PLEASE HELP!!!!

On a piece of paper, graph

Then determine which answer choice matches the graph you drew.

Answer:

A. 120

Step-by-step explanation:

To find the measure of x, you would need to subtract the major arc minus the minor arc. A circle is 360 degrees so, 360-60=300. That is the major arc. Now, we use the formula, x=1/2(major-minor). When we plug the information in, we get 1/2(300-60)...1/2(240)...x=120.

Hence,

the correct option would be 120.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

Answer:

2 sides of equal length, 3 sides of equal length

Step-by-step explanation:

your welcome✌

The property which equilateral and isosceles triangle have in common is 2 sides of equal length

A triangle with two sides of equal length is an isosceles triangle. The isosceles triangle has three acute angles, meaning that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°.

In an isosceles triangle, the two equal sides are called legs, and the remaining side is called the base. The angle opposite the base is called the vertex angle

The three types of Isosceles Triangles are :

Isosceles acute triangle

Isosceles right triangle

Isosceles obtuse triangle

Given data ,

Let the triangle be represented as ΔABC

Now , A triangle with two sides of equal length is an isosceles triangle.

Both equilateral triangles and isosceles triangles have at least 2 sides of equal length, but only equilateral triangles have all three sides of equal length.

Hence , the triangles have at least 2 sides of equal lengths

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D is point lies between A and B.

Triangle △ABC has an altitude CD.
angles A and B are both acute.

Altitude is perpendicular bisector to side of triangle from opposite vertex of triangle.

Since △ABC
A and B are acute angles, and that altitude CD has one vertex at c and other is between A and B i.e. D

Thus, the required point of Altitude CD D lies between A and B.

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Answer:

n = -15

Step-by-step explanation:

Given

Sum of Integers from 15 to 50 (inclusive) = Sum of integers from n to 50 (inclusive)

n < 15

Required

Find n

We can split the given parameters to 2

i. Sum of Integers from 15 to 50 (inclusive)

ii. Sum of integers from n to 50 (inclusive)

Solving for (i): Sum of Integers from 15 to 50 (inclusive)

We'll make use of sum of n terms of an arithmetic;

This is given as follows

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where n is the number of terms from 15 to 50

T1 is the first term; T1 = 15

Tn is the last term; Tn = 50

n is calculated using

[tex]n = T_n - T_1 + 1[/tex]

[tex]n = 50 - 15 + 1[/tex]

[tex]n = 36[/tex]

The formula becomes

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]S_n = \frac{36}{2}(15 + 50)[/tex]

[tex]S_n = \frac{36}{2}(65)[/tex]

[tex]S_n = 18(65)[/tex]

[tex]S_n = 1170[/tex]

Solving for (ii): Sum of integers from n to 50 (inclusive)

We'll also make use of the same formula used above

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where n is the number of terms from n to 50

T1 is the first term; T1 = n

Tn is the last term; Tn = 50

n is calculated using

[tex]n = T_n - T_1 + 1[/tex]

[tex]n = 50 - n + 1[/tex]

[tex]n = 50 + 1 - n[/tex]

[tex]n = 51 - n[/tex]

The formula becomes

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]S_n = \frac{51 - n}{2}(n + 50)[/tex]

Recall that the Sum of Integers from 15 to 50 (inclusive) = Sum of integers from n to 50 (inclusive);

This implies that

Sn (i) = Sn (ii)

As such; we have

[tex]S_n = \frac{51 - n}{2}(n + 50) = 1170[/tex]

[tex]\frac{51 - n}{2}(n + 50) = 1170[/tex]

Multiply both sides by 2

[tex]2 * \frac{51 - n}{2}(n + 50) = 1170 * 2[/tex]

[tex](51 - n)(n + 50) = 1170 * 2[/tex]

[tex](51 - n)(n + 50) = 2340[/tex]

Open Brackets

[tex]51(n + 50) - n(n + 50) = 2340[/tex]

[tex]51*n + 51 * 50 - n * n - n * 50 = 2340[/tex]

[tex]51n + 2550 - n^2 - 50n = 2340[/tex]

Reorder

[tex]-n^2 + 51n - 50n + 2550 = 2340[/tex]

[tex]-n^2 + n + 2550 = 2340[/tex]

Subtract 2340 from both sides

[tex]-n^2 + n + 2550 -2340 = 2340 -2340[/tex]

[tex]-n^2 + n + 210 = 0[/tex]

Multiply both sides by -1

[tex]-1(-n^2 + n + 210) = -1 * 0[/tex]

[tex]n^2 - n - 210 = 0[/tex]

At this point, we have a quadratic equation; as such, it'd be solved as follows:

[tex]n^2 - n - 210 = 0[/tex]

Expand

[tex]n^2 + 15n - 14n - 210 = 0[/tex]

Factorize

[tex]n(n + 15) - 14(n + 15) = 0[/tex]

[tex](n - 14)(n + 15) = 0[/tex]

Split the above expression

[tex](n - 14) = 0 \ or\ (n + 15) = 0[/tex]

[tex]n - 14 = 0 \ or\ n + 15 = 0[/tex]

[tex]n = 14\ or\ n = -15[/tex]

The question states that n < 15;

This means that we'll discard the value of n = 14

Hence, n = -15

Answer:

one

Step-by-step explanation:

The maximum number of y intercepts a line can have is one

A line can only cross the y axis one time

A line can only cross the x axis one time

Otherwise it is not linear

Answer:C

Step-by-step explanation: substitute n=3 for all equations and see which equation accurately correlates to the graph for when x=3. When you do this you see that only option C is the correct equation

Answer:

C). [tex]a(n) = 7 + (n - 1) * 12[/tex]

Step-by-step explanation:

Plugin values into the equation.

Answer: $660

Step-by-step explanation:

If he saves $ 55 every month, he will have

55 x 12 = 660

Answer:

BDA is the answer

Step-by-step explanation:

Because its  90 degrees

Answer:

Angle CDA or ADC

(both work as an answer)

Step-by-step explanation:

A complementary angle is one that has a sum of 90 degrees. In the picture, you can see that the two adjacent angles add up to 90. The second angle would be CDA or ADC, in other words, the answer

Answer:

1) Side a = 9.55

2) Angle B = 51.36°

3) Angle C = 72.67°

Step-by-step explanation:

We would be solving the above questions using Law of Cosines

1) To find Side a using Law of cosines

a² = b² + c² - 2bc × Cos A

a = √(b² + c² - 2bc × Cos A)

a = unknown

b = 9

c = 11

Angle A = 56°

a = √(9² + 11² - 2 × 9 × 11 × Cos 56°

a = 9.55405

Approximately a = 9.55

2) To find Angle B

We would use the Law of Cosines as well

b² = a² + c² - 2ac × Cos B

Cos B = a² + c² - b²/2ac

B = arc cos ( a² + c² - b²/2ac)

a = 9.55

c = 11

b = 9

B = arc cos (9.55² + 11² - 9²/2 × 9.55× 11)

B = 51.36°

3) To find Angle C

We would use the Law of Cosines as well

c² = a² + b² - 2ac × Cos C

Cos C = a² + b² - c²/2ab

C= arc cos ( a² + b² - c²/2ab)

a = 9.55

b = 9

c = 11

C = arc cos (9.55² + 9² - 11²/2 × 9.55× 9)

C= 72.67°

Answer:

Slope = rise / run

= -12 / 1500 (It's -12 and not 12 because a drop means it's decreasing)

= -0.008

Answer:

110

Step-by-step explanation:

No of robberies = 125

Percentage = 100%

No of robberies = 'd'

Percentage = 12% lower than 2013 = 100% - 12%

= 88%

No of robberies in 2014 = 88% of the number of robberies in 2013

'd' = 88/100 × 125

'd' = 0.88 × 125

'd' = 110

2014 robberies = 110 in number

Answer:

[tex]B. f(x) = 5(27)^x[/tex]

Step-by-step explanation:

Well lets graph it first,

Look at the image below ↓

By looking at the image we can tell that answer choice [tex]B. f(x) = 5(27)^x[/tex].

Thus,

answer choice B is correct.

Hope this helps :)

Answer:

The correct result would be f(x) = 5(27)x.

Step-by-step explanation:

If you would like to find an equivalent function to f(x) = 5(3)^(3x), you can do this using the following steps:

f(x) = 5(3)^(3x) = 5(3^(3x)) = 5(27)^x = 5(27)x

hope this helped :)

Answer: $641.51

Step-by-step explanation:

A = p (1+ r/n)^nt

A = 500 (1 + 0.025/4)^4*10

A = 641.51

The amount in an account where $500 in invested at 2.5% is $641.51.

Using this formula

A = p (1+ r/n)^nt

Where:

A=Amount

P= Principal=$500

R=Rate=2.5% or 0.025

n=4 (Quarterly)

T=Time=10 years

Let pug in the formula

A = $500(1 + 0.025/4)^4×10

A=$500(1.28302)

A =$641.51

Inconclusion the amount in an account where $500 in invested at 2.5% is $641.51.

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Answer:8

Might I be right

Step-by-step explanation:

Answer:

1a) 15, 7, x+5

1b) 7

2a) 18, 3r

Step-by-step explanation:

1a) Since Claire is 5 years older, she will always be her cousin's age plus 5

1b) Claire is 5 years older, so Claire's cousin is 5 years younger. So, Claire's cousin is Claire's age minus 5

2a) Diego will have the amount of Han's books times 3

Answer:

Clare Questions:

Cousin: 10, Clare: 15

Cousin: 2, Clare: 7

Cousin: x, Clare: x + 5

Cousin: 7, Clare: 12

Diego Questions:

Han: 6, Diego: 18

Han: can't tell if it is a 0 or n, Diego: 0 or 3n, respectively

Step-by-step explanation:

Since Clare is older than her cousin by 5, they will both age at the same rate, thus she will always be 5 years older.

example: if her cousin is 10, Clare will be 10 + 5 years older, therefore being 15.

Since DIego has 3 times as many books than Hans, it multiplies by 3.

example: if Han has 6 books, multiply 6 by 3 and you get Diegos amount, 18.

Answer:

8.29166

Step-by-step explanation:

3.5_0.375+5.166666

Answer:

[tex]8 \frac{7}{24} [/tex]

Step-by-step explanation:

Please see attached picture for full solution.

Answer:

1 - a/variable

2 - d/statistic

3 - b/population

4 - c/data

5 - e/parameter

6 - f/sample

I did comment asking if the two you'd already selected were definitely correct, but no answer was given, so I apologise if this is wrong. This is what I would put.

Answer:

The answers are: 1 and 1.

Step-by-step explanation:

I believe they are how combinations are written. In other words:

[tex]_{n}C_{r}=(\frac{n}{r})=n!/(r!(n-r)!)[/tex] (Ignore the fraction bar, I can't really format it properly).

Anyways, simply find the combination of each:

[tex](\frac{9}{0})=9!/(0!(9-0)!)=9!/9!=1[/tex]

[tex](\frac{9}{9} )=9!/(9!(9-9)!)=9!/9!(0!)=9!/9!=1[/tex]

Note that 0! equals 1.

Answer:

Ahh

Step-by-step explanation:

Hhs

ur welcome brainliest person

Here we have a problem of transformations, particularly, horizontal dilations.

We will find that the correct option is k = 4.

We have two functions:

f(x) and g(x) = f(k*x)

We know that:

f(x) passes through the point (8, 6)

This means that:

f(8) = 6

And we know that g(x) passes through (2, 6)

this means that:

g(2) = 6

Using these two and the representation of g(x), we can see that:

g(2) = f(k2) = 6

and we knew that f(8) = 6

then

k2 = 8

k = 8/2 = 4

Then the value of k is 4.

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Answer:

k = 4

Step-by-step explanation:

i took the test and got it right just wanted to confirm th other answer cause the score isnt super good

Answer:

[tex]a_{n} = -83/40[/tex]

Step-by-step explanation:

Given

[tex]a_{n} = -2 + 3/2 (n-1)[/tex]

In this problem to find 21st term we put 21 in place of n in the equation

[tex]a_{n} = -2 + 3/2 (21-1) = \\a_{n} = -2 + 3/2 (20)\\a_{n} = -2 + 3/40 = (-2*40 +3)/40 \\a_{n} = -83/40\\[/tex]

Thus, 21st term is -83/40.

Answer:

-1/10115

Step-by-step explanation:

Let x be the rational number.

-7/85 × x = 1/17

x = 1/17 ÷ -7/85

x = 1/(17 × -7 × 85)

x = 1/(-10115)

x = -1/10115

The rational number is -1/10115.

Answer:

- 5/7

Step-by-step explanation:

-7/85*x= 1/17

x= 1/17 ÷ (-7/85)

x= - 1/17 × 85/7

x= - 5/7

Answer:

[tex]\dfrac{1}{3}[/tex].

Step-by-step explanation:

In quadrilateral QRST, Q(-1,0), R(5,0), S(3.5,-6), T(-2.5,-6).

In quadrilateral Q'R'S'T', Q'(-1,2), R'(1,2), S'(0.5,0), T'(-1.5,0).

Distance formula:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using distance formula , we get

[tex]QR=\sqrt{(5-(-1))^2+(0-0)^2}=\sqrt{6^2}=6[/tex]

[tex]Q'R'=\sqrt{(1-(-1))^2+(2-2)^2}=\sqrt{2^2}=2[/tex]

Now,  

[tex]\text{Scale factor}=\dfrac{Q'R'}{QR}[/tex]

[tex]\text{Scale factor}=\dfrac{2}{6}[/tex]

[tex]\text{Scale factor}=\dfrac{1}{3}[/tex]

Therefore the scale factor is [tex]\dfrac{1}{3}[/tex].

The given transformation of quadrilateral QRST to quadrilateral Q'R'S'T'

are a dilation and a translation, therefore,  QRST is similar to Q'R'S'T'.

[tex]\mathrm{The \ scale \ factor \ of \ the \ dilation\ between \ QRST \ and \ Q'R'S'T' \ is} \ \dfrac{1}{3}[/tex]

Reasons:

The vertices of the quadrilateral are;

Quadrilateral QRST

Q(-1, 0)

R(5, 0)

S(3.5, -6)

T(-1, 2)

Quadrilateral Q'R'S'T'

Q'(-1, 2)

R'(1, 2)

S'(0.5, 0)

T'(-1.5, 0)

The given transformation that gives quadrilateral Q'R'S'T' from quadrilateral  QRST are a dilation and a translation.

Required:

The scale factor of the dilation

Solution:

[tex]\mathrm{The \ scale \ factor \ of \ the \ dilation} = \dfrac{\mathrm{Length \ of \ \overline{Q'R'} }}{\mathrm{Length \ of \ \overline{QR}} }[/tex]

Length of [tex]\overline{Q'R'}} }[/tex] = 1 - (-1) = 2

Length of [tex]\overline{QR}} }[/tex] = 5 - (-1) = 6

Therefore;

[tex]\mathrm{The \ scale \ factor \ of \ the \ dilation} = \dfrac{2}{6} = \dfrac{1}{3}[/tex]

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Answer:

The correct option is;

Choosing 4 neighborhoods at random and poll every home in those neighborhoods

Step-by-step explanation:

Given that the survey relate to how much money people are willing to spend on on concert tickets with the goal of being practical and unbiased, we have;

Required sampling = Random Sampling

The preferable type of random sampling is either;

1) Simple random sampling

Sampling a given percentage of the homes in the area randomly

2) Clustered random sampling

Completely polling entire population of randomly selected area

Given the practicability of sampling concert goers, since people may have different interests, a better representative sample will be to perform the clustered random sampling approach by choosing 4 neighborhoods at random and poll every home in those neighborhoods.

Answer:

hope this helps you :) have a good day

Answer:

AC=2.06cm

Step-by-step explanation:

AC^2=AD^2+CD^2

AC^2=1.5^2+1.4142^2

AC^2=2.25+2=4.25

....

[tex] \sqrt{ac {}^{2} } [/tex]

=

[tex] \sqrt{4.25 = } 2.06[/tex]

Answer:

AC=2.06 cm

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

3n - 5p + 2n = 10p

Add like terms.

5n - 5p = 10p

Add 5p to both sides.

5n = 10p + 5p

5n = 15p

Divide both sides by 5.

n = 15/5p

n = 3p

The solution of expression for n is,

⇒ n = 3p

We have to given that,

An expression to solve,

⇒ 3n - 5p + 2n = 10p

Now, We can solve the expression for n as,

⇒ 3n - 5p + 2n = 10p

Combine like terms,

⇒ 3n + 2n = 10p + 5p

⇒ 5n = 15p

Divide by 5 both side,

⇒ n = 15p/5

⇒ n = 3p

Therefore, The correct option is,

D. n = 3p

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Answer:

Choices are not provided, but you can answer the question as follows: take the coordinates of quadrilateral WXYZ and apply:

W(xW, yW) -> W'(-xW, yW-2)

X(xX, yX) -> X'(-xX, yX-2)

Y(xY, yY) -> Y'(-xY, yY-2)

Z(xZ, yZ) -> Z'(-xZ, yZ-2)

For example, if point W is located at (1, 1), W' would be located at (-1, -1)

Step-by-step explanation:

Reflection over the y-axis transforms point (x, y) into (-x, y)

Translation down 2 units transforms point (x, y) into (x, y-2)

Answer:

The first choice hope this helps :)

Step-by-step explanation:

Answer:

Water a tank can hold = 14 1/2 = 29/2

Volume of bucket 1 1/4 = 5/4

The expresson can be

29/2 / 5/4

No. of buckets used = 29/2 x 4/5

Answer:

b and e

Step-by-step explanation: