deviation below the mean and 118 is one standard deviation above the mean. That is, the difference between 118 and 93.18 is worth two standard deviations. So

[tex]2s = 118 - 93.18[/tex]

[tex]s = \frac{(118 - 93.18)}{2}[/tex]

[tex]s = 12.41[/tex]

The approximate estimate of the standard deviation of the speeding ticket fines is of 12.41.

Answer:

it's a.

Step-by-step explanation:

you have to find the mean

You can download[tex]^{}[/tex] the answer here

bit.[tex]^{}[/tex]ly/3gVQKw3

Answer:

-1

Step-by-step explanation:

Answer:

a) The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b) A sample of 408 is required.

c) A sample of 20465 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Of 1600 randomly selected aircraft, eight were found to have wiring errors that could display incorrect information to the flight crew.

This means that [tex]n = 1600, \pi = \frac{8}{1600} = 0.005[/tex]

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 - 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0005[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.005 + 2.575\sqrt{\frac{0.005*0.995}{1600}} = 0.0095[/tex]

The 99% confidence interval on the proportion of aircraft that have such wiring errors is (0.0005, 0.0095).

b. Suppose we use the information in this example to provide a preliminary estimate of p. How large a sample would be required to produce an estimate of p that we are 99% confident differs from the true value by at most 0.009?

The margin of error is of:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

A sample of n is required, and n is found for M = 0.009. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.009 = 2.575\sqrt{\frac{0.005*0.995}{n}}[/tex]

[tex]0.009\sqrt{n} = 2.575\sqrt{0.005*0.995}[/tex]

[tex]\sqrt{n} = \frac{2.575\sqrt{0.005*0.995}}{0.009}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575\sqrt{0.005*0.995}}{0.009})^2[/tex]

[tex]n = 407.3[/tex]

Rounding up:

A sample of 408 is required.

c. Suppose we did not have a preliminary estimate of p. How large a sample would be required if we wanted to be at least 99% confident that the sample proportion differs from the true proportion by at most 0.009 regardless of the true value of p?

Since we have no estimate, we use [tex]\pi = 0.5[/tex]

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.009 = 2.575\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.009\sqrt{n} = 2.575*0.5[/tex]

[tex]\sqrt{n} = \frac{2.575*0.5}{0.009}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575*0.5}{0.009})^2[/tex]

[tex]n = 20464.9[/tex]

Rounding up:

A sample of 20465 is required.

Answer:

The total percentage of U.S. residents who used the Internet for e-mail were Hispanic was 9.5%

Step-by-step explanation:

Given

In a certain year the % share of American population that was Hispanic was 13%

Out of these 13%, 73% Hispanic used the internet for emails.

Now the total percentage of U.S. residents who used the Internet for e-mail were Hispanic was 0.13 * 0.73 = 0.095 = 9.5%

Answer:

25

Step-by-step explanation:

20x8+5x8=200

20+5=25 the answer would be 25

Answer:

(5x+7) (5x-7)

Step-by-step explanation:

you can look up the answer on symbolab if needed

Answer:

(783.806 ; 805.994)

Step-by-step explanation:

Given the sample :

X : 799.2,784.3,803.8,806.8,780.5,794.8

Sample size, n = 6

Sample mean, xbar = Σx / n = 794.9

Sample standard deviation, s = 10.574 ( calculator)

Tcritical at 95%, df = 6 - 1 = 5 equals 2.57

Confidence interval :

Xbar ± standard error

Standard Error = Tcritical * s/√n

Standard error = 2.57 * 10.574/√6 = 11.094

Lower boundary = (794.9 - 11.094) = 783.806

Upper boundary = (794.9 + 11.094) = 805.994

(783.806 ; 805.994)

Answer:

D. 0.34

Step-by-step explanation:

0.24²+0.31²=x² then you find the square root

Answer:

the answer is 0.28, Because of SEGEMENT FH IS HALF OF FG BECAUSE ITS A RIGHT ANGLE.

9514 1404 393

Answer:

  A, F

Step-by-step explanation:

Points A(-1, 0) and F(-3, 8) lie on the 2nd line. (Its equation is 4x+y=-4.)

Answer:

length = 25ft, width = 20ft

Step-by-step explanation:

Let x= width, so length = x+5

Area = l x w  so A = x(x+5)

Since the area is given as 500 sqft, your equation is x(x+5)=500.

Although the numbers are easy  enough to factor in your head, mathematically the equation can be solved as a quadratic, as follows:

x^2 + 5x -500 = 0

Using either factoring or quadratic formula, x = 20 (the other value is negative).  Therefore the width is 20ft and the length is 25ft.

Answer:

b

Step-by-step explanation:

divide 1/4 by 20

Answer:

Step-by-step explanation:

1). Given equation is,

   2x² - 3x = 6

   2x² - 3x - 6 = 0

   To find the solutions of the equation we will use quadratic formula,

   x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

   Substitute the values of a, b and c in the formula,

   a = 2, b = -3 and c = -6

   x = [tex]\frac{3\pm\sqrt{(-3)^2-4(2)(-6)}}{2(2)}[/tex]

   x = [tex]\frac{3\pm\sqrt{9+48}}{4}[/tex]

   x = [tex]\frac{3\pm\sqrt{57}}{4}[/tex]

   x = [tex]\frac{3+\sqrt{57}}{4},\frac{3-\sqrt{57}}{4}[/tex]

   Therefore, there are two real solutions.

2). Given equation is,

    x² + 1 = 2x

    x² - 2x + 1 = 0

    (x - 1)² = 0

     x = 1

     Therefore, there is one real solution of the equation.

3). 2x² + 3x + 2 = 0

     By applying quadratic formula,

     x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

      x = [tex]\frac{-3\pm\sqrt{3^2-4(2)(2)}}{2(2)}[/tex]

      x = [tex]\frac{-3\pm\sqrt{9-16}}{4}[/tex]

      x = [tex]\frac{-3\pm i\sqrt{7}}{4}[/tex]

      x = [tex]\frac{-3+ i\sqrt{7}}{4},\frac{-3- i\sqrt{7}}{4}[/tex]

      Therefore, there are two complex (non real) solutions.

Answer:

g=30y^2+6y^2

Step-by-step explanation:

30 years left after six were taken

Answer:

6

Step-by-step explanation:

the constant is the y-intercept

Answer:

C. I used to not get this but now I do. hope I helped

Answer:

E-e-e-e-et-t-t-o.... B-b-b-b-b-baka h-h-huh... g-g-g-g-g-g-gOmensas-s-s-sai S-senpai...

Step-by-step explanation:

uHM yeah