Please help/ show work !!! Also don’t answer by putting a link!!

Answer:

Spherical mirror is a mirror with a curved reflecting surface.

There are two spherical mirrors -

Concave Mirror - A spherical mirror , whose reflecting surface is curved inwards , that is , faces towards the centre of the sphere , is called concave mirror.

Cnovex Mirror - A spherical mirror whose reflecting surface is cirved outwards is called convex mirror.

Explanation:

Points of difference :

Answer:

the height of the potential energy is 3,200 J

Explanation:

The computation of the kinetic energy is shown below:

Kinetic energy = 1 ÷ 2 × mass × velocity^2

= 1 ÷ 2 × 4 kg × 40 m/s^2

= 3,200 J

Hence the height of the potential energy is 3,200 J

Answer:

10 kg

Explanation:

p=ma

25=2.5m

m=25/2.5

m=10 kg

mark as brainliest plzzzzz

Answer:

The answer is elastic

Explanation:

hope this helps!

Explanation:

work input is the work done by the machine in lifting the drum = Force × distance

100N × 10m

= 1000 J

Answer:

Force = 2802.8 Newton

Explanation:

Given the following data;

Mass = 130 lbs

But, 2.2 lbs = 1.0 kg

130 lbs to kg = 130 * 2.2 = 286 kg

Acceleration due to gravity = 9.8m/s²

To find the force in Newton;

Force = mass * acceleration due to gravity

Force = 286 * 9.8

Force = 2802.8 Newton

Answer:

Rome became the most powerful state in the world by the first century BCE through a combination of military power, political flexibility, economic expansion, and more than a bit of good luck. This expansion changed the Mediterranean world and also changed Rome itself.

Explanation:

Answer:

I'm pretty sure it's mist, drizzle, droplet, and then rain.

Answer:

gravity

Explanation:

Answer:

55 ohms

Explanation:

if it was series circuit, then you just need to add all the resistances

Answer:

D. OJ

Explanation:

Answer:

b

Explanation:

light colors deflect ligjt

Complete Question:

Suppose [tex]A = B^n C^m[/tex], where A has the dimensions LT, B has dimensions L²T⁻¹, and C has dimensions LT². Then the exponents n and m have the values

Answer:

The value of n = ¹/₅

The value of m = ³/₅

Explanation:

Given dimensions;

A = LT

B = L²T⁻¹

C = LT²

The values of n and m are calculated as follows;

[tex]LT = [L^2T^{-1}]^n[LT^2]^m\\\\L^1T^1 = [L^{2n}T^{-n}]\times [L^mT^{2m}]\\\\L^1 \times T^1 = [L^{(2n+m)}] \times [T^{(-n +2m)}]\\\\1 = 2n + m -----(1)\\\\1 = -n + 2m ----(2)\\\\from \ (1); \ m = 1-2n, \ \ substitute \ the \ value \ of \ m \ in\ (2)\\\\1= -n +2(1-2n)\\\\1 = -n + 2-4n\\\\1-2 = -5n\\\\-1 = -5n\\\\1= 5n\\\\n = \frac{1}{5} \\\\m = 1 - 2n\\\\m = 1 - 2(\frac{1}{5} )\\\\m = 1- \frac{2}{5} \\\\m = \frac{3}{5}[/tex]

Answer:

a)  v = 126.5 m / s,  b)   λ₁ = 1.6 m,   λ₂ = 0.8 m, λ₃ = 0.533 m,   f1 = 79 Hz,    

λ₂ = 0.8 m,   f₃ = 237 Hz

Explanation:

This is an exercise we are going to solve in parts, let's start by looking for the speed of the wave in the string.

         v = [tex]\sqrt { \frac{T}{ \mu } }[/tex]

the rope tension is T = 90 N and the density can be calculated

         μ = m / l

let's calculate

         μ = 4.5 10⁻³ / 0.80

         μ = 5.625 10⁻³  kg/m

let's calculate the speed

         v = [tex]\sqrt{ \frac{90 }{5.625 \ 10^{-3}} }[/tex]

         v = 126.5 m / s

For the second part there is a process of resonance in the string. The points where it is attached are nodes so, if L is the length of the chord

         L = ½ λ         1st harmonic

         L = 2/2 λ      2nd harmonic

         L = 3/2 λ      3rd harmonic

         L = n/2 λ      n harmonic

the wavelength of the first three harmonics is requested

let's calculate

          λ₁ = 2L

          λ₁ = 2 0.8

          λ₁ = 1.6 m

          λ₂ = L

          λ₂ = 0.8 m

          λ₃ = ⅔ L

          λ₃ = ⅔ 0.8

          λ₃ = 0.533 m

To calculate the frequency we use that the speed is related to the wavelength and the frequency

           v = lam f

           f = v / lam

we calculate

           f1 = 126.5 / 1.6

           f1 = 79 Hz

           f2 = 126.5 / 0.8

           f2 = 158 Hz

           f3 = 126.5 / 0.533

           f3 = 237 Hz

Answer:

-4,651.42N

Explanation:

Since we are not asked what to find, we can calculate the force applied by the track as shown;

F = ma

F = m(v-u)/t

Substitute the given value

F = 4400(7.6-52)/42

F = 4400(-44.4)/42

F = -4,651.43N

Hence the required force is -4,651.42N

Answer:

There are three forces acting upon the system - the gravity force (the Earth pulls down on the 15.0 kg of mass), the normal force (the floor pushes up on the system to support its weight), and the applied force (the hand is pushing on the back part of the system).

Explanation:

Answer:

what he said

Explanation:

Answer:

Explanation:

Time is a major factor in how much force is being applied.  so when there are crumple zones. they crumple and that takes a little longer in an impact and hence lowers the forces considerably   :)   safety first  

Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

Workdone = F.S (force x displacement)

Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

Workdone = 50 x 9.8 x 1.5 J

= 735 J

Answer:

750J

Explanation:

Solution;

M=50kg, g=10m/s

Distance=15×10÷100

=1.5m

W=M×g×h

=50×10×1.5

=750J

Answer:

i cant even see it

Explanation:

Answer:

B

Explanation:

B

Answer:

I dont get it

Explanation:

Answer:

Amperage is the rate of electrical charge per time.

1 amp = 1 coulomb / second

Power is the product of amperage and voltage.

P = IV

Explanation:

Answer:

Plants and animals that live in a biome must be able to live and reproduce in the conditions

Explanation:

Answer:

30N

Explanation:

if it is pushing the object to the left then it would be 30N left and if it is pushing the object to the right it would be 30N right

Answer: 30N

Explanation:

Answer:

6.075×10²³ Electrons

Explanation:

From the question,

Q = it............................. Equation 1

Where Q = quantity of charge, i = current, t = time.

Given: i = 27 A, t = 1 hours = 1×60×60 = 3600 seconds.

Substitute these values into equation 1

Q = 27×3600

Q = 97200 C.

If, one electron = 1.6×10⁻¹⁹ C,

Therefore, n electron = 97200×1/1.6×10⁻¹⁹ C.

n = 6.075×10²³ Electrons