Answer:
The answer is B)
[tex]y = - \frac{1}{2}x + 8[/tex]
Answer:
B. y = -[tex]\frac{1}{2}[/tex]x + 8
Step-by-step explanation:
The line is perpendicular to line whose equation is:
y = 2x + 4 and;
passes through point (4,6) .
The product slopes of two perpendicular lines is -1.
The slope of the line whose equation is y = 2x + 4 is; 2
Let the slope of the perpendicular line (l2) be [tex]m_{l2}[/tex]
[tex]m_{l2} * 2 = -1[/tex]
[tex]m_{l2}[/tex] = [tex]-\frac{1}{2}[/tex]
Taking another point xy on line l2;
[tex]\frac{y - 6}{x - 4} = -\frac{1}{2}[/tex]
Cross multiplying this gives;
y = -[tex]\frac{1}{2}[/tex]x + 8 which is the equation of the perpendicular line!
b - 8 = 9
---------------
Answer:
b-8=9
b=9+8
b=17
Step-by-step explanation:
hope it will help you mark me as a brilliant.
Answer:
b=17
Step-by-step explanation:
b-8=9
first isolate the variable by adding 8 to both sides
this gives us
b=17
calculate with reasons, the size of the unknown indicated angles
pls help !!
Answer:
x+125+25=180 angles of triangle
x=180-150
x=30
Find the greatest common factor for each of the following expressions, then factor each expression. a. 4p – 4 = ? b. x4 + x3 + x2 = ? c. 8p2 + 9p2q = ? d. x2y2 + 3xy – 4x – 2x4y3 = ? Factor each of the following expressions. a. 4a3 + 28a2 + 4a + 28 = ? b. x3 + 3x2− 2x − 6 = ? c. 8x2− 4xy + 2x − y = ? Factor each of the following, using the difference of perfect squares where possible. a. u2 – 100 = ? b. 4a2 − 49 = ? c. 81 − y2= ? d. 16q4− 16 = ? e. 9c3− 9c = ? f. 48a2b − 12b = ?
Answer:
1. a. Greatest common factor: 4
b. Greatest common factor: x2
c. Greatest common factor: p2
d. Greatest common factor: x
2. a. (a2 + 1)(4a + 28)
b. (x + 3)(x2− 2)
c. (4x+ 1)(2x−y)
3. a. u2 – 100 = (u + 10)(u − 10)
b. 4a2 − 49 = (2a + 7)(2a − 7)
c. 81 − y2= (9 + y)(9 − y)
d. 16q4− 16 = 16(q4 − 1) 16 (q4 −1) = 16(q2 + 1) (q2− 1) = 16(q2 + 1) (q + 1) (q − 1)
e. 9c3− 9c = 9c (c2− 1) = 9c(c + 1)(c − 1)
f. 48a2b − 12b = 12b (4a2− 1) = 12b(2a + 1)(2a − 1)
Step-by-step explanation:
I got it at PennFoster
help me with the question of o.math
Answer:
A= 5 8 11
7 10 13
11 14 17
x=3 y=2 z=-1 w=1/2
Step-by-step explanation:
Let matrix A= a11 12 13
a21 a22 a23
a31 a32 a33
aij=2^i+3j
When i=1 and j=1,
aij=2^1+3*1=2+3=5
Solve for all the elements and you'll get,
A= 5 8 11
7 10 13
11 14 17
For no 7,
x+y 0 = 5 2w-1
1 x-y z+2 1
Equating,
x+y =5 z+2=1 2w-1=0 x-y=1
x=5-y z=-1 w=1/2 From 1st 5-y-y=1 -2y=-4 y=2
x=5-2(from last)
x=3
Harold used 6 centimeters of tape to wrap 3 presents. What is the unit rate?
Answer:
2cm/present is the unit rate
[tex]\huge\text{Hey there!}[/tex]
[tex]\huge\text{Harold used \underline{\underline{6 centimeters of tape}} to wrap}\\\huge\text{\underline{\underline{3 presents}}. \underline{\underline{\underline{What is the unit rate?}}}}[/tex]
[tex]\huge\boxed{\star \ Formula: \mathsf{\dfrac{a}{b}= unit\ rate \ }\star}[/tex]
[tex]\huge\boxed{\mathsf{Equation\boxed{\rightarrow}\ \dfrac{6}{3} = \boxed{unit\ rate}}}[/tex]
[tex]\huge\boxed{\mathsf{\dfrac{6}{3} = \boxed{\bf unit\ rate}}}\\\\\\\huge\boxed{\mathsf{ 6 \ \boxed{\div} \ 3\ \boxed{= } \ \bf\boxed{\bf unit\ rate}}}\\\\\\\\\huge\boxed{\boxed{=} \bf \ 2}[/tex]
[tex]\huge\boxed{\star\ \textsf{Therefore, the UNIT RATE IS: \bf \boxed{\bf 2}}\ \star}[/tex]
[tex]\boxed{\boxed{\huge\text{Answer: the unit rate is \bf \boxed{\underline{\underline{\underline{\underline{\bf 2}}}}}}}}\huge\checkmark\\\\\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\\\\\huge\boxed{\frak{Amphitrite1040:)}}[/tex]
The standard normal curve shown below models the population distribution of a random variable. What proportion of the values in the population does not lie between the two z-scores indicated on the diagram? z = -1.2 z = 0.85
Answer:
31.28%
Step-by-step explanation:
The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the raw score is above the mean then the z score is positive while if the raw score is below the mean then the z score is negative. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Given the z score z = -1.2 z = 0.85. From the normally distribution table, the probability that a value falls between z = -1.2 and z = 0.85 = P(z < 0.85) - P(z < -1.2) = 0.8023 - 0.1151 = 0.6872
The proportion of values that do not fall between z = -1.2 and z = 0.85 = 1 - 0.6872 = 0.3128 = 31.28%
-5x-10=10 solve for x
Answer:
x = -4
Step-by-step explanation:
-5x-10=10
Add 10 to each side
-5x-10+10=10+10
-5x = 20
Divide each side by -5
-5x/-5 = 20/-5
x = -4
Answer: x= -4
Step-by-step explanation:
[tex]-5x-10=10[/tex]
add 10 on both sides
[tex]-5x=20[/tex]
divide -5 on both sides
[tex]20/-5=-4[/tex]
[tex]x=-4[/tex]
Take away 3 from 8 times K
Answer:
8×k-3
Step-by-step explanation:
that would be the equation (:
Answer:
8k - 3 is the answer because they are not like terms.
(10 PTS) How do I solve for this? Please show work
Answer:
4
Step-by-step explanation:
8 ^ 2/3
Rewriting 8 as 2^3
( 2^3) ^ 2/3
We know that a^ b^c = a^ (b*c)
2 ^ ( 3 * 2/3)
2 ^ 2
4
what is the cost of paving a driveway that is 18m long and 4 m wide, if the paving costs $35 per square metre?
Answer:
$2520
Step-by-step explanation:
→ Work out the area of the drive way
18 m × 4 m= 72 m²
→ Multiply the area by the cost per square metre
72 m² × $35 = $2520
The cost of paving a driveway that is 18m long and 4 m wide, if the paving costs $35 per square metre is $2520.
To calculate the cost of paving the driveway, you need to find the total area of the driveway and then multiply it by the cost per square meter.
The total area of the driveway can be calculated using the formula:
Area = length × width.
Given that the driveway is 18 meters long and 4 meters wide, the area would be:
Area = 18m × 4m
Area = 72 square meters.
Now, find the cost of paving the driveway by multiplying the area by the cost per square meter:
Cost = Area × Cost per square meter
Cost = 72 square meters × $35/square meter
Cost = $2520.
So, the cost of paying the driveway would be $2520.
To learn more on Area click:
https://brainly.com/question/20693059
#SPJ4
Kelly goes to the mall and buys a shirt for $27.99. This price is called the _________. The price paid by the retailer, for the product being sold, is known as the
Answer:
selling price; cost
Step-by-step explanation:
Please Help! Select the correct systems of equations. Which systems of equations intersect at point A in this graph?
Answer:
The systems of equation satisfying the problem are
Y= 4x+9
Y= -3x-5
Y= 2x+5.
Y= 5x+11
Y= 3x+7
Y= -x-1
Step-by-step explanation:
From the graph in the figure
The point A ; x= -2,y=1
So the equations that will interest at point A are the equations that both pass through the point A.
To know the equations that pass through the point A we solve them simultaneously.
For
Y = 10x-1
Y= -3x-5
0= 13x +4
X= -4/13..... definitely not this one
For
Y= 4x+9
Y= -3x-5
0= 7x +14
-14= 7x
-2= x
Substituting the value of x into Y= 4x+9
Y= 4x+9
Y= 4(-2)+9
Y = -8+9
Y= 1
So it's definitely this one
Let's check to know if there is any more
Y = 2x+5
Y= x-1
0= x +6
Definitely not this one
For
Y= 2x+5.
Y= 5x+11
0 = 3x+6
-6= 3x
-2= x
Y= 2x+5.
Y=2(-2)+5
Y= 1
Definitely this one
For
Y= 3x+7
Y= -x-1
0 = 4x +8
-8= 4x
-2= x
Y= -x-1
Y= -(-2)-1
Y= +2-1
Y= 1
Definitely this one too
The correct options are system of equations shown by options (B)[tex]Y= 4x+9 \ and \ y = -3x-5[/tex]
(D) [tex]y= 2x+5 and \ y= 5x+11[/tex]
and (E) [tex]y= 3x+7 \ and\ y= -x-1[/tex].
Given, Coordinates of point A is (-2,1).
We have to find which systems of equations intersect at point A in this graph.
The system of equation which satisfy the point A(-2,1) will intersect at point A.
On putting the value of x=-2 and y= 1, in 1st pair
the equation doesn't satisfy.
similarly checking all the options, we find that the below system equations intersect at point A.
[tex]Y= 4x+9 \ and y = -3x-5 \\y= 2x+5 and \ y= 5x+11\\y= 3x+7 \ and y= -x-1[/tex]
Hence the correct options are system of equations shown by options (B), (D) and (E).
For more details follow the link:
https://brainly.com/question/1680887
Carter draws one side of equilateral △PQR on the coordinate plane at points P(-3,2) and Q(5,2). Which ordered pair is a possible coordinate of vertex R?
A. (-3, -6)
B. (0, 8)
C. (1, 8.9)
D. (1, -8.9)
Step-by-step explanation:
Hey, there!!!
Let me simply explain you about it.
We generally use the distance formula to get the points.
let the point R be (x,y)
As it an equilateral triangle it must have equal distance.
now,
let's find the distance of PQ,
we have, distance formulae is;
[tex]pq = \sqrt{( {x2 - x1)}^{2} + ( {y2 - y1)}^{2} } [/tex]
[tex]or \: \sqrt{( {5 + 3)}^{2} + ( {2 - 2)}^{2} } [/tex]
By simplifying it we get,
[tex] 8[/tex]
Now,
again finding the distance between PR,
[tex] pr = \sqrt{( {x2 - x1}^{2} + ( {y2 - y1)}^{2} } [/tex]
or,
[tex] \sqrt{( {x + 3)}^{2} + ( {y - 2)}^{2} } [/tex]
By simplifying it we get,
[tex] = \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } [/tex]
now, finding the distance of QR,
[tex]qr = \sqrt{( {x - 5)}^{2} + ( {y - 2)}^{2} } [/tex]
or, by simplification we get,
[tex] \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 } [/tex]
now, equating PR and QR,
[tex] \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13} = \sqrt{ {x}^{2} + {y}^{2} - 10x - 4y + 29 } [/tex]
we cancelled the root ,
[tex] {x}^{2} + {y}^{2} + 6x - 4y + 13 = {x}^{2} + {y}^{2} -10x - 4y + 29[/tex]
or, cancelling all like terms, we get,
6x+13= -10x+29
16x=16
x=16/16
Therefore, x= 1.
now,
equating, PR and PQ,
[tex] \sqrt{ {x}^{2} + {y}^{2} + 6x - 4y + 13 } = 8} [/tex]
cancel the roots,
[tex] {x}^{2} + {y}^{2} + 6x - 4y + 13 = 8[/tex]
now,
(1)^2+ y^2+6×1-4y+13=8
or, 1+y^2+6-4y+13=8
y^2-4y+13+6+1=8
or, y(y-4)+20=8
or, y(y-4)= -12
either, or,
y= -12 y=8
Therefore, y= (8,-12)
by rounding off both values, we get,
x= 1
y=(8,-12)
So, i think it's (1,8) is your answer..
Hope it helps...
Answer:
1,8.9
Step-by-step explanation:
Is {3,…} a defined set
Answer:
no it's not a defined state it's undefined
4. Suppose you make $12 an hour as a lifeguard at the community pool during the summer. Let h
represent the number of hours you work in a week. Write an expression that represents the
amount of money you earn in a week and evaluate it for ) = 15.
O 12.; $180
O 12 + 1; $27
7(12.1); $1,260
O5(127); $900
Answer:
Option A
Step-by-step explanation:
Expression: y = 12h
If h = 15, then:
y = 12(15)
y = $180
Option A
5. Write down at least five number
pairs to solve the equation
(r - 2)(s + 1) = 100.
Answer:
1. (52 - 2) (1 + 1) = 1002. (12 - 2) (9 + 1) = 1003. (6 - 2) (24 + 1) = 1004. (3 - 2) (99 + 1) = 1005. (102 - 2) (0 + 1) = 100Step-by-step explanation:
1. let r= 52 and s= 1(52 - 2) (1 + 1) = 10050 × 2 = 1002. let r= 12 and s= 9(12 - 2) (9 + 1) = 10010 × 10 = 1003. let r= 6 and s= 24(6 - 2) (24 + 1) = 1004 × 25 = 1004. let r= 3 and s= 99(3 - 2) (99 + 1) = 1001 × 100 = 1005. let r= 102 and s= 0(102 - 2) (0 + 1) = 100100 × 1 = 100[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
2t(t-1)-t+1 factorise
Answer:
this is the answer of this question
hoping it will help u
root 64 divided by root 3 64
Answer:
4
Step-by-step explanation:
4x4x4=64
Answer:
0.4193
Step-by-step explanation:
Root 64=8
Root 364=19.08...in 4 s.f
8÷19.08=0.4193...in 4 significant figures (4s.f)
A rectangular prism has a volume of 864 cubic units. How many cubic unit will fill the volume of the solid if they were packed without any gaps or overlaps
Answer: 864.
Step-by-step explanation:
The volume of a rectangular prism has a volume equal to:
V = W*L*H
W = width
L = length
H = height
We know that the volume is equal to 864 cubic units.
This means that if we want to fill the prism such that there is no gap or overlap, we should use exactly 864 unit cubes.
can someone explain this please?
Answer:
Hey there!
Our equation can be: 2y+3=4y+2
Hope this helps :)
Answer:
2y+3=4y+2
I hope you got it..
What is another way to write 100,203 in other forms
Answer:
You can write in
Step-by-step explanation:
Lakhs
First write 100,203.
Put ones,tens,hundreds,thousands,ten thousands and lakh on top of each number from the extreme left.
This is how you can write 100,203 in another way. You can't write in any other way than this one.
Hope this helps....
Have a nice day!!!!
HELP idk what the slope is
Answer:
the slope is -3
Step-by-step explanation:
Answer:
the slope is 3
Step-by-step explanation:
I need help FAST!!!Make sure you can explain the problem
Answer:
AB is not a tangent to the circle
Step-by-step explanation:
The angle between a tangent and the radius at the point of contact = 90°
Using Pythagoras' identity to determine if the triangle is right at A
If the square of the longest side is equal to the sum of the squares on the other 2 sides then A is right.
longest side = 15 , then 15² = 225
8² + 9² = 64 + 81 = 145 ≠ 225
Then AB is not a tangent to the circle
If EH = 76, calculate DI.
Answer:
DI = 38
Step-by-step explanation:
Δ EHC and Δ DIC are similar and ratios of corresponding sides are equal, that is
[tex]\frac{DI}{EH}[/tex] = [tex]\frac{DC}{EC}[/tex] , substitute values
[tex]\frac{DI}{76}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2DI = 76 ( divide both sides by 2 )
DI = 38
I am a 2 dimensional shape that has four sides. I have two obtuse angles and two acute angles. I have two different sets of parallel sides. I also have two sides that are one length, and my other two sides are a different length.
Answer:
Quadrilateral
Step-by-step explanation:
Anyone here that can help me with?
Answer:
D. 16 years old
Step-by-step explanation:
Step 1: Let T be Tien's age and J as Jordan's age (today),
[tex]T=\frac{1}{4}J[/tex]
Step 2: Let T be Tien's age and J as Jordan's age (in 2 years),
[tex]T+2=\frac{1}{3} (J+2)[/tex]
[tex]T=\frac{1}{3}(J+2)-2[/tex]
Step 3: As their age differences will always be similar we can have the two equations above equal to find Jordan's age,
[tex]\frac{1}{4} J=\frac{1}{3}(J+2)-2\\\frac{1}{4}J-\frac{1}{3}J=\frac{2}{3} -2 \\-\frac{1}{12}J= -\frac{4}{3} \\\\J=16[/tex]
For what value of x is the rational expression below equal to zero?
x-4/(x+5)(x-1)
O A. -5
O B. 4
C. -4
O D. 1
Answer:
x=4
Step-by-step explanation:
(x-4)/(x+5)(x-1)
For this to be equal to zero, the numerator must be zero and the denominator not equal to zero
x-4 = 0
x=4
Christine, Dale, and Michael sent a total of 71 messages during the weekend. Dale sent 9 fewer messages than Christine. Michael sent 2 times as many messages as Christine. How many messages did they each send?
Answer:
Micheal sent 40 messages, Christine sent 20, and Dave sent 11.
Step-by-step explanation:
Christine, Dale, and Michael sent a total of 71 messages
C + D + M = 71
Dale sent 9 fewer messages than Christine
D = C - 9
Michael sent 2 times as many messages as Christine
M = 2C
Plug-in the numbers.
C + C - 9 + 2C = 71
4C - 9 = 71
4C = 80
C = 20
Now, plug in to other equations for other results.
D = (20) - 9
D = 11
M = 2(20)
M = 40
Micheal sent 40 messages, Christine sent 20, and Dave sent 11.
Verify?
40 + 20 + 11 = 71.
Line m and point P are shown below. Part A: Using a compass and straightedge, construct line n parallel to line m and passing through point P. Leave all construction marks. Part B: Explain the process that you used to construct line n.
Answer:
see the attached
Step-by-step explanation:
In the attachment, we will refer to the circles, bottom-to-top, as circles 1, 2 and 3. The black points of intersection, bottom-to-top, will be referred to by the letters A, B, C, D. The transversal line through the white point (W) and pink point (P) will be line q.
Step 1. Draw line q through point P so it intersects line m at some convenient point. Label that point W.
Step 2. Choose an arbitrary radius for your compass. Here, we have chosen it to be the length WB. It happens to be less than half the length of WP, but that is not a requirement.
Step 3. Draw an arc of the chosen radius centered at W and intersecting line q and line m. Label the intersection points A (on line m) and B (on line q). These intersection points are on circle 1.
Step 4. Draw an arc of the same radius centered at P. It should be a long enough arc that it would intersect the proposed line parallel to m. Label the intersection point on line q with label C. This intersection point is on circle 3.
Step 5. Adjust the compass width (radius) to the distance from A to B. This is the radius of circle 2.
Step 6. Draw an arc centered at C so that it intersects the arc of Step 4. This is circle 2, and you want it to intersect circle 3. Label that point of intersection D.
Step 7. Draw line PD parallel to m.
_____
The point of the construction is to create congruent alternate interior angles AWB and CPD, so that lines AW and PD are parallel.
2,000
10,000
milligrams
grams
6
7
HELPPPPPPPPP
Answer:
2000 milligrams —> 2 grams
6000 milligrams —> 6 grams
7000 milligrams —> 7 grams
10000 milligrams —> 10 grams
I hope I helped you^_^