Answer:
it changes by taking the air from below the plane and curving it to the top causing draw wich slows it down then the weight that pulls it down to land.
please put me brainliest
Explanation:
Which object orbits object E?
A
B
C
Or D
Answer:
its D I hope this helps you
A car of mass, 1200 kg is pulled with constant force of 3000N in 20s. Work out A) The acceleration resulted: B) Distance travelled by the car, in the given time? C) Work done by the engine of the car D) The kinetic energy of the Car
Answer:
D
Explanation:
the energy is coming up and down
The answer is:
D) The kinetic energy of the car
If a ball rolls down a hill at a speed of 6.5m/s for 7s, how far did it travel?
Answer:
DABABY CONVERTIBLE LESS GOOO HA YE YE
The continuous changing of rocks from one kind to another is called:
Question 5 options:
Metamorphosis
Extrusion
The carbon cycle
The rock cycle
The continuous changing of rocks from one kind to another is called as the Rock cycle. So, the correct option is D.
What is Rock cycle?The rock cycle is defined as the change of rocks from one form to another as molten magma cools down and becomes an igneous rock which then breaks down into sediments and again forms sedimentary rocks under great pressure. The same rock that can become a metamorphic rock when subjected to great heat and pressure.
Every rock type is altered when it is forced out of its equilibrium conditions. Rock cycle is explained as the chain of processes which produce and transform the rock types in Earth's crust.
Thus, the continuous changing of rocks from one kind to another is called as the Rock cycle. So, the correct option is D.
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A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N child is 1.5 m from its center, How far is the 350-N child from the center
Determine the upward force exerted on the board?
Answer:
2.14 m
Explanation:
2.14m if it is write thank me hitting the heart ❤️ I took a lot of time to solve
how to makee them love you I AM JK U ARE BEAUTIFUL U DONT NEED A MAN GIRL GO STUDY INSTEAD OF CHECKING UR PHONE 100 TIMES A DAY. ILYYY DONT FORGET THAT
Explanation:
lol ....you are right.......
Your car gets a flat! You go from 90 kilometers per hour to a stop in 6 seconds. What is your rate of deceleration?
Answer:
The rate of deceleration is 15 km/h^2.
Explanation:
Since the car comes in 90km/h, it will need deceleration for 15 km/h for 6 seconds to finally stop the car. 15*6=90
Exposure to a sufficient quantity of ultraviolet will redden the skin, producing erythema - a sunburn. The amount of exposure necessary to produce this reddening depends on the wavelength. For a 1.0 cm2 patch of skin, 3.7 mJ of ultraviolet light at a wavelength of 254 nm will produce reddening; at 300 nm wavelength, 13 mJ are required. Part A What is the photon energy corresponding to each of these wavelengths
Answer:
Energy = 7.83 x 10⁻¹⁹ J
Energy = 6.63 x 10⁻¹⁹ J
Explanation:
The energy of a photon in terms of wavelength can be calculated by the following formula:
[tex]Energy = \frac{hc}{\lambda}\\[/tex]
where,
h = Plank's Constant = 6.63 x 10⁻³⁴ Js
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
Now, for λ = 254 nm = 2.54 x 10⁻⁷ m:
[tex]Energy = \frac{(6.63\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{2.54\ x\ 10^{-7}\ m}\\[/tex]
Energy = 7.83 x 10⁻¹⁹ J
Now, for λ = 300 nm = 3 x 10⁻⁷ m:
[tex]Energy = \frac{(6.63\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{3\ x\ 10^{-7}\ m}\\[/tex]
Energy = 6.63 x 10⁻¹⁹ J
- Is the kinetic energy conserved in the collision between
the ball and the pendulum?
Answer:
No, Momentum is conserved.
Explanation:
The ballistic pendulum is a device in which a projectile such as a bullet is fired into a suspended heavy wooden stationary block. Some kinetic energy gets transformed into heat and sound, and some is used to deform the block. However, momentum is conserved.
Groups of organs that work together to complete a series of takes are called:
A: Skeletal System
B: Organ System
C: Muscular System
A group of organs working together comprises an organ system, B.
Al, Bo, Cy, Di, Ed, and Fred assumed different positions in the room as shown in the image below. Their reflections are marked in red with the apostrophe.
Check all the reflections Ed can see
Answer:
A<L BO DI ED
Explanation:
The speed of a train is reduced uniformly from to while travelling a distance of 90 m. a. Compute the deceleration b. How much further will the train travel before coming to rest, provided the acceleration remains constant?
Answer:
290 m.a.
Is answer
I don't know properly
But I hope you like it
Sorry
A wave pulse travels along a stretched string at a speed of 100 cm/s. What will be the speed in cm/s if the string's tension is quadrupled, the length halved and its mass is doubled
Answer:
The new velocity of the string is 100 centimeters per second (1 meter per second).
Explanation:
The speed of a wave through a string ([tex]v[/tex]), in meters per second, is defined by the following formula:
[tex]v = \sqrt{\frac{T\cdot L}{m} }[/tex] (1)
Where:
[tex]T[/tex] - Tension, in newtons.
[tex]L[/tex] - Length of the string, in meters.
[tex]m[/tex] - Mass of the string, in kilograms.
The expression for initial and final speeds of the wave are:
Initial speed
[tex]v_{o} = \sqrt{\frac{T_{o}\cdot L_{o}}{m_{o}} }[/tex] (2)
Final speed
[tex]v = \sqrt{\frac{(4\cdot T_{o})\cdot (0.5\cdot L_{o})}{2\cdot m_{o}} }[/tex]
[tex]v = \sqrt{\frac{T_{o}\cdot L_{o}}{m_{o}} }[/tex] (3)
By (2), we conclude that:
[tex]v =v_{o}[/tex]
If we know that [tex]v_{o} = 1\,\frac{m}{s}[/tex], then the new speed of the wave in the string is [tex]v = 1\,\frac{m}{s}[/tex].
A 1.0-kg object moving 9.0 m/s collides with a 2.0-kg object moving 6.0 m/s in a direction that is perpendicular to the initial direction of motion of the 1.0-kg object. The two masses remain together after the collision, and this composite object then collides with and sticks to a 3.0-kg object. After these collisions, the final composite (6.0-kg) object remains at rest. What was the speed of the 3.0-kg object before the collisions
Answer:
v₃ = - (3 i ^ + 4 j ^) m / s
v₃ = 5 m / s, θ = 233º
Explanation:
This is a momentum problem. Let us form a system formed by the three objects so that the forces during the collisions have been internal and the moment is conserved.
Let's start working with the first two objects. As each object moves in a different direction let's work with the components in an xy coordinate system
X axis
initial instant. Before the shock
p₀ₓ = m₁ v₁₀ + 0
final instant. After the crash
p_{fx} = (m1 + m2) vₓ
the moment is preserved
p₀ₓ = p_{fx}
m₁ v₀₁ = (m₁ + m₂) vₓ
vₓ = [tex]\frac{m_1}{m_1+m_2} \ v_{o1}[/tex]
Y axis
initial instant
p_{oy} = 0 + m₂ v₀₂
final moment
p_{fy} = (m₁ + m₂) v_y
the moment is preserved
p_{oy} = p_{fy}
m₂ v₀₂ = (m₁ + m₂) v_y
v_y = [tex]\frac{m_2}{m_1 +m_2 } \ v_{o2}[/tex]
We already have the speed of the set of these two cars, now let's work on this set and vehicle 3
X axis
initial instant
p₀ₓ = (m₁ + m₂) vₓ + m₃ v₃ₓ
final instant
p_{fx} = 0
p₀ₓ = p_{fx}
(m₁ + m₂) vₓ + m₃ v₃ₓ = 0
v₃ₓ = [tex]- \frac{m_1+m_2 }{m_3} \ v_x[/tex]
Y Axis
initial instant
p_{oy} = (m₁ + m₂) v_y + m₃ v_{3y}
final moment
p_{fy} = 0
p_{oy} = p_{fy}
(m₁ + m₂) v_y + m₃ v_{3y} = 0
v_{3y} = [tex]- \frac{m_1+m_2}{m_3} \ v_y[/tex]
now we substitute the values of the speeds
v₃ₓ = [tex]- \frac{m_1+m_2}{m_3} \ \frac{m_1}{m_1+m_2} \ v_{o1}[/tex]
v₃ₓ = [tex]- \frac{m_1}{m_3} \ v_{o1}[/tex]
v_{3y} = [tex]- \frac{m_1+m_2}{m_3} \ \frac{m_2}{m_1+m_2} \ v_{o2}[/tex]
v_{3y} = [tex]- \frac{m_2}{m_3} \ v_{o2}[/tex]
let's calculate
v₃ₓ = - ⅓ 9
v₃ₓ = - 3 m / s
v_{3y} = - ⅔ 6
v_{3y} = - 4 m / s
therefore the speed of vehicle 3 is
v₃ = - (3 i ^ + 4 j ^) m / s
It can also be given in the form of modulus and angles using the Pythagorean theorem
v₃ = [tex]\sqrt{v_{3x}^2 + v_{3y}^2}[/tex]
v₃ = [tex]\sqrt{3^2+4^2}[/tex]
v₃ = 5 m / s
let's use trigonometry for the angle
tan θ' = [tex]\frac{v_{3y}}{v_{3x}}[/tex]
θ' = tan⁻¹ (\frac{v_{3y}}{v_{3x}})
θ' = tan⁻¹ (4/3)
θ' = 53º
That the two speeds are negative so this angle is in the third quadrant, measured from the positive side of the x axis
θ = 180 + θ'
θ = 180 +53
θ = 233º
difference between centrifugal and semi-centrifugal clutches
Answer:
Semi-centrifugal clutches are used in high powered race cars, to reduce the driver effort. Working is just like semi-centrifugal clutch.
The clutch action is purely under centrifugal force.
At low engine rpm the centrifugal force is low, so there is slip, as engine rpm increases, so does the centrifugal force.
How are rainbows made?
Answer:
when it rains and at the same time it sunny there would appear a rainbow
Scientists have measured the distance between the Earth and the Moon by reflecting a beam of laser
light off the Moon. They measure the time taken for light to travel to the Moon and back.
a) What other piece of information is needed to calculate the Earth-Moon distance?
b) How would the distance be calculated?
Answer:
a)speed of light.
a)speed of light×time=distance.
Explanation:
light has a constant speed of 299,792,458m/s
This distance is analyzed quantitatively by LIDAR (Light Detection And Ranging) stations, which bounce laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.
What is LIDAR?
Lidar is a method of determining ranges that involves using a laser to target an object or a surface and measuring the time it takes for the reflected light to return to the receiver.
LiDAR is a type of remote sensing technology. LiDAR technology collects measurements by using a laser pulse. These are employed in the production of 3D models and maps of objects and environments.
Lidar, which stands for light detection and ranging, has been around for quite some time. It employs lasers to ping off objects and return to the laser source, measuring distance by timing the travel, or flight, of a light pulse.
LIDAR (Light Detection And Ranging) stations analyze this distance quantitatively by bouncing laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.
Thus, this way, the distance can be calculated.
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a 12v battery delivers a 3.6 a current to an electric motor. How much power was delivered to the current?
Answer:
P = 43.2 W
Explanation:
Known:
Voltage = 12 v = 12 kgm^2s^-3A^-
Current = 3.6 A
Unknown:
Power =?
Strategy:
We need an equation the relates voltage, power, and current. According to Watt's Law, the power in a circuit is a product of voltage and current.
This defines the relationship between power, voltage, and current.
The mathematical expression of watt's law is P = IV where p is the power delivered or generated by a given source, I is current, and V is the voltage.
Solution:
P = 3.6 A * (12 kgm^2s^-3A^-1)
P = (43.2 kgm^2s^-3A)/A [ I have moved the A^-1 into the denominator as A so that we can see that we have the same term in the numerator and denominator.
P = 43.2 kgm^2s^-3
P = 43.2 W
Three identical very dense masses of 3800 kg each are placed on the x axis. One mass is at x1 = -
230 cm, one is at the origin, and one is at
x2 = 350 cm. Take the gravitational constant to be G = 6.67×10−11N⋅m2
/kg2
a) calculate the gravitational attraction of the object located at x1 on the object sitting at the
origin. (magnitude and direction. Take the direction from the origin to the right as
POSITIVE)
b) Calculate the gravitational attraction of the object located at X2 on the object at the origin.
(magnitude and direction)
c) Calculate the total gravitational attraction of the objects located at x1 and the object sitting at
x2 on the mass located at the origin. (magnitude and direction).
Answer:C
Explanation:
I think its c im pretty sure
A particle with a charge of 34.0 $\mu C$ moves with a speed of 65.8 m/s in the positive $x$ direction. The magnetic field in this region of space has a component of 0.545 T in the positive $y$ direction, and a component of 0.828 T in the positive $z$ direction. What is the magnitude of the magnetic force on the particle
Answer:
0.00221 N
Explanation:
Given that,
The charge on the particle, [tex]q=34\mu C[/tex]
The speed of the particle, v = 65.8 m/s (+x direction)
Magnetic field, B = 0.545 T (in +y direction) and 0.828 T in the positive z direction.
The magnetic force is given by the formula as follows :
[tex]F=q(v\times B)[/tex]
Substitute all the values,
[tex]F=34\times 10^{-6}\times (65.8i\times (0.545j+0.828 k))\\\\=34\times 10^{-6}\times (65.8i\times 0.545j +65.8i\times 0.828 k)\\\\=34\times 10^{-6}\times(35.86k +(-54.48j))\\\\=34\times 10^{-6}\times \sqrt{35.86^2+54.48^2} \\\\=0.00221\ N[/tex]
So, the magnitude of the magnetic force on the particle is equal to 0.00221 N.
How does mass differ from weight? List 2 differences.
weight is vector vary from place to place
Answer:
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
Explanation:
Mass is the measure of the amount of matter in a body. Mass is denoted using m or M. ... Weight is mass multiplied by the acceleration of gravity (g).
what part of the rocket reaches space
Answer:
7
Explanation:
There is really no explanation needed
Wind turbines continue to generate energy even when there isn't any wind.
O True
O False
The two uniform, slender rods B1and B2, each of mass 2kg, are pinned together at P, and then B1is suspended from a pin at O. (This arrangement is called a double pendulum.) The counterclockwise couple C0, having moment 150????⋅m, is applied to B2beginning at t=0. Find the angular accelerations of B1and B2upon application of the couple, and the force exerted on B2at P.
Answer:
hello the diagram relating to this question is attached below
a) angular accelerations : B1 = 180 rad/sec, B2 = 1080 rad/sec
b) Force exerted on B2 at P = 39.2 N
Explanation:
Given data:
Co = 150 N-m ,
a) Determine the angular accelerations of B1 and B2 when couple is applied
at point P ; Co = I* ∝B2'
150 = ( (2*0.5^2) / 3 ) * ∝B2
∴ ∝B2' = 900 rad/sec
hence angular acceleration of B2 = ∝B2' + ∝B1 = 900 + 180 = 1080 rad/sec
at point 0 ; Co = Inet * ∝B1
150 = [ (2*0.5^2) / 3 + (2*0.5^2) / 3 + (2*0.5^2) ] * ∝B1
∴ ∝B1 = 180 rad/sec
hence angular acceleration of B1 = 180 rad/sec
b) Determine the force exerted on B2 at P
T2 = mB1g + T1 -------- ( 1 )
where ; T1 = mB2g ( at point p )
= 2 * 9.81 = 19.6 N
back to equation 1
T2 = (2 * 9.8 ) + 19.6 = 39.2 N
Explain What's make up macromolecules?
Answer:
Atoms
Explanation:
Atoms make up everything
Which wave has the smallest wave
period? What is its period?
Answer:
C
Explanation:
The said wave takes the shortest time to move/get transmitted
What range of the electromagnetic spectrum does this wave belong to?
Answer:
please give me brainlist and follow
Explanation:
Infrared radiation
The infrared part of the electromagnetic spectrum covers the range from roughly 300 GHz to 400 THz (1 mm – 750 nm). It can be divided into three parts: Far-infrared, from 300 GHz to 30 THz (1 mm – 10 μm). The lower part of this range may also be called microwaves or terahertz waves.
how do people in your community deal with loud sound
Answer: Nothing they mind thier own business instead of being really noisy.
Explanation
Now if someone was screaming they probley would go investagate investigate but something else nah.
A wire 0.50 m long carrying a current of 16.0 A is at right angles to a 0.20 T magnetic field. How strong a force acts on the wire
Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm.
Required:
What is V(star) , the speed at which the star is moving relative to the earth?
Answer:
The speed will be "18km/s". A further explanation is given below.
Explanation:
According to the question, the values are:
Wavelength,
[tex]\lambda = 656.46 \ nm[/tex]
[tex]\Delta \lambda = 0.04[/tex]
[tex]c=3\times 10^8[/tex]
As we know,
⇒ [tex]\frac{\Delta \lambda}{\lambda} =\frac{v}{c}[/tex]
On substituting the values, we get
⇒ [tex]\frac{656.46}{0.04} =\frac{v}{3\times 10^8}[/tex]
⇒ [tex]v=\frac{656.46}{0.04} (3\times 10^8)[/tex]
⇒ [tex]=16411.5\times 3\times 10^8[/tex]
⇒ [tex]=18280 \ m/s[/tex]
or,
⇒ [tex]=18 \ km/s[/tex]
The speed at which the star is moving relative to the earth is 18 km/s
Calculation of the speed:Since the wavelength is 656.46 nm.
And, Δλ=0.04nm
Here Wavelength should represent the distance between the same points in the cycles of a signal propagated in space or it should be along a wire.
Now the speed should be
[tex]= 0.04 \div 656.46 \times 3 \times 10^8[/tex]
= 1820m/s
= 18 km.s
Therefore, The speed at which the star is moving relative to the earth is 18 km/s
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