Please help with this problem.
MODELING REAL LIFE A service center charges a fee of X dollars for an oil change plus y dollars per quart of oil used. Customer A receives 5 quarts of oil and pays a total of $37.45. Customer B receives 7 quarts of oil and pays a total of $46.45. Find the fee and cost per quart of oil.
___
FREE $ -
COST PER QUART OF OIL $ -

Answers

Answer 1

Answer:

The fee is $14.95

The cost per qt of oil is $4.50

Step-by-step explanation:

Let f = fee, and let q = cost of 1 qt of oil.

Customer A:

5q + f = 37.45

Customer B:

7q + f = 46.45

Rewrite the equations with the second one above the first one; then, subtract the equations.

    7q + f = 46.45

(-)  5q + f = 37.45

------------------------

    2q      = 9

Divide both sides by 2.

q = 4.5

Use the first equation:

5q + f = 37.45

Substitute 4.5 for q and solve for f.

5(4.5) + f = 37.45

22.5 + f = 37.45

Subtract 22.5 from both sides.

f = 14.95

Answer:

The fee is $14.95

The cost per qt of oil is $4.50


Related Questions

find the measures of the angles of the triangle whose vertices are a = ( − 2,0), b = (2,1), and c = (1, − 2).

Answers

So the triangle has three equal angles of 60 degrees.

To find the measures of the angles of the triangle with vertices at (-2,0), (2,1), and (1,-2), we can use trigonometry.

Let's use the following notation:

a = (-2,0)

b = (2,1)

c = (1,-2)

First, we need to find the coordinates of the midpoint of line segment AB, which is the length of the hypotenuse of the triangle.

Using the Pythagorean theorem, we have:

[tex]c^2 = a^2 + b^2\\1^2 + (-2)^2 = 2^2 + 1^2[/tex]

25 = 4 + 1

23 = 3

So the length of the hypotenuse is 3 units.

Next, we need to find the coordinates of the midpoint of line segment BC, which is the length of one of the legs of the triangle.

Again, using the Pythagorean theorem, we have:

[tex]b^2 = a^2 + c^2\\1^2 + (-2)^2 = 2^2 + 1^2[/tex]

25 = 4 + 1

23 = 3

So the length of the leg of the triangle is 3 units.

Now, we can use the law of cosines to find the measures of the angles of the triangle.

Let's denote the angle between lines AB and BC as alpha, the angle between lines AB and AC as beta, and the angle between lines BC and AC as gamma.

Using the law of cosines, we have:

[tex]cos(alpha) = (b^2 + c^2 - a^2) / (2bc)\\cos(beta) = (a^2 + c^2 - b^2) / (2ac)\\cos(gamma) = (a^2 + b^2 - c^2) / (2ab)[/tex]

We know that:

a = (-2,0)

b = (2,1)

c = (1,-2)

So we can substitute these values into the above equations:

[tex]cos(alpha) = (2^2 + (-2)^2 - (-2)^2) / (2(-2)1) = (2 + (-2) + 2) / (2(-2)1) = 4 / 3\\cos(beta) = ((-2)^2 + 2^2 - (-2)^2) / (2(-2)2) = (-2 + 4 + 2) / (2(-2)2) = -1\\cos(gamma) = (2^2 + 1^2 - 1^2) / (2(1)(-2)) = 2 + (-1) + (-1) / (2(1)(-2)) = 1[/tex]

Now we can substitute these values into the Pythagorean theorem to find the length of the legs of the triangle:

sin(alpha) = length of leg 1 / (2bc)

sin(beta) = length of leg 2 / (2ac)

sin(gamma) = length of leg 2 / (2ab)

We know that:

a = (-2,0)

b = (2,1)

c = (1,-2)

So we can substitute these values into the above equations:

sin(alpha) = √(8) / (2(-2)1)

= √(8) / √(3)

= √(2)

sin(beta) = √(5) / (2(1)2)

= √(5) / √(3)

= √(2)

sin(gamma) = √(5) / (2(1)(-2))

= √(5) / 1

= √(5)

Therefore, the measures of the angles of the triangle are:

alpha = 60 degrees

beta = 60 degrees

gamma = 60 degrees

So the triangle has three equal angles of 60 degrees.  

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Please help me with this problem

Answers

The answer to your question is (x-7)^2+(y+2)^2=10

find a matrix p that orthogonally diagonalizes a, and determine p − 1ap. a=[4 1 1 4]

Answers

The matrix P that orthogonally diagonalizes A is obtained by finding the eigenvalues and eigenvectors of A, normalizing the eigenvectors, and using them as columns of P.

First, we find the eigenvalues and eigenvectors of A:

|4-λ 1| (4-λ)(λ-1) - 1 = 0 → λ1 = 5, λ2 = 3

|1 4-λ|

For λ1 = 5, we get the eigenvector (1,1)/√2, and for λ2 = 3, we get the eigenvector (1,-1)/√2.

Thus, P = [ (1/√2) (1/√2); (1/√2) (-1/√2) ].

Then, P^-1AP = D, where D is the diagonal matrix of the eigenvalues of A.

P^-1 = P^T (since P is orthogonal), so we have:

P^-1AP = P^TAP = [ (1/√2) (1/√2); (1/√2) (-1/√2) ] [ 4 1; 1 4 ] [ (1/√2) (1/√2); (1/√2) (-1/√2) ] = [ 5 0; 0 3 ]

Therefore, the matrix P that orthogonally diagonalizes A is [ (1/√2) (1/√2); (1/√2) (-1/√2) ], and P^-1AP = [ 5 0; 0 3 ].

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Given the following exponential function, identify whether the change represents
growth or decay, and determine the percentage rate of increase or decrease.
y = 990(0.95)

Answers

The exponential function y = 990(0.95) represents exponential decay with a 5% decrease per unit increase in x.

The given exponential function is y = 990(0.95). To determine whether it represents growth or decay, we need to examine the base of the exponent, which is 0.95 in this case.

When the base of an exponential function is between 0 and 1, such as 0.95, it represents exponential decay. This means that as x increases, the corresponding y-values decrease exponentially.

To calculate the percentage rate of decrease, we can compare the base (0.95) to 1. A decrease from 1 to 0.95 represents a difference of 0.05. To convert this difference into a percentage, we multiply by 100.

Percentage rate of decrease = 0.05 * 100 = 5%

Therefore, the given exponential function y = 990(0.95) represents exponential decay with a rate of 5% decrease per unit increase in x. This implies that for each unit increase in x, the y-value will decrease by 5% of its previous value.

It's important to note that the rate of decrease remains constant throughout the function. As x increases, the value of y will continue to decrease by 5% with each unit increase.

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find the taylor series for f(x) centered at the given value of a. f(x) = 10 x - 4 x^3 text(, ) a=-2

Answers

The taylor series for f(x) centered at the given value of a. f(x) = 10 x - 4 x^3 text(, ) a=-2 is:
f(x) = -56 + 34(x+2) + 12(x+2)^2 - 4(x+2)^3/3 + ...



The Taylor series for f(x) centered at a=-2 is:

f(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)*(x-a)^3/3! + ...

Plugging in the given function and the value of a:

f(-2) = 10(-2) - 4(-2)^3 = -56

f'(-2) = 10 - 4(3)(-2)^2 = 34

f''(-2) = -4(6)(-2) = 48

f'''(-2) = -4(6) = -24

Thus, the Taylor series for f(x) centered at a=-2 is:

f(x) = -56 + 34(x+2) + 24(x+2)^2/2! - 24(x+2)^3/3! + ...

Simplifying:

Therefore the final equation is:
f(x) = -56 + 34(x+2) + 12(x+2)^2 - 4(x+2)^3/3 + ...

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Please Help Me On This one! Tsym! if you do I really do appreciate help!

Answers

Answer:

15

Step-by-step explanation:

Since the angles are complementary, that means that when the angles are added together, they are equal to 90*. With this information, we can make the equation: x + (3x + 30) = 90

From this we can add like terms and get 4x + 30 = 90

After this, subtract 30 from both sides: 4x = 60

Divide both sides by 4

x = 15

(Ignore the degree sign in my picture, sorry!)

Solve the system of equations. − 5 � + 2 � = 9 � = 7 � ​ −5x+2y=9 y=7x ​

Answers

To solve the system of equations:

Equation 1: -5x + 2y = 9
Equation 2: y = 7x

We can substitute the value of y from Equation 2 into Equation 1 to eliminate y and solve for x:

-5x + 2(7x) = 9
-5x + 14x = 9
9x = 9
x = 1

Now that we have the value of x, we can substitute it back into Equation 2 to find y:

y = 7(1)
y = 7

Therefore, the solution to the system of equations is x = 1 and y = 7.

5x2-17/2x+3/2=0 please help

Answers

Answer:

x= 3/2

x= 1/5

Step-by-step explanation:

The annual per capita consumption of milk is 21. 6 gallons. Being from the Midwest, you believe milk consumption is higher and wish to support your opinion. A sample of 16 individuals from the midwestern town of Webster City showed a sample mean annual consumption of 24. 1 gallons with a standard deviation of 4. 8. A. Develop a hypothesis test that can be used to determine whether the mean annual consumption in Webster City is higher than the national mean. B. What is a point estimate of the difference between mean annual consumption in Webster City and the national mean?c. At α = 0. 05, test for a significant difference. What is your conclusion?

Answers

a) Null Hypothesis is μ ≤ 21.6 and Alternative Hypothesis is μ > 21.6.

b) Point estimate of the difference between mean annual consumption in Webster City and the national mean is 2.5.

c) We can conclude that there is sufficient evidence to suggest that the mean annual consumption of milk in Webster City is higher than the national mean.

A. The hypothesis test to determine whether the mean annual consumption in Webster City is higher than the national mean can be set up as follows:

Null Hypothesis: μ ≤ 21.6

Alternative Hypothesis: μ > 21.6

where μ is the true population mean annual consumption of milk in Webster City.

B. The point estimate of the difference between mean annual consumption in Webster City and the national mean is simply the difference between the sample mean and the national mean:

Point Estimate = x' - μ = 24.1 - 21.6 = 2.5

C. To test for a significant difference at α = 0.05, we need to calculate the test statistic and compare it to the critical value.

t = (x' - μ) / (s / √n) = (24.1 - 21.6) / (4.8 / √16) = 2.083

Using a t-table with 15 degrees of freedom and a significance level of 0.05, we find the critical value to be 1.753. Since our test statistic (2.083) is greater than the critical value (1.753), we reject the null hypothesis.

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Find the appropriate values of n1 and n2​ (assume n1equalsn2​) needed to estimate ​(mu1minusmu2​) with each of the following. a. A sampling error equal to 3.6 with​ 95% confidence. From prior experience it is known that sigma1almost equals13 and sigma2almost equals22. b. A sampling error equal to 6 with​ 99% confidence. The range of each population is 60. c. A​ 90% confidence interval of width 1.3.

Answers

To estimate (mu1 - mu2) with a sampling error of 3.6 and 95% confidence, n1 and n2 should be determined based on the known standard deviations (sigma1 = 13, sigma2 = 22), to estimate (mu1 - mu2) with a sampling error of 6 and 99% confidence, n1 and n2 should be determined based on the range of each population (60 and to achieve a 90% confidence interval of width 1.3, the appropriate values of n1 and n2 need to be calculated.

a) To estimate (mu1 - mu2) with a sampling error of 3.6 and 95% confidence, we can use the formula:

\[ n = \left(\frac{{Z * \sqrt{{\sigma_1^2 + \sigma_2^2}}}}{{E}}\right)^2 \]

where Z is the Z-score corresponding to the desired confidence level (95% corresponds to Z = 1.96), sigma1 and sigma2 are the known standard deviations (sigma1 = 13, sigma2 = 22), and E is the desired sampling error (E = 3.6).

By plugging in the values, we get:

\[ n = \left(\frac{{1.96 * \sqrt{{13^2 + 22^2}}}}{{3.6}}\right)^2 \]

Simplifying this expression will give us the appropriate value for n1 and n2.

b) To estimate (mu1 - mu2) with a sampling error of 6 and 99% confidence, we can use the formula:

\[ n = \left(\frac{{Z * R}}{{2 * E}}\right)^2 \]

where Z is the Z-score corresponding to the desired confidence level (99% corresponds to Z = 2.58), R is the range of each population (R = 60), and E is the desired sampling error (E = 6).

By substituting the values, we get:

\[ n = \left(\frac{{2.58 * 60}}{{2 * 6}}\right)^2 \]

Simplifying this expression will give us the appropriate value for n1 and n2.

c) To achieve a 90% confidence interval of width 1.3, we can use the formula:

\[ n = \left(\frac{{Z * \sigma}}{{E}}\right)^2 \]

where Z is the Z-score corresponding to the desired confidence level (90% corresponds to Z = 1.645), sigma is the unknown standard deviation, and E is the desired interval width (E = 1.3).

Since the standard deviation (sigma) is unknown, we don't have enough information to calculate the appropriate values for n1 and n2.

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find the general solution of the given differential equation. y'' − y' − 2y = −6t 4t2

Answers

The general solution of the given differential equation is y(t) = [tex]c_1 e^{2t} + c_2 e^{-t} -2t^2 + 6t -5[/tex]

We first solve the associated homogeneous equation y'' − y' − 2y = −8t + 4t² to find the general solution of the given differential equation y'' − y' − 2y = 0.

The characteristic equation is r² - r - 2 = 0, which factors as (r - 2)(r + 1) = 0. Therefore, the roots are r = 2 and r = -1.

The general solution of the associated homogeneous equation is y_h(t) = [tex]c_1 e^{2t} + c_2 e^{-t}[/tex], where c_1 and c_2 are constants.

To find a particular solution of the given non-homogeneous equation, we use the method of undetermined coefficients. Since the right-hand side of the equation is a polynomial of degree 2, we assume a particular solution of the form y_p(t) = At² + Bt + C. Substituting this into the differential equation, we get:

2A - 2A t - 2At² - B - 2Bt - 2C = -8t + 4t²

2A -B -2C - (2A + 2B)t -2At²= -8t + 4t²

Equating coefficients of like terms, we get:

2A -B -2C = 0

- (2A + 2B) = -8

-2A = 4

Therefore, A = -2, B = 6, and C = -5. Thus, a particular solution of the given non-homogeneous equation is y_p(t) = -2t² + 6t -5.

The general solution of the given differential equation is the sum of the general solution of the associated homogeneous equation and a particular solution of the non-homogeneous equation. Therefore, the general solution is:

y(t) = y_h(t) + y_p(t)

= [tex]c_1 e^{2t} + c_2 e^{-t} -2t^2 + 6t -5[/tex]

where c_1 and c_2 are constants.

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in the book the giver, birth mothers are allowed to have only 3 babies. when they have twins one of released. how can the problem be solved in a different way

Answers

One possible solution could be to allow birth mothers to have as many children as they want, but enforce strict population control measures on the entire community to ensure resources are not depleted.

The practice of releasing one twin in The Giver is a harsh and unjust method of population control. In a hypothetical scenario where population growth is a concern, there are more humane and effective ways to address it. For instance, the community could implement measures such as providing incentives for small families, investing in education and healthcare to reduce infant mortality rates, and promoting family planning. Additionally, the community could implement policies to encourage sustainable resource use and reduce waste, such as recycling and renewable energy initiatives. By taking a comprehensive and sustainable approach to population control, the community can ensure a better future for all its members, without resorting to cruel and arbitrary methods like releasing babies.

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Find the point at which the line with parametric equations I = 1+ 21, y = 4t and z = 2 - 3t intersects the plane 2 + 2y – z + 1 = 0.Previous question

Answers

The point of intersection is (17/9, -4/9, 29/9). The process of finding the point of intersection between a line and a plane involves substituting the parametric equations of the line into the equation of the plane.

To find the point of intersection between the line and plane, we need to substitute the parametric equations of the line into the equation of the plane. This gives us:
2 + 2(4t) - (2 - 3t) + 1 = 0
Simplifying, we get:
9t + 1 = 0
Therefore, t = -1/9. We can substitute this value of t into the parametric equations of the line to find the coordinates of the point of intersection:
x = 1 + 2(-1/9) = 17/9
y = 4(-1/9) = -4/9
z = 2 - 3(-1/9) = 29/9
So the point of intersection is (17/9, -4/9, 29/9). The process of finding the point of intersection between a line and a plane involves substituting the parametric equations of the line into the equation of the plane. This allows us to solve for the value of the parameter that corresponds to the point of intersection. Once we have this value, we can substitute it back into the parametric equations of the line to find the coordinates of the point. It is important to note that not all lines intersect with all planes, and some may intersect at multiple points or not intersect at all. Therefore, it is important to carefully analyze the equations and properties of both the line and plane before attempting to find their point of intersection.

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33% of the population has 20/20 vision. if 70 individuals are selected at random from the population, what is the mean number who will have 20/20 vision?

Answers

The mean number of individuals with 20/20 vision is 23.

To find the mean number of individuals with 20/20 vision, we can use the formula for the expected value of a binomial distribution. In this case, the probability of an individual having 20/20 vision is p = 0.33, and the number of trials (i.e. individuals selected) is n = 70.
The formula for the expected value of a binomial distribution is:
E(X) = np
Substituting in our values, we get:
E(X) = 70 x 0.33
E(X) = 23.1
So, the mean number of individuals with 20/20 vision out of 70 selected at random from the population is approximately 23.1. However, since we can't have a fraction of a person, we should round our answer to the nearest whole number.
Therefore, the mean number of individuals with 20/20 vision is 23.

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what is the slope of the line tangent to the polar curve r = 2θ2 when θ = π

Answers

The slope of the line tangent to the polar curve r = 2θ² when θ = π is 4π.

How we find the slope of the line tangent?

To find the slope of the line tangent to the polar curve r = 2θ² at θ = π, we need to find the derivative of r with respect to θ, and then evaluate it at θ = π.

Differentiating r = 2θ² with respect to θ, we get:

dr/dθ = 4θ

Evaluating this expression at θ = π, we get:

dr/dθ = 4π

This is the slope of the tangent line to the polar curve r = 2θ² at the point where θ = π.

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pls hurry. 2. Which step is the first incorrect step in the solution shown below?

Answers

Answer:

step 1

Step-by-step explanation:

Step 1: they accidentally changed the 20 in the original prob to 2.

Answer:

step 1

Step-by-step explanation:

they wrote 2x+6=3x+2 but they wrote 2 instead of 20

it should have been 2x+6=3x+20

12 A quantity of 20c and 50c coins has a total value of $54. There are twice as many 20c coins as 50c coins. How many 20c coins are there?

Answers

120

Step-by-step explanation:

turning $54 to cents

$1= 100c

$54=54×100= 5400

calling the number of 20c coins a and 50c coins b

20a + 50b= 5400 ...equ(1)

since there are twice as many 20c coins as 50c coins

a=2b ...equ(2)

substituting a=2b in equ(1)

20(2b) + 50b = 5400

40b + 50b = 5400

90b = 5400

dividing both sides by 90

b= 60

to get the number of 20c coins I'm substituting b=60 in equ(2)

a= 2×60

a=120

therefore the number of 20c coins is 120

Find the cos of angle c and tangent of angle c round answer up two decimal places

Answers

The cosine of angle C is 7/25 and using tangent, the value of C is 73.7°

What is trigonometric ratio?

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

sinθ = opp/ hyp

cos θ = adj/ hyp

tan θ = opp/adj

The value of cosine of C is

cos C = adj/hyp

= 7/25

therefore the value of cos C is 7/25

to find the value of C

Tan C = 24/7

TanC = 3.43

C = tan^-1 ( 3.43)

C = 73.7°

Therefore the value of C is 73.7°

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A student randomly selected 65 vehicles in the student parking lot and noted the color of each. She found that 9 were black, 10 were blue, 13 were brown, 7 were green, 12 were red, and 14 were a variety of other colors. What is P(not blue)?

Answers

Answer:

p(not blue) = 11/13 = 0.8461538462 = approx 0.85 = approx 85%

Step-by-step explanation:

65-10 = 55 are not blue, so 55 out of 65 cars are not blue.

p(not blue) = 55/65 = 11/13 = 0.8461538462 = approx 0.85 = approx 85%

When a group of individuals selects a particular consumer-submitted entry, it is called a:SamplePremiumContestSweepstake

Answers

A contest is a type of promotional marketing strategy that requires participants to submit their entries based on specific criteria or requirements. The correct answer to your question is "contest."

A long answer to your question is that when a group of individuals selects a particular consumer-submitted entry, it is called a contest.

The entries are then judged by a panel or group of individuals who select the best or most appropriate entry.

The winner of the contest may receive a prize or premium, such as cash, gift cards, or products.

Unlike a sweepstake, which randomly selects a winner, a contest is based on merit or creativity and involves a selection process.

Therefore, the correct answer to your question is "contest."

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please answer with solution

a.4/5

b.5/4

c.-4/5

d. -5/4​

Answers

Answer: 5/4

Step-by-step explanation:

Ah yes terminal angles. I love these. Here's a formula to solve these.

With point P(x,y) and value r where r = square-root of x square + y square, we have:

Sin = y/r

Cos = x/r

Tan = y/x

Csc = r/y

Sec = r/x

Cot = x/y

so tan = y/x. here y = 5 and x = 4 so the answer is 5/4

Answer:

b. 5/4

Step-by-step explanation:

Without knowing the exact angle C, we cannot determine the value of tan θ.

However, we can use the coordinates of point P to determine the ratio of the opposite side to the adjacent side (which is equal to the value of tan θ).

Recall that in the coordinate plane, the x-coordinate represents the adjacent side and the y-coordinate represents the opposite side.

Therefore, in this case:

adjacent side = 4

opposite side = 5

tan θ = opposite/adjacent = 5/4

So, tan θ = 1.25.

1.25 = 5/4

If S = {a,b,c) with P(a) = 2P(b) = 4P(c), find P(a).

Answers

The probability of event a, P(a), is 4/7 for the given sample set.

To find P(a), we need to use the given information about the probabilities and the fact that the total probability of all outcomes in a sample space S is equal to 1. We have:
S = {a, b, c}
P(a) = 2P(b) = 4P(c)

First, we can express P(b) and P(c) in terms of P(a):
P(b) = P(a) / 2
P(c) = P(a) / 4

Now we use the fact that the sum of probabilities of all outcomes in S equals 1:
P(a) + P(b) + P(c) = 1

Substitute P(b) and P(c) with their expressions in terms of P(a):
P(a) + (P(a) / 2) + (P(a) / 4) = 1

To solve for P(a), combine the terms:
P(a) * (1 + 1/2 + 1/4) = 1
P(a) * (4/4 + 2/4 + 1/4) = 1
P(a) * (7/4) = 1

Now, divide both sides by (7/4) to isolate P(a):
P(a) = 1 / (7/4)
P(a) = 4/7

So, the probability of event a, P(a), is 4/7.


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Simplify the expression and then put your answer in scientific notation. (8. 2 x 107 7 ) - (4. 1 x 106 6 )

Answers

The expression in the scientific notation will be 7.79 × [tex]10^{7}[/tex] .

Simplifying 8.2 × [tex]10^{7}[/tex] - 4.1 × [tex]10^{6}[/tex]

To simplify the equation power should be same

To convert to decrease power the decimal will move to the right

It can be written as

8.2 × [tex]10^{7}[/tex] = 82.0 × [tex]10^{6}[/tex]

Now solving the equation

82.0 × [tex]10^{6}[/tex] - 4.1 × [tex]10^{6}[/tex]

= 77.9 × [tex]10^{6}[/tex]

To convert the equation into scientific notation

The decimal should be after one significant figure

To convert to increase power the decimal will move to the left

It can be written as

7.79  × [tex]10^{7}[/tex]

Simplifying the equation will give 7.79 × [tex]10^{7}[/tex] .

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in problems 1–8, classify the equation as separable, linear, exact, or none of these. notice that some equations may have more than one classification. 1. 1x2 y x4 cos x2 dx - x3 dy = 0

Answers

The given equation dy/dx - (1/x)y = (xcosx)/x³ is linear with y as the dependent variable.

Given differential equation is (x²y+x⁴ cosx)dx -x³dy = 0

The given equation can indeed be classified as linear with y as the dependent variable.

A linear equation with respect to the dependent variable y is of the form:

dy/dx + P(x)y = Q(x),

where P(x) and Q(x) are functions of x. In this case, we have:

(x²y + x⁴cosx)dx - x³dy = 0.

By rearranging the terms, we can write it as:

x²ydx - x³dy + x⁴cosxdx = 0.

Now, we can rewrite the equation in the form:

dy/dx + (-x²/x³)y = x⁴cosx/x³.

Simplifying further, we get:

dy/dx - (1/x)y = (xcosx)/x³.

As you can see, the equation is in the form of a linear equation with respect to y. The coefficient of y, (-1/x), is a function of x, while the right-hand side (RHS) is also a function of x. Therefore, the given equation is linear with y as the dependent variable.

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Please please help please please

Answers

Answer:

G(9, -5)

Step-by-step explanation:

Point G is not shown in the figure, but I assume point G is on the bottom side of the square, directly below point F.

We are told each side of the square is 8 units long.

Starting at point E, to get to point G, go 8 units right and 8 units down.

Start at E(1, 3).

Then go 8 units right to point F(9, 3).

Now go 8 units down to point G(9, -5).

suppose y is exp(1). conditionally on y=y, let x is exp(y) find the joint probability

Answers

The joint probability of x and y, given y=y and x follows an exponential distribution with parameter y, is:

P(x=x, y=y) = e^(-x-y) / y

To find the joint probability of x and y, we can use the conditional probability formula:
P(x=x, y=y) = P(x=x | y=y) * P(y=y)

Since we know that y follows an exponential distribution with parameter 1, we can write:
P(y=y) = f(y) = e^(-y)

Now, to find the conditional probability of x given y, we can use the probability density function of the exponential distribution:
f(x | y=y) = λ * e^(-λ*x)

where λ = 1/y, since y is the parameter of the exponential distribution.

Therefore,
P(x=x | y=y) = (1/y) * e^(-x/y)

Combining these equations, we get:
P(x=x, y=y) = (1/y) * e^(-x/y) * e^(-y)

Simplifying this expression, we get:
P(x=x, y=y) = e^(-x-y) / y

So the joint probability of x and y, given y=y and x follows an exponential distribution with parameter y, is:

P(x=x, y=y) = e^(-x-y) / y

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someone please help me!!

Answers

Answer:

See below

Step-by-step explanation:

Slope-intercept form of an equation of line:

[tex]y = mx + c[/tex]  —— eq(i)

Where:

c = y-intercept

  = y-value for which the corresponding x-value is 0

  = [tex]-1[/tex] (From the provided table)

m = slope
   = [tex]\frac{rise}{run}[/tex]

   = [tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex] —- eq(ii)

Choose any two sets of coordinates and then substitute in eq(ii). I chose:

[tex](3, 8)[/tex] as [tex](x_{1}, y_{1})[/tex]

[tex](4, 11)[/tex] as [tex](x_{2}, y_{2})[/tex]

   = [tex]\frac{11 - 8}{4 - 3}[/tex]

   = [tex]\frac{3}{1}[/tex]

m = [tex]3[/tex]

Substituting the values of c and m in eq(i):

[tex]y = (3)x + (-1)[/tex]

Equation for the function

[tex]y = 3x - 1[/tex]

Problem 3. A shoe store sells a new type of basketball shoe. The table shows the pairs sold s over time f
(in weeks).
Week (t)
Pairs sold (s)
1
5
32
3.1 Write a function that models the pairs sold s over time t.
Model:
5
48
3.2 Estimate the number of pairs of shoes sold after 6 weeks.
ANSWER:
7
58
65

Answers

3.1 The function that models the pairs sold (s) over time (t) is:

[tex]s(t) = -3t^2 + 6t + 2.[/tex]

3.2 The estimated number of pairs of shoes sold after 6 weeks is -70.

3.1 To write a function that models the pairs sold (s) over time (t), we can use the given data points to find the pattern or relationship between the weeks (t) and the pairs sold (s).

From the table:

Week (t) Pairs sold (s)

1 5

3 2

5 48

By observing the data, we can see that the pairs sold (s) increases by a certain amount after each week. Let's calculate the difference between consecutive pairs sold:

Difference between pairs sold at week 3 and week 1: 2 - 5 = -3

Difference between pairs sold at week 5 and week 3: 48 - 2 = 46

We notice that the difference is not constant, which suggests a nonlinear relationship. To model this, we can use a quadratic function.

Let's assume the function is of the form s(t) = at^2 + bt + c, where a, b, and c are constants to be determined.

Substituting the given data point (t, s) = (1, 5) into the function, we get:

[tex]5 = a(1)^2 + b(1) + c[/tex]

5 = a + b + c (Equation 1)

Substituting the data point (t, s) = (3, 2) into the function, we get:

[tex]2 = a(3)^2 + b(3) + c[/tex]

2 = 9a + 3b + c (Equation 2)

Substituting the data point (t, s) = (5, 48) into the function, we get:

[tex]48 = a(5)^2 + b(5) + c[/tex]

48 = 25a + 5b + c (Equation 3)

Now we have a system of three equations (Equations 1, 2, and 3) that we can solve to find the values of a, b, and c.

Solving the system of equations, we find:

a = -3

b = 6

c = 2

Therefore, the function that models the pairs sold (s) over time (t) is:

[tex]s(t) = -3t^2 + 6t + 2.[/tex]

3.2 To estimate the number of pairs of shoes sold after 6 weeks, we can substitute t = 6 into the function [tex]s(t) = -3t^2 + 6t + 2.[/tex]

[tex]s(6) = -3(6)^2 + 6(6) + 2[/tex]

s(6) = -3(36) + 36 + 2

s(6) = -108 + 36 + 2

s(6) = -70

Therefore, the estimated number of pairs of shoes sold after 6 weeks is -70.

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draw the graph of a function
[tex]y = x^{2} + 2x - 5[/tex]

Answers

The graph of the function y = x^2 + 2x - 5 is a U-shaped curve opening upwards, with the vertex at (-1, -4).

To graph the function y = x^2 + 2x - 5, we can follow a few steps to plot the points and sketch the curve.

Step 1: Determine the vertex of the parabola.

The vertex of the parabola occurs at the minimum or maximum point. We can find the x-coordinate of the vertex by using the formula x = -b/2a, where a, b, and c are coefficients of the quadratic equation in standard form (ax^2 + bx + c = 0).

For our function, a = 1, b = 2, and c = -5.

Plugging these values into the formula, we get x = -2/2(1) = -1.

To find the y-coordinate of the vertex, we substitute the x-coordinate back into the function: y = (-1)^2 + 2(-1) - 5 = -4.

Therefore, the vertex is at (-1, -4).

Step 2: Find additional points.

To plot more points, we can choose some x-values and calculate the corresponding y-values using the function. Let's select x-values of -3, 0, and 2.

For x = -3, y = (-3)^2 + 2(-3) - 5 = 9 - 6 - 5 = -2.

For x = 0, y = (0)^2 + 2(0) - 5 = 0 + 0 - 5 = -5.

For x = 2, y = (2)^2 + 2(2) - 5 = 4 + 4 - 5 = 3.

Step 3: Plot the points and sketch the curve.

Plot the points (-3, -2), (0, -5), (2, 3), and the vertex (-1, -4) on a coordinate plane.

The vertex (-1, -4) is the lowest point, so the parabola opens upwards.

Connect the points with a smooth curve, following the shape of a parabola.

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scale 1:100
If the length of the whale on the picture is 250 cm find the actual length of the whale in meters.​

Answers

1:100
250:x

Scale factor= 250

100x250= 25000cm

25000cm= 250m
Scale 1:100

Whale in the picture = 250cm, so

Actual whale = 250cm x 100 = 2500cm or 25 meters
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