Please solve as soon as possible

Answer:

Step-by-step explanation:

Calculating the Perimeter of a Compound Shape made from Rectangles. A compound shape (or composite shape) is a more complex shape that is made up of two or more simple shapes.  To find the perimeter, we simply add up the lengths of each outside edge.

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Answer:

it is b sorry I tried to work out it best have a nice day

Answer:

a=

Step-by-step explanation:

Answer:

$0.05 i think

Step-by-step explanation:

Answer:

a = 3

b = 5

c = -8

abc = -120

Step-by-step explanation:

Answer:

-120

Step-by-step explanation:

sorry just looked at the answer below *HAXZ*:)

Answer:

9.3

Step-by-step explanation:

Answer:

a + b + c= 90

30+30+30=90

90=90.

30 is the ans

Answer:

Step-by-step explanation:

50 degree

Answer:

Well, there are 12 inches ina foot so let's multiply 56 by 12. Now, divide 672 by 8: 672/8 = 84 So, we have 84 which means that if we multiply 84 by 2.5 it should equal however many inches there are in 21, if it is to be a true scale model. It is not equal, so no, it is not a true scale model.

Step-by-step explanation:

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BRAINLIEST PLZ???

Answer:

It is not equal, so no, it is not a true scale model.

Step-by-step explanation:

Well, we need to find the ratio of it and see if both measurements of the 'scale' model are the same. But before we do, take in mind we can't divide 56/8 because 56 needs to be converted into inches.

56 • 12 = 672

divide 672 by 8:

672/8 = 84

So, we have 84 which means that if we multiply 84 by 2.5 it should equal however many inches there are in 21, if it is to be a true scale model

21 • 12 = 252

2.5 • 84 = 210

It is not equal, so no, it is not a true scale model.

Answer:

Whole Number

Step-by-step explanation:

Answer:

A whole is a fraction with the denominator of one.

Step-by-step explanation:

Answer:

The distance from the ball to the left post is 50 feet.

Step-by-step explanation:

Since a soccer goal is composed of a pair of 8 ft upright posts, positioned 48ft apart with a horizontal crossbar and netting boxing in the goal, and a soccer ball is positioned directly in front of the right goal post at a distance of 14ft, to To determine what is the ground distance from the ball to the left goal post, the Pythagorean theorem must be applied through the following calculation:

A ^ 2 = B ^ 2 + C ^ 2

A ^ 2 = 14 ^ 2 + 48 ^ 2

A ^ 2 = 196 + 2,304

A = √2500

A = 50

Thus, the distance from the ball to the left post is 50 feet.

Answer: The answer in this photo thanks for a little quiz

The number of day it will be until Addison and Bert each have  read the same number of pages in total is 8 days.

In mathematics, an equation is a statement of equality between two expressions, indicated by the equals sign (=). Solutions to equations are the values for unknowns which, when substituted into the expression, make it true.

Given that, the book they're reading right now is 256 pages long.

Let the number of days be x.

Addison has read 102 pages so far and decides to read 16 pages every day until she finishes the book.

102+16x -------(i)

Bert has read 142 pages, and he plans to read 11 pages every day.

142+11x -------(ii)

Addison and Bert have each read the same number of pages in total.

So, (i)=(ii)

102+16x=142+11x

16x-11x=142-102

5x=40

x=8

Hence, the number of day it will be until Addison and Bert each have  read the same number of pages in total is 8 days.

To learn more about an equation visit:

https://brainly.com/question/14686792.

#SPJ3

39.5% of 373. is 147.336

Answer:

[tex]A=p^2-2p-3[/tex]

Step-by-step explanation:

The area for a triangle is given by:

[tex]\displaystyle A=\frac{1}{2}bh[/tex]

The base is p + 1 and the height is 2p - 6. Therefore:

[tex]\displaystyle A=\frac{1}{2}(p+1)(2p-6)[/tex]

Simplify the second term:

[tex]\displaystyle A=(p+1)(\frac{1}{2})(2p-6)=(p+1)(p-3)[/tex]

Distribute:

[tex]A=p(p-3)+1(p-3)[/tex]

Distribute:

[tex]A=p^2-3p+p-3[/tex]

Combine like terms:

[tex]A=p^2-2p-3[/tex]

Answer:

the answer is x= 5 and y = 1.5

Here we have been given with two equations and we will solve them by elimination by substitution method inorder to get the value of x and y.

★ From Equation No 2 :-

>> x + 2y = 8

>> x = 8 - 2y

★ In Equation No 1 :-

Substituting here the value of x which we got above as (8 - 2y).

>> 5x - 4y = 19

>> 5 (8 - 2y) - 4y = 19

>> 40 - 10y - 4y = 19

>> 40 - 14y = 19

>> -14y = 19 - 40

>> -14y = -21

>> 14y = 21

>> y = 21 / 14

>> y = 1.5

★ Finding out value of x :-

>> x = 8 - 2y

>> x = 8 - 2 (1.5)

>> x = 8 - 2 × 1.5

>> x = 8 - 3

>> x = 5

The answer is the first one . A

Answer:

The scale Myra should use is one graph unit = 400 km or;

←--→ = 400 km

Step-by-step explanation:

The question relates to the representation of scale drawing

The actual distance between Perth and Sydney = 3294 kilometers

The given coordinates of Perth on the grid = (1.3, 3.4)

The given coordinates of Sydney on the grid = (9.2, 3.3)

The measure of the distance between Perth and Sydney, 'd', is given by using the following formula for finding the distance between two points given their 'x', and 'y' coordinates;

[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Therefore, by substitution, we have;

[tex]d = \sqrt{\left (9.2-1.3 \right )^{2}+\left (3.3-3.4 \right )^{2}} = \sqrt{\left (7.9 \right )^{2}+\left (-0.1 \right )^{2}} = \dfrac{\sqrt{6242} }{10} \approx 7.9[/tex]

d ≈ 7.9 units

Therefore, we have;

7.9 units of the graph = 3294 kilometers

1 unit of the graph ≈ 3294/7.9 km = 416.962025316 km ≈ 416.96 km

Therefore, the scale Myra should use for her map is 1 unit = 400 km.

Answer:

the one going this way -------------------------- not up and down

Step-by-step explanation:

Answer:

Step-by-step explanation:

the one on the right

Step-by-step explanation:

Easy steps!

Answer:

19 degrees.

Step-by-step explanation:

First solve the angles in the top triangle:

FHG = 180 - 135 = 45 (angles on a straight line = 180)

FGH = 180 - 105 = 75 (angles on a straight line = 180)

Using these we get HFG = 180 - 45 - 75 = 60 (angles in a triangle = 180)

Then because HFG is directly opposite DFC on the crossed lines, we know they are equal: DFC = 60

FDC = 180 - 119 = 61 (anges on a straight line = 180)

Now if we label ABC (the target angle) as x then we known ACB = 180 - 40 - x.

With this we know FCD = 180 - ACB = 180 - (180 - 40 - x) = 40 + x (angles on a straight line).

Finally using the FDC triangle we have 40 + x + 60 + 61 = 180 so x = 180 - 40 - 60 - 61 = 19 degrees.

Answer:

47x=5

or 5/47

Step-by-step explanation:

Answer:

x=85

Step-by-step explanation:

x/5 + 2 = 19

5(x/5 + 2) = 5(19) *multiply both sides of the equation by 5 to get rid of the fraction

x + 10 = 95

x = 85 *subtract 10 on both sides

Check:

x/5 + 2 = 19

85/5 + 2 = 19

17 + 2 = 19

19 = 19

Answer:

Bro its easssssssssssssssssssssssssssssssy

Step-by-step explanation:

you must do the rule of threee.

Answer:

r=1

Step-by-step explanation:

77 - 88 = -11

-11/-11 = 1

Answer:

$7.50

Step-by-step explanation:

formula for simple interest:

I = prt

I = ($125)(0.03)(2)

I = $7.50

Answer:

You time 125 by 1.03 twice subtract 125 from that awnser to get the amount of money from interest 7.6125 is the awnser

Step-by-step explanation:

Answer:

12a

3 x 4 =12a

Answer:

5/12

Step-by-step explanation:

Answer:

D) -47/36

Step-by-step explanation:

Trust me.

Answer:

CD = [tex]\sqrt{164}[/tex]

Step-by-step explanation:

Calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = C(5, - 2) and (x₂, y₂ ) = (D(- 3, 8)

d = [tex]\sqrt{(-3-5)^2+(8+2)^2}[/tex]

   = [tex]\sqrt{(-8)^2+10^2}[/tex]

    = [tex]\sqrt{64+100}[/tex]

    = [tex]\sqrt{164}[/tex]

     = 2[tex]\sqrt{41}[/tex] ← in simplest form

As, we have C (5, - 2) and D (- 3, 8), to find CD let's use distance formula :

[tex] \underline{\boxed{\tt{Distance \: between \: two \: points = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}}}}[/tex]

Here,

So, by filling values :

[tex] \sf : \implies CD = \sqrt{(-3 - 5)^{2} + (8 - (-2))^{2}}[/tex]

[tex] \sf : \implies CD = \sqrt{(-8)^{2} + (8 +2))^{2}}[/tex]

[tex] \sf : \implies CD = \sqrt{64 + (10)^{2}}[/tex]

[tex] \sf : \implies CD = \sqrt{64 + 100}[/tex]

[tex] \sf : \implies CD = \sqrt{164}[/tex]

Hence, distance of CD is [tex] \bold{\sf \sqrt{164}.}[/tex]