Answers
Answer:
1. 180° ∑triangle angles=180°
2. 2x
3. 52°
Related Questions
15. Write the first four terms of the sequence:
a. f(n) = −2[tex]n^{2}[/tex] + 4
b. f (1) = 7, f(n)= −4 ∙ f(n-1) − 1 + 15
Answers
Answer:
16 17
Step-by-step explanation:
I need help with this equation. I'm not that smart so I can't figure it out-
Answers
Answer:
x = 0
Step-by-step explanation:
In order to solve for x, first combine both fractions on the left
To add 4x-2/8 + 3+x/4 first find the least common denominator of 8 and 4
It's 8 so multiply the numerator and denominator of 3+x/4 by 8, you would get:
8x+24/32
Multiply 4x-2/8 by 4, you will get:
16x-8/32
Now you can add 16x-8/32 + 8x+24/32, you would get:
24x+16/32
Now you can start to solve for x
Your new equation is 24x+16/32 = 1/2
To solve for x, first multiply diagonally, then solve like a regular equation.
Multiply 24x+16 by 2 to get 48x+32
Then multiply 32 by 1 to get 32
Your new equation is 48x+32=32
Now subtract 32 by 32 to get 48x=0
Now divide 48 by 0 to get x=0
The rectangle shown
Answers
a^2 + b^2=c^2
Given g(x)=2x+3, solve for x when g(x)=3
Answers
Answer:
-3/2
Step-by-step explanation:
How many different ways can you write a ratio?
Answers
Answer:
3 different ways
Step-by-step explanation:
Answer:
3 different ways
Step-by-step explanation:
hope this helps
example of the diffrent way to write a ratio :
5 to 10
5 : 10
[tex]\frac{5}{10}[/tex]
Identify a pair of perpendicular lines in the given figure.
Question 1 options:
p and t
q and t
s and t
p and q
Answers
write and equation of the line below
Answers
Answer:
y = 1/4x + 0 or just y = 1/4x
Step-by-step explanation:
First I need the slope so I look at the dots and see how much boxes it goes up and then to the side. So it’s up 2 to the side 8. The slope would be 2/8 but you can simply it by 2 and you get 1/4. And the y intercept is given its zero.
Pls help really fast I don't know this!!!!!
Answers
I think it's (3,4) but I am not confident so please be understanding
Answer:
(3, 1 )
Step-by-step explanation:
The centre of the circle is at the midpoint of the diameter.
Given endpoint (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
Here (x₁, y₁ ) = (9, 7) and (x₂, y₂ ) = (- 3, - 5 ) , then
midpoint = ( [tex]\frac{9-3}{2}[/tex], [tex]\frac{7-5}{2}[/tex] ) = ( [tex]\frac{6}{2}[/tex], [tex]\frac{2}{2}[/tex] ) = (3, 1 )
Thus centre of circle = (3, 1 )
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A box contains 7 plain pencils and 3 pens. A second box contains 5 color pencils and 5 crayons. One item from each box is chosen at random. What is the
probability that a plain pencil from the first box and a color pencil from the second box are selected?
form
Answers
Answer:
60%
Step-by-step explanation:
add them all to 20
add 7 and 5 to get 12
12 over 20 is 60 percent
The terminal side of Ø is in quadrant II and sin ø = 5/13 What is cos ø?
A. 5/12
B. -12/13
C. -5/12
D. 12/13
Answers
Step-by-step explanation:
In Quadrant II, cosine is negative.
We know that sin²x + cos²x = 1, so:
cosx = sqrt[1 - sin²x]
= sqrt[1 - (5/13)²]
= sqrt(144/169)
= -12/13 (since cosx is negative here)
The answer is -12/13. (B)
Option B is correct.
Quadrants and the "cast" Rule:In the first quadrant, the values for sin, cos, and tan are positive.In the second quadrant, the values for sin are positive only.In the third quadrant, the values for tan are positive only.In the fourth quadrant, the values for cos are positive only.
According to the given question
We have, sin ∅ = 5/13
From the trigonometric identities we know that
[tex]sin^{2}[/tex]∅ + [tex]cos^{2}[/tex]∅ =1
substitute the value of sin∅ in the above identity
[tex](\frac{5}{13} )^{2} + cos^{2}[/tex]∅ =1
⇒ [tex]\frac{25}{69} +cos^{2}[/tex]∅ =1
⇒ [tex]cos^{2}[/tex]∅ = 1 - [tex]\frac{25}{169}[/tex]
⇒ [tex]cos^{2}[/tex]∅ = [tex]\frac{169-25}{69} =\frac{144}{169}[/tex]
⇒[tex]cos[/tex]∅ = [tex]\sqrt{\frac{144}{169} }[/tex]
⇒cos∅ = ±[tex]\frac{12}{13}[/tex]
Since, ∅ is in quadrant II, then cos<0
⇒ cos∅ = -[tex]\frac{12}{13}[/tex]
Hence, option B is correct.
Learn more about quadrant and cast rule here:
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