Please help need this done asap

Answer:

Step-by-step explanation:

Chinese people eat beans so it would be Chinese

people

The program should print the integers according to this formula is

nums[0][0]=a;

nums[0][1]=b;

nums[1][0]=c;

nums[1][1]=d;

nums[0][2]= nums[0][0] + nums[0][1]; //a+b

nums[1][2]= nums[1][0] + nums[1][1]; //c+d

nums[2][0] = nums[0][0] + nums[1][0]; //a+c

nums[2][1] = nums[0][1] + nums[1][1]; //b+d

//sum = (a+b) + (c+d) + (a+c) + (b+d)

nums[2][2] = nums[0][2] + nums[1][2] + nums[2][0] + nums[2][1];

The nums array is 2 dimensional as shown below.

row, column column 0 column 1 column 2

row 0 a b a+b

row 1 c d c+d

row 2 a+c b+d (a+b)+(c+d)+(a+c)+(b+d)

The first index of an array always starts from 0.

Thus, nums[rows][columns] is used to access each element of the array.

The sum of first row elements is to be stored in the last index of row0, that is in nums[1][2].

Thus we equate nums[0][2] = nums[0][0] + nums[0][1]

Similarly, for 2nd row; nums[1][2] = nums[1][0] + nums[1][1]

The sum of first column is to be stored in last index of column0.

Thus, nums[2][0] = nums[0][0] + nums[1][0]

and for 2nd column,

nums[2][1] = nums[0][1] + nums[1][1].

Thus, the answer is--  

-------------------------------------------------------------------------------------------------------------------------------------

nums[0][0]=a;

nums[0][1]=b;

nums[1][0]=c;

nums[1][1]=d;

nums[0][2]= nums[0][0] + nums[0][1]; //a+b

nums[1][2]= nums[1][0] + nums[1][1]; //c+d

nums[2][0] = nums[0][0] + nums[1][0]; //a+c

nums[2][1] = nums[0][1] + nums[1][1]; //b+d

//sum = (a+b) + (c+d) + (a+c) + (b+d)

nums[2][2] = nums[0][2] + nums[1][2] + nums[2][0] + nums[2][1];

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The goal is to determine whether or not the following binary operations are closed.

A. Subtraction of positive integers: Under normal substation operation, a set of positive integers is not near. Since 1∈Ζ⁺ and 2∈Ζ⁺ but (2-1) = ₋1∉Z⁺.

B. A division of nonzero integers: Non-zero integer set Z/{0} is not closed under the operation. Since 1∈Z/{0} and 2∈ Z/{0} but 1/2 ∉ Z/{0}.

C.  Function composition of polynomials with real coefficients: The set of polynomials with real coefficients is closed when using the typical binary operator. Use the obvious conclusion that a polynomial is a combination of two polynomials [tex]f(x)[/tex] and [tex]g(x)[/tex]. Since every polynomial coefficient is real, every polynomial's composition will also have real coefficients.

D. The multiplication of 2×2 matrices with integer entries: Under the action of standard matrix multiplication Μ₂ₓ₂ (Z), the collection of matrices with integer elements, is close.

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Christopher's statement "whenever you multiply a whole number by a fraction the product is either greater or less than the whole number" is correct.

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

The statement made by Christopher is correct, this is because a fraction is always either greater or lesser than 1. And multiplying a fraction to a whole number will give result either greater or less than the whole number, depending upon the type of fraction it is.

For example let's take the number 100,

Let's take a proper fraction, 2/5. Therefore, the result will be,

100 × (2/5) = 40

Let's take an improper fraction, 7/5. Therefore, the result will be,

100 × (7/5) = 140

Hence, Christopher's statement is correct.

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Answer:

f(3) = 5

f(8) = 3

f(-1) = 0

Step-by-step explanation:

Just plug in the number from the parentheses into the inequalities and whichever makes the inequality true plug into that equation so for example f(3) = ?

first plug 3 into the inequalities: 3 ≤ 0, 0 < 3 ≤ 5, 3 > 5

then find the one that's true which is: 0 < 3 ≤ 5  

then plug into the equation that corresponds to that inequality: 2(3) - 1 → 6 - 1 = 5

We prove that QR≅SR, using SAS to show triangle PRQ is congruent to triangle PRS. So option B is correct.

In the given question;

Given: PR bisects ∠QPS. PQ=12 units, and PS=12 units.

Prove: QR≅SR

We have to find how we prove QR≅SR.

As we can see that;

PQ = PS

Since PR is bisector.

So PR is common in both triangles PRQ and PRS.

PR=PR

Since PR is bisector.

So ∠PRQ=∠PRS

As we know that if two sides and one angle are congruent, then using the Side-Angle-Side (SAS) Theorem, the both triangle is congruent.

So ∠PRQ≅∠PRS

So QR≅SR

Hence, we prove that QR≅SR, using SAS to show triangle PRQ is congruent to triangle PRS. So option B is correct.

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The average rate of change of the function f(x) from x = 1 to x = 2 is, -3.75 when the function f(x)=20(1/4)ˣ.

Given that,

We have to find what is the function f(x)=20(1/4)ˣ average rate of change from x = 1 to x = 2.

We know that,

Average rate of change(A(x)) of f(x) over a interval [a,b] is given by:

A(x)=(f(b)-f(a))/b-a

We get the function:

f(x)=20(1/4)ˣ

Now, the average rate of change from x = 1 to x= 2

At x = 1

Then;

f(1)=20(1/4)¹=5

At x = 2

Then;

f(2)=20(1/4)²=1.25

Substitute these in above formula we have;

A(x)=f(2)-f(1)/2-1=-3.75

Therefore, The average rate of change of the function f(x) from x = 1 to x = 2 is, -3.75 when the function f(x)=20(1/4)ˣ.

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The dimensions of the package of maximum volume that can be sent are 20 inches by 40 inches.

Let us represent the length of the square cross-section of the postal package with x, and the width of the package with y.

So, the perimeter is given by the equation -

y + 4x = 120

y = 120-4x    -----------(1)

the volume will be

V = [tex]x^{2} y[/tex]        -----------(2)

Now, substitute (1) in (2), and we get,

V = [tex]x^{2}[/tex] (120-4x)

V = 120[tex]x^{2}[/tex] - 4[tex]x^{3}[/tex]

Differentiating with respect to x, we get,

V' = 240x - 12[tex]x^{2}[/tex]

V'=0

hence, 240x - 12[tex]x^{2}[/tex] = 0

12[tex]x^{2}[/tex] = 240x

dividing by 120x on both sides,

hence, x=20

Now, we know that,

y = 120 - 4x

y = 120-4(20)

y = 120-80

y=40

Hence, the dimensions that maximize the volume of the package are 20 inches by 40 inches.

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The total number of oranges present in the bag was 21.

For the stated question.

Let the total number of oranges in the bag be 'x'.

Total stale oranges = 7.

Thus,

Probability (first orange is stale) = Total stale oranges/ Total oranges.

Probability (first orange is stale) = 7/x

Probability (second orange is stale) = 6/(x - 1).

But, probability to pick two stale oranges is 2/21

7/x . 6/(x - 1) = 2/21

On solving,

x ² - x - 441 = 0

x = 21

Thus, the total number of oranges present in the bag was 21.

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Answer:

green

Step-by-step explanation:

green

Answer:

should be the first one because 12 is the common factor between the two of them(had to be 20 characters long so i could answer your question)

Answer:

g(x)=1/2x+2

Step-by-step explanation:

the coordinates provided here are (2,3) and (6,5)
slope intercept form is g(x)=mx+b

m is slope and b is y intercept

We use slope formula to find slope y2-y1/x2-x1

5-3/6-2

2/4

1/2

Now we can find b by putting the values in

g(x)=1/2x+b

5=1/2(6)+b

5=3+b

-3 -3

2=b

g(x)=1/2x+2

Hopes this helps please mark brainliest

The odds she will win this competition is 14 to 11.

What is probability?

Odds in favor of an event is ratio of probability of an event to its completion:

Probability =0.56 / 1-0.56

= 0.56/0.44

= 56/44

= 14/11

Hence, the odds she will win this competition is 14 to 11.

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The following is a code in python.

Python is a popular computer programming language used to create software and websites, automate processes, and analyze data. Python is a general-purpose language, which means it can be used to make many different types of programs and isn't tailored for any particular issues.

One of Python's biggest benefits is the variety of libraries and frameworks it offers. Everything from data visualization, machine learning, data science, natural language processing, and complex data analysis uses the Python Library, from NumPy to TensorFlow.

#Specify the function in

DefinedSum(tu)

# Verify whether the tuple contains 0

if len(tu) == 0

#Then, give back 0

return 0

#Otherwise

else:

#invoke the recursive function.

return tu[0]+Sum (tu[1:])

Set a variable of the tuple type

tu=(2,5,1,8,10)

#print, then invoke the function.

 print("The total of tuple is:"), sum(tu),

Output:

The sum of tuple is: 26

Here, we define the method "sum()" and send the parameter "tu" to the function, which saves the value of the tuple type.

If the length of the tuple is 0, then the if conditional expression should verify the condition and return 0.

If not, invoke the function, return the tuple's total (which is determined recursively), and exit.

Last but not least, initialize the "tu" variable of the tuple type, print, then run the sum function.

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When two variables are correlated negatively, the other variable's value falls as the value of the first variable rises.

When two variables are correlated negatively, the other variable's value falls as the value of the first variable rises.

Zero denotes the absence of a correlation: There is no propensity is for variables to change simultaneously.

Thus, when two variables are correlated negatively, the other variable's value falls as the value of the first variable rises.

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The percent decrease in the number of people who went to the pool over these four weeks is 15%.

A percentage is a value or ratio that may be stated as a fraction of 100. If we need to calculate a percentage of a number, we should divide it's entirety and then multiply it by 100.

The number of people by the fourth week will be:

= 1060 - 105 + 145 - 199

= 901

The percentage decrease will be:

= (1060 - 901) / 1060 × 100

= 159/1060 × 100

= 15%

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answer:

(1/y)^3(1/z)^4

step-by-step explanation:

negative exponents just move the number to the denominator. so all you have to do is move the y & z to the denominator to change the exponents to positive. hope that helps!

The equation that describes the proportional relationship between the variables on the graph is given as follows:

y = 12x.

The general format of a proportional relationship is defined as follows:

y = kx.

In which k is the constant of proportionality, and hence the output variable y is obtained as the multiplication of the input x and the constant of proportionality k.

One point from the graph given at the end of the answer is given as follows:

(8, 96).

Hence the constant of the proportional relationship is given as follows:

k = 96/8 = 12.

Then the equation is of:

y = 12x.

Meaning that the output variable y is obtained by the multiplication of the input variable x and the constant of proportionality k.

The graph is given by the image presented at the end of the answer.

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Answer:

The answer is $1.70

Step-by-step explanation:

What I did is $31.80-21.60=$10.20. $10.20 is the amount of money for all 6 pendants, so to find how much 1 pendant is I just divided $10.20 by 6 which got me $1.70. Hope that helped you. :)

The inequality contain -12 in its solution is  x + 5 ≤ -4.

What is inequality?

The phenomenon of an unfair and/or unequal distribution of opportunities and resources among the people who make up a society is referred to as inequality. To different people and in various contexts, the word "inequality" may mean different things.

We have to find from the given inequalities which inequality has -12 in its solution.

Consider, the given inequalities

(1)  x + 6 < -8

⇒ x < - 8 - 6

⇒ x < -14

This inequality does not contain -12 in its solution.

(2) x + 4 ≥ - 6

⇒  x ≥ -6 - 4

⇒ x ≥ - 10

This inequality does not contain -12 in its solution.

(3) x - 3 > -10

⇒  x  > -10 + 3

⇒  x > -7

This inequality does not contain -12 in its solution.

(4) x + 5 ≤ -4

⇒  x ≤ - 4 - 5

⇒  x ≤ -9

This inequality contain -12 in its solution.

Hence, the inequality contain -12 in its solution is  x + 5 ≤ -4.

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This is the UML diagram for the development of the program, in which Shapes 2D is the superclass and Circle, Square, Triangle, Rectangle, Rhombus, and Parallelogram are subclasses.

​​​​​​​This is the program in C++ demonstrating the above classes.

#include<iostream>

using namespace std;

class shapes

{

public:

   string name;

   string color;

   virtual void getAttributes()=0;

};

class Circle: public shapes

{

public:

   float radius;

   Circle(string n,string c, float r)

   {

       name=n;

       color=c;

       radius=r;

   }

   float getPerimeter()

   {

       return(2*(3.142)*radius);

   }

   float getArea()

   {

       return((3.142)*(radius*radius));

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Square:public shapes

{

public:

   float side;

   Square(string n,string c, float s)

   {

       name=n;

       color=c;

       side=s;

   }

   float getPerimeter()

   {

       return(4*side);

   }

   float getArea()

   {

       return(side*side);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Triangle:public shapes

{

public:

   float base;

   float height;

   float side1;

   float side2;

   float side3;

   Triangle(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter side1\n";

       cin>>side1;

       cout<<"Enter side2\n";

       cin>>side2;

       cout<<"Enter side3\n";

       cin>>side3;

       return(side1+side2+side3);

   }

   float getArea()

   {

       cout<<"Enter base\n";

       cin>>base;

       cout<<"Enter height\n";

       cin>>height;

       return((0.5)*base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rectangle:public shapes

{

public:

   float length;

   float breadth;

   Rectangle(string n,string c, float l,float b)

   {

       name=n;

       color=c;

       length=l;

       breadth=b;

   }

   float getPerimeter()

   {

       return(2*(length+breadth));

   }

   float getArea()

   {

       return(length*breadth);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Rhombus:public shapes

{

public:

   float diagonal1;

   float diagonal2;

   float side;

   Rhombus(string n,string c)

   {

       name=n;

       color=c;

   }

   float getPerimeter()

   {

       cout<<"Enter Side\n";

       cin>>side;

       return(4*side);

   }

   float getArea()

   {

       cout<<"Enter diagonal 1\n";

       cin>>diagonal1;

       cout<<"Enter diagonal 2\n";

       cin>>diagonal2;

       return((0.5)*diagonal1*diagonal2);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

class Parallelogram:public shapes

{

public:

   float base;

   float height;

   Parallelogram(string n,string c, float b,float h)

   {

       name=n;

       color=c;

       base=b;

       height=h;

   }

   float getPerimeter()

   {

       return(2*(base+height));

   }

   float getArea()

   {

       return(base*height);

   }

   void getAttributes()

   {

       cout<<"Name  :"<<name<<endl;

       cout<<"Color :"<<color<<endl;

   }

};

int main()

{

   int choice;

   while(1)

   {

       cout<<"\n\nEnter your choice :";

       cout<<"\n1 for Circle\n";

       cout<<"2 for Square\n";

       cout<<"3 for Triangle\n";

       cout<<"4 for Rectangle\n";

       cout<<"5 for Rhombus\n";

       cout<<"6 for Parallelogram\n";

       cin>>choice;

       system("cls");

       switch(choice)

       {

       case 1:

           {

               float r;

               cout<<"Enter radius\n";

               cin>>r;

               Circle c("Circle","Yellow",r);

               c.getAttributes();

               cout<<"Perimeter : "<<c.getPerimeter()<<endl;

               cout<<"Area : "<<c.getArea()<<endl;

           }break;

       case 2:

           {

               float side;

               cout<<"Enter side\n";

               cin>>side;

               Square s("Square","Red",side);

               s.getAttributes();

               cout<<"Perimeter : "<<s.getPerimeter()<<endl;

               cout<<"Area : "<<s.getArea()<<endl;

           }break;

       case 3:

           {

               Triangle t("Triangle","Green");

               t.getAttributes();

               cout<<"Perimeter : "<<t.getPerimeter()<<endl;

               cout<<"Area : "<<t.getArea()<<endl;

           }break;

       case 4:

           {

               float l,b;

               cout<<"Enter Length and breadth\n";

               cin>>l>>b;

               Rectangle r("Rectangle","Blue",l,b);

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 5:

           {

               Rhombus r("Rhombus","Purple");

               r.getAttributes();

               cout<<"Perimeter : "<<r.getPerimeter()<<endl;

               cout<<"Area : "<<r.getArea()<<endl;

           }break;

       case 6:

           {

               float b,h;

               cout<<"Enter base\n";

               cin>>b;

               cout<<"Enter height\n";

               cin>>h;

               Parallelogram p("Parallelogram","Pink",b,h);

               p.getAttributes();

               cout<<"Perimeter : "<<p.getPerimeter()<<endl;

               cout<<"Area : "<<p.getArea()<<endl;

           }break;

       }

   }

}

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The equation to determine the number of persons is x/(y+z) and total 2 people are there in total.

Given: Several buddies want to visit the theme park. Spending money for parking and entry totals $69.75. Tickets cost $17.50 per person, tax included, and parking is $17.25.

Let,

x = total amount for parking and admission fee

y = ticket per person

z = parking cost per person

Total number of people who can go to the amusement park is given as:

= x/(y+z)                                                                                               =69.75/(17.50+17.25)

= 2

Therefore, the equation to determine the number of persons is x/(y+z)   and total 2 people are there in total.

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The linear equation for the attendance in terms of the price, p is

2600= -150p + 3650

A =m*p + b

where A= attendance , m = slope , b = y-intercept and p = price

When p=11 then A=2000 , i  e , (11, 2000).

When p= 7 , then A=2600, i .e ,  (7 , 2600).

m= (b-d)/(a-c)

=> m = (2600-2000)/(7 - 11)

        = -150

Therefore , 2600= -150p + b

To get the value of b,

putting the value of p in the obtained equation,

we get,

2600= -150 * 7+ b

2600 = -1050 + b

b = 3650

Hence , our equation becomes

2600= -150p + 3650

Linear equations are equations of the first order. The linear equations are defined for lines in the coordinate system. When the equation has a homogeneous variable of degree 1 (i.e. only one variable), then it is known as a linear equation in one variable. A linear equation can have more than one variable. If the linear equation has two variables, then it is called linear equations in two variables and so on

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Answer:

1.5

Step-by-step explanation:

Answer:

The zeros of ƒ(x) are 4, 1, and -2.

The big oh notation for the given algorithm that is T := 0 for i := 1 to n for j := 1 to n t := t + i + j will be O(n).

Big O notation is a type of mathematical notation that expresses how a function limits itself when the argument goes to zero or infinity. Big O Notation is a technique for expressing how time-consuming an algorithm is. As the input increases, it calculates how long it will take to perform an algorithm. In other words, it determines an algorithm's worst-case time complexity. The maximum runtime of an algorithm is expressed using the Big O Notation in data structures.

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Answer:

first this is English

providential

slow congealed

innovative, effectual

more easy to