please select all that would be categorized as vectors

Circuit A is correct

Answer:

"0.049 W" is the correct answer.

Explanation:

According to the given question,

[tex]r = \sqrt{(3.5)^2+(2.5)^2}[/tex]

  [tex]=\sqrt{8.5}[/tex]

[tex]SL=85[/tex]

As we know,

⇒  [tex]SL=10 \ log(\frac{I}{I_o} )[/tex]

     [tex]85=10 \ log(\frac{I}{10^{-12}} )[/tex]

      [tex]I=3.162\times 1^{-4} \ W/m^2[/tex]

Now,

⇒  [tex]P_{front} = I(2\pi r^2)[/tex]

               [tex]=(3.162\times 10^{-4})(2\pi\times 18.5)[/tex]

               [tex]=0.0368 \ W[/tex]

               [tex]=0.75 \ P[/tex]

or,

                [tex]=0.049 \ W[/tex]

Answer:

Hello There!!

Explanation:

The answer is=> It is a common component of antacids.

hope this helps,have a great day!!

~Pinky~

Answer:

Movement of Electrons in opposite direction of the rotation of the pickup coil leads to the direction of Electrical energy ( Alternating current ).

Explanation:

For a Generator to generate electricity, Electrons that is found in the rotating coil of the Generator will experience some sort of force that makes them to start moving in a direction that is perpendicular to the direction of the rotating/pickup coil found in the Generator.

The conversion of mechanical energy (Rotation of the pickup coil ) to electrical energy takes place in the Generator

The generator makes an alternating current because electrons move in opposite direction of the rotating coil

In other to generate a Direct current using a generator we have to replace the slip rings with commutator.

Answer:

blocks of ice are usually covered with cloth or sawdust while being stored

Answer:

a) the speed of the bat is 5.02 m/s

b) the wavelength of the sound that the bat hears is 0.011 m

Explanation:

Given the data in the question;

Frequency of sound emitted by a bat f = 30.0 kHz = 30000 Hz

detected frequency by the bat δf = 900 Hz

speed of sound in air c = 340 m/s

Let speed of sound and speed of bat be c and [tex]v_s[/tex] respectively;

Now, frequency of the sound that is coming from the bat towards the wall due to DROPPLER EFFET will be;

f₁ = ( c / ( c - [tex]v_s[/tex] ) )f ----- let this be equ 1

Also, frequency does not change after deflection. The bat becomes an observer as the dropper is shifted because the reflected sound wave is coming towards it;

Hence, Doppler shifted frequency will be;

f₂ = ( (c + [tex]v_s[/tex] ) / c )f₁

from equ 1, f₁ = ( c / ( c - [tex]v_s[/tex] ) )f, so we substitute

f₂ = ( (c + [tex]v_s[/tex] ) / c ) × ( c / ( c - [tex]v_s[/tex] ) )f

f₂ = ( (c + [tex]v_s[/tex] ) / ( c - [tex]v_s[/tex] ) )f

∴ beat frequency will be;

δf = f₂ - f = ( (c + [tex]v_s[/tex] ) / ( c - [tex]v_s[/tex] ) )f - f

δf = ( 2[tex]v_s[/tex] / c - [tex]v_s[/tex] )f

δf = ( 2[tex]v_s[/tex] / c - [tex]v_s[/tex] )f

2f/δf = c - [tex]v_s[/tex] / [tex]v_s[/tex]

2f/δf = c/[tex]v_s[/tex] - [tex]v_s[/tex] / [tex]v_s[/tex]

2f/δf = c/[tex]v_s[/tex] - 1

c/[tex]v_s[/tex] = 2f/δf + 1

[tex]v_s[/tex] =  c / (2f/δf + 1)

now, we substitute in our values;

[tex]v_s[/tex] =  340 / ((2×30000 / 900 ) + 1)

[tex]v_s[/tex] =  340 / (66.6666 + 1)

[tex]v_s[/tex] =  340 / 67.6666

[tex]v_s[/tex] =  5.02 m/s

Therefore, the speed of the bat is 5.02 m/s

b) the wavelength of the sound that the bat hears

frequency of reflected wave is;

f₂ = f + δf = 30000 + 900 = 30900 Hz

λ₂ = c / f₂

we substitute

λ₂ = 340 / 30900

λ₂ = 0.011 m

Therefore, the wavelength of the sound that the bat hears is 0.011 m

Answer:

0.3 A

Explanation:

Build the circuit attached. Make sure the switch is turned off as you build the circuit. Set the Selected battery voltage to 10 volts.

A.      Based on the number on the fuse, what do you think is the maximum current allowed in this circuit?

Solution:

A fuse is a safety device which is used in circuits for preventing very high currents which can cause overloading or start a fire. A fuse is made up of a low resistance thin piece of metal such that the flow of high current can cause the metal to melt leading to an open circuit. A fuse lets current flow up to a maximum value before it melts and the circuit will be broken.

From the image attached, since the maximum rating of the fuse is 0.3 A, hence the maximum current that can flow through the circuit is 0.3 A.

Answer:

6 W

Explanation:

From the given information:

The resistance in Parallel for 2R is:

[tex]R_p = \dfrac{2R\times 2R}{2R+2R} \\ \\ R_p= R[/tex]

The equivalent resistance:

[tex]R_{eq} = R_p + R = 2R[/tex]

[tex]R_{eq} = 2(3)[/tex]

[tex]R_{eq} = 6 \ \ ohms[/tex]

The current through the circuit in R is:

[tex]= \dfrac{12}{R+R} \\ \\ = \dfrac{12}{2\times 3} \\ \\ = 2 A[/tex]

The current through the circuit in 2R is:

[tex]I_2R = (2A) \times \dfrac{2R}{2R+2R}[/tex]

[tex]I_2R = 2A \times \dfrac{1}{2} \\ \\ I_2R = 1A[/tex]

Finally, the thermal energy:

[tex]P_{2R} = (1)^2 (2R)[/tex]

[tex]P_{2R} = (1)^2 (2\times 3)[/tex]

[tex]P_{2R} = 6W[/tex]

Answer:

Average :

UCL = 4.15

LCL = 2.65

Range :

UCL = 2.75

LCL = 0

Explanation:

Given :

Sample size, n = 5

Average, X = 3.4

Range, R = 1.3

A2 for n = 5 ; equals 0.577 ( X chart table)

For the average :

Upper Control Limit (UCL) :

X + A2*R

3.4 + 0.577(1.3) = 4.1501

Lower Control Limit (LCL) :

X - A2*R

3.4 - 0.577(1.3) = 2.6499

FOR the range :

Upper Control Limit (UCL) :

UCL = D4*R

D4 for n = 5 ; equals = 2.114

UCL = 2.114*1.3 = 2.7482

Lower Control Limit (LCL) :

LCL = D3*R

D3 for n = 5 ; equals = 0

LCL = 0 * 1.3 = 0

Answer:

Check how much energy was released during the reaction or check for a change in total mass

Answer:

Explanation:

Given that:

the initial angular velocity [tex]\omega_o = 0[/tex]

angular acceleration [tex]\alpha[/tex] = 4.44 rad/s²

Using the formula:

[tex]\omega = \omega_o+ \alpha t[/tex]

Making t the subject of the formula:

[tex]t= \dfrac{\omega- \omega_o}{ \alpha }[/tex]

where;

[tex]\omega = 1.53 \ rad/s^2[/tex]

∴

[tex]t= \dfrac{1.53-0}{4.44 }[/tex]

t = 0.345 s

b)

Using the formula:

[tex]\omega ^2 = \omega _o^2 + 2 \alpha \theta[/tex]

here;

[tex]\theta[/tex] = angular displacement

∴

[tex]\theta = \dfrac{\omega^2 - \omega_o^2}{2 \alpha }[/tex]

[tex]\theta = \dfrac{(1.53)^2 -0^2}{2 (4.44) }[/tex]

[tex]\theta =0.264 \ rad[/tex]

Recall that:

2π rad = 1 revolution

Then;

0.264 rad = (x) revolution

[tex]x = \dfrac{0.264 \times 1}{2 \pi}[/tex]

x = 0.042 revolutions

c)

Here; force = 270 N

radius = 1.20 m

The torque = F * r

[tex]\tau = 270 \times 1.20 \\ \\ \tau = 324 \ Nm[/tex]

However;

From the moment of inertia;

[tex]Torque( \tau) = I \alpha \\ \\ Since( I \alpha) = 324 \ Nm. \\ \\ Then; \\ \\ \alpha= \dfrac{324}{I}[/tex]

given that;

I = 84.4 kg.m²

[tex]\alpha= \dfrac{324}{84.4} \\ \\ \alpha=3.84 \ rad/s^2[/tex]

For re-tardation; [tex]\alpha=-3.84 \ rad/s^2[/tex]

Using the equation

[tex]t= \dfrac{\omega- \omega_o}{ \alpha }[/tex]

[tex]t= \dfrac{0-1.53}{ -3.84 }[/tex]

[tex]t= \dfrac{1.53}{ 3.84 }[/tex]

t = 0.398s

The required time it takes= 0.398s

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is [tex]12.5\ km[/tex]

Speed of car is [tex]100\ km/h[/tex]

Car drives for [tex]30\ \text{minute}\ or\ 0.5\ hr[/tex]

(a)Distance traveled is

[tex]\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km[/tex]

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by [tex]\frac{5}{18}[/tex]

[tex]\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s[/tex]

Answer:

65 Newtons

Explanation:

A book is kept on the table. The book is applying 65 N of force down on the table. So the table will also apply 65 N force to the book.

According to physics, a force is an effect that has the power to change an object's motion. A force can cause a massed item to accelerate or modify its velocity. A push or a pull is a straightforward method to explain force. Considering that a force has both a magnitude and a direction, it is a vector quantity.

The pace at which an object's direction changes when it is traveling is referred to as its velocity, and is measured by a particular unit of time and from a particular point of view.

When the book is applying force on the table that is mg, and it is 65 N the table will also generate a normal reaction force which will be equal to the force applied by the book which is 65 N.

To get more information about Force :

https://brainly.com/question/13191643

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Today's cosmologists assume that matter was not uniformly distributed in the universe after the Big Bang. Dense places attract more matter than the surrounding area according to their gravitational forces. Over the course of billions of years, these gas agglomerations eventually led to the formation of the galaxies we see today.

Answer:

201.8 days

Explanation:

The activity of a radioactive sample as a function of times is :

[tex]$R=R_0e^{\frac{0.693t}{T_{1/2}}}$[/tex]

Here, [tex]$R_0$[/tex] = the initial activity

          [tex]$T_{1/2}$[/tex] = half life

          t = elapsed time

Now rearranging the equation for time, t, we get:

[tex]$\frac{R}{R_0}=e^{-\frac{0.693t}{T_{1/2}}}$[/tex]

[tex]$\ln\left(\frac{R}{R_0}\right)=-\frac{0.693t}{T_{1/2}}$[/tex]

[tex]$t=\frac{-\ln\left(\frac{R}{R_0}\right)T_{1/2}}{0.693}$[/tex]

[tex]$t=\frac{-\ln\left(\frac{25}{350}\right)\times 53}{0.693}$[/tex]

 = 201.8 days

Therefore, the required time is 201.8 days

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

[tex]f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\[/tex]

f = - 0.143 m = - 14.3 cm

Negative focal length indicates that combination will act as diverging lens.

Answer:

60

Explanation:

A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what

depth it sinks when placed in a tank of water (assume the sides are sufficiently high,

so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.​

Answer:

No, it does not.

Explanation:

According to the Law of Gravitation, something going down has more kinetic energy than something going up because it attracts pressure from around it when going down. When it goes up, it has less gravitational force and inertia also stops the ball from rolling upward. Therefore, without the amount of kinetic energy, it will not have the same amount of acceleration.

You could hold rallies which attract a lot of people, they come and you discuss apon making the world a better place and how you want to shape the society.

Answer:

Answer:

I believe it’s A

Explanation:

Answer:

A is correct (1 nm to 100 nm)

Explanation:

I just took the exam

Answer:

A) you can't see far ahead

D. You may struggle to stay at the same speed.

Winding roads and sharp curves are dangerous because of centrifugal forces while taking curves, whose classic formula is described below:

[tex]F = m\cdot \frac{v^{2}}{r}[/tex] (1)

Where:

Sharps curves are characterized by low radii of curvature. Given that centrifugal force is inversely proportional to the square radius of curvature and it is opposed to friction force between tires and pavement, if centrifugal force is higher than maximum static friction force, then a car accident could if driver does not decelerate.

Therefore, correct choice is D.

We kindly invite to see this question on centrifugal forces: https://brainly.com/question/545816

Answer:

There are stars in our galaxy that appear to be over 15 billion years old.

Explanation:

Answer:

Heat transfer is an engineering discipline that concerns the generation, use, conversion, and exchange of heat (thermal energy) between physical systems.

Explanation:

Answer:

Heat transfer is a discipline of thermal engineering that concerns the generation, use, conversion, and exchange of thermal energy between physical systems. Heat transfer is classified into various mechanisms, such as thermal conduction, thermal convection, thermal radiation, and transfer of energy by phase changes.

Explanation:

hope that helps

Answer:

134 f

Explanation:

The hottest temperature ever reliably measured in a desert was 134 degrees F, in Death Valley of the Mojave Desert in 1913.

Temperature. During the day, desert temperatures rise to an average of 38°C (a little over 100°F). At night, desert temperatures fall to an average of -3.9°C (about 25°F). At night, desert temperatures fall to an average of -3.9 degrees celsius (about 25 degrees fahrenheit).

Desert surfaces receive a little more than twice the solar radiation received by humid regions and lose almost twice as much heat at night. Many mean annual temperatures range from 20-25 degrees Celsius. The extreme maximum ranges from 43.5-49 degrees Celsius. Minimum temperatures sometimes drop to -18 degrees Celsius.