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What is the difference between a short-term goal and a long-term goal? Give an example of each.

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Answer 1
Short-term goals are planned for the near future while long-term goals will take longer to complete. An example of a short-term goal is trying to get into a certain college. A long-term goal is wanting to have a big family.

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In a science lab, Cash mixes two clear liquids together in a beaker. Bubbles are produced, and a white solid forms and settles to the bottom. Which statement below describes what happened?


a

A physical change occurred, a gas and precipitate was produced

b

A physical change occurred, only a gas was produced

c

A chemical change occurred, only a gas was produced

d

A chemical change occurred, a gas and precipitate was produced

Answers

Answer:

I think it is D

Explanation:

I did a couple mins of research on this topic but there is no clear line that separates a physical and chemical reaction, so do with that as you will. i hope I somewhat helped.

How do I answer all the questions on this page?

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Answer:

Create a google docs copy everything and paste hope this helps! :)

Explanation:

A function is different from a procedure because a functiondoes not contain a set of instructions.can have only a limited number of steps.returns a value.is mathematical.​

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Answer: A function returns a value and a procedure just executes commands.

Explanation:

Answer:

c - returns a value.

Explanation:

on edge pls mark brainiest

Expert Review is done by end users.

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Answer:nononononono

Explanation:

CAD(computer-aided design) software and is used in__________and __________that show how to construct an object. Technical drawings show in detail how the pieces of something relate to each other.

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Answer:

Plans; blueprints.

Explanation:

In Engineering, it is a common and standard practice to use drawings and models in the design and development of various tools or systems that are being used for proffering solutions to specific problems in different fields such as engineering, medicine, telecommunications and industries.

Hence, a design engineer make use of drawings such as pictorial drawings, sketches, or technical drawing to communicate ideas about a design to others, to record and retain informations (ideas) so that they're not forgotten and to analyze how different components of a design work together.

Technical drawing is mainly implemented with CAD (computer-aided design) software and is typically used in plans and blueprints that show how to construct an object.

Additionally, technical drawings show in detail how the pieces of something (object) relate to each other, as well as accurately illustrating the actual (true) shape and size of an object in the design and development process.

For three control stations,there should be how many start buttons in parallel with the suxiliary contact

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The three load contacts connected between the three-phase power line and the motor close to connect the motor to the line. The normally open auxiliary contact connected in parallel with the two Start buttons closes to maintain the circuit to M coil when the Start button is released.

1. Drill press size is determined by the largest__

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Drill press size is determined by the largest piece of stock


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A ramjet operates by taking in air at the inlet, providing fuel for combustion, and exhausting the hot air through the exit. Th e mass fl ow at the inlet and outlet of the ramjet is 60 kg/s (the mass fl ow rate of fuel is negligible). Th e inlet velocity is 225 m/s. Th e density of the gases at the exit is 0.25 kg/m3 , and the exit area is 0.5 m2 . Calculate the thr

Answers

Answer:

15300 N

Explanation:

[tex]\rho_i[/tex] = Density of air at inlet

[tex]\dfrac{m}{t}[/tex] = Mass flow rate = 60 kg/s

[tex]v_i[/tex] = Inlet velocity = 225 m/s

[tex]\rho_o[/tex] = Density of gas at outlet = [tex]0.25\ \text{kg/m}^3[/tex]

[tex]A_i[/tex] = Inlet area

[tex]A_o[/tex] = Outlet area = [tex]0.5\ \text{m}^2[/tex]

Since mass flow rate is the same in the inlet and outlet we have

[tex]\rho_iv_iA_i=\rho_ov_oA_o\\\Rightarrow v_o=\dfrac{\dfrac{m}{t}}{\rho_oA_o}\\\Rightarrow v_o=\dfrac{60}{0.25\times 0.5}\\\Rightarrow v_o=480\ \text{m/s}[/tex]

Thrust is given by

[tex]F=\dfrac{m}{t}(v_o-v_i)\\\Rightarrow F=60\times (480-225)\\\Rightarrow F=15300\ \text{N}[/tex]

The thrust generated is 15300 N.

An annealed copper strip of 228 mm wide and 25 mm thick being rolled to a thickness of 20 mm, in one pass. The roll radius is 300 mm, and the rolls rotate at 100 rpm. Calculate the roll force and the power required in this operation

Answers

Answer:

The roll force is 1.59 MN

The power required in this operation is 644.96 kW

Explanation:

Given;

width of the annealed copper, w = 228 m

thickness of the copper, h₀ = 25 mm

final thickness, hf = 20 mm

roll radius, R = 300 mm

The roll force is given by;

[tex]F = LwY_{avg}[/tex]

where;

w is the width of the annealed copper

[tex]Y_{avg}[/tex] is average true stress of the strip in the roll gap

L is length of arc in contact, and for frictionless situation it is given as;

[tex]L = \sqrt{R(h_o-h_f)} \\\\L = \sqrt{300(25-20)}\\\\L = 38.73 \ mm[/tex]

Now, determine the average true stress, [tex]Y_{avg}[/tex], for the annealed copper;

The absolute value of the true strain, ε = ln(25/20)

ε = 0.223

from true stress vs true strain graph; at true strain of 0.223, the true stress is 280 MPa.

Then, the average true stress = ¹/₂(280 MPa.) = 180 MPa

Finally determine the roll force;

[tex]F = LwY_{avg}[/tex]

[tex]F = (\frac{38.73 }{1000})(\frac{228}{1000})*180 \ MPa\\\\F = 1.59 \ MN[/tex]

The power required in this operation is given by;

[tex]P = \frac{2\pi FLN}{60}\\\\P = \frac{2\pi (1.59*10^6)(0.03873)(100)}{60}\\\\P = 644955.2 \ W\\\\P = 644.96 \ kW[/tex]

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