Please help! Need it ASAP!!!

Y=-1/4+4

-1/4 is the slope and the 4 is the y-intercept (where the line touches the y-axis)

I hoped this help's!!!

Answer:

y=-1/4x+4

Step-by-step explanation:

Since the line is decreasing the slope in down 1 and to the right 4 and the y-intercept is 4. Hope this helps:)

Answer:

1.5

- 3/4

Step-by-step explanation:

To find the opposite of a number, you just have to either add or remove a negative sign.

- 1.5 is negative, so the opposite of negative 1.5 is positive 1.5 or 1.5

3/4 is positive, so the opposite of positive 3/4 is negative 3/4 or - 3/4

I Hope That This Helps! :)

Answer:

1.5

- 3/4

Step-by-step explanation: CREDIT TO GUY ABOVE!

Answer:

about 6000π

Step-by-step explanation:

Answer:

x^2+5x-14

Step-by-step explanation:

you multiply both equations so that you get:

x^2-2x+7x-14

and then you simplify it to:

x^2+5x-14

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Answer:

5=x=x-1

Step-by-step explanation:

Mutiply each equation by 5x

You will get 5=x=x-1

Answer:

4

Step-by-step explanation:

7/2+1/2=8/2

8/2=6=5/2

8/2-5/2=3/2

3/2=6

3/2=1.5

6/1.5=4

Answer:

[tex]a+b+c=9+8+6=23[/tex]

Step-by-step explanation:

Let’s first simplify our expression. We have:

[tex]\displaystyle {\sqrt2+\frac{1}{\sqrt2}+\sqrt3+\frac{1}{\sqrt{3}}[/tex]

For the second term, multiply both the numerator and denominator by √2. This yields:

[tex]\displaystyle \frac{1}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{2}}{2}[/tex]

Similarly, for the fourth term, multiply both the numerator and denominator by √3. This yields:

[tex]\displaystyle\frac{1}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}=\frac{\sqrt{3}}{3}[/tex]

Hence, our expression is now:

[tex]\displaystyle =\sqrt{2}+\frac{\sqrt{2}}{2}+\sqrt{3}+\frac{\sqrt{3}}{3}[/tex]

Let’s combine them. First, we will need common denominators.

Our denominators are 2 and 3. So, our common denominator will be its LCM.

The LCM of 2 and 3 is 6.

Hence, let’s make each term’s denominator 6.

For the first term, we can multiply both layers by 6. Hence:

[tex]\displaystyle \sqrt{2}=\frac{6\sqrt{2}}{6}[/tex]

For the second term, we can multiply both layers by 3. Hence:

[tex]\displaystyle \frac{\sqrt{2}}{2}=\frac{3\sqrt{2}}{6}[/tex]

For the third term, we can multiply both layers by 6. Hence:

[tex]\displaystyle \sqrt{3}=\frac{6\sqrt{3}}{6}[/tex]

And for the last term, we can multiply both layers by 2. Hence:

[tex]\displaystyle \frac{\sqrt{3}}{3}=\frac{2\sqrt{3}}{6}[/tex]

So, our expression is:

[tex]\displaystyle =\frac{6\sqrt{2}}{6}+\frac{3\sqrt{2}}{6}+\frac{6\sqrt{3}}{6}+\frac{2\sqrt{3}}{6}[/tex]

Add:

[tex]\displaystyle =\frac{6\sqrt{2}+3\sqrt{2}+6\sqrt{3}+2\sqrt{3}}{6}[/tex]

Combine like terms:

[tex]\displaystyle=\frac{9\sqrt{2}+8\sqrt{3}}{6}[/tex]

This cannot be simplified. So, c is as small as possible.

Hence: a=9, b=8, and c=6.

Therefore:

[tex]a+b+c=9+8+6=23[/tex]

Answer:

Slope: Rise/run

= -2/4

= -1/2

Answer:

-1/2

Step-by-step explanation:

Like I said in your previous question!!

RISE/RUN.

Choose a point, rise how many you need to, then run. Since you run 'backwards' after rising, this slope is negative!

I hope this helps!!

Answer:

B

Step-by-step explanation:

The y-int. is -5 like the equation and the slope is positive

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a .

Parallel lines → a & c

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b .

Parallel lines → d & e

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

c .

I couldn't read it....

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

d .

Parallel lines → ---

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e .

Parallel lines → b & c

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f .

Parallel lines → a & c

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

√3, and -√3

Step-by-step explanation:

to find the zeros or roots of the polinomial x²-3 make it equal to zero and solve for x

x²-3=0 add 3 to both sides to isolate x

x² = 3 squareroot both sides

√x²= √3

x= ±√3 are the two zeros

Answer:

rate of change = 1.75 over 1 or just 1.75

Step-by-step explanation:

this represents the cost of each cantaloupe. This basically means that each cantaloupe is $1.75.

Answer:

About 19.8

Step-by-step explanation:

First find the side lengths. In this example, 56/4=14

Next use the Pythagorean theorem, to us it, here's the formula a squared plus b squared equals c squared. For this example use 14 squared plus 14 squared which equals 392.

Finally take the square root of 392 because we still need to take the squared out in c. The square root of 392 rounded to the nearest tenth is 19.8.

Answer:

ummm im pretty sure its d

Step-by-step explanation:

Answer:

im pretty sure its last option y=2x

Step-by-step explanation:

on the graph it touches all even numbers

Answer:

Step-by-step explanation:

The slope of a line can be calculated:

[tex]m = \frac{y_2-y_1}{x_2-x_1}\\[/tex]

We know that the slope is 7, so we want to solve for [tex]y_2[/tex]

[tex]\frac{n-(-4)}{5-4} = 7\\\frac{n+4}{1} = 7\\n+4 = 7\\n = 3[/tex]

Answer:

A. 4

Step-by-step explanation:

90% of 40 is = 36

40 - 36 = 4

Since he got 36 right out of 40, he got 4 wrong.

Answer:

y = -18

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define systems

y = 5x - 3

3x - 2y = 27

Step 2: Rewrite systems

Step 3: Redefine

y = 5x - 3

x = 2/3y + 9

Step 4: Solve for y

The translation rule applied to the quadrilateral ABCD is T(1,0). The correct option is B.

A translation in mathematics moves a shape left, right, up, or down but does not turn it. The translated (or image) shapes appear to be the same size as the original shape, indicating that they are congruent.

Given that the quadrilateral is translated on the x-y plane from ABCD to A'B'C'D'.

The translation applied to the coordinates of the quadrilateral will be one unit to the right and zero units up or down.

The translation will be written as,

T ( 1 , 0 )

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Answer:

4s

Step-by-step explanation:

The perimeter of a square is 4 times it's side length.

Formula for a perimeter of a square: [tex]4s[/tex]

s - side length

Hope this helps.

Answer:

the answer is A because it has all numbers less than 15

Step-by-step explanation:

Answer:

I think it's 7.5 correct me if i'm wrong

Step-by-step explanation:

7.5 is half of 15

Use the midsegement theorem

Answer:

.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6​

Step-by-step explanation:

.Graph f(x) = 6x + 2 and g(x) = 6x - 4. Then describe the transformation from the graph of f(x) to the graph of g(x). у 6. 5. 4. 3. 2 . 0 1 A -3 -2 -1 3 2 -i - 5 4 5 6 -3 ### 5. -6​

The transformation from the graph of f(x) to the graph of g(x) is a vertical shift down by 6 units

The functions are given as:

[tex]f(x) = 6x + 2[/tex]

[tex]g(x) = 6x - 4[/tex]

Subtract function f(x) from g(x),

[tex]k = g(x) - f(x)[/tex]

This gives

[tex]k = 6x - 4 - 6x - 2[/tex]

Collect like terms

[tex]k = 6x- 6x - 4 - 2[/tex]

[tex]k = -6[/tex]

The above represents the unit of translation of function f(x) to g(x).

Hence, the transformation from the graph of f(x) to the graph of g(x) is a vertical shift down by 6 units

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Answer:

1.3,-1, and -4

Answer:

20/8 = 2.5

1/2+1/2+1/2=

1  1/2

Step-by-step explanation:

Ur welcome:)

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

The congruence theorems that can be used for each of the given pair of triangles are;

1) SSS

2) SAS

3)SAS

4) SSS

5) SAS

6) SAS

1) From the image we see that;

FY ≅ CW  

FP ≅ CM  

YP ≅ MW

This means that 3 corresponding sides of the 2 triangles are congruent and as such it means  ΔMCW ≅ ΔFPY using the Side-Side-Side (SSS) congruency theorem.

2) From the image we see that;

∠CBD and ∠BCA are both alternate interior angles and are therefore congruent. Thus;

∠CBD ≅ ∠BCA

Also, we see that;

EB ≅ EC

DB ≅ CA

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;

ΔBED ≅ ΔAEC using the Side-Angle-Side (SAS) congruency theorem.

3) From the image, we see that;

∠SVU ≅ ∠SVT

Using reflexive property, the shared sides give;

SV ≅ SV  

VT ≅ VU

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;

ΔVSU ≅ ΔVST using Side-Angle-Side (SAS) congruency theorem.

4) From the image, we see that;

MN ≅ QP

MQ ≅ NP

Using reflexive property, the shared sides give;

NQ ≅ NQ

This means that 3 corresponding sides of the 2 triangles are congruent and as such it means  ΔQNM ≅ ΔQNP using the Side-Side-Side (SSS) congruency theorem.  

5) From the image, we see that;

GL ≅ HL

GJ ≅ HK  

∠JLG and ∠HLK are vertically opposite angles and as such;

∠JLG ≅ ∠HLK

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;  

ΔQNM ≅ ΔQNP using Side-Angle-Side (SAS) congruency theorem.

6) We observe from the given triangles that;

∠XZY ≅ ∠XZW (They are both right angles = 90°)

Using reflexive property, the shared side is congruent to itself and so;

XZ ≅ XZ  

Also;

ZW ≅ ZY

This means that 2 corresponding sides and an angle of the 2 triangles are congruent and as such it means;  

ΔXYZ ≅ ΔXWZ  using Side-Angle-Side (SAS) congruency theorem.

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Answer:

A. They are equidistant from origin.

The correct statement for the relationship between points N and N' is,

⇒ They are equidistant from origin.

A transformation that occurs when a figure is moved from one location to another location without changing its size or shape is called translation.

Given that;

Rectangle LMNO is rotated 90° clockwise around the origin to create rectangle L'M'N'O'.

Now,

Since, Rectangle LMNO is rotated 90° clockwise around the origin to create rectangle L'M'N'O'.

Hence, We know that;

After rotation of 90° clockwise around the origin the shape are equidistance from the origin.

Thus, The relationship between points N and N' is,

⇒ They are equidistant from origin.

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Answer:

= 3

/3 + 5a/12 = 9/4

Answer:

If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division. Solve 3y + 2 = 11. Subtract 2 from both sides of the equation to get the term with the variable by itself.

Step-by-step explanation:

hope this helps, sorry if late