The cross-sectional area of the cylindrical copper wire is 1.7 x 10⁻⁹ m².
What is meant by resistivity ?Resistivity is defined as the amount of electrical resistance of a conductor, per unit cross-sectional area and unit length.
Here,
Resistance of the wire, R = 10 Ω
Length of the wire, l = 1 m
Resistivity of the wire, ρ = 1.7 x 10⁻⁸ Ωm
The expression for the resistivity of a conductor is given as,
ρ = RA/l
where A is the cross-sectional area of the conductor.
Therefore, the area of cross-section of the copper wire,
A = ρl/R
A = 1.7 x 10⁻⁸ x 1/10
A = 1.7 x 10⁻⁹ m²
Hence,
The cross-sectional area of the cylindrical copper wire is 1.7 x 10⁻⁹ m².
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Convert 13.7g to mg
HELP ASAP-WILL GIVE BRAINLIEST-NO FILES
When a person is moving a desk, which one of the following has the greater amount of force?
A. the desk itself
B. the push from the person moving the desk
C. the drawers as they slide in and out
Answer:C
Explanation:
What is acceleration?
[tex]\huge\boxed{✍ ACCELERATION\hookrightarrow}[/tex]
⎆ Acceleration is defined as the ⇻ rate of change of velocity with respect to time / rate of change of velocity in unit time.
⎆ It's a vector quantity (it has both magnitude & direction).
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
# ꧁❣ RainbowSalt2²2² ࿐
what is the work done on the object by the machine.
The work input is the work done on a machine. (Input work)
A man has 887.5 J of kinetic energy while running with a velocity of 5 m/s. What is his mass?
Answer:
The mass of the man is 71 kg
Explanation:
Given;
kinetic energy of the man, K.E = 887.5 J
velocity of the man, v = 5 m/s
The mass of the man is calculated as follows;
K.E = ¹/₂mv²
where;
m is the mass of the man
2K.E = mv²
m = 2K.E / v²
m = (2 x 887.5) / (5)²
m = 71 kg
Therefore, the mass of the man is 71 kg
Water in an electric teakettle is boiling. The power absorbed by the water is 0.90 kW. Assuming that the pressure of vapor in the
kettle equals atmospheric pressure, determine the speed of effusion of vapor from the kettle's spout if the spout has a cross-
sectional area of 1.60 cm2. Model the steam as an ideal gas.
Answer:
v = 4.233 m/s
Explanation:
By applying the rate of boiling from [tex]Q= mL_v[/tex];
the rate of the boiling can be described as:
[tex]\mathcal{P} = \dfrac{Q}{\Delta t} \\ \\ \mathcal{P} = \dfrac{mL_v}{\Delta t}[/tex]
The mode of the steam (water vapor) as an ideal gas can be illustrated by formula:
[tex]P_oV_o = nRT[/tex] --- (1)
where;
n = number of moles;
[tex]n = \dfrac{mass (m)}{Molar mass (M)}[/tex]
Then; equation (1) can be rewritten as:
[tex]P_oV_o = (\dfrac{m}{M}) RT \\ \\ \dfrac{P_oV}{\Delta T} = \dfrac{m}{\Delta t} ( \dfrac{RT}{M})[/tex]
∴
[tex]\dfrac{m}{\Delta t} = \dfrac{\mathcal{P}}{L_v}[/tex]
Then:
[tex]P_o \times A \times v= \dfrac{\mathcal{P}}{L_v}\Big ( \dfrac{RT}{M }\Big)[/tex]
making (v) the subject of the formula:
[tex]v= \Big ( \dfrac{\mathcal{P} RT}{M\times L_v \times P_o \times A }\Big)[/tex]
Given that:
[tex]\mathcal{P}[/tex] = 0.90 kW = 900 W
R(rate constant) = 8.314 J/mol.K
Temperature at 100° C = 373K
For water vapor:molar mass= 18.015 g/mol ≅ 0.0180 kg/mol
Latent heat of vaporisation [tex]L_v[/tex] = 2.26 × 10⁶ J/kg
Atmospheric pressure [tex]P_o = 1.013 \times 10^6 \ N/m^2[/tex]
Cross sectional area A =1.60 cm² = 1.60 × 10⁻⁴ m²
[tex]v= \Big ( \dfrac{900 W (8.314 \ J/mol.K)(373)}{0.0180 \ kg/mol) (2.26 \times 10^6 \ J/kg) (1.013 \times 10^5 \ N/m^2)(1.60 \times 10^{-4} \ m^2)}\Big)[/tex]
v = 4.233 m/s
Convert 0.0334 to scientific notation
Answer:
[tex]3.34 * 10^{-2}[/tex]
Explanation:
Scientific notation is writing a number between 1 and 10, and multiplying the number by a power of 10.
Our number is 0.0334
Let's move the decimal point of the number to make it so that the number is at least 1 and less than 10.
We get: 3.34
We moved the decimal point 2 places to the right, so the power of 10 would be -2
Putting what we got together, the scientific notation for the number is:
[tex]3.34 * 10^{-2}[/tex]
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 5.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do
Answer:
1568 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 80 Kg
Distance (d) = 5 m
Coefficient of kinetic friction (μ) = 0.4
Workdone (Wd) =?
Next, we shall determine the normal reaction. This can be obtained as follow:
Mass (m) = 80 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?
N = mg
N = 80 × 9.8
N = 784 N
Next, we shall determine force of friction. This can be obtained as follow:
Coefficient of kinetic friction (μ) = 0.4
Normal reaction (N) = 784 N
Force of friction (F) =?
F = μN
F = 0.4 × 784
F = 313.6 N
Finally, we shall determine the work done. This can be obtained as follow:
Distance (d) = 5 m
Force of friction (F) = 313.6 N
Workdone (Wd) =?
Wd = F × d
Wd = 313.6 × 5
Wd = 1568 J
Thus, the workdone is 1568 J
You have a well-trained athlete (although not specifically a track athlete) come to the lab to perform a Wingate anaerobic test (WAnT). The subject is a 24-year-old male. He is 89.2kg, and 1.85 m tall. His Resting HR is 47 bpm, and his BMI is ~26.The participant does a warm-up on the cycle ergometer to prepare for the test. You are getting the weights ready to be applied to the flywheel. How much resistance will you use (in kg)
Answer:
6.69 kg
Explanation:
Given that:
The mass of the athlete = 89.2 kg
Height = 1.85 m
Resting HR = 47 bpm
BMI = ~26
The essence of the Wingate anaerobic test is to evaluate and access how much energy is released by phosphagen breakdown and anaerobic glycolysis. By applying a fixed amount of weight to that same cycle's weight tray, tension is added to the flywheel. The flywheel resistance is usually set at 0.075 kg per kilogram of body weight.
For athlete sprinters, the resistance is usually set at 1.0 kg which is then multiplied by the body mass up to 1.3 kg
Hence, the amount of the resistance applied for the athlete = (0.075 × 89.2)kg
= 6.69 kg
URGENT!!!!!!!!!: If an electromagnetic wave has a frequency of 6 x 10^5 Hz, what is its
wavelength? Use v/f. The speed of light is 3 x 10^8 m/s.
Answer:
A
Explanation:
because the speed divide by the frequency is equal to the wavelength(in meters)
5×10² m
if something is frictionless does it have thermal energy
Answer:
No
Explanation:
because there is no pressure
Phenotype is the actual genes that make a person True or False
Answer:
True?
Explanation:
Genotype and phenotype are two fundamental terms in the science of genetics. ... An organism's genotype is the set of genes in its DNA responsible for a particular trait. An organism's phenotype is the physical expression of those genes.
The term "phenotype" refers to the observable physical properties of an organism; these include the organism's appearance, development, and behavior. An organism's phenotype is determined by its genotype, which is the set of genes the organism carries, as well as by environmental influences upon these genes.
This is why I think it's true. You don't have to read the rest,but that's why I know.
Answer:
The answer is true
Explanation:
I dont know but trust is probably true.
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 11 A, and that of the vacuum cleaner is 4.0 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in one- half hour.
Answer:
(a) P₁ = 1320 W
(b) P₂ = 480 W
(c) [tex]\frac{E_1}{E_2} = 0.46[/tex]
Explanation:
(a)
The power consumed by the blow dryer can be calculated as follows:
[tex]P_1 = VI[/tex]
where,
P₁ = Power Consumed by the blow dryer = ?
V = Voltage = 120 V
I = Current Rating of the blow dryer = 11 A
Therefore,
[tex]P_1 = (120\ V)(11\ A)\\[/tex]
P₁ = 1320 W
(b)
The power consumed by the blow dryer can be calculated as follows:
[tex]P_2 = VI[/tex]
where,
P₂ = Power Consumed by the vacuum cleaner = ?
V = Voltage = 120 V
I = Current Rating of the vacuum cleaner = 4 A
Therefore,
[tex]P_2 = (120\ V)(4\ A)\\[/tex]
P₂ = 480 W
(c)
[tex]\frac{E_1}{E_2} = \frac{P_1t_1}{P_2t_2}[/tex]
where,
E₁ = Energy used by the blow-dryer
E₂ = Energy used by the vacuum cleaner
t₁ = time of use of the blow-dryer = (15 min)(60 s/1 min) = 900 s
t₂ = time of use of the vacuum cleaner = (1.5 h)(3600 s/1 h) = 5400 s
Therefore,
[tex]\frac{E_1}{E_2} = \frac{(1320\ W)(900\ s)}{(480\ W)(5400\ s)}\\\\\frac{E_1}{E_2} = 0.46[/tex]
The temperatures of one northeastern state range from 105° F in the summer to -25°F in the winter. Express this temperature range in degrees Celsius and in kelvins. *
Farenheit is an interesting unit so the conversions get a bit weird.
To convert from Farenheit to Celcius you follow this formula:
T(°C) = (T(°F) - 32) × 5/9
It is also easier to convert to Celcius to Kelvin shown in this formula:
T(K) = T(°C) + 273.15
To Answer your question:
105° F = 40.5°C
-25° F = -31.7°C
105° F = 313.65K
-25° F = 241.45K
8. Main Idea How do animals reproduce?
Answer: Many multicellular animals like fishes, mammals, birds, etc. reproduce through sexual reproduction process. Even reproduction in domestic animals also occurs through the sexual process. Domestic animals (pets or farm animals) are an essential part of our life. MARK AS BRAINLIST PLZ
Explanation:
A ball of mass 8kg falls from rest from a height of 100m. Neglecting air resistance, calculate its total energy after falling a distance of 40m.
Answer:
Total energy, T= 4704 Joules
Explanation:
Given the following data;
Mass = 8kg
Initial height, h1 = 100m
Final height, h2 = 40 m
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the total energy, T;
T = mg(h1 - h2)
T = 8 * 9.8 * (100 - 40)
T = 78.4 * 60
Total energy, T= 4704 Joules
oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?
Answer:
Mass, m = 6.18 kg
Explanation:
Given the following data;
Frequency, F = 10 Hz
Spring constant, k = 250 N/m
We know that pie, π = 22/7
To find the mass, we would use the following formula;
F = 1/2π√(k/m)
Where;
F is the frequency of oscillation.
k is the spring constant.
m is the mass of the spring.
Substituting into the formula, we have;
10 = 1/2 * 22/7 * √250/m
10 = 22/14 * √250/m
Cross-multiplying, we have;
140 = 22 * √250/m
Dividing both sides by 22, we have;
140/22 = √250/m
6.36 = √250/m
Taking the square of both sides, we have;
6.36² = (√250/m)²
40.45 = 250/m
Cross-multiplying, we have;
40.45m = 250
Mass, m = 250/40.45
Mass, m = 6.18 kg
can any one help me with this?
Question 1 of 5 Which term describes a measurement of the movement of atoms or molecules within an object? O A. Temperature O B. Heat O C. Pressure O D. Density
Answer:
Temperature
Explanation:
A region of vacuum contains both a uniform electric field with magnitude E and a uniform magnetic field with magnitude B.
Part A What is the ratio E/B if the energy density for the magnetic field equals the energy density for the electric field? Express your answer in volts per meter-tesla to three significant figures. IVO ADV A O O ?
Part B If E = 750 V/m, what is B, in teslas, if the magnetic field and electric-field energy densities are equal? Express your answer in teslas. O ALQ * R O 2 ?
Answer:
A) E / B = 2.99 10⁸ V/ mT, B) B = 2.50 10⁻⁶ T
Explanation:
A) the expressions for the energy densities are:
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
indicate that the two densities are equal
½ ε₀ E² = ½ B² /μ₀
E / B = 1 /[tex]\sqrt{\epsilon_o \ \mu_o }[/tex]
we calculate
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹9
E / B = 2.99 10⁸ V/ mT
B) for this case E = 750 V / m, ask the magnetic field
E / B = 1 /[tex]\sqrt{\epsilon_o \ \mu_o}[/tex]
B = E [tex]\sqrt{\epsilon_o \ \mu_o}[/tex]
we calculate
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
Energy densities can be expressed as
u_E = ½ ε₀ E²
u_B = ½ B² /μ₀
When the two densities are equal we use the formula
½ ε₀ E² = ½ B² /μ₀
E / B = 1 / μ₀
E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷)
E / B = 1 /√( 11.1212 10⁻¹⁸)
E / B = 0.29986 10⁹
E / B = 2.99 10⁸ V/ mT
If the magnetic field and electric-field energy densities are equal and E = 750 V / m, we can deduce thatE / B = 1 / √ ξ₀ μ₀
B = E √ ξ₀ μ₀
We substitute the values into the equation
B = 750 √(8.85 10⁻¹² 4π 10⁻⁷)
B = 750 3.3348 10⁻⁹
B = 2.50 10⁻⁶ T
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Pls help! What is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours?
A.
800 km/hr
B.
80 km/hr
C.
0.00125 km/hr
D.
28,800 km/hr
Answer:
800 meters per hour
Explanation:
800 meters per hour is the average speed of an airplane that travels from New York to Los Angeles, a total distance of 4800 km, in 6.0 hours.
Q.4) Two table tennis balls hang with their centers 10.0 cm apart. The charge on ball
A is +12x10°C, and the charge on Ball B is -15x10°C. What is the force of
attraction between the balls?
Answer:
F = 1.62 x 10¹⁴ N
Explanation:
The electrostatic force of attraction between the balls can be given by the following formula:
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
where,
F = attractive force = ?
k = Colomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = Charge on ball A = 12 C
q₂ = Charge on ball B = 15 C
r = distanc between the balls = 10 cm = 0.1 m
Therefore,
[tex]F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(12\ C)(15\ C)}{(0.1\ m)^2}[/tex]
F = 1.62 x 10¹⁴ N
Two cars collide in an intersection. The speed limit in that zone is 30 mph. The car (mass of 1250 kg) was going 17.4 m/s (38.9 mph) the truck (2020 kg) t boned the car in the middle of the intersection. The car was slowed down to only 6.7 m/s. The truck after colliding with the car was going 10.3 m/s. How fast did the truck go into the intersection?
Answer:
u₂ = 3.7 m/s
Explanation:
Here, we use the law of conservation of momentum, as follows:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\[/tex]
where,
m₁ = mass of the car = 1250 kg
m₂ = mass of the truck = 2020 kg
u₁ = initial speed of the car before collision = 17.4 m/s
u₂ = initial speed of the tuck before collision = ?
v₁ = final speed of the car after collision = 6.7 m/s
v₂ = final speed of the truck after collision = 10.3 m/s
Therefore,
[tex](1250\ kg)(17.4\ m/s)+(2020\ kg)(u_2)=(1250\ kg)(6.7\ m/s)+(2020\ kg)(10.3\ m/s)\\\\(2020\ kg)(u_2) = 8375\ N.s + 20806\ N.s - 21750\ N.s\\\\u_2=\frac{7431\ N.s}{2020\ kg}[/tex]
u₂ = 3.7 m/s
A 1500 kg tractor pulls a 750 kg trailer north and applies a 2250 N force on it. What is the force on the tractor?
Answer:
law of Action and Reaction F = 2250 N
Explanation:
The tractor and the trailer are two bodies that interact, therefore, by the law of Action and Reaction, the force that one applies on the other is equal to the force that the second body (trailer) applies on the first (tractor), but with opposite direction
F = 2250 N
directed from trailer to tractor
A person is 88 J of work lifting a grocery bag straight off the ground to a height of 1.7 m what is a grocery bags mass
Answer:
5.277 kg
Explanation:
Since the formula for work is W = F * d and we are given distance and work, the force on the grocery bag is 88 = F * 1.7 F = 88 / 1.7 = 51.765 N.
We also know that force follows the equation F = m * a. Since the constant gravitational acceleration on earth is 9.81 m / s^2, we can find the mass through 51.765 = m * 9.81 m = 51.765/9.81 = 5.277 kg
Which of these would have the most kinetic energy?
O A. a stormy ocean
O B. a running stream
O C. an icy lake
O D. a lake in summer
Answer:
A stormy ocean, having the most kinetic energy means it moves more and faster
Two events are observed in a frame of reference S to occur at the same space point, the second occurring 1.80 s after the first. In a frame S′ moving relative to S, the second event is observed to occur 2.05 s after the first. What is the difference between the positions of the two events as measured in S^?
Answer:
The difference between the positions of the two events as measured in = 3.53 *10^8 m/s
Explanation:
As we know -
[tex]\Delta x = -\gamma \mu\Delta t[/tex]
Here,
[tex]\Delta x[/tex] is the difference between the positions of the two events as measured in S^
[tex]\gamma[/tex] [tex]= \frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }[/tex]
And
[tex]\mu[/tex] = 0.547 c
Substituting the given values in above equation, we get -
[tex]\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{\mu^2}{c^2} } }*2.15\\\Delta x = (0.547 c)*\frac{1}{\sqrt{1-\frac{(0.547 c)^2}{c^2} } }*2.15\\\Delta x = (0.547 *3*10^8)*\frac{1}{\sqrt{(1-\(0.547 )^2 } }*2.15\\\Delta x = 3.53 *10^8[/tex]meter per second
A 1.5 V battery is connected to a 1,000 μF capacitor in series with a 150 Ω resistor. a. What is the maximum current that flows through the resistor during charging? b. What is the maximum charge on the capacitor? c. How long does the capacitor take to reach a potential of 1.0V?
Answer:
[tex]0.01\ \text{A}[/tex]
[tex]0.0015\ \text{C}[/tex]
[tex]0.0608\ \text{s}[/tex]
Explanation:
[tex]V_0[/tex] = Voltage = 1.5 V
[tex]C[/tex] = Capacitance = [tex]1000\ \mu\text{F}[/tex]
[tex]R[/tex] = Resistance = [tex]150\ \Omega[/tex]
Current is given by
[tex]I=\dfrac{V_0}{R}\\\Rightarrow I=\dfrac{1.5}{150}\\\Rightarrow I=0.01\ \text{A}[/tex]
Current flowing in the resistor is [tex]0.01\ \text{A}[/tex].
Charge is given by
[tex]Q=CV\\\Rightarrow Q=1000\times 10^{-6}\times 1.5\\\Rightarrow Q=0.0015\ \text{C}[/tex]
The charge on the capacitor is [tex]0.0015\ \text{C}[/tex].
Voltage is given by
[tex]V=V_0e^{-\dfrac{t}{RC}}\\\Rightarrow t=-RC\ln\dfrac{V}{V_0}\\\Rightarrow t=-150\times 1000\times 10^{-6}\times\ln\dfrac{1}{1.5}\\\Rightarrow t=0.0608\ \text{s}[/tex]
Time taken to reach 1 V is [tex]0.0608\ \text{s}[/tex].
23. Lunar Gravity Compare the force holding a
10.0-kg rock on Earth and on the Moon. The
gravitational field on the Moon is 1.6 N/kg.
Explanation:
Given
mass of the rock is 10 kg
Force requires to hold the rock is equal to its weight
Weight is given by the product of mass and acceleration due to gravity
Weight on the earth surface
[tex]\Rightarrow W_e=10\times 9.8\\\Rightarrow W_e=98\ N[/tex]
Weight on the moon surface
[tex]\Rightarrow W_m=1.6\times 10\\\Rightarrow W_m=16\ N[/tex]
So, the force holding the rock on earth is approximately 6 times the force on the moon.
A metal spherical shell with inner radius 14 cm and outer radius 24 cm has a net charge of 1= -3 nC. At the center of the shell is a small particle with charge Q2= -7 nC. What is the charge density in (C/m2) on the outer surface of the spherical shell?
Answer:
I don't no the answer sorry