Please help number 5 thank you

Answer:

The following classification is found:

[tex](0.2, 6)[/tex] - Absolute minimum

[tex](-0.2, 10)[/tex] - Absolute maximum

Step-by-step explanation:

Let be [tex]f(x) = 125\cdot x^{3}-15\cdot x + 8[/tex], we need to find first and second derivatives of this expression at first:

First derivative

[tex]f'(x) = 375\cdot x^{2}-15[/tex] (Eq. 1)

Second derivative

[tex]f''(x) = 750\cdot x[/tex] (Eq. 2)

Critical points are points that equals first derivative to zero and that may be maxima or minima. That is:

[tex]375\cdot x^{2} -15 = 0[/tex]

[tex]x = \pm \sqrt{\frac{15}{375} }[/tex]

Which leads to the following critical points:

[tex]x_{1}\approx 0.2[/tex] and [tex]x_{2} \approx -0.2[/tex]

Now we evaluate each result in second derivative expression:

[tex]f''(x_{1}) = 750\cdot (0.2)[/tex]

[tex]f''(x_{1})=150[/tex] (Absolute minimum)

[tex]f''(x_{2})= 750\cdot (-0.2)[/tex]

[tex]f''(x_{2}) = -150[/tex] (Absolute maximum)

Lastly we evaluate the function at each critical point:

[tex]f(x_{1})= 125\cdot (0.2)^{3}-15\cdot (0.2)+8[/tex]

[tex]f(x_{1})= 6[/tex]

[tex]f(x_{2})= 125\cdot (-0.2)^{3}-15\cdot (-0.2)+8[/tex]

[tex]f(x_{2}) = 10[/tex]

And the following classification is found:

[tex](0.2, 6)[/tex] - Absolute minimum

[tex](-0.2, 10)[/tex] - Absolute maximum

Answer:

There are 119 bacteria after 3 hours.

Step-by-step explanation:

Let be [tex]b(t) = 100\cdot 1.06^{t}[/tex], where [tex]t[/tex] is the time, measured in hours, and [tex]b(t)[/tex] is the number of total bacteria, dimensionless. The number of total bacteria after 3 hours is found after evaluating the function at given function:

[tex]b (3) = 100\cdot 1.06^{3}[/tex]

[tex]b(3) = 119.102[/tex]

We rounded to the nearest preceeding whole number, since number of bacteria represents a discrete set. There are 119 bacteria after 3 hours.

Answer:

A; (X=5)

Step-by-step explanation:

Move the constants and variable terms to one side:

3x-5= -2x+10

-5+10= -2x+ 3x

Combine like terms:

5=x or x=5

Answer:

The answer is C

Step-by-step explanation:

If you take the equation and simplify it.

3x-5=-2x+10

You would minus 3x from both sides, leaving the equation like

-5=-5x+10

Then you would minus 10 from both sides, leaving the equation like

-15=-5x

If you wanted to go further you could divide both sides by -1 and get rid of the negatives. Leaving the equation like

15=5x

Then to put it into the simpleist   form you would divide both sides by 5, leaving the equation like

3=x

I hope this helps.

Answer:

11

Step-by-step explanation:

(1) f(x) = (1 - x³) / (x - 1)

(a) The domain is the set of values that this function can take on. If x = 1, the denominator becomes 0 and the function is undefined. Any other value of x is okay, though, since for x ≠ 1, we have

f(x) = (1 - x³) / (x - 1) = - (1 - x³) / (1 - x) = -(x² + x + 1)

which is defined for all x. This also tells us that the plot of f(x) is a parabola with a hole at x = 1. So, the domain is the interval (-∞, 1) ∪ (1, ∞).

(b) The range is the set of values that the function actually does take on. Taking the simplified version of f(x), we can complete the square to write

-(x² + x + 1) = -(x² + x + 1/4 - 1/4) - 1 = -(x + 1/2)² - 3/4

which is represented by a parabola that opens downward, with a maximum value of -3/4. So the range is the interval (-∞, -3/4).

(c) Judging by the plot of f, the limits at both negative and positive infinity are -∞.

(d) Same answer as part (a).

(2) f(x) = x³ - x

(a) The derivative of f at x = 3, and hence the slope of the tangent line to this point, is

[tex]f'(3)=\displaystyle\lim_{h\to0}\frac{f(3+h)-f(3)}h[/tex]

[tex]f'(3)\displaystyle=\lim_{h\to0}\frac{((3+h)^3-(3+h))-24}h[/tex]

[tex]f'(3)=\displaystyle\lim_{h\to0}\frac{(27+27h+9h^2+h^3)-(3+h)-24}h[/tex]

[tex]f'(3)=\displaystyle\lim_{h\to0}\frac{26h+9h^2+h^3}h[/tex]

[tex]f'(3)=\displaystyle\lim_{h\to0}(26+9h+h^2)=\boxed{26}[/tex]

(b) The tangent line at x = 3 has equation

y - f (3) = f ' (3) (x - 3)

y - 24 = 26 (x - 3)

y = 26 x - 54

We also want to find any other tangent lines parallel to this one, which requires finding all x for which f '(x) = 26. We could use the same limit definition as in part (a), but to save time, we exploit the power rule to get

f '(x) = 3 x² - 1

Then solve for when this is equal to 26:

3 x² - 1 = 26   ==>   x² = 9   ==>   x = ±3

The other tangent line occurs at x = -3, for which we have f (-3) = -24, and so the equation for the tangent is

y - f (-3) = 26 (x - (-3))

y + 24 = 26 (x + 3)

y = 26 x + 54

Answer:

C. -2n² - n + 5

Step-by-step explanation:

In expression C, the coefficient of the n term is -1;

  The expression in choice C is given as:

               -2n² - n + 5

The coefficient is the number before a variable;

  For n², the coefficient is -2

    for n, the coefficient is -1

Answer:

5x-5

Step-by-step explanation:

add the expression and simplify 2x - 1 + 3 x  -4 add 2x and 3x

5x-1-4 subtract 4 from -1

equals 5x-5

Answer:

nope

Step-by-step explanation:

Answer:

0.070

Step-by-step explanation:

Y = number on trial

Y has a negative binomial distribution

r = 3

P = 30% = 0.3 probability of positive indication.

P(Y = 11) probability of 11 employees that must be tested to get 3 positives

Y-1Cr-1*p^r*q^(y-r)

Y-1 = 11-1 = 10

r-1 = 3 -1 = 2

10C2 x 0.3³x0.7⁸

45x0.027x0.05764801

= 0.070

This is the probability that 11 employees must be tested to get 3 positives.

Answer:

There are two solutions

1.x =(8-√152)/4=2-1/2√ 38 = -1.082

2.x =(8+√152)/4=2+1/2√ 38 = 5.082

Step-by-step explanation:

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

[tex]\frac{dm}{dt} = -\frac{m}{\tau}[/tex] (Eq. 1)

Where:

[tex]\frac{dm}{dt}[/tex] - First derivative of mass in time, measured in miligrams per year.

[tex]\tau[/tex] - Time constant, measured in years.

[tex]m[/tex] - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

[tex]\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt[/tex]

[tex]\ln m = -\frac{1}{\tau} + C[/tex]

[tex]m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }[/tex] (Eq. 2)

Where:

[tex]m_{o}[/tex] - Initial mass of isotope, measured in miligrams.

[tex]t[/tex] - Time, measured in years.

And time is cleared within the equation:

[tex]t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right][/tex]

Then, time constant can be found as a function of half-life:

[tex]\tau = \frac{t_{1/2}}{\ln 2}[/tex] (Eq. 3)

If we know that [tex]t_{1/2} = 5730\,yr[/tex] and [tex]\frac{m(t)}{m_{o}} = 0.35[/tex], then:

[tex]\tau = \frac{5730\,yr}{\ln 2}[/tex]

[tex]\tau \approx 8266.643\,yr[/tex]

[tex]t = -(8266.643\,yr)\cdot \ln 0.35[/tex]

[tex]t \approx 8678.505\,yr[/tex]

The wood was cut approximately 8679 years ago.

Answer:

Y=2x-1

Step-by-step explanation:

In order to find the slope, its rise over run. So you would move from (0,-1) to the next point it intercepts, (1,1) and find it from there

As for the Y-Intercept, it would just be wherever the line connects with the Y axis, which happens to be (0,-1) or Negative 1.

Answer:

a. -14

b. -13

c. -5

d. -3

e. -12

f. 0

Step-by-step explanation:

hope it helps

Answer:

A is -14.

B is -13

C is -5

D is -3

E is -12

F is 0

Step-by-step explanation:

A, B, E both numbers are negative so you just add them together and add a negative sign.

C would read 4-9

D 10-7 and add a - to the answer

F is 6-6

Answer:7 to 3

Step-by-step explanation:

Answer:

3:10

Step-by-step explanation:

3 Parrots

Total Number of Birds: 3+7=10

Answer:

what you have to do is do 30000 * 5 and then do 6 divided by the number and then four times that number and whatever the answer you get be your answer hope this help

Answer:

7.21

Step-by-step explanation:

Given that:

P1=(-1,3) and P2=(5,-1)

Distance between two points :

d = Sqrt[(x2 - x1)² + (y2 - y1)²]

x1 = - 1 ; y1 = 3

x2 = 5 ; y2 = - 1

d = Sqrt[(5 - (-1))² + ((-1) - 3)²]

d = Sqrt[(5 + 1)² + (-1 - 3)²]

d = sqrt[(6)^2 + (-4)^2]

d = sqrt(36 + 16)

d = sqrt(52)

d = 7.21

Answer:

A. 1 in. = 22.5 mi

Step-by-step explanation:

Since 22.5 x 10 = 225, we can conclude that this will fit the scale needed. B. is incorrect because it is simply illogical in context with a scale and the question. C. is incorrect since 10 x 0.04 is 0.4, which does not equal 10. D. is incorrect since we need the scale to add up to equal 225 mi, not 22.5.

Hope this helps!

Answer:

-132/5

Step-by-step explanation:

-4(2x+13) + 3x = 80

-8x - 52 + 3x = 80

-5x = 80+52

5x = -132

x = -132/5

Feel free to mark this as brainliest! :D

you should just have to times the yards by three like the second one is 12

10/4  if its right also have a good my dude

Step-by-step explanation:

The order of the numbers doesn't matter, so we'll use combinations instead of permutations.  The number of combinations is:

₄₅C₈ = 215,553,195

So the probability of a ticket having the winning combination is 1 / 215,553,195.

The expected value to the state is:

E(X) = 10,000 (1) ($2) + 10,000 (1 / 215,553,195) (-$1,000,000)

E(X) = $19954

The expected value to you is:

E(X) = 10,000 (1) (-$2) + 10,000 (1 / 215,553,195) ($1,000,000)

E(X) = -$19954

Answer:

C

Step-by-step explanation:

Answer:

(-6,3)

Step-by-step explanation:

Answer:

0.948

Step-by-step explanation:

Given that:

Number of character ID = 32

Numbers = 0 - 9 = 10

Alphabets = A - F = 6

Likelihood of each number or alphabet is equal

Probability that atleast 16 characters in the ID are numbers

Probability of success (p) = required outcome / Total possible outcomes

p = 10/(10 + 6) = 5/8

P(at least 16 numbers), similar to 1 - p(at most 15)

Using the specified calculator :

Binomcdf(number of trials, p, 15) = 0.0520

1 - 0.0520 = 0.948

Answer:

is leo has d dollars then dale has 2d + 3 dollars

Step-by-step explanation:

dale has twice the amount and three extra dollars.

so 2 x d is 2d

2d + 3

Answer:

[tex]6k^{11}[/tex]  

I hope this helps!

Answer:

6 k^ 11

Step-by-step explanation:

2k^8×3k^3

2*3  * k^8 * k^3

6 * k^8 * k^3

When multiplying exponents with the same base, we can add the exponents

6 k^( 8+3)

6 k^ 11