Please help! Please help!

Answer:

x=13 y=25

Step-by-step explanation:

Answer:

Step-by-step explanation:

ΔABC has AB = 2BC, hypotenuse is twice the leg

ΔBCD is isosceles right triangle

ΔMPN is isosceles right triangle (∠M = 45°)

ΔMKP is isosceles right triangle (∠M = 45°)

Answer:

Question 13 is 27/2 (decimal form, 13.5, Mixed fraction 13 1/2)

Question 14 = 4

Step-by-step explanation:

hope this helped you:)

Answer:

y=-5x+176

Step-by-step explanation:

Write an algebraic equation showing that the two points equal each other and then evaluate it.

Answer:

Sample B: A random sample of 5 gallons of water from five different locations in the river

Step-by-step explanation:

Answer:

128°

Step-by-step explanation:

180-52=128

Answer:

3

Step-by-step explanation:

24 + 12 = ___(8+4)

36 = ___(12)

36/12 = 3

Answer: -628

Step-by-step explanation:

F(140) = 212 - 6(140)

F(140) = 212 - 840

F(140) = -628

Answer:

A  , B, and C

Step-by-step explanation:

i just did it

Answer:

3n-4= 44

3n=40

no u can solve

Answer:

17°

Step-by-step explanation:

3n - 5° + 90° + 44° = 180° { being linear pair }

3n + 129° = 180°

3n = 180° - 129°

3n = 51°

n = 51° / 3

n = 17°

Hope it will help :)

Answer:

168.75

Step-by-step explanation:

......

Answer:

168.75

Step-by-step explanation:

Hello!

[tex]\large\boxed{\frac{2\pi}{3} \text{ and } \frac{4\pi}{3}}[/tex]

2cosФ + 1 = 0

Begin by isolating for cosФ. Subtract both sides by -1:

2cosФ = -1

Divide both sides by 2:

cosФ = -1/2

Using the unit circle, we know that from [0, 2π), values that have a cosine of -1/2 are 2π/3 and 4π/3.

Therefore, the solutions of this equation are:

Ф = 2π/3 and 4π/3

Answer:

≈3.464

Step-by-step explanation:

1. the required 'x' belongs to the hypotenuse of the given triangle. It means, the formula of its length is:

x=4*cos30°=4*sin60°, note sin60°=cos30°=√3/2≈0.866.

2. according to the formula above the required length 'x' is:

x=4*0.866=3.464 (or 2√3)

The value of the expression is 17.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

r + 4

When r = 13

r + 4

= 13 + 4

= 17

Thus,

The value is 17.

Learn more about expressions here:

https://brainly.com/question/3118662

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Answer:

I love alegbra anyways

The ans is in the picture with the steps how i got it

(Hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Answer:

Sophie has 12 feet more

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

We know that when x=0 y=5

B and D are the only ones that meet this criteria

we know that when x=2 y= 13 or so

D no longer works

it has to be B

Answer:

170t+D=8500

D=170t−6460

Step-by-step explanation:

Mathematical models are used to explain real life situations.

We can see from the question that the total debt is $8500  while there is  interest rate of 0% for 24 months. We are also told that after 12 months, the remaining debt was $6460.

Now, the equations that correctly model the situation are;

Learn more about mathematical models:https://brainly.com/question/731147

Answer:

20/45

6/45

Step-by-step explanation:

A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).

--------------------

# of red/yellow pairs: 4*5 = 20

# of random pairs: 10C2 = 45

P(1red & 1yellow) = 20/45

# of red pairs: 4C2 = 6

# of random pairs = 45

P(2 red) = 6/45

Answer:

10

Step-by-step explanation:

Answer:

If your polynomial is x^2+x-30, then your answer is (−5)(+6)

Answer:

Step-by-step explanation:

[tex]\tan22=h_1/200,\ \tan29=h_2/200

h_2+h_1=200(\tan29+\tan22)

H\approx 191.667ft

H\approx 191’ 8”

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

Learn more about length of the arc of a curve here:

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Answer:

16/3

Step-by-step explanation:

Step-by-step explanation:

Using Pythagoras theorem

x=✓(35²-21²)=✓784=28 units

Answer:

1.52%

Step-by-step explanation: