please someone help its due soon

a. The induced current is i = 1.42 A

b. The force is F = 0.46 N

c. The force is in the positive z - direction along the rod

Current is the flow of electric charge ina circuit.

Force is that thing which causes a change in motion of an object.

Since the figure shows a 23 cm -long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.3 m/s . The rails have negligible resistance, but the rod has a resistance of 0.75 Ω, the current in the rod is the induced current given by

i = BLv/R where

Substituting the values of the variables into the equation, we have

i = BLv/R

i = 1.4 T × 0.23 m × 3.3 m/s/0.75 Ω

i = 1.0626 Tm²/s/0.75 Ω

i = 1.4168 A

i ≅ 1.42 A

The current is i = 1.42 A

The magnitude of the force the force on a metallic conductor is given by

F = B²L²v/R where

Substituting the values of the variables into the equation, we have

F = B²L²v/R

F = (1.4 T)² × (0.23 m)² × 3.3 m/s/0.75 Ω

F = 1.96 T² × 0.0529 m² × 3.3 m/s/0.75 Ω

F = 0.3422 T²m³/s ÷ 0.75 Ω

F = 0.456 N

F ≅ 0.46 N

The force is F = 0.46 N

We know that the force F = q(v × B) where

So, F =q(v × B)

= q(-vi × Bj)

= q(vB (i × j)

= (qvB)k

Since F is in the positive k direction, the force is in the positive z - direction along the rod

The force is in the positive z - direction along the rod

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Answer:

dimond and 21

Explanation:

The most appropriate method to study the potential impacts of oil drilling on coastal California would be design a computer simulation of an oil spill in the area to determine the environmental impact design a computer simulation of an oil spill in the area to determine the environmental impact. The correct option to this question is C.

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The coefficient of friction is 0.125

The friction coefficient is defined as the ratio of the frictional resistive force to the perpendicular force pushing the objects together. The friction coefficient is represented as, μ = f × N

where is the friction coefficient μ ,

F is the frictional force,

and N is the normal force.

As we know, 2f = W

and f = μ × N

Where, W = weight of tin box

Thus, the co-efficient of friction,

μ = W ÷ 2 N

μ = 100N ÷ (2 × 400 N)

μ = 0.125

Thus, the coefficient of friction is 0.125

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Explanation:

a) 8.2 J

The work done by the force on the block is equal to the force multiplied by the distance moved in the direction of the force. Since the force is applied at an angle of 26.0° with the horizontal, only a component of the force is acting in the direction of motion. The component of the force in the direction of motion is equal to the magnitude of the force multiplied by the cosine of the angle between the force and the direction of motion. Therefore, the work done by the force on the block is equal to:

Work = Force x Distance x cos(26.0°)

= (1.0 kg)(9.81 m/s2)(3.0 m) x cos(26.0°)

= 8.2 J

Answer:

7,229sec

Explanation:

first convert 6km to m and km/h to m/s

1km = 1000m

6km = 6 × 1000m = 6000m

3km/h to m/s

3 × 1000m/ 60min × 60sec = 3000m/3600sec = 0.83m/s

Time=?

distance= average speed/velocity × Time

6000 = 0.83 × t

t=6000/0.83

t= 7,229 sec

or 120min 29sec

Answer:

The free body diagram for this scenario is shown below. The force of 300 N is the applied force, pushing the block across the floor. The force of friction is opposing the applied force, and is equal to the coefficient of friction (0.25) multiplied by the weight of the block (100 kg). This gives a force of friction of 25 N.

b) Calculate the acceleration of the block

The acceleration of the block can be calculated using Newton's Second

The time needed to run up two flights of stairs is 8.41 Second.

Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.

The power of an average person with good physical condition: P = 1 hp = 745.7 watts.

The work done to run up two flights of stairs with a total height of 8 meters = mgh = 80×9.8×8 Joule = 6272 joule.

So  the time needed to run up two flights of stairs is= 6272/745.7 second = 8.41 Second.

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Answer:

Thread tension:

T = F + P = 9 108 + 21 120 ≈ 30 230 N

Explanation:

Given:

m = 2155 kg

R = 17.5 m

V = 8.6 m/s

g = 9.8 m/s²

_______________

T - ?

Modulus of centripetal force (force is directed towards the center of the circular arc):

[tex]F = \frac{m\cdot V^2}{R} = \frac{2155\cdot 8.6^2}{17.5} = 9108 N[/tex]

Ball weight (directed vertically down):

W = m·g = 2155·9.8 ≈ 21 120 N

Let's use the hint. Thread tension:

T = F + W = 9 108 + 21 120 ≈ 30 230 N

The tension in the cable at the lowest point of the swing is [tex]30248.196 N[/tex].

To determine the tension in the cable at the lowest point of the swing, we can use the hint provided:

[tex]T-mg=\frac{mv^{2}}{r}[/tex]

where T represents tension,

m is the mass of the demolition ball (2155 kg),

g is the acceleration due to gravity (approximately 9.8 m/s^2),

v is the velocity of the ball (8.6 m/s), and

r is the radius of the circular path (17.5 m).

Plugging in the given values, we have:

[tex]T-2155\times 9.81=\frac{2155\times 8.6^{2}}{17.5}[/tex]

[tex]T=30248.196 N[/tex]

Therefore, the tension in the cable at the lowest point of the swing is approximately [tex]30248.196 N[/tex].

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I'll assume that the properties of the water are that sound waves in fresh water move at a speed of 1497 m/s at a temperature of 25 °C. If the speed is 0.01s, you must divide it by 100 to get 14.97; but, since it travels there and back in 0.01s, you must split it in half i.e 7.485m.

Without a medium, what kind of wave can travel?

Electromagnetic waves

In contrast to mechanical waves, electromagnetic waves can travel without a medium. This implies that electromagnetic waves can pass not only through solid objects like air and rock but also through empty space.

Answer and justification Since electromagnetic waves are not conveyed by the vibration of particles, they do not need a medium to travel. Electric and magnetic fields, which can exist anywhere, oscillate, creating waves. Waves can therefore exist in solids, liquids, gases, or empty space.

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The change in the internal energy of the system is  4 kJ.

We know that according to the first law of thermodynamics, energy can neither  be  created nor destroyed but it can be converted from one form to the other.

In this case we know that the internal energy can be obtained by the use of the formula;

ΔE = q + w

ΔE = Change in internal energy

q = Heat absorbed or evolved

w = work done

Where;

q = 9.0 kJ

w = 5.0 kJ

It then follows that;

ΔE = 9 - 5

ΔE = 4 kJ

The gas expands hence the work done is negative.

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The magnitude of acceleration of the crate be 7.14 m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Mass of the create be: m = 38kg.

Force applied on the create : F = 83N.

From Newton's second law of motion, we can write:

force = mass × acceleration

⇒ acceleration = force/mass = 38/83m/s² = 0.45 m/s².

Hence, acceleration of the create be 0.45 m/s².

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Based on the study conducted by Rebecca, the statement that would not be an appropriate hypothesis for Rebecca's experiment is:

A hypothesis is an explanation that is given in the form of a statement to explain an observation based on limited evidence and which serves as a starting point for further investigation.

A hypothesis may or may not be true and must be investigated to prove or disprove it.

Experiments are conducted to prove or disprove a given hypothesis.

A hypothesis is divided into a null and an alternate hypothesis.

A null hypothesis is a hypothesis that state that the treatment given to the subjects of the experiment does not produce any significant effect.

An alternate hypothesis states that the treatment given to the subjects of the experiment produces significant effects on the subjects.

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Pressure gauge is located at the bottom of the container thus, the depth of the mercury = 11.05 cm

Pressure refers to the force applied on a unit area of a surface. It works parallel to the pressure-applied surface. Pressure = force multiplied by the area on which it operates. The stronger the power, the smaller the area.

Given that,

pressure exerted by block ([tex]P_{B}[/tex])= weight / cross-section area of block

[tex]P_{B}[/tex] = (1 ×9.81) ÷ (10 × 10⁻⁴)

     = 9810 Pa

Now, pressure at bottom of container is given as:

[tex]P_{Bottom}[/tex] = [tex]P_{B}[/tex] + ρ × g × h + ρ₁ × g × h₁  

[ ρ = density of water,

ρ₁ = density of Hg,

h = height of water and

h₁ = height of Hg ]

Thus, 27000 = 9810 + (1000 × 9.81 × 0.25) + (13600 × 9.81 × h₁)

h₁ = 14737.5 ÷ 133416

h₁ = 0.1105 m

h₁ = 11.05 cm

Thus, depth of the mercury = 11.05 cm.

So, the depth of the mercury = 11.05 cm

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The liquid's surface tension in N/m is determined as 0.25 N/m.

Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Mathematically, the formula for surface tension of a liquid is given as;

γ = F/L

γ = F/2x

where;

From Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.

F = kx

where;

The final equation for the surface tension of the liquid film becomes;

γ = F/2x

γ = kx/2x

γ = k/2

γ = (0.5 N/m) / 2

γ = 0.25 N/m

Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.

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The momemtum is not conserved in scenario d.

Momentum of an object is the product of its mass and velocity.

To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.

The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.

If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.

In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.

So, the momemtum is not conserved in scenario d.

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Hope this answer helps you

Answer:

I can say words like cheese and balls

Answer:

where u put it last time or retrace ur steps to where u last put it

Answer: If you have "A, B, C" as answers chose the answer: "A".

Explanation:

Trust me.

The x component of the ball's final velocity is 7.35 m/s.

The y component of the ball's final velocity is 4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball along x axis: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin at a -77.0° angle.: v = 20.1 m/s

Let the x component of the ball's final velocity is V₁ m/s.

The y component of the ball's final velocity is V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, The x component of the ball's final velocity is 7.35 m/s.

The y component of the ball's final velocity is 4.90 m/s.

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The x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given that:

Mass of the ball: M = 6.35 kg.

Initial velocity of ball: U = 8.49 m/s.

Mass of the pin at rest: m = 1.59 kg.

Final velocity of pin: v = 20.1 m/s at a -77.0° angle.

Let the x and y component of the ball's final velocity are respectively V₁ m/s and  V₂ m/s.

Appling conservation of momentum along x axis:

MU + m.0 = MV₁ + mvcos(-77.0°)

⇒ V₁ = u - (m/M) v cos(-77.0°)

After putting the values we get:

V₁ = 7.35 m/s.

Appling conservation of momentum along y-axis:

M.0 + m.0 = MV₂ + mvsin(-77.0°)

⇒ V₂ = - (m/M) vsin(-77.0°)

After putting the values we get:

V₂ = 4.90 m/s.

Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and  4.90 m/s.

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The force acting on the box is 250N if the object's velocity changes from being stationary to 25.0 m/s in 5 seconds when it is subjected to a force.

We are aware that the formula F = ma could be used to determine a force's magnitude.

where F = force

m = mass

a = acceleration

Although the question already contains the mass m, it does not directly state the acceleration.

In this case, the acceleration is equal to the change in velocity divided by the time interval,

From the formula, we can determine acceleration.

[tex]a = \frac{25 - 0}{5}[/tex]

[tex]a = 5ms^{-2}[/tex]

Using the equation,

F = ma

F = 50 * 5

F = 250N

Therefore, The force acting on the box is 250N if the object's velocity changes from being stationary to 25.0 m/s in 5 seconds when it is subjected to a force.

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The atom that has been shown is an atom of carbon(C).

We know that in an atom is the smallest particle of a substance that can be able to take part in a chemical reaction. In this case, we have a an atom that have been shown. As expected, the protons that are in the atom have been shown as the circle that is in the innermost part of the image.

The electrons are found around the shells of the atom. The electrons that are in the shells of the atom must be equal to the number of protons that are in the atom of the element.

Given that the number of electrons must be equal to the number of protons and the number of protons gives us the identity of the element that have been shown in the image, we can conclude that this is an atom of carbon.

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The gravitational field strength of the moon at this new distance is gr/4

The gravitational field is the amount of gravitational force that would be applied to a little mass at that location per unit of mass. It is a vector field that is oriented in the mass's expected direction of force.

A gravitational field is the force field that surrounds any mass or collection of masses in space. Although this field spreads out in all directions, the gravitational force becomes weaker the further an object is from the source. This is a method of calculating the gravitational pull. Weight divided by mass equals the strength of the gravitational field. Strength of gravitational field = mass/weight in kilograms, or N/kg.

The complete question is : A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v.

The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?

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The time taken by the car to stop will be 4.53 seconds. The final velocity is zero and the initial velocity will be 86.08 ft./s.

Velocity is a vector quantity which measures distance covered per unit time. It is given that the acceleration of the car a is  19 ft/s². The distance it covered is 195 ft.

We have the expression for final velocity v initial velocity u and the time t with acceleration a as follows where the final velocity v for the car is zero.

0 = U -  at

u = at.

The relation between time, acceleration and initial velocity with distance d is written as:

d = u t - 1/2 at²

  =  at²  -1/2 at²

  = 1/2 at²

Thus, t = √(2d/a)

            = √(2×195 ft / 19 ft/s²)  

            = 4.53 s.

Initial velocity u = a t

                          = 4.53 s ×19 ft/s²

                          = 86.08 ft./s

Therefore, the initial velocity will be 86.08 ft./s.

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With the knowledge of bearing, the airplane will be 24 degrees east of north relative to the ground. The correct answer is option d

Relative motion can be defined as a change of position of an object with a point or frame of reference which we may assumed to be at rest.

Given that an airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, the magnitude of  degrees Ф east of north in which the airplane will travel relative to the ground can be known by using a trigonometry ratio.

The Y component is 190 km/h heads due north.

The X component is 86 km/h from west to east.

TanФ = Y/X

Ф = [tex]Tan^{-1} (\frac{Y}{X})[/tex]

Ф =    [tex]Tan^{-1} (\frac{190}{86})[/tex]

Ф =  [tex]Tan^{-1} (2.209)[/tex]

Ф = 65.65°

The degrees east of north  = 90 - 65.65

The degree east of north = 24.4°

Therefore, the magnitude of degrees east of north in which the airplane will travel relative to the ground is 24° approximately.

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The heat of the room does not flow outside naturally actually it requires an input of work by the air conditioner. Therefore, option (A) is correct.

The air conditioner work on the principles of heat sinks. It functions to cool the temperature of a closed space while transferring the heat from a closed space to another place known as a sink. This process consists of four thermodynamic stages that result in the transformation of electrical energy into a thermal heat absorption system.

Air Conditioners are cooling devices that are used to cool large spaces. The capacity of the air conditioner depends on how much space it needs to cool. An air conditioner takes the thermal energy away to make the air cooler.

Therefore, the heat flow outside the room due to work done by the air conditioner.

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Answer:

a 0.50m

0.50

L=0.50m

w=0.50m

A=L.w

0.50*0.50=25