9514 1404 393
Answer:
(x, y) ⇒ (y+1, 7-x) . . . rotation 90° CW about (4, 3)
or
(x, y) ⇒ (y+1, x+1) . . . glide reflection across y=x; and translation (1, 1)
Step-by-step explanation:
The figure is apparently rotated 90° clockwise. This can be accomplished a couple of ways: (1) rotation 90° CW about some center; (2) reflection across the line y=x. Because of the symmetry of the figure, we cannot tell which of these is used.
Rotation
The center of rotation can be found by looking at the perpendicular bisectors of the segments joining a vertex and its image. One such segment has endpoints (1, 6) and (7, 6), so is a horizontal line with midpoint (4, 6). The perpendicular bisector of that is x=4.
Another segment joining a point with its image has endpoints (5, 6) and (7, 2). Its midpoint is (6, 4), and the slope of the bisector through that point is 1/2. It intersects the line x=4 at (4, 3), the center of rotation.
Rotation 90° CW about the origin is the transformation (x, y) ⇒ (y, -x), so rotation of (x, y) 90° about the point (4, 3) will be the transformation ...
(x, y) ⇒ ((y -3) +4, (-(x -4) +3) = (y +1, 7 -x)
The transformation A to B is rotation 90° CW about (4, 3):
(x, y) ⇒ (y +1, 7 -x).
__
Reflection
Simple reflection across the line y=x is the transformation (x, y) ⇒ (y, x). Applying that transformation, we see that an additional translation of 1 unit right and one unit up is required. The complete transformation is a "glide reflection", a reflection followed by a translation.
The transformation A to B is a glide reflection across the line y=x with a translation up 1 and right 1:
(x, y) ⇒ (y +1, x +1).
10) An amount of $1500.00 is invested for 3 years at rate of 2% for the first year and 5%, for
the 2nd year and 6% for the 3rd year.
a) Calculate the interest amount you will get if this is simple interest?
b) How much more or less you will get if this is compound interest?
Answer:
the interest is 195dollars
LOOK AT CAPTURE AND ASNWER 100 POINTS
Answer:
132 degrees
Step-by-step explanation:
Looking at angle A and angle B, they are alternate interior angles. That means they are congruent to one another. Knowing that, we can set up an equation A=B
We can now fill A and B with their given equations
5x-18=3x+42
Now we solve
2x=60
x=30
Now that we know x is 30, we can replace it in the equation for A
5x-18
5(30)-18
150-18
132 degrees
Answer:
132
Step-by-step explanation:
ANGLE A = ANGLE B
(INTERIOR ALTERNATE ANGLES)
5x - 18 = 3x + 42
2x = 60
x = 30
angle a = 150 - 18
= 132
Which of the following theorems verifies that A DEF - AXZY?
O A. LL
B. HA
C. HL
D. AA
HA
Step-by-step explanation:See In Triangle DEF and Triangle XZY
[tex]\because\begin{cases}\sf \angle E=\angle Z=90° \\ \sf \ FD\sim XY=Hypotenuse\end{cases}[/tex]
Hence
[tex]\sf \Delta DEF\sim \Delta XZY(Angle-Angle)[/tex]
The theorems that verify that Δ DEF ~ Δ XZY is AA theorem of similarity.
What are similar triangles?Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion.
Given that, two triangles, Δ DEF and Δ XZY, we need to find a theorem that will verify that, Δ DEF and Δ XZY are similar,
So, we have, ∠ X = 40°,
Therefore, ∠ Y = 90°-40° = 50°
Now, we get,
∠ Y = ∠ F = 50°
∠ E = ∠ Z = 90°
We know that,
if two pairs of corresponding angles are congruent, then the triangles are similar.
Therefore, Δ DEF ~ Δ XZY by AA rule
Hence, the theorems that verify that Δ DEF ~ Δ XZY is AA theorem of similarity.
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Which graph matches the exponential function f(x) = (3)x?
1 If a = p^1/3-p^-1/3
prove that: a^3 + 3a = p - 1/p
Hello, please consider the following.
We know that
[tex]a = p^{\frac{1}{3}}-p^{-\frac{1}{3}}\\\\=p^{\frac{1}{3}}-\dfrac{1}{p^{\frac{1}{3}}}[/tex]
And we can write that.
[tex](p-\dfrac{1}{p})^3=(p-\dfrac{1}{p})(p^2-2+\dfrac{1}{p^2})\\\\=p^3-2p+\dfrac{1}{p}-p+\dfrac{2}{p}-\dfrac{1}{p^3}\\\\=p^3-\dfrac{1}{p^3}-3(p-\dfrac{1}{p})[/tex]
It means that, by replacing p by [tex]p^{1/3}[/tex]
[tex](p^{1/3}-\dfrac{1}{p^{1/3}})^3=p-\dfrac{1}{p}-3(p^{1/3}-\dfrac{1}{p^{1/3}})\\\\\\\text{ So }\\\\a^3=p-\dfrac{1}{p}-3a\\\\<=>\boxed{ a^3+3a=p-\dfrac{1}{p} }[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
A technician is testing light bulbs to determine the number of defective bulbs. The technician records the table below to show the results. Result of Light Bulb Test Number of Bulbs Tested 14 28 84 336 Number of Defective Bulbs Found 1 2 6 ? The technician expects to find 24 defective bulbs when 336 are tested. Which statement explains whether the technician’s reasoning is correct, based on the information in the table?
Answer:
He should find 24 defective lightbulbs.
Step-by-step explanation:
1. Divide the number of defective bulbs by the total number of bulbs for each section.
2. Make sure the number you get is the same each time.
3. Divide the guessed number of bulbs (24) by the total number of bulbs (336)
4. If the number you got for step 4 matches the number you got for step 3, then he is right
Answer:
The answer is A
Step-by-step explanation:
on NCCA
Find the volume of the solid. When appropriate, use π=3.14 and round your answer to the nearest hundredth.
Answer:
3179.25
Step-by-step explanation:
Hello!
To find the volume of a cylinder we use the equation
[tex]V = \pi r^{2} h[/tex]
V is volume
r is radius
h is height
Put in what we know. It is says to use pi as 3.14
[tex]V = 3.14 * 7.5^{2} *18[/tex]
Solve
V = 3.14 * 56.25 * 18
V = 3179.25
Hope this Helps!
Pls halppppppppppppppp
Answer:
-6 + 14
8
Step-by-step explanation:
Given: Hank is -6 below feet. He rises +14 feet above level.
-6 + 14 = 8
Addition expression: -6 + 14
Sum: 8
Hope this helped.
Which of the following statements accurately describes the period of a trigonometric function?
Answer:
b
Step-by-step explanation:
b is correct.
A pharmacy has purchased 550 products over a period of 3 months. If their average inventory was 235 products in a 3 month period what was their inventory turnover rate for this period
Answer:
2.34
Step-by-step explanation:
A pharmacy purchased 550 products over a period of 3 months
The average inventory was 235 products during the period of 3 months
Therefore, the inventory turnover rate for this period can be calculated as follows
= 550/235
= 2.34
Hence the inventory turnover rate for this period is 2.34
A line passes through A(3,7) and B(-4,9). Find the value of a if C(a, 1) is on the line.
Answer: a=24
Step-by-step explanation:
Lets find the line's formula (equation of the line).
As known the general formula of any straight line (linear function) is
y=kx+b
Lets find the coefficient k= (Yb-Ya)/(Xb-Xa)=(9-7)/(-4-3)=-2/7
(Xb;Yb)- are the coordinates of point B
(Xa;Ya) are the coordinates of point A
Now lets find the coefficient b. For this purpose we gonna use the coordinates of any point A or B.
We will use A
7=-2/7*3+b
7=-6/7+b
b=7 6/7
So the line' s equation is y= -2/7*x+7 6/7
Now we gonna find the value of a usingcoordinates of point C.
Yc=1, Xc=a
1=-2/7*a+7 6/7
2/7*a= 7 6/7-1
2/7*a=6 6/7
(2/7)*a=48/7
a=48/7: (2/7)
a=24
Answer:
a=24
Step-by-step explanation:
Ted and Katie have saved up a total of $94. Ted has saved 6 dollars less than 4 times as much as Katie. How much has Katie saved
Let
Kettie saved be xTed saved=4x-6ATQ
[tex]\\ \sf\longmapsto x+4x-6=94[/tex]
[tex]\\ \sf\longmapsto 5x-6=94[/tex]
[tex]\\ \sf\longmapsto 5x=94+6[/tex]
[tex]\\ \sf\longmapsto 5x=100[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{100}{5}[/tex]
[tex]\\ \sf\longmapsto x=20[/tex]
Answer:
$20
Step-by-step explanation:
T is Ted
K is Katie
T+K=94.
T=4K-6
I mostly just tried a bunch of numbers.
To check:
T+20=94
T=74
74=4(20)-6
74=80-6
74=74
I hope this helps!
pls ❤ and give brainliest pls
what percent is 50cent of 50cent
what
Step-by-step explanation:
pretty sure its 25 percent
Answer:
25%
Step-by-step explanation:
if you take half of 50 it is 25 so all of it is used or 25%
Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3
Karl needs a total of $30 to buy a bike. He has $12. He can earn $6 an hour
babysitting. Which equation can be used to find the number of hours, h, Karl has to
babysit to have the money he needs?
30 - 6h + 12 = 0
6+ n = 12
6 + 12 h = 30
6 h + 12 = 30
Answer:
6h + 12 = 30
Step-by-step explanation:
Hence, the equation obtained for number of hours worked is given as 12 + 6h = 30.
How to write a linear equation?A linear equation for the given case can be written by assuming any variable as the unknown quantity. Then, as per the given data the required operations are done and it is equated to some value.
The total money required is given as $30.
Suppose the number of hours for babysitting be h.
Then, the money earned by doing it is $6h.
And, the total money with Karl is 12 + 6h.
As per the question, the following equations can be written as,
12 + 6h = 30
Hence, the equation for finding the number of hours is given as 12 + 6h = 30.
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Determine what type of model best fits the given situation: A 4% raise in salary each year.
the models aren't given..
Answer: no models given
Step-by-step explanation:
The average value of a function f(x, y, z) over a solid region E is defined to be fave = 1 V(E) E f(x, y, z) dV where V(E) is the volume of E. For instance, if rho is a density function, then rhoave is the average density of E. Find the average value of the function f(x, y, z) = 5x2z + 5y2z over the region enclosed by the paraboloid z = 9 − x2 − y2 and the plane z = 0.
Answer:
An aluminum bar 4 feet long weighs 24 pounds
Step-by-step explanation:
According the the U.S. Department of Education, full-time graduate students receive an average salary of $15,000 with a standard deviation of $1,200. The dean of graduate studies at a large state university in PA claims that his graduate students earn more than this. He surveys 100 randomly selected students and finds their average salary is $16,000. Use a significance level of 0.05 to test if there is evidence that the dean's claim is correct. What are the hypotheses
Answer:
Step-by-step explanation:
Given that :
population Mean = 15000
standard deviation= 1200
sample size n = 100
sample mean = 16000
The null and the alternative hypothesis can be computed as follows:
[tex]\mathtt{H_o : \mu = 15000 }\\ \\ \mathtt{H_1 : \mu > 15000}[/tex]
Using the standard normal z statistics
[tex]z = \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}[/tex]
[tex]z = \dfrac{16000 -15000}{\dfrac{1200 }{\sqrt{100}}}[/tex]
[tex]z = \dfrac{1000}{\dfrac{1200 }{10}}[/tex]
[tex]z = \dfrac{1000\times 10}{1200}[/tex]
z = 8.333
degree of freedom = n - 1 = 100 - 1 = 99
level of significance ∝ = 0.05
P - value from the z score = 0.00003
Decision Rule: since the p value is lesser than the level of significance, we reject the null hypothesis
Conclusion: There is sufficient evidence that the Dean claim for his graduate students earn more than average salary of $15,000
Dean's Claim of Average Salary = 16000, ie greater than 15000 : is correct
Null Hypothesis [ H0 ] : Average Salary = 15000
Alternate Hypothesis [ H1 ] : Average Salary > 15000
Hypothesis is tested using t statistic.
t = ( x - u ) / ( s / √ n ) ; where -
x = sample mean , u = population mean , s = standard deviation, n = sample size
t = ( 16000 - 15000 ) / ( 1200 / √100 )
= 1000 / 120
t {Calculated} = 8.33,
Degrees of Freedom = n - 1 = 100 = 1 = 99
Tabulated t 0.05 (one tail) , at degrees of freedom 99 = 1.664
As Calculated t value 8.33 > Tabulated t value 1.664 , So we reject the Null Hypothesis in favour of Alternate Hypothesis.
So, conclusion : Average Salary > 15000
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algebra pyramid please answer !! be the first to be marked as a brainliest .
Answer:
The first pyramid:
63x
39x 24x
23x 16x 8x
The second pyramid:
162x
82x 80x
4x 78x 2x
The third pyramid:
12a+2b
9a+b 3a+b
9a b 3a
The fourth pyramid:
-19a
-5a -14a
3a -8a -6a
Step-by-step explanation:
All that an alegbra pyramid is is adding the two terms below it.
So you can see how I added the terms that lied below each number, such as in number 1: I added 23x and 16x to get me 39x, and I added 16x and 8x to get me 24.
Hope this helped!
The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes n1"=15 and n2"=17 are selected, and the sample means and sample variances are x1 =8.73, s2=0.35, x =8.68, and s2=0.40, respectively. Assume that σ1^2 = σ2^2 that the data are drawn from a normal distribution.
Required:
a. Is there evidence to support the claim that the two machines produce rods with different mean diameters? Use alpha=0.05 in arriving at this conclusion.
b. Find the P-value for thet-statistic you calculated in part (a).
c. Construct a 95% confidence interval for the difference in mean rod diameter. Interpret this interval.
Answer:
a) No sufficient evidence to support the claim that the two machines produce rods with different mean diameters.
b) P-value is 0.80
c) −0.3939 <μ< 0.4939
Step-by-step explanation:
Given Data:
sample sizes
n1 = 15
n2 = 17
sample means:
x1 = 8.73
x2 = 8.68
sample variances:
s1² = 0.35
s2² = 0.40
Hypothesis:
H₀ : μ₁ = μ₂
H₁ : μ₁ ≠ μ₂
Compute the pooled standard deviation:
[tex]s_{p} = \sqrt{\frac{(n_{1} - 1)s_{1}^{2} + (n_{2} - 1)s_{2}^{2}}{n_{1} +n_{2} -2} }[/tex]
[tex]= \sqrt{\frac{(15-1)0.35+(17-1)0.40}{15+7-2}}[/tex]
[tex]= \sqrt{\frac{(14)0.35+(16)0.40}{30}}[/tex]
[tex]= \sqrt{\frac{4.9+6.4}{30}}[/tex]
[tex]= \sqrt{\frac{11.3}{30}}[/tex]
[tex]= \sqrt{0.376667}[/tex]
= 0.613732
= 0.6137
Compute the test statistic:
[tex]t = \frac{x_{1} -x_{2} }{s_{p} \sqrt{\frac{1}{n_{1} }+\frac{1}{n_{2} } } }[/tex]
[tex]= \frac{8.73-8.68}{0.6137\sqrt{\frac{1}{15}+\frac{1}{17} } }[/tex]
[tex]= \frac{0.05}{0.6137\sqrt{0.06667+0.05882} } }[/tex]
[tex]= \frac{0.05}{0.6137\sqrt{0.12549} } }[/tex]
[tex]= \frac{0.05}{0.6137(0.354246)} } }[/tex]
[tex]= \frac{0.05}{0.6137(0.354246)} } }[/tex]
= 0.05 / 0.217401
= 0.22999
t = 0.230
Compute degree of freedom:
df = n1 + n2 -2 = 15 + 17 - 2 = 30
Compute the P-value from table using df = 30
P > 2 * 0.40 = 0.80
P > 0.05 ⇒ Fail to reject H₀
Null hypothesis is rejected when P-value is less than or equals to level of significance. But here the P-value = 0.80 and level of significance = 0.05. So P-value is greater than significance level. Hence there is not sufficient evidence to support the claim that population means are different.
Construct a 95% confidence interval for the difference in mean rod diameter:
confidence = c = 95% = 0.95
α = 1 - c
= 1 - 0.95
α = 0.05
Compute degree of freedom:
df = n1 + n2 -2 = 15 + 17 - 2 = 30
Compute [tex]t_{\alpha /2}[/tex] with df = 30 using table:
t₀.₀₂₅ = 2.042
Compute confidence interval:
= [tex](x_{1}-x_{2})-t_{\alpha/2} ( s_{p} )\sqrt{\frac{1}{n_{1} }+\frac{1}{n_{2} } }[/tex]
= (8.73 - 8.68) - 2.042 ( 0.6137 ) [tex]\sqrt{\frac{1}{15} +\frac{1}{17} }[/tex]
= 0.05 - 2.042 ( 0.6137 ) [tex]\sqrt{\frac{1}{15} +\frac{1}{17} }[/tex]
= 0.05 - 1.253175 [tex]\sqrt{0.06667+0.05882} } }[/tex]
= 0.05 - 1.253175 [tex]\sqrt{0.12549} } }[/tex]
= 0.05 - 1.253175 (0.35424))
= 0.05 - 0.443925
= −0.393925
= −0.3939
[tex](x_{1}-x_{2})+t_{\alpha/2} ( s_{p} )\sqrt{\frac{1}{n_{1} }+\frac{1}{n_{2} } }[/tex]
= (8.73 - 8.68) + 2.042 ( 0.6137 ) [tex]\sqrt{\frac{1}{15} +\frac{1}{17} }[/tex]
= 0.05 + 2.042 ( 0.6137 ) [tex]\sqrt{\frac{1}{15} +\frac{1}{17} }[/tex]
= 0.05 + 1.253175 [tex]\sqrt{0.06667+0.05882} } }[/tex]
= 0.05 + 1.253175 [tex]\sqrt{0.12549} } }[/tex]
= 0.05 + 1.253175 (0.35424))
= 0.05 + 0.443925
= 0.493925
= 0.4939
−0.3939 <μ₁ - μ₂< 0.4939
A car is traveling 40 kilometers per hour. What is the speed of that car in meters per second?
We have to convert it to m/s
[tex]\boxed{\sf 1km/h=\dfrac{5}{18}m/s}[/tex]
[tex]\\ \sf\longmapsto 40km/h[/tex]
[tex]\\ \sf\longmapsto 40\times \dfrac{5}{18}[/tex]
[tex]\\ \sf\longmapsto \dfrac{200}{18}[/tex]
[tex]\\ \sf\longmapsto 11.1m/s[/tex]
km/h > m/s
when converting km/h to m/s all you need to do is divide by 3.6
and vise versa when converting m/s to km/h multiply by 3.6
so therefore,
40km/h > m/s
= 40 / 3.6
= 11.11 m/s (4sf)
Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the password is a lowercase English letter, an uppercase English letter, a digit, or one of the six special characters ∗, >, <, !, +, and =.
a) How many different passwords are available for this computer system?
b) How many of these passwords contain at least one occurrence of at least one of the six special characters?
c) Using your answer to part (a), determine how long it takes a hacker to try every possible password, assuming that it takes one nanosecond for a hacker to check each possible password.
Part a)
There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.
If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwordsIf there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwordsIf there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwordsIf there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwordsAdding up those subtotals gives
68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21
different passwords possible.
Answer: Approximately 9.9207 * 10^21======================================================
Part b)
Let's find the number of passwords where we don't have a special symbol
There are 52+10 = 62 different characters to pick from
If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible. If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwordsAdding those subtotals gives
62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21
different passwords where we do not have a special character. Subtract this from the answer in part a) above
( 9.9207 * 10^21) - (3.2792 * 10^21) = 6.6415 * 10^21
which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.
Answer: Approximately 6.6415 * 10^21======================================================
Part c)
The answer from part a) was roughly 9.9207 * 10^21
It will take about 9.9207 * 10^21 nanoseconds to try every possible password from part a).
Divide 9.9207 * 10^21 over 1*10^9 to convert to seconds
(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000
This number is 9.9 trillion roughly.
It will take about 9.9 trillion seconds to try every password, if you try a password per second.
------
To convert to hours, divide by 3600 and you should get
(9,920,700,000,000)/3600 = 2,755,750,000
So it will take about 2,755,750,000 hours to try all the passwords.
------
Divide by 24 to convert to days
(2,755,750,000)/24= 114,822,916.666667
which rounds to 114,822,917
So it will take roughly 114,822,917 days to try all the passwords.
------
Then divide that over 365 to convert to years
314,583.334246576
which rounds to 314,583
It will take roughly 314,583 years to try all the passwords
------------------------------
Answers:9.9 trillion seconds2,755,750,000 hours114,822,917 days314,583 yearsAll values are approximate, and are roughly equivalent to one another.
A) 9,920,671,339,261,325,541,376 different passwords are available for this computer system.
B) 875,353,353,464,234,606,592 of these passwords contain at least one occurrence of at least one of the six special characters.
C) It would take 314,582.42 years for a hacker to try every possible password.
To determine how many different passwords are available for this computer system; how many of these passwords contain at least one occurrence of at least one of the six special characters; and how long it takes a hacker to try every possible password, assuming that it takes one nanosecond for a hacker to check each possible password, the following calculations must be performed:
26 + 26 + 10 + 6 = 68 A) 68 ^ 12 + 68 ^ 11 + 68 ^ 10 + 68 ^ 9 + 68 ^ 8 = X 9,920,671,339,261,325,541,376 = XB)6 x (68^11) + 6 x (68^10) + 6 x (68^9) + 6 x (68^8) + 6 x (68^7) = X875,353,353,464,234,606,592 = XC)1 nanosecond = 1,66667e-11 minutes9,920,671,339,261,325,541,376 nanoseconds = 165344522321.02209473 minutes165344522321.02209473 minutes = 2755742038.6837015152 hours2755742038.6837015152 hours = 114822584.94515423477 days114822584.94515423477 days = 314582.4245072719059 years
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PLEASE HELP..............
Which of the following has no solution?
{x | x < 0} and {x I x > 0}
{x | x ≤ 0} and {x | x ≥ 0}
{x | x ≤ 0} or {x | x ≥ 0}
Answer:
{x | x < 0} and {x I x > 0} has no solution
Step-by-step explanation:
x cannot be less than zero AND more than zero at the same time, so the first inequality has no solution.
{x | x < 0} and {x I x > 0}
Answer:
A
Step-by-step explanation:
Choice A has the two options:
[tex]x<0 \text{ and } x>0[/tex]
In other words, x must be a number such that it is negative (left option) and positive (right option) at the same time.
There can't be such number (and 0 is not included in the answer choices since it is not less/more than or equal to). Thus, Choice A has no solution.
The keyword here is and. If instead of and it was or, then the choice does indeed have a solution.
What is the volume of a cube with side lengths that measure 8 cm?
Answer: 512 cm³
Explanation: Since the length, width, and height of a cube are all equal,
we can find the volume of a cube by multiplying side × side × side.
So we can find the volume of a cube using the formula v = s³.
In the cube in this problem, we have a side length of 8 cm.
So plugging into the formula, we have (8 cm)³
or (8 cm)(8 cm)(8 cm), which is 512 cm³.
So the volume of the cube is 512 cm³.
Answer:512[tex]cm^{3}[/tex]
Step-by-step explanation:
All sides are equal. Hence, volume =[tex]l^{3} = 8^{3} =512cm^{3}[/tex]
Help needed! Thank you!
Which of the following is correct based on this picture?
A. sinD=3124
B. cosK=3124
C. tanK=3124
D. tanD=3124
Answer:
C but see below.
Step-by-step explanation:
If I'm reading this correctly, you mean 31/24. It really can't be much else. The sine and cosine are both incorrect because both involve the hypotenuse which must be calculated in order for them to be considered. In addition 31/24 is greater than one which is impossible for both the Sine and the Cosine.
That leaves K and D
Tan(D) = 24/31 which is not an option.
That leaves C.
tan(K) = 31/24 which is what you have to choose. If your choice is not written this way, then there is no answer.
Answer:
The answer to this problem is C. tanK=3124
A cyclist rides her bike at a speed of 30 kilometers per hour. What is this speed in kilometers per minute? How many kilometers will the cyclist travel in 2
minutes? Do not round your answers,
Step-by-step explanation:
The answer is mentioned above.
The weight of an object above the surface of the Earth varies inversely with the square of the
distance from the center of the Earth. If a body weighs 50 pounds when it is 3,960 miles from
Earth's center, what would it weigh if it were 4,015 miles from Earth's center?
Answer:
weight =48.71228786pounds
Step-by-step explanation:
[tex]w = \frac{k}{ {d}^{2} } \\ 50 = \frac{k}{ {3960}^{2} } \\ \\ k = 50 \times {3960}^{2} \\ k = 50 \times 15681600 \\ k = 784080000 \\ \\ w = \frac{784080000}{ {d}^{2} } \\ w = \frac{784080000}{16120225} \\ \\ w = 48.71228786 \\ w = 48.7pounds[/tex]
If a body weighs 50 pounds when it is 3,960 miles from Earth's center, it would weigh approximately 48.547 pounds if it were 4,015 miles from Earth's center, according to the inverse square law formula.
We know the inverse square law formula:
W₁ / W₂ = D²₂ / D²₁
Where W₁ is the weight of the body at the initial distance D₁, and W₂ is the weight at the final distance D₂.
So we have,
W₁ = 50
D₁ = 3,960
D₂ = 4015
We know that the body weighs 50 pounds when it is 3,960 miles from Earth's center,
So we can plug in those values as follows:
50 / W₂ = (4,015)²/ (3,960)²
To solve for W₂, we can cross-multiply and simplify as follows:
W₂ = 50 x (3,960)² / (4,015)²
W₂ = 50 x 15,681,600 / 16,120,225
W₂ = 48.547 pounds (rounded to three decimal places)
Therefore, if the body were 4,015 miles from Earth's center, it would weigh approximately 48.547 pounds.
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I need help solving this please
1/8+2/3-11/12
PLEASE I HAVE AN HOUR Why might you use the distributive property to simplify 3(30-2)
PLEASEEEE I NEED HELP, 8TH GRADE MATH
Answer:
(6, ....... ) ( -3, .........) ( 1, .......)
x,y values therefore = (6, 29) ( -3, -34) (1, -6)
as x = 0 when y = -13
we simply x 6 into equation to find 30
y = 7 x 6 -13
y = 42 - 13
y = 29
Then for -3 we simply x by -3 to find y
y = 7 x -3 -13
y = -21 - 13
y = -34
then for 1 we simply x by 1 to find y
y = 7 x 1 -13
y = 7 - 13
y = -6
y = 7x - 13
Step 1) Set above equation equal to 0 by remembering the methods;
Solve y-7x+13 = 0
Step 2) Calculate the y intercept;
Notice that when x = 0 the value of y is -13/1 so this line "cuts" the y axis at y=-13.00000 see attached to help memorize.
Step 3) Calculate the X-Intercept :
When y = 0 the value of x is 13/7 Our line therefore "cuts" the x axis at x= 1.85714
Step 4) Calculate the Slope :
Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is -13.000 and for x=2.000, the value of y is 1.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 1.000 - (-13.000) = 14.000 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)
Slope = 14.000/2.000 = 7.000
As seen below.
x-intercept = 13/7 = 1.85714
slope = 14000/2000 = 7000
x intercept = 13/7 = 1.85714
y intercept = 13/1 = 13.00000
the rainfall R(t) (inmm) over the course of a year in bali, indonesia as a function of time t(in days) can be modeled by a sinusoidal expression of the form a*sin(b*t)+d. At t=0, in mid april, the expected daily rainfall is 2.3mm, which is the daily average value throughout the year. 1 quarter of the year leter, at t=91.25, when the rainfall is at its minimum, the expected daily value is 1.4mm. find R(t).
[tex]\bold{\text{Answer:}\quad R(t)=-0.96\sin\bigg(\dfrac{\pi}{182.5}t}\bigg)+2.3}[/tex]
Step-by-step explanation:
The equation of a sin function is: y = A sin (Bx - C) + D where
Amplitude (A) is the distance from the midline to the max (or min)Period (P) = 2π/B --> B = 2π/PC/B is the phase shift (not used for this problem)D is the vertical shift (aka midline)D = 2.3
It is given that t = 0 is located at 2.30. The sin graph usually starts at 0 so the graph has shifted up 2.3 units. --> D = 2.3
A = -0.96
The amplitude is the difference between the maximum (or minimum) and the centerline. A = 2.30 - 1.44 = 0.96
The minimum is given as the next point. Since the graph usually has the next point as its maximum, this is a reflection so the equation will start with a negative. A = -0.96
B = π/182.5
It is given that [tex]\frac{1}{4}[/tex] Period = 91.25 --> P = 365
B = 2π/P
= 2π/365
= π/182.5
C = 0
No phase shift is given so C = 0
Input A, B, C, & D into the equation of a sin function:
[tex]R(t)=-0.96\sin\bigg(\dfrac{\pi}{182.5}t-0}\bigg)+2.3[/tex]