Please show work for number 3 and 4!

Answer:

US

World

Step-by-step explanation:

It depends on where you are. A "trapezium" outside the US is the same as a "trapezoid" in the US, and vice versa.

A trapezium (World; trapezoid in the US) is characterized by exactly one pair of parallel lines. One of the lines that are not parallel may be perpendicular to the parallel lines, but that will only be true for the specific case of a "right" trapezium.

__

A trapezium (US; trapezoid in the World) is characterized by no parallel lines. It may have one angle or opposite angles that are right angles (one or two sets of perpendicular lines), but neither diagonal may bisect the other.

In the US, "trapezium" is rarely used. The term "quadrilateral" is generally applied to a 4-sided figure with no sides parallel.

Answer:

The answer is nothing duh

Step-by-step explanation:

Answer:

The lowest score eligible for an award is 92.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

[tex]\mu = 82.2, \sigma = 5[/tex]

If the top 2.5% of test scores receive merit awards, what is the lowest score eligible for an award

The lowest score is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975. So X when Z = 1.96. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.96 = \frac{X - 82.2}{5}[/tex]

[tex]X - 82.2 = 5*1.96[/tex]

[tex]X = 92[/tex]

The lowest score eligible for an award is 92.

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is

The manager of the Danvers-Hilton Resort Hotel stated that the mean guest bill for a weekend is $600 or less. A member of the hotel’s accounting staff noticed that the total charges for guest bills have been increasing in recent months. The accountant will use a sample of

weekend guest bills to test the manager’s claim.

a. Which form of the hypotheses should be used to test the manager’s claim? Explain.

1) H0:μ ≥ 600

Ha:μ < 600

2) H0:μ ≤ 600

Ha:μ > 600

3) H0:μ=600

Ha:μ≠600

b. What conclusion is appropriate when H0 cannot be rejected?

c. What conclusion is appropriate when H0 can be rejected?

Solution:

a) the hypotheses should be used to test the manager’s claim is

H0:μ ≤ 600

Ha:μ > 600

This is because the already known or assumed mean guest bill for a weekend is 600 or less. This forms the null hypothesis. The alternative is the opposite of the null hypothesis. Since the alternative states that it is increasing, the sign,> would be used.

b) If H0 cannot be rejected, it means that there is no sufficient evidence to reject H0 at the given level of significance.

c) if H0 can be rejected, it means that there is sufficient evidence to reject H0 at the given level of significance.

Answer:

Step-by-step explanation:

Hi,

the function is defined for all reals so the domain is [tex]]-\infty;+\infty[[/tex]

for x real

|x| >= 0

so f(x) >= 4

so the range is [tex][4;+\infty[[/tex]

do not hesitate if you need any further explanation

hope this helps

Answer:

Domain: (-∞,∞) Range: (4,∞)

Answer:

1/26

Step-by-step explanation:

There is 1 four of spades, and 1 ace of clubs.

So the probability is 2/52, or 1/26.

Answer:

P(four of spades or ace of clubs)= 1/26

Step-by-step explanation:

In a deck of 52 cards, there is one four of spaces and one ace of clubs. we want to find the probability of selecting those cards.

P(four of spades or ace of clubs)=four of spades+ace of clubs/total cards

There is 1 four of spades and 1 ace of clubs. 1+1=2

P(four of spades or ace of clubs)=2/total cards

There are 52 total cards in a deck.

P(four of spades or ace of clubs)=2/52

This fraction can be simplified. Both the numerator (top number) and denominator (bottom number) can be divided by 2.

P(four of spades or ace of clubs)= (2/2) / (52/2)

P(four of spades or ace of clubs)= 1/26

Answer:

a.) 8x + 6y

b.) 4x + 2y

Step-by-step explanation:

Simply add like terms together (x with x and y with y).

Answer:

25/88

Step-by-step explanation:

25 red marbles, 27 blue marbles, and 36 yellow marbles. = 88 marbles

P(red) = number of red/total

          = 25/88

Answer:

Dear user,

Answer to your query is provided below

Probability of choosing a red marble is 0.28 or (25/88)

Step-by-step explanation:

Total number of marbles = 88

Number of red marbles = 25

Probability = 25/88

Answer:

Yes, the sample has a bias

Step-by-step explanation:

Bias is the term used in statistics to describe a systematic distortion in the samples obtained for the parameter being estimated. It is evident by obtaining values higher or lower than that of the average population for the parameter being measured. As such the data is a misrepresentation of the population and cannot be trusted to give a good indices of things.

This sample has a bias because the concerned citizen opted to use a convenience sampling instead of using random sampling. In random sampling, every individual has an equal chance of being chosen which is unlike the convenience sampling when only a specific group of individuals can be chosen. In this case, the bias was introduced when the citizen went to stand outside the courthouse with his petition, the citizen should have taken samples across diverse geographical locations and professional institutions. The implication of this sampling is that a significant percentage of the population has been sidelined (considering they would not be in or around the courthouse) from the sampling and the sampling has been restricted to only those who have business around the courthouse. The result is that whatever samples he/she obtains will not be an accurate representation of the parameter being measure from the population.

As such, the sampling technique is biased

Answer:

C

Step-by-step explanation:

3x+2-x>8

2x+2>8

2x>8-2

2x>6

x>3

Answer:

C

Step-by-step explanation:

Answer:

72√3

Step-by-step explanation:

30 60 90 triangles are what you start out with.

Step 1: 30-60-90

x = 12

WZ = 12√3

Step 2: Area formula

A = 1/2(12)(12√3)

*Since the 2 30-60-90 triangles are congruent, both segments of the base are 12

Plug it into the calc and you should get A = 72√3 as your final answer!

Answer:

Step-by-step explanation:

max can be found by the formula:

t=-b/2a

t=-9.8/2*(-4.9)

t=-9.8/-9.8

t=1

1 sec

to find maximum height obtained we find the vertex:

plug in 1 for t and simply solve:

h(t)= -4.9t^2 + 9.8t + 1

h(t)= -4.9*1^2 + 9.8*1 + 1

h(t)= -4.9*1 + 9.8 + 1

h(t)= -4.9 + 10.8

h(t)= 5.9

height is 5.9

Answer:

the correct answer is

Step-by-step explanation:

So, the probability is:P(greater than 4)=26=13. This is a theoretical probability, which is the observed number of favorable outcomes out of a certain number of trials. For instance, suppose you rolled the six-sided die five times, and got the following results:2,6,4,5,6

hope this help you!!!!!

Answer:

1/5 chance.

Step-by-step explanation:

There is only one number, 5, that is greater than 4 and there are 5 total numbers so there is a 1/5 chance selecting that number.

Answer: Undefined

Step-by-step explanation:

For this problem, we know that 3ˣ=-9. All we have to do is figure out what x is.

We know that any integer raised to the power cannot be negative. The closest answer we can get is x=2 because 3²=9. Unfortunately, we are looking for -9. Therefore, this x is undefined.

Answer:

a) Option D is correct.

H0​: μ = 71

Ha​: μ > 71

b) Option F is correct

z > 1.28

c) z = 2.85

d) Option C is correct.

Reject H0.There is sufficient evidence at the α = 0.10 level of significance to conclude that the true mean heart rate during laughter exceeds 71 beats per minute.

Step-by-step explanation:

a) For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

This question aims to test the the true mean heart rate during laughter exceeds 71 beats per minute.

Hence, the null hypothesis is that there isn't sufficient evidence to say that the true mean heart rate during laughter exceeds 71 beats per minute. That is, the true mean doesn't exceed 71 beats per minute.

And the alternative hypothesis is that there is sufficient evidence to say that the true mean heart rate during laughter exceeds 71 beats per minute.

Mathematically,

The null hypothesis is represented as

H₀: μ = 71

The alternative hypothesis is represented as

Hₐ: μ > 71

b) Using z-distribution, the rejection area is obtained from the confidence level at which the test is going to be performed. Since the hypothesis test tests only in one direction,

Significance level = (100% - confidence level)/2

0.10 = 10% = (100% - confidence level)/2

20% = 100% - (confidence level)

Confidence level = 100% - 20% = 80%

Critical value for 80% confidence level = 1.28

And since we are testing if the true mean heart rate during laughter exceeds 71 beats per minute, the rejection area would be

z > 1.28

c) The test statistic is given as

z = (x - μ)/σₓ

x = sample mean = 73.4

μ = 71

σₓ = standard error = (σ/√n)

σ = 8

n = Sample size = 90

σₓ = (8/√90) = 0.8433

z = (73.4 - 71) ÷ 0.8433

z = 2.846 = 2.85

d) Since the z-test statistic obtained, 2.85, is firmly in the rejection area, z > 1.28, we reject the null hypothesis, accept the alternative hypothesis and say that there is sufficient evidence at the α = 0.10 level of significance to conclude that the true mean heart rate during laughter exceeds 71 beats per minute.

Hope this Helps!!!

Answer:

Nothing can be further done to this equation. It has been simplified all the way.

Answer:

(a) The probability that at least one individual with a reservation cannot be accommodated on the trip is 0.4202.

(b) The expected number of available places when the limousine departs is 0.338.

Step-by-step explanation:

Let the random variable Y represent the number of passenger reserving the trip shows up.

The probability of the random variable Y is, p = 0.70.

The success in this case an be defined as the number of passengers who show up for the trip.

The random variable Y follows a Binomial distribution with probability of success as 0.70.

(a)

It is provided that n = 6 reservations are made.

Compute the probability that at least one individual with a reservation cannot be accommodated on the trip as follows:

P (At least one individual cannot be accommodated) = P (X = 5) + P (X = 6)

[tex]={6 \choose 5}\ (0.70)^{5}\ (1-0.70)^{6-5}+{6 \choose 6}\ (0.70)^{6}\ (1-0.70)^{6-6}\\\\=0.302526+0.117649\\\\=0.420175\\\\\approx 0.4202[/tex]

Thus, the probability that at least one individual with a reservation cannot be accommodated on the trip is 0.4202.

(b)

The formula to compute the expected value is:

[tex]E(Y) = \sum X\cdot P(X)[/tex]

[tex]P (X=0)={6 \choose 0}\ (0.70)^{0}\ (1-0.70)^{6-0}=0.000729\\\\P (X=1)={6 \choose 1}\ (0.70)^{1}\ (1-0.70)^{6-1}=0.010206\\\\P (X=2)={6 \choose 2}\ (0.70)^{2}\ (1-0.70)^{6-2}=0.059535\\\\P (X=3)={6 \choose 3}\ (0.70)^{3}\ (1-0.70)^{6-3}=0.18522\\\\P (X=4)={6 \choose 4}\ (0.70)^{4}\ (1-0.70)^{6-4}=0.324135[/tex]

Compute the expected number of available places when the limousine departs as follows:

[tex]E(Y) = \sum X\cdot P(X)[/tex]

         [tex]=(4\cdot 0.000729)+(3\cdot 0.010206)+(2\cdot 0.059535)+(1\cdot 0.18522)\\+(0\cdot 0.324135)\\\\=0.002916+0.030618+0.11907+0.18522+0\\\\=0.337824\\\\\approx 0.338[/tex]

Thus, the expected number of available places when the limousine departs is 0.338.

Answer:

Your correct answer is 31/50 + -4/25 i

Step-by-step explanation:

5+4i/6+8i = 31/50 + -4/25 i

Answer:

[tex]y = -\frac{7x}{3} - 24[/tex]

Step-by-step explanation:

We can model this function using the equation of a line:

[tex]y = ax + b[/tex]

Where a is the slope of the line and b is the y-intercept.

To find the values of a and b, we can use the two points given:

(-9, -3):

[tex]-3 = a * (-9) + b[/tex]

[tex]-9a + b = -3[/tex]

(-12, 4):

[tex]4 = a * (-12) + b[/tex]

[tex]-12a + b = 4[/tex]

If we subtract the second equation from the first one, we have:

[tex]-12a + b - (-9a + b) = 4 - (-3)[/tex]

[tex]-12a + 9a = 4 + 3[/tex]

[tex]-3a = 7[/tex]

[tex]a = -7/3[/tex]

Then, finding the value of b, we have:

[tex]-12a + b = 4[/tex]

[tex]28 + b = 4[/tex]

[tex]b = -24[/tex]

So the equation is:

[tex]y = -\frac{7x}{3} - 24[/tex]

Answer:

48620

Step-by-step explanation:

There are 6 fruits and 18 non-fruits.  Cory wants to buy all 6 fruits, and 9 of the 18 non-fruits.

The number of ways he can choose 6 fruits from 6 is ₆C₆ = 1.

The number of ways he can choose 9 non-fruits from 18 is ₁₈C₆ = 48620.

The total number of combinations is 1 × 48620 = 48620.

Answer:

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

Answer:

216-343

Step-by-step explanation:

the number 312 lies between 125 and 330

Answer:

20 x 20 grid = 1066.67 cm wire

Step-by-step explanation:

Using unitary method

9 grid = 24 cm wire

1 grid = [tex]\frac{24}{9}[/tex] cm wire

Multiplying both sides by 400 (20 x 20)

400 grid = [tex]\frac{24}{9} * 400[/tex] cm

20 x 20 grid = 1066.67 cm wire

Answer:

2

Step-by-step explanation:

Scale Factor = [tex]\frac{AnySideOfDiagram}{AnySideOfMP3Player}[/tex]

So,

Scale Factor = [tex]\frac{8}{4} = \frac{14}{7}[/tex] = 2

So,

The scale factor is 2

Answer:

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

f(x) = (x + 1)^2

Let x=2

f(2) = (2 + 1)^2

     = 3^2

     = 9

Answer:

39

Step-by-step explanation:

12+20+22+22+23=99

new mean=23

23*6=138

138-99=39

Answer:

P(33) = 0.0826

Step-by-step explanation:

The binomial distribution in this case has parameters n=55 and p=0.55.

The probability that k successes happen with these parameters can be calculated as:

[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{55}{k} 0.55^{k} 0.45^{55-k}\\\\\\[/tex]

We have to calculate the probability fo X=33 succesess.

This can be calculated using the formula above as:

[tex]P(x=33) = \dbinom{55}{33} p^{33}(1-p)^{22}\\\\\\P(x=33) =1300853625660220*0.0000000027*0.0000000235\\\\\\P(x=33) =0.0826\\\\\\[/tex]

Answer:

[tex]n=(\frac{2.58(0.34)}{0.05})^2 =307.79 \approx 308[/tex]

So the answer for this case would be n=308 rounded up to the nearest integer

Step-by-step explanation:

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =0.1/2 =0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} s}{ME})^2[/tex]   (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution since the sample size is large enough to assume the estimation of the standard deviation as the population deviation. The critical value for this case is [tex]z_{\alpha/2}=2.58[/tex], replacing into formula (b) we got:

[tex]n=(\frac{2.58(0.34)}{0.05})^2 =307.79 \approx 308[/tex]

So the answer for this case would be n=308 rounded up to the nearest integer