pls helpp !!! ASAP i’ll give you the brainlest answer ONLY if the answer is correct!! BUT PLS HELP ME outt last minute

Answer:

b

Step-by-step explanation:

Answer:

It is A. 2^x

Step-by-step explanation:

For relative rates of growth, we know: Log < Poly < Exponential.

This rules out B, C, and D quickly. Although, if you do L'Hôpital's rule, it might seem like A & D are very comparable. However, if you continually took the derivative of 2^x and x^20, eventually x^20 would equal zero, while 2^x would still be a variable. So, you would have:

[tex]\lim_{x \to \infty} \frac{2^{x}}{0} =[/tex] ∞

When the limit of x as it approaches infinity is infinity, then f(x) grows at a faster rate than g(x).

Also, by looking at the graph (which is attached), you can see that 2^x grows faster than x^20.

Answer:

A) The null hypothesis is H₀; [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]

The alternative hypothesis is Hₐ; [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]

B) The critical value is 4.604

C) The pooled variance is 11,870.2777

D) The standard error is-0.2321

E) The obtained is -0.2040  

Step-by-step explanation:

The given values are;

[tex]\overline x_1[/tex] = 23.76, [tex]\overline x_2[/tex] = 34.54

s₁ = 123.43, s₂ = 105.65

n₁ = 5, n₂ = 20

A) The null hypothesis, H₀; [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]

The alternative hypothesis, Hₐ; [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]

B) The degrees of freedom, df = 4 - 1 = 3

The critical t-value is given at α = 0.01 is given on the t-table for two tailed test as t = 4.604

C) The pooled variance is given by the following formula;

[tex]S_P^2 = \dfrac{(n_1 - 1) \cdot s_1^2 + (n_2-1) \cdot s_2^2}{n_1 + n_2 - 2 }[/tex]

Plugging in the values gives;

[tex]S_P^2 = \dfrac{(5 - 1) \cdot 123.43^2 + (20-1) \cdot 105.65^2}{5+ 20 - 2 } = 11,870.2777[/tex]

The pooled variance, [tex]s_p^2[/tex] = 11,870.2777

D) The standard error, SE, is given as follows;

[tex]t=\dfrac{(\bar x_{1}-\bar x_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}[/tex]

Therefore, we get;

[tex]t=\dfrac{(23.76-35.34)}{\sqrt{\dfrac{123.43^{2} }{5}-\dfrac{105.65^{2}}{20}}} = -0.2321[/tex]

The standard error, SE ≈ -0.2321

E) The obtained 't' is given as follows;

[tex]\sigma _{\overline x_1 - \overline x_2} = \sqrt{\dfrac{s_1^2}{n_1-1} +\dfrac{s_2^2}{n_2-1} }[/tex]

Therefore, we have;

[tex]\sigma _{\overline x_1 - \overline x_2} = \sqrt{\dfrac{123.43^2}{5-1} +\dfrac{105.65^2}{20-1} } \approx 56.7564[/tex]

The obtained t is given as follows;

[tex]t(Obtained)=\dfrac{(\bar x_{1}-\bar x_{2})}{\sigma _{\overline x_1 - \overline x_2} }[/tex]

Therefore, we get;

[tex]t(Obtained)=\dfrac{(23.76-34.54)}{56.7564} \approx -0.2040[/tex]

The obtained t = -0.2040

Answer:

9165.0

Step-by-step explanation:

13*94*7.5 = 9165.0

Answer:

4:7

Step-by-step explanation:

The word ACCOMPLISHMENT has 4 vowels (A, O, I, and E), which is where I got the four. It also has 7 consonants (C, C, M, P, L, S, H, M, N, T). Hence where the 7 was found.

Answer:

x = 2

Step-by-step explanation:

AB/BC = AD/DE

[tex]\frac{2}{1}[/tex] = [tex]\frac{2+x}{2}[/tex]

cross-multiply:

2+x = 4

x = 2

Answer:

Franklin Delano Roosevelt, often referred to by his initials FDR, was an American politician who served as the 32nd president of the United States from 1933 until his death in 1945. A member of the Democratic Party, he won a record four presidential elections and became a central figure in world events during the first half of the 20th century. Roosevelt directed the federal government during most of the Great Depression, implementing his New Deal domestic agenda in response to the worst economic crisis in U.S. history. As a dominant leader of his party, he built the New Deal Coalition, which defined modern liberalism in the United States throughout the middle third of the 20th century. His third and fourth terms were dominated by World War II, which ended shortly after he died in office.

Step-by-step explanation:

to this ‘Great Man Theory’ it can be said that Franklin Delano Roosevelt upheld his victorious and highly regarded government through means of social, economic and political reforms, as well as ambitious personal and strategic decisions that have successfully remained influential to American society today and maintained his image as a prominent historic leader.

Answer:

C. (6 × 5) × 2 = 60 m³

D. 5 × (6 × 2)

E. (2 × 5) × 6

Step-by-step explanation:

Volume of a rectangular prism can be given as, V = L*W*H

L = 6

W = 5

H = 2

However, whichever way we choose to use as either L, W, or H, we would still get the same value as the volume.

Thus:

✔️V = (6 × 5) × 2 = 60 m³

✔️V = 5 × (6 × 2) = 60 m³

✔️V = (2 × 5) × 6 = 60 m³

These are the three expressions that can be used to find the volume.

Answer:

hello your question is poorly written attached below is the complete question

answer

a)  ( 1.9802 , 1.9998 )

b) The population of soft drink does not have to be normally distributed in order to calculate the confidence interval for a sample mean.

c)  A single value of 2.02 is not unusual

d)   (1.9602, 1.9798)

Step-by-step explanation:

A) set up 95% confidence interval estimate

std = 0.05 liter

average ( mean ) X = 1.99 liters

n = 100

95% confidence interval = X ± [tex]Z_{95%}[/tex] ( std / √n )

                                         = 1.99 ± 1.96 ( 0.05 / √100 )

                                         = ( 1.9802 , 1.9998 )

B) The population of soft drink does not have to be normally distributed in order to calculate the confidence interval for a sample mean. as seen in this scenerio the value of n > 30 and sampling distribution of X  is required instead

C) A single value of 2.02 is not unusual because the confidence interval we calculated above is for 100 samples of the soft drink ( using true population mean ) but when we calculate for a one sample we will observe that the value ( 2.02 ) will not be unusual e.g. ( 2 ± 2*0.05 ) = ( 1.9, 2.1 )

D) when the sample average ( X )  = 1.97

confidence interval =  X ± [tex]Z_{95%}[/tex] ( std / √n )

                                = 1.97 ± 1.96 ( 0.05 / √100 )

                                =  (1.9602, 1.9798)

There are four sub-parts in the question, whose answers are mentioned below:

Given information:

Mean of sample = [tex]\overline{x}[/tex] =1.99

Standard deviation of population= [tex]\sigma[/tex] = 0.05

Size of sample = n = 100

Part a: Setting 95% confidence interval

[tex]CI = \overline{x} \: \pm Z_{0.95}\dfrac{\sigma}{\sqrt{n}}\\CI = 1.99 \pm 1.96 \times \dfrac{0.05}{10}\\CI = (1.9802, 1.9998)\\[/tex]

Part b: Yes, the population has to be normally distributed here, since the CI here cannot be calculated without it being normally distributed.

Part c: It is because we took n = 100 and not for single value of observation. The single value of observation has 2 liter or value is 2, and 2.02 is near 2 thus not an unusual value.

Part d: If sample average be 1.97, then CI will be as follows:

[tex]CI = \overline{x} \: \pm Z_{0.95}\dfrac{\sigma}{\sqrt{n}}\\CI = 1.97 \pm 1.96 \times \dfrac{0.05}{10}\\CI = (1.9602, 1.9798)\\[/tex]

Learn more here:

https://brainly.com/question/2396419

Answer:

Step-by-step explanation:

Ans.......

YTC ...................................

Step-by-step explanation:

Answer:

The integral of the volume is:

[tex]V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

The result is: [tex]V = 78.97731[/tex]

Step-by-step explanation:

Given

Curve: [tex]x^2 + 4y^2 = 4[/tex]

About line [tex]x = 2[/tex] --- Missing information

Required

Set up an integral for the volume

[tex]x^2 + 4y^2 = 4[/tex]

Make x^2 the subject

[tex]x^2 = 4 - 4y^2[/tex]

Square both sides

[tex]x = \sqrt{(4 - 4y^2)[/tex]

Factor out 4

[tex]x = \sqrt{4(1 - y^2)[/tex]

Split

[tex]x = \sqrt{4} * \sqrt{(1 - y^2)[/tex]

[tex]x = \±2 * \sqrt{(1 - y^2)[/tex]

[tex]x = \±2 \sqrt{(1 - y^2)[/tex]

Split

[tex]x_1 = -2 \sqrt{(1 - y^2)}\ and\ x_2 = 2 \sqrt{(1 - y^2)}[/tex]

Rotate about x = 2 implies that:

[tex]r = 2 - x[/tex]

So:

[tex]r_1 = 2 - (-2 \sqrt{(1 - y^2)})[/tex]

[tex]r_1 = 2 +2 \sqrt{(1 - y^2)}[/tex]

[tex]r_2 = 2 - 2 \sqrt{(1 - y^2)}[/tex]

Using washer method along the y-axis i.e. integral from 0 to 1.

We have:

[tex]V = 2\pi\int\limits^1_0 {(r_1^2 - r_2^2)} \, dy[/tex]

Substitute values for r1 and r2

[tex]V = 2\pi\int\limits^1_0 {(( 2 +2 \sqrt{(1 - y^2)})^2 - ( 2 -2 \sqrt{(1 - y^2)})^2)} \, dy[/tex]

Evaluate the squares

[tex]V = 2\pi\int\limits^1_0 {(4 +8 \sqrt{(1 - y^2)} + 4(1 - y^2)) - (4 -8 \sqrt{(1 - y^2)} + 4(1 - y^2))} \, dy[/tex]

Remove brackets and collect like terms

[tex]V = 2\pi\int\limits^1_0 {4 - 4 + 8\sqrt{(1 - y^2)} +8 \sqrt{(1 - y^2)}+ 4(1 - y^2) - 4(1 - y^2)} \, dy[/tex]

[tex]V = 2\pi\int\limits^1_0 { 16\sqrt{(1 - y^2)} \, dy[/tex]

Rewrite as:

[tex]V = 16* 2\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

[tex]V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

Using the calculator:

[tex]\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy = \frac{\pi}{4}[/tex]

So:

[tex]V = 32\pi\int\limits^1_0 {\sqrt{(1 - y^2)} \, dy[/tex]

[tex]V = 32\pi * \frac{\pi}{4}[/tex]

[tex]V =\frac{32\pi^2}{4}[/tex]

[tex]V =8\pi^2[/tex]

Take:

[tex]\pi = 3.142[/tex]

[tex]V = 8* 3.142^2[/tex]

[tex]V = 78.97731[/tex] --- approximated

Answer:

The probability that tails and an even number do not occur together is 3/4.

Step-by-step explanation:

There are three outcomes in which tails occurs with an even number (2, tails), (4, tails), (6, tails). The probability of this event is 3/12 = 1/4 . The probability that tails and an even number do not occur together is 1 - 1/4 = 3/4.

Answer:

Sample answer for Edmentum

Step-by-step explanation:

Answer:

27.5

Step-by-step explanation:

To find the mean you basically just add all of the numbers then divide by how many there are.

So, for this problem, 19+22+24+45=110

110/4=27.5

Hope this helped!!

Answer:

253 boxes

Step-by-step explanation:

757/3 = 252.33

Answer: Hello the statement related to your question is missing attached below is the statement

answer : The statement is false

Step-by-step explanation:

The statement is false

This is because a confidence interval gives a range of values for an unknown parameter.

A 95% confidence interval is calculated and it gives a lower and upper limit in which the 58% of the voters can fall into i.e. The 58% of voters can fall within the upper and lower limit of the 95% confidence interval and not exactly 95% . Hence the statement is false.

Step-by-step explanation:

hope u get it...

mark brainlist!!!

Answer:

16/20=0.8

Step-by-step explanation:

hope this helps

Answer:

I think it's the second one

Answer:

78

Step-by-step explanation:

this the first valuvate but It

Answer:

12

Step-by-step explanation:

First,

Add 45+52+15

Then the answer will be 112

Then -(minus) from 100

Answer:

18 students

Step-by-step explanation:

45 - 15 = 30 students only read physics

52 - 15 = 37 students only read chemistry

15 students read both

add all of them:

30 + 37 + 15 = 82

subtract the sum from 100

100 - 82 = 18

18 students doesn't study neither

Answer:

9

Step-by-step explanation:

18 x 1/2

18/2

9

Answer: 9

Step-by-step explanation:

Parenthesis first, so 8+10 =18 .

18 multiplied by 1/2 = 9

Answer:

8/12 or 2/3

Step-by-step explanation:

5/12+3/12=8/12

8/12 simplifies to 2/3

Answer:

54000

Step-by-step explanation:

53,738

3 is in the thousands place so we look at the hundreds place

7 is 5 or above so we round the 3 up to 4

54000

Answer:

0.266 percent

Step-by-step explanation:

With labor increasing by 1 percent, we are to find how much level of production would also increase given the coubglas function in the question.

Level of production = ∆Q/Q

We differentiate the function Q with respect to Labour, L.

∆Q/∆L = 0.266Q/L

∆Q/Q = 0.266∆L/L

∆L/L = 1

∆Q/Q x 100 = 1 *0.266

= 0.266%

Please refer to the attachment

Step-by-step explanation:

Boys

[tex]20 + (20 \div 100)30 = \\ = 20 + 0.2 \times 30 = \\ = 20 + 6 = \\26[/tex]

Girls

[tex]26 - (26 \div 100)15 = \\ = 26 - 0.26 \times 15 = \\ = 26 - 3.9 = \\ = 22[/tex]

Total last year 46

Total this year 48

Increase

Answer:

a=81.0

there ya go