PLEASE HELP!!!!!!!!!!!! VOLUME OF A CONE!!!!!!

PLEASE HELP!!!!!!!!!!!! VOLUME OF A CONE!!!!!!

Answers

Answer 1

Hi! Your answer is 125/3 π

Please see an explanation for a clear understanding to the problem.

Any questions about the answer/explanation can be asked through comments! :)

Step-by-step explanation:

For this problem, I'll be demonstrating two methods to solve your problem which are Integration method and Formula method. Let's start with Formula method first!

Formula Method

Volume of Cone Formula

[tex]V=\huge{\frac{1}{3}\pi r^2h}[/tex]

r is a radius. Therefore, r² is a diameter.

h is height of cone.

Our r is 5. Therefore, 5² = 25.

Our h is 5.

Substitute these values in the equation.

[tex]V=\huge{\frac{1}{3}\pi (5)^2(5)}\\V=\huge{\frac{1}{3}\pi (25)(5)} \\V=\huge{\frac{1}{3}\pi (125)}\\V=\huge{\frac{125}{3}\pi}[/tex]

Hence, the volume of a cone is 125/3 pi. If you want in Mixed Number form then It'd be 41 and 2/3 pi [ 41 2/3 pi]

Integration Method - Proof

Let r':r = x:h

Therefore,

[tex]\huge{\frac{r'}{r}=\frac{x}{h}}\\\huge{r'=\frac{x}{h}r[/tex]

r and h both are same (r is still radius while h is still height)

[tex]\huge{S(x)=\pi(r')^2[/tex]

The reason why we add pi because the surface is a circle. If the surface is not a circle, we don't add pi.

[tex]\huge{S(x)=\pi(\frac{x}{h}r)^2}\\\huge{S(x)=\pi(\frac{x^2r^2}{h^2})}\\\huge{S(x)=\frac{\pi r^2}{h^2}x^2}\\[/tex]

The range starts from 0 ≤ x ≤ h

[tex]\huge{V=\int\limits^h_0 {S(x)} \, dx[/tex]

Substitute S(x) in.

[tex]\huge{V=\int\limits^h_0 {\frac{\pi r^2}{h^2}x^2 } \, dx[/tex]

Integrate, separate everything in the integrand out except for x^2

[tex]\huge{V=\frac{\pi r^2}{h^2} \int\limits^h_0 {x^2} \, dx}\\\huge{V=\frac{\pi r^2}{h^2}[\frac{1}{3}x^3]^h__0}}\\\huge{V=\frac{\pi r^2}{h^2}[\frac{1}{3}h^3]}\\\huge{V=\pi r^2[\frac{1}{3}h]}\\\huge{V=\frac{1}{3}\pi r^2h}[/tex]

As you notice, Integration method is pretty useful, but it's mostly for an advanced volume lesson only.

Integration Method - Problem Solving

Let r':r = x:h

r is given as 5

h is given as 5 as well.

Therefore, r':5 = x:5

[tex]\huge{\frac{r'}{5}=\frac{x}{5}}\\\huge{r'=\frac{x}{5}(5)}\\r'=x[/tex]

[tex]\huge{S(x)=\pi(r')^2}\\\huge{S(x)=\pi(x^2)}\\\huge{S(x)=\pi x^2}[/tex]

The range of volume starts from surface to height. Therefore the range is 0 ≤ x ≤ 5

[tex]\huge{V=\int\limits^5_0 {S(x)} \, dx }\\\huge{V=\int\limits^5_0 {\pi x^2} \, dx }\\\huge{V=\pi\int\limits^5_0 {x^2} \, dx }\\\huge{V=\pi[\frac{1}{3}x^3]^5__0}}\\\huge{V=\pi[(\frac{1}{3}(5)^3-\frac{1}{3}(0)^3]}\\\huge{V=\pi[(\frac{1}{3}(125)-0)]}\\ \huge{V=\pi[(\frac{1}{3}(125)]}\\\huge{V=\pi(\frac{125}{3})}\\\huge{V=\frac{125}{3}\pi}[/tex]

Notice that both methods have same answer. Hence, we can conclude that the volume of a cone is 125/3 pi units²


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A large bakery has many different products for sale. Suppose that 200 customers come in between 6 am and 10 am. Of the 200 customers, 140 order donuts, 100 order cinnamon rolls, and 80 order both. Suppose a customer is randomly selected. Find P(no donuts and no cinnamon rolls).

Answers

Out of 200 customers, the probability of a customer not ordering either donuts or cinnamon rolls is 0.2 or 20%.

Use the concept of probability defined as:

For the occurrence of an event, it is a ratio of the number of favorable outcomes to the number of total outcomes.

Given that,

Time frame: 6 am to 10 am

Total number of customers: 200

Number of customers who ordered donuts: 140

Number of customers who ordered cinnamon rolls: 100

Number of customers who ordered both donuts and cinnamon rolls: 80

To find the probability of a customer ordering neither donuts nor cinnamon rolls:

Subtract the probability of a customer ordering either donuts or cinnamon rolls or both from 1.

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Probability of ordering donuts:

140 out of 200 customers ordered donuts,

The probability of ordering donuts is,

140/200 = 0.7.

Probability of ordering cinnamon rolls:

100 out of 200 customers ordered cinnamon rolls,

The probability of ordering cinnamon rolls is,

100/200 = 0.5.

Probability of ordering both donuts and cinnamon rolls:

80 out of 200 customers ordered both,

The probability of ordering both is,

80/200 = 0.4.

Now, to find the probability of a customer ordering neither donuts nor cinnamon rolls,

Subtract the probability of ordering either or both from 1:

P(no donuts & no cinnamon rolls) = [tex]1 - P( \text{donuts}) - P(\text{cinnamon rolls}) + P(\text{donuts & cinnamon rolls})[/tex]

[tex]\text{P(no donuts & no cinnamon rolls)}= 1 - 0.7 - 0.5 + 0.4[/tex]

[tex]\text{P(no donuts & no cinnamon rolls)} = 0.2[/tex]

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The probability of a customer not ordering either donuts or cinnamon rolls is 0.2 or 20%.

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Answers

Answer:

10 yards

Step-by-step explanation:

;)

The required length of the longer side is 10 yards.

What is the perimeter?

Perimeter, is the measure of the figure on its circumference.

Here,
Let's assume that the length of one side of the rectangle is x yards. According to the problem, the other side of the rectangle is 3 yards longer than twice the length of this side. So, the length of the other side can be expressed as 2x + 3 yards.

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Answers

Answer:

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Step-by-step explanation:

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Hope I helped!

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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Answer:

80 percent

Step-by-step explanation:

What is value of x?

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Enter your answer in the box.

x = ?
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Answers

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Answer:

27

Step-by-step explanation:

Verified correct with test results.

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Step-by-step explanation:

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Step-by-step explanation:

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5n 6, 7, 8, 9, 10
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Answers

Answer:

a) aₙ = n+5 → 6,7,8,9,10....

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Step-by-step explanation:

Explanation

Given [tex]n^{th}[/tex] term of the sequence

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put n =2

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b)

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c)

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and so on

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d)

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