pls help me w this, I've been doing this since 5 minutes ago​

Pls Help Me W This, I've Been Doing This Since 5 Minutes Ago

Answers

Answer 1

Answer:

t=0.0625s

Explanation:

F=number of swings/time taken

DATA

Frequency=4.0Hz

number of swings from Q to R

=1/4

time taken=?

Frequency=number of swings/time taken

make t the subject of the formula

t=n/f

substitute the given date

t=0.25/4.0

t=0.0625s

option A is collect


Related Questions

Which of the following is NOT one of the essential components of an exercise program?

Answers

Answer:

i dont know dude but ask someone who is in your grade lol

Explanation:

the diagram shows the apparent motion of the sun across the sky?

Answers

The answer is “B” hope I helped

Answer:

The earth rotates west to east

Explanation:

Considering that the sun doesn't really move and the earth is rotating around the sun, and it is moving from east to west with us (the earth) facing it in which means the earth rotates around the sun west to east!

explain why an inflated balloon is likely to burst if you leave it near a window with the sun streaming it?

Answers

Answer:

the sun light will heat up the balloon causing it to burst

HELP ASAP!! WILL TRY TO GIVE BRAINLIEST

Explain how receptor-mediated endocytosis is more specific than pinocytosis or phagocytosis

Answers

Answer:

it selects what molecules to engulf, whereas pinocytosis or phagocytosis engulf anything in the vicinity

Trust!

A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?

Answers

Answer:

[tex]2.33\ m/s^2[/tex]

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn = m.a

Where a is the acceleration of the object.  The net force is the sum of the individual vector forces applied to the object.

The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.

The net force is Fn = 5000 N - 1500 N = 3500 N

To find the acceleration, we solve the equation for a:

[tex]\displaystyle a=\frac{Fn}{m}[/tex]

[tex]\displaystyle a=\frac{3500}{1500}[/tex]

[tex]\boxed{a = 2.33\ m/s^2}[/tex]

The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]

The air is an example of a gas in a gas solution. True or false

Answers

True! Air is in fact a natural gas in a gas solution.

Hope this helped!
true, air is an example of a gas in a gas solution.

Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
covered by Asha.(a) (Numbering problem)_​

Answers

Distance walked to the west= 15m

" " " " north= 20m

" " " " east = 15m

Total Distance= (15+ 20+ 15) m

= 50m

Asha covered 50m distance in total.

If you could change one property of a substance ( solid, liquid, and gas) you have to use in your daily life, what would it be and why?
Please hurry
I will give you BRAINLIEST!!!!!!
And pleaseee write 5 sentences why??

Answers

Answer

Soap into a liquid

Explanation:

water into ice cubes, because lukewarm water is nasty.

WILL MARK BRAINLY!! QUICK HELP PLEASE!
A 40.0 kg rocket produces a
764 N upwards force ("thrust").
What is the net force acting on
the rocket?

Answers

Answer:                                                                              

372                              

Explanation:(40.0)×(9.8)=392

764N-392=372

Calculate the kinetic energy of a 50 kg cart moving at a speed of 18.6 m/s.

Answers

Answer:

8649 J

Explanation:

KE = 1/2mv^2

1/2(50)(18.6)^2

1/2(50)(345.96) = 8649 J


Ek = ½mv^2
This is for calculate the kinetic energy

26. For this table of data, which column is the independent variable?
radius of circle (m) area of circle (m2)
3.4
36.317
4.5
63.617
4.6
66.476
6.2
120.763
7.6
181.458
7.7
186.265
8.6
232.352
9.7
295.592
area of circle
o
radius of circle
O
None of these is correct.

Answers

Answer:

radius of a circle is measured by an instrument, so it is the independent variable

Explanation:

The independent variable corresponds to the magnitude controlled by the experimenter and in general can be measured by an instrument.

The dependent variable is the variable used to perform the calculations, obtained from a mathematical transformation of the independent variable.

The radius of a circle is measured by an instrument, so it is the independent variable and the area is calculated by

         A = π r²

Therefore the area corresponds to the dependent variable

A merry go round exerts a force of 1000 N on a rider on the
outer ring of animals when it takes 15 seconds to make a
complete revolution. If the person weighs 750 N, the radius
of the circle he is making is m. Round your answer to
the nearest tenth.

Answers

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

[tex]F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r[/tex]

Where;

m = The mass of the person

v = The velocity of the person

[tex]F_c[/tex] = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

[tex]F_c[/tex] = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.

Answers

Answer:

The final velocity, [tex]v_{f}[/tex], is gd.

Explanation:

The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;

[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs

where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.

Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.

So that;

[tex]v_{f}[/tex] = 0 + 2gd

   = 2gd

[tex]v_{f}[/tex] = 2gd

When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.

Then;

[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]

[tex]v_{f}[/tex] = g x d

When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.

A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?


This needs to be done in 3 mins

Answers

Answer:

Okay I might be wrong and sorry if i am either its 12 or 0.402

Explanation:

* I recommend the second one cause its more logical

Be aware I might be wrong

An alkane has molecular weight 86. Write its molecular formula. What will be its physical state?

Answers

C6H14

Gaseous state

it's unsaturated hence gaseous

A train travels with a speed of 115km/hr. How much time does it take to cover a distance of 470km.​

Answers

It would take approximately 4 hours for the train to cover a distance of 470km.

4 hours 5 minutes 13.04 seconds

Which best compares radiation and conduction?

A. Both transfer thermal energy from warm objects to cooler objects.
B. Both can transfer energy through empty space.
C. Both transfer thermal energy by electromagnetic waves.
D. Both involve the transfer of energy through direct contact.

And also who likes Rick and Morty OwO

Answers

Answer:

A

Explanation:

Which one of the following is not a member of the solar family: (a) Morning Star (b) Evening Star (c) Pole Star (d) Tailed Star plzzz answer this...

Answers

Answer:

Tailed star

Explanation:

Tailed star

Directions: Summarize the main ideas of this lesson by answering the question below.
How might a person acquire a fear of or aversion to something even though it has no negative effect
on him or her?

Answers

Answer:

Explanation:

Trypophobia is a fear or disgust of closely-packed holes. People who have it feel queasy when looking at surfaces that have small holes gathered close together.A person may start by imagining what they fear, then looking at pictures of the fear object, and then finally being near or even touching the source of their anxiety. In the case of trypophobia, a person with symptoms may start by simply closing his eyes and imagining something such as a honeycomb or seed poThey can help you find the root of the fear and manage your symptoms. Last medically reviewed on July 20, 2017 Medically reviewed by Timothy J. Legg, Ph.D., CRNP — Written by Annamarya Scaccia ...


1. A man is running on the straight road with the uniform velocity
3 m/s. Calculate acceleration produced by him.​

Answers

None he is undergoing constant uniform velocity. Acceleration is the rate of change of velocity
1 . your answer will be a man is running on the straight road with uniform velcocity

Which of the following does not illustrate a complete circuit?

Answers

Answer:

I think A

Explanation:

because it dosn't have enough tools

An object has a force of 29.43 N acting on it. Its acceleration is 3.5 m/s2. What is the mass of this object?

Answers

Answer:

The mass of the object is 8.41 Kg.

Explanation:

Mechanical Force

The second Newton's law states that the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object. The SI unit for the force is the Newton: [tex]1\ Nw = 1~Kg.m/s^2[/tex]

We are given the net force of F=29.43 N acting on an object and producing an acceleration of a=3.5~m/s^2.

To calculate the mass of the object, we solve the above equation for m:

[tex]\displaystyle m=\frac{F}{a}[/tex]

[tex]\displaystyle m=\frac{29.43}{3.5}[/tex]

Calculating:

m = 8.41 Kg

The mass of the object is 8.41 Kg.

Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above

Answers

Answer:

Explanation:

Hell im good dude

calculate the kinetic energy of running kitten that has a mass of 4 kg and velocities of 2 m/s​

Answers

The equation you use is Ke = 1/2mv^2. when you plug in the numbers that are given you get Ke= 1/2(4)(2^2) which gives you a Kinetic Energy of 8

The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7 x 10 to the -9th power coulombs what is the distance between the two charges

Answers

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

A washing machine is being dragged with a starting force of 380.8 N to the West, but this is reduced by friction. If the mass of the washing machine is 37 kg
and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?
A 10.27 m/s^2 South
B 5 m/s^2 South
C 19.01 m/s^2 South
D 7.6 m/s^2 South

Answers

Answer:

B. [tex]5\,\frac{m}{s^{2}}[/tex] South

Explanation:

The correct statement is:

A washing machine is being dragged with a starting force of 380.8 N to the South, but this is reduced by friction. If the mass of the washing machine is 37 kg  and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?

The net force of the washing machine moving on the horizontal ground is equal to the external force minus the friction force, where the normal force from the ground on the washing machine is equal to its weight. The free body diagram of the washing machine is presented below. The equation of equilibrium associated with the acceleration of the washing machine is:

[tex]\Sigma F = P -\mu_{k}\cdot m \cdot g = m\cdot a[/tex] (1)

Where:

[tex]P[/tex] - External force exerted on the washing machine, measured in newtons.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the washing machine.

If we know that [tex]P = 380.8\,N[/tex], [tex]m = 37\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\mu_{k} = 0.54[/tex], then the net acceleration experienced by the washing machine is:

[tex]a = \frac{P}{m}-\mu_{k}\cdot g[/tex]

[tex]a = \frac{380.8\,N}{37\,kg}-(0.54)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]a = 4.996\,\frac{m}{s^{2}}[/tex]

The correct answer is B.

4 pleasee i have to submit in 10 minutes

Answers

Answer:

True

Explanation:


When the net force on an object is zero, what do we know about the motion of that object

Answers

Answer:

The objects speed or motion does not change if the net force is 0.

Explanation: There basically doesn't have anything acting on it so it stays put.

Calculate the mass of a man jogging north along the highway at a rate of 2.65 m/s and a momentum of 225.3 kg*m/s

Answers

Answer:

85.02 kg

Explanation:

The mass of the man can be found by using the formula

[tex]m = \frac{p}{v} \\ [/tex]

v is the velocity

p is the momentum

From the question we have

[tex]m = \frac{225.3}{2.65} \\ = 85.01886...[/tex]

We have the final answer as

85.02 kg

Hope this helps you

How long will it take an object traveling at 7 m/s to reach a distance of 26 meters

Answers

Answer:

3 hours 71 minutes

Explanation:

As because Speed= distance/time taken

so time taken= 3.71

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