Answers
=============================================
Explanation:
To compute the speed, we divide the distance traveled over the time duration.
For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.
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For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)
speed = distance/time = (30 km)/(2 hrs) = 15 km/hr
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We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.
You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.
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For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)
So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr
The steeper slope of section C, compared to section A, means the car is going faster.
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Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km
(60 km)/(1.5 hrs) = 40 km/hr
The speed of the car during section D is 40 km per hour.
Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.
Related Questions
In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.
Find the central force acting on the electron as it revolves in a circular orbit of radius 4.63 x 10-11 m.
Answer in units of N.
Answers
The central force acting on the electron as it revolves in a circular orbit is [tex]9.52 \times 10^{-8} \ N[/tex].
The given parameters;
speed of electron, v = 2.2 x 10⁶ m/sradius of the circle, r = 4.63 x 10⁻¹¹ mThe central force acting on the electron as it revolves in a circular orbit is calculated as follows;
[tex]F = \frac{M_e v^2}{r} \\\\[/tex]
where;
[tex]M_e[/tex] is mass of electron = 9.11 x 10⁻³¹ kg
[tex]F = \frac{(9.11 \times 10^{-31}) \times(2.2\times 10^6)^2 }{4.63 \times 10^{-11}} \\\\F = 9.52 \times 10^{-8} \ N[/tex]
Thus, the central force acting on the electron as it revolves in a circular orbit is [tex]9.52 \times 10^{-8} \ N[/tex].
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I am unique even though there are billions of me no two are the same what am I
AND IT'S NOT A FINGER-PRINT
Answers
Since every ice crystal takes a different route to the ground. They will float through various clouds with various temperatures and moisture contents, which will cause the ice crystal to develop in a distinctive manner.
What make snowflakes unique?A snowflake's shape changes as it flies through the atmosphere, thus no two are ever the same. Even two flakes floating side by side will each be blown through various vapour and humidity levels to produce a genuinely unique shape.
One of the most recognizable representations of winter weather are snowflakes. There are an unlimited amount of conceivable shapes for snowflakes, and each one is distinct.
Therefore, snowflakes unique even though there are billions.Even two floating flakes will each be exposed to different vapour and humidity conditions, creating a really distinctive form.
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A projectile is to be launched at an angle of 30° so that it falls beyond the pond of length 20 meters as shown in the figure.
a) What is the range of values of the initial velocity so that the projectile falls between points M and N?
Answers
Answer: A
Explanation:
I want my points so yea
The mass of a water skier is 54 kg. Calculate his/her weight if the gravitational field strength is 10 N/kg.
Answers
Answer:
weight=mass×gravity
the mass in this question is 54kg and the gravity is 10
therefore:
w=54×10
=540N
I hope this helps
if clarisses mass on earth is 52kg what would be her weight on venus if the acceleration due to gravity on that planet is 8.87 m/s^2
Answers
Answer:
Weight=F=MA=52*8.87=461.24
What net force is needed to increase the velocity of a 5 kg object by 3 m/s over the course of 2.5 seconds?
Answers
Hi there!
Recall Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}[/tex]
∑F = net force (N)
m = mass (kg)
a = acceleration (m/s²)
We must begin by solving for the acceleration using the following:
a = Δv/t
In this instance:
Δv = 3 m/s
t = 2.5 sec
a = 3/2.5 = 1.2 m/s²
Now, plug this value along with the mass into the equation for net force:
[tex]\Sigma F = 5(1.2) = \boxed{6 N}}[/tex]
Answer:
[tex]\boxed {\boxed {\sf 6 \ Newtons}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration. The mass of the object is 5 kilograms, but the acceleration is unknown.
We can find acceleration using the following formula:
[tex]a= \frac{ \Delta v}{t}[/tex]
The velocity of the object increases by 3 meters per second. It accelerates in 2.5 seconds.
Δv= 3 m/s t= 2.5 sSubstitute the values into the formula.
[tex]a= \frac{3 \ m/s}{2.5 \ s}[/tex]
[tex]a= 1.2 \ m/s/s = 1.2 \ m/s^2[/tex]
Now we know the mass and acceleration.
m= 5 kg a= 1.2 m/s²Substitute the values into the force formula.
[tex]F=ma[/tex]
[tex]F= (5 \ kg)(1.2 \ m/s^2)[/tex]
[tex]F= 6 \ kg*m/s^2[/tex]
Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 6 kilogram meters per second squared is equal to 6 Newtons.
[tex]F= 6 \ N[/tex]
Help me pls both answers i’ll give brainly
Answers
A weightlifter lifts a 350 N set of weights over his head a vertical distance of 2.5 meters above the floor. Calculate the work the athlete does on the weights, assuming he lifts them at a constant speed.
A. 525 J
B. 750 J
C. 1005 J
D. 700 N•m
E. 875 J
Answers
Answer: Took that test already
Please help if you can
Answers
Answer:
The answer is B
Explanation:
Because when the both sides aren't balanced one side has to cause motion. (fall down)
a 25 kg crate is pushed horizontally with a force of 70N. if the coefficient of friction is .20, calculate the acceleration of the crate.
Answers
From Newton's second law of motion, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
Given that a 25 kg crate is pushed horizontally with a force of 70N and the coefficient of friction is 0.20
To calculate the acceleration of the crate, We will consider the net force acting on the crate. The net force will be sum of the applied force F and the frictional force [tex]F_{r}[/tex].
Let us first calculate the frictional force [tex]F_{r}[/tex]. That is,
[tex]F_{r}[/tex] =- μN
[tex]F_{r}[/tex] = μmg
[tex]F_{r}[/tex] = 0.2 x 25 x 9.8
[tex]F_{r}[/tex] = 49N
Using Newton's second law,
F = ma
F - [tex]F_{r}[/tex] = ma
70 - 49 = 25 a
21 = 25a
a = 21 / 25
a = 0.84 m/[tex]s^{2}[/tex]
Therefore, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
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will mark brainliest if answer
Answers
I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.
Hi, please help! •_•
One workman is measured as having a power of 528W. His weight is 800N. He can develop the same power climbing a ladder, whose rungs are 30cm apart. How many rungs can he climb in 5s?
Answers
Answer:
He can climb 11 rungs
Explanation:
Power = 528W, Force = 800N, Time= 5s Total Distance moved = 30x cm or 0.3x m, where x is the number of rungs he climbed
Power = Work done/time
Work done = Power × time
= 528 × 5
= 2640Joules
Also Work done = Force × total distance moved
Total Distance moved = Work done/force
0.3x = 2640/800
0.3x = 33
x = 3.3/0.3
x = 11
3. Which is not an example of energy
(5 Points)
light
thermal
heat
chemical
Answers
Answer:
Heat, Chemical
Answer:
heat is not an energy is a process.
Explanation:
Convert 8 m/s to miles per hour
Answers
Answer:
17.8954903 or 17.9 mph
Explanation:
m/s is meters per second. 1609.344 meters is one mile. There are 3,600 seconds in an hour. 8 meters *3600 seconds= 28,800. 28,800/1609.344 = 17.8954903. Simplify to 17.9
Consider a car of mass m moving with an initial speed Vo on a straight, flat road. At time t=0, the driver fully applies the breaks to avoid colliding with debris in the road in front of the car. The car’s wheels lock, causing the car to slide on the roadway until the car stops, before running over the debris. The distance that the car slides is D. The coefficient of kinetic friction between the car’s tires and the roadway is a constant value of Uk.
A) Sketch a free body diagram for the car sliding to rest and write Fnet equations
A) does the value D increase or decrease with increasing initial speed?
B) does the value D increase or decrease with increasing the coefficient of friction?
C) derive an equation for the acceleration of the car in terms of Uk and physical consonants
Answers
A father places his daughter in a swing that is 0.60\,\text{m}0.60m0, point, 60, start text, m, end text above ground. Then he raises the swing to a height of 1.3\,\text{m}1.3m1, point, 3, start text, m, end text and lets go. The girl and the swing have a combined mass of 14\,\text{kg}14kg14, start text, k, g, end text. Assume friction is negligible and use g = 9.8\,\text{m/s}^2g=9.8m/s
2
g, equals, 9, point, 8, start text, m, slash, s, end text, squared.
Calculate the girl’s fastest speed.
Answers
This question involves the concepts of the law of conservation of energy and kinetic energy.
The girl's fastest speed is "3.7 m/s".
According to the law of conservation of energy, the girl will have the fastest speed at mean position, which will be calculated as follows:
Loss in Potential Energy = Gain in Kinetic Energy
[tex]mg\Delta h=\frac{1}{2}mv^2\\\\v=\sqrt{2g\Delta h}[/tex]
where,
v = maximum speed = ?
g = acceleration due to gravity = 9.81 m/s²
Δh = change in height = 1.3 m - 0.6 m = 0.7 m
Therefore,
[tex]v=\sqrt{2(9.81\ m/s^2)(0.7\ m)}[/tex]
v = 3.7 m/s
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I need help asap! Will give brainliest
Answers
[tex]\\ \tt\hookrightarrow \dfrac{(3\times 10^4kg)(4\times 10^4m)}{6\times 10^4s)}[/tex]
[tex]\\ \tt\hookrightarrow \dfrac{12\times 10^8kgm}{6\times 10^4s}[/tex]
[tex]\\ \tt\hookrightarrow 2kgm/s[/tex]
We have calculated momentum
A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?
Answers
The orbital period of the moon is T= 14.48 hr
What would be the difference in your welght if you were four times farther from the center of Earth than you are now?
Answers
you would die.
the core of the earth is as hot as the sun surface so you would be dead
The deceleration of the dummy is less than the deceleration of the passenger compartment.
Explain why this is of benefit for the safety of a passenger.
Answers
Based on the information given, this is beneficial because the passenger is less likely to be injured.
Deceleration simply means acceleration in a reverse way. Deceleration simply means the rate at which an object slows down.
From the complete information, it should be noted that the fact that the deceleration of the dummy is less than the deceleration of the passenger compartment is beneficial as it impacts on passenger or dummy less than without the airbag or seat belt.
Therefore, this is important as the passenger is less likely to be injured.
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Do two indentical objects become statically charged when you rub them together? Explain why they do or do not.
Answers
Answer:
Yes, they do. When two different materials are rubbed together, there is a transfer of electrons from one material to the other material. This causes one object to become positively charged and the other object to become negatively charged.
Explanation:
hope this helps
A 2-kg object is pulled to the left with a force of 30 N and to the right with a force of 9 N. What is the acceleration of the object?
Answers
An object that weighs 75 N is pulled horizontally to the right with a force of 50 N. The force of friction on this object is 30 N to the left. What is the acceleration of the object?
The force on the object is 50 N to the right and 30 N to the left.
⇒ The net force on the object is, =50−30=20 N to the right.
The weight of the object is, =75 N.
⇒ The mass of the object is ==759.8 kg.
⇒ The acceleration of the object is ==20759.8=2.613 m/s 2.
The acceleration of the object is 10 [tex]m/s^2[/tex].
What is Acceleration?Acceleration is defined as the rate of change of velocity of an object with respect to time which are vector quantities i.e. both magnitude and direction. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
It can be expressed as:
a= v/t
where, a is the acceleration
v is the velocity
t is the time taken
It can also be expressed as F=ma
where, F= force applied
m= mass of the object
So, for above given information
The force on the object is 9N to the right and 30N to the left. The net force on the object is 21N to the left
The mass of the object is 2kg
So, a= 21N/ 2 kg = 10.5 [tex]m/s^2[/tex]
Thus, the acceleration of the object is 10 [tex]m/s^2[/tex].
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what was stored when you bent the ruler in your left hand?
Answers
Answer:
potential energy
the name comes from the fact that the ruler has "potential" to act
Explanation:
Explanation:
The deformation of the ruler creates a force in the opposite direction, known as a restoring force.
I'm not sure if it's correct...
Does the coefficient of kinetic friction depend on the speed?
Answers
Answer:
yes because if the speed/K.E. of body increases the friction will also apply more instantly
write of the following does not represent electrical power in a circuit ?
(a) I²R
(b) IR²
(c)VI
(d) V²/R
Answers
The equations for electrical power are as follows:
P=I^2R
P=VI
P=V^2/R
(You can get this equation by rearranging V=IR, making I the subject to get I=V/R and substituting that into P=VI)
P=E/T
what is the purpose of the thermal energy tranfer lab
Answers
Answer:thermal Energy Transfer in Mixtures Purpose: The purpose of this experiment is to discover how exactly the final temperature of a mixture, involving a substance and hot water, is affected and impacted by the type of substance used. This means that when hot water is mixed with another substance, it must be determined
Explanation:
did this on edge
Physicists call any change in energy an impulse true or false?
Answers
.!.7:&//‘is sis sis did is
What two things related to sedimentary rocks do you see at the Grand Canyon ?
Answers
Answer:
sandstone and mudstone
Explanation:
a)iii) as the wheelbarrow was being pushed, the tyre went over a small stone. Describe and explain how the pressure changes.
Answers
Answer:
it changed because the rock put the pressure all in one spot.
Explanation:
free tingsssssssssss
Answers
Explanation:
yayyy thx u soo muchihuhuhu
Answer:
thx
Explanation: