Explanation:
CH4 + 4S ---> CS2 + 2H2S
4) 0.75 mol S × (1 mol CS2/4 mol S) = 0.19 mol CS2
5) 3 mol H2S × (1 mol CH4/2 mol H2S) = 1.5 mol CH4
Fe2O3 + 2Al ---> 2Fe + Al2O3
6) 25 g FeO3 × (1 mol Fe2O3/159.69 g Fe2O3) = 0.16 mol Fe2O3
0.16 mol Fe2O3 × (2 mol Al/1 mol Fe2O3) = 0.32 mol Al
0.32 mol Al × (26.98 g Al/1 mol Al) = 8.6 g Al
7) Given:
45 g Al × (1 mol Al/26.98 g Al) = 1.6 mol Al
85 g Fe2O3 ×(1 mol Fe2O3/159.69 g Fe2O3)
= 0.53 mol Fe2O3
Let's look at how much Fe each reactant will produce:
1.6 mol Al × (2 mol Fe/2 mol Al) = 1.6 mol Fe
0.53 mol Fe2O3 × (2 mol Fe/1 mol Fe2O3) = 1.1 mol Fe
Note that the given amount of Fe2O3 will give us fewer Fe. Therefore, Fe2O3 is the limiting reactant.
8) Al will produce 1.6 mol Fe × (55.845 g Fe/1 mol Fe)
= 89 g Fe
Fe2O3 will produce 1.1 mol Fe × (55.845 Fr/1 mol Fe)
= 61 g Fe
9) Since Fe2O3 is the limiting reactant, the ideal yield of Fe for the reaction is 61 g. If the actual reaction only gave us 25 g Fe. then the percent yield of Fe is
%yield = (25 g Fe/61 g Fe) × 100% = 41%
10) If we only got 25 g Fe, then the amount of Al actually used in the reaction is
25 g Fe × (1 mol Fe/55.845 g Fe) = 0.45 mol Fe
0.45 mol Fe × (2 mol Al/2 mol Fe) = 0.45 mol Al
0.45 mol Al × (26.98 g Al/1 mol Al) = 12 g
Therefore, the leftover amount of Al is
25 g Al - 12 g Al = 13 g Al
2. Identify the limiting reactant when 4.68 g of iron reacts with 2.88 g of sulfur to produce Fes.
Fe +
_Sg → FeS
B
C с
A
+
Help please I’ll mark brainliest
Answer:
Iron is limiting reactant
Explanation:
Based on the reaction:
Fe + S → FeS
1 mole of iron reacts per mole of Sulfur
To solve this question we must convert the mass of each reactant to moles using molar masses of each reactant. As the reaction is 1:1, the reactant with the lower amount of moles is limiting reactant.
Moles Fe -Molar mass: 55.845g/mol-
4.68g * (1mol / 55.845g) = 0.0838 moles
Moles S -Molar mass: 32.065g/mol-
2.88g * (1mol / 32.065g) = 0.0898 moles
As the amount of moles of Fe < Moles S,
Iron is limiting reactant
When 4.68 g of iron reacts with 2.88 g of sulfur to produce FeS, iron is the limiting reagent.
What is limiting reagent?
If in a chemical reaction two reactants are present and one of them is present in less quantity as compared to other, is known as limiting reagent.
Given chemical reaction is:
Fe + S → FeS
From the stoichiometry of the reaction it is clear that equal moles of both reactant is required for the formation of product, so their mole ratio is 1:1.
Now we calculate the moles by using the formula:
n = W/M, where
W = given mass
M = molar mass
Moles of 4.68g of iron = 4.68g / 55.845g/mole = 0.0838 moles
Moles of 2.88 of sulfur = 2.88g / 32.065g/mole = 0.0898 moles
Moles of iron is less as compare to the sulfur, so it is the limiting reagent.
Hence, iron is the limiting reagent.
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If 4.0 mol of NO and 4.0 mol of O2 are combined, how many moles
of NO2 can be produced?
2NO + O2 —> 2NO2
Answer:
There will be 4 moles of NO2 produces at the end of the reaction.
Explanation:
First of all, you should consider that the limiting reactant is NO, since it's the first it's going to end in the reaction.
After that, the conversion factor must be done with the limiting reactant (NO). So since you have 4 mol of NO and the relation of NO with NO2 its 2:2, you will end up having 4 moles of NO2.
How many moles of Ca(OH)2 are needed to make 200.0 mL of 0.250 M solution? Ca(OH)2
Answer:
0.05 moles of Ca(OH)2
Explanation:
The formula for molarity is: mol/L = M
First, convert 200.0 mL to L.
200 mL/1000 = 0.2 L
Next, plug in the values given.
mol/0.2 = 0.250
Rearrange the equation.
mol = 0.2*0.250
mol = 0.05
If you'd like to check it, simply plug in 0.05 to mol and divide it by 0.2. In theory, you should get 0.250.
Why are humans responsible for oil spills
Answer:
Oil spills into rivers, bays, and the ocean most often are caused by accidents involving tankers, barges, pipelines, refineries, drilling rigs, and storage facilities.
Spills can be caused by:
people making mistakes or being careless.
equipment breaking down.
natural disasters such as hurricanes.
deliberate acts by terrorists, countries at war, vandals, or illegal dumpers.
Explanation:
Hope this helped Mark BRAINLIEST!!!
They have one electron in the outermost electron shell. These are very active metals and easily lose their single valence electron.
Answer: The statement they have one electron in the outermost electron shell. These are very active metals and easily lose their single valence electron, is true.
Explanation:
Metals are the species which tend to lose electron(s) to acquire stable noble gas configuration.
Elements which tend to lose a single electron in order to acquire stability are active in nature because losing one electron is more easy as compared to losing two or more electrons.
For example, atomic number of sodium is 11 and its electronic distribution is 2, 8, 1.
Since, it contains only one valence electron and by losing it sodium will acquire stability. Hence, sodium is a very reactive metal.
Thus, we can conclude that the statement they have one electron in the outermost electron shell. These are very active metals and easily lose their single valence electron, is true.
3. How much heat (in joules) is needed to raise the temperature of 355 g of ethanol I
(c = 2.4 J/gºC) by 63°C?
q=mcAT
Answer:
53676 J
Explanation:
m = 355 g
c = 2.4 J/gºC
ΔT = 63°C
q = mcΔT
= (355)(2.4)(63)
= 53676 J
The amount of heat is 53676J to raise the temperature of 355 g of ethanol.
What is temperature?Temperature is a measurement of the amount of energy of the atoms in a system or a physical quantity that expresses hot and cold.
What is heat?Heat is energy that is transmitted through one body to some other due to a temperature differential. When two bodies of different temperatures come together, energy can be transferred (heat flows) from the hotter to the colder.
It can be determined by the formula:
q =mCΔT.
where, q is heat, m is mass , C is and T is temperature.
Calculation of heat is shown below:
It is given that, mass of ethanol = 355 g, c = [tex]2.4 J/g^{0}[/tex] C, ΔT. = [tex]63^{0} C[/tex]
Now, put the values of given data in heat formula:
q =mCΔT
= 355×2.4×63
=53676J.
Therefore, the amount of heat will be 53676J to raise the temperature of 355 g of ethanol
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Proponer una propuesta de acción contra la degradación del suelo basándose en tres tipos de argumentos de fuentes confiables
Answer:
Cobertura vegetal, mantillo y piedra triturada.
Explicación:
Para evitar la degradación del suelo, debemos plantar una cubierta vegetal perenne que proteja el suelo de la erosión del viento y el agua sujetándolo firmemente con sus raíces. El mantillo también se usa para prevenir la erosión del suelo. En aquellas zonas donde la cobertura vegetal no es posible, tenemos que utilizar piedras trituradas para cubrir el suelo con el fin de evitar el contacto directo con el viento. Entonces, estas acciones pueden prevenir la degradación del suelo y mantener el suelo en su estado original.
(part 1 of 3) Copper reacts with silver nitrate through a single replacement. If 1.29 g of silver are produced from the reaction, how much copper(II) nitrate is also produced? Answer in units of mol. (part 2 of 3) How much Cu is required in this reaction? Answer in units of mol. (part 3 of 3) 1.0 points How much AgNO3 is required in this reaction? Answer in units of mol.
Answer:
See explanation.
Explanation:
Hello there!
In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:
[tex]Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2[/tex]
Thus, we proceed as follows:
Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:
[tex]m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2[/tex]
Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:
[tex]m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu} \\\\m_{Cu}=0.380gCu[/tex]
Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:
[tex]m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3} \\\\m_{AgNO_3}=2.03gAgNO_3[/tex]
Best regards!
The decomposition of potassium chlorate, KClO3, is used as a source of oxygen in labs.
How many moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas?
Reaction takes place is
2KClO3 --> 2KCl + 3O2
from above equation 2 moles of potassium chlorate is forming 3 moles of Oxygen gas.
now given 6.83 moles of oxygen and moles of potassium chlorate is missing,
consider x moles of potassium chlorate are needed to form 6.83 moles of oxygen
from above condition, .
3 》》》》2
x 》》》》6.83
3/x = 2/6.83
x = 3×6.83/2
x= 10.245
Answer- 10.245 moles of potassium chlorate are needed to produce 6.83 moles of oxygen gas.
What molar concentration (molarity) results when 1.28 L of 14.38 M HCl is diluted to 9.45 L of water?
Answer:
1.95 M
Explanation:
Molarity is a measure of the molar concentration of a substance (solution). In relation to the volume, it is calculated using the formula as follows;
C1V1 = C2V2
Where;
C1 = initial concentration (M)
C2 = final concentration (M)
V1 = initial volume (L)
V2 = final volume (L)
According to the provided information in this question;
C1 = 14.38 M
C2 = ?
V1 = 1.28 L
V2 = 9.45 L
Using C1V1 = C2V2
14.38 × 1.28 = C2 × 9.45
18.4064 = 9.45 C2
C2 = 18.4064 ÷ 9.45
C2= 1.95 M
Balance :FeCl3 + __Ca(OH)2 → ___ Fe(OH)3 + __ CaCl2
What does temperature surround when the kinetic energy is moving fast ?
When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.
In chemistry, we define the temperature of a substance as the average kinetic energy of all the atoms or molecules of that substance. Not all of the particles of a substance have the same kinetic energy. At any given time, the kinetic energy of the particles can be represented by a distribution.
In physics, temperature is defined as the average kinetic energy of the particles in an object. ... When particles move more quickly, temperature is higher and an object feels warmer. When particles move more slowly, temperature is lower and an object feels cooler.
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.?lkikjjjmmjj
hhhhgyhhjjj
Answer:
ertyuioekgdctifrofy?
Explanation:
PLEASE HELP!
an element with 8 protons and 10 neutrons
Answer:
oxygen ion O2-
Explanation:
because it has 8 protons and gave gained 2 electron so O2-.
On the following chemical equation, label the acid, the base, the
conjugate acid, and the conjugate base.
HX(aq) + H2O(1) = H30+(aq) + X (aq)
Answer:
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)
Acid Base Conj. acid Conj. base
Explanation:
The equation is:
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)
This is the typical equilibrium for a weak acid. It would complete if we notice the Ka.
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq) Ka
1 mol of hypothetic HX acid react to 1 mol of water in order to release a proton and make hydronium and generate the X⁻ anion.
HX will be the acid, in this case a weak one and water will be the base. Water is able to accept a proton to make itslef hydronium
Hydronium is the conjugate acid.
The X⁻ will be the conjugate strong base.
This ion can generate the acid form again, that's why it is strong, because it can make hydrolisis.
X⁻ (aq) + H₂O (l) ⇄ HX (aq) + OH⁻(aq) Kb
In this case, the anion will be the conjugate base which it takes a proton from water (acid form) to make a conjugate acid, the HX and a conjugate base, OH⁻
Mrs. Borunda has a sample of oxygen gas that occupies a volume of 600 L at 400 atm pressure. What will the pressure be if she increases the volume to
800 L?
300 atm
450 atm
540 atm
250 atm
Answer:
P₂ = 300 atm
Explanation:
Given that,
Initial volume, V₁ = 600 L
Initial pressure, P₁ = 400 atm
We need to find the pressure if the volume is 800 L.
We know that the relation between pressure and volume is given by :
[tex]P\propto \dfrac{1}{V}\\\\\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{600\times 400}{800}\\\\P_2=300\ atm[/tex]
So, the new pressure is equal to 300 atm.
All of the following are empirical formulas except:
C2H3O2
C6H6
CHO2
CH2O
Drag each tile to the correct box,
Arrange the processes of the water cycle in the correct order, starting with the heat from the Sun.
Answer:
4
3
2
6
1
5
I hope this helped!
DIRECTIONS: Classify the following unbalanced chemical equations according to the six types
of chemical reactions. Write your answer on the space provided for each number.
1. NaOH + KNO3 NaNO3 + KOH
2. CH4 + O2 CO2 + 2H2O
3. Fe + NaBr FeBr3 + Na
4. CaSO4 + Mg(OH)2 Ca(OH)2 + MgSO4
5. NH4OH + HBr H2O + NH4Br
6. P4 + O2 P2O4
7. NaNO3 NaNO2 + O2
8. C18H18 + O2 CO2 + H2O
9. H2SO4 + NaOH NaSO4 +H2O
10.NiSO4 + Li3PO4 Ni3(PO4)2 + Li2SO4
How many grams of Ca(OH)2 would be needed to make 500 mL of a 0.450 mol/L solution?
113 g
133 g
41.2 g
16.68 g
Answer:
[tex]\boxed {\boxed {\sf 16.68 \ g\ Ca(OH)_2}}[/tex]
Explanation:
Molarity is a measure of concentration in moles per liter.
[tex]molarity = \frac{moles \ of \ solute}{liters \ of \ solution}[/tex]
The molarity is 0.450 moles per liter. The moles of solute is unknown.
The volume of the solution is 500 milliliters, but we want to know the liters. We need to convert the units. Remember that 1 liter contains 1000 milliliters.
[tex]\frac{ 1 \ L}{1000 \ mL}[/tex][tex]500 \ mL *\frac{ 1 \ L}{1000 \ mL}[/tex][tex]500 *\frac{ 1 \ L}{1000 }[/tex][tex]\frac{500}{1000} \ L =0.500 \ L[/tex]So, we have values for all the variables:
molarity= 0.450 mol/L moles of solute = xliters of solution =0.500 LSubstitute the values into the formula.
[tex]0.450 \ mol /L *\frac{x}{0.500 \ L}[/tex]
We want to solve for x, the moles of solute. x is being divided by 0.500 liters. The inverse of division is multiplication, so multiply both sides by 0.500 L.
[tex]0.500 \ L *0.450 \ mol /L =\frac{x}{0.500 \ L}*0.500 \ L[/tex]
[tex]0.500 \ L *0.450 \ mol /L =x[/tex]
The units of liters cancel.
[tex]0.500 *0.450 \ mol=x[/tex]
[tex]0.225 \ mol =x[/tex]
Now we have the moles and need to convert to grams. This is done using the molar mass (mass per 1 mole). The values are found on the Periodic Table as atomic masses, but the units are grams per mole instead of atomic mass units.
The solute is Ca(OH)₂, so lookup the molar masses of the individual elements.
Ca:40.08 g/mol O: 15.999 g/mol H: 1.008 g/molNote there is a subscript of around OH. There are 2 hydroxide molecules, so there are 2 oxygen and 2 hydrogen atoms. We must multiply their molar masses by 2 before adding all the values.
Ca(OH)₂= 40.08 + 2(15.999)+2(1.008)=74.094 g/molUse the molar mass as a ratio.
[tex]\frac{74.094 \ g \ Ca(OH)_2} {1 \ mol \ Ca(OH)_2}[/tex]
Multiply by the number of moles calculated.
[tex]0.225 \ mol \ Ca(OH)_2 *\frac{74.094 \ g \ Ca(OH)_2} {1 \ mol \ Ca(OH)_2}[/tex]
The units of moles of calcium hydroxide cancel.
[tex]0.225 *\frac{74.094 \ g \ Ca(OH)_2} {1}[/tex]
[tex]16.67115 \ g\ Ca(OH)_2[/tex]
16.68 grams of calcium hydroxide are needed.
Reaction B: 2 H2O2 (aq) + 2 H20 (L) + O2 (g)
10. Identify the reactants in Reaction B.
11. Identify the products in Reaction B.
12. How many molecules are present on the reactant side of the equation?
13. How many molecules are present on the product side of the equation?
Answer: 10. The reactant in Reaction B is [tex]H_{2}O_{2}[/tex].
11. The products in Reaction B are [tex]H_{2}O[/tex] and [tex]O_{2}[/tex].
12. There are 2 molecules present on the reactant side of the equation.
13. There are 3 molecules present on the product side of the equation.
Explanation:
The given reaction equation is as follows.
[tex]Reaction B: 2H_{2}O_{2}(aq) \rightarrow 2H_{2}O(l) + O_{2}(g)[/tex]
Reactants are the species present on the left side of a chemical equation.
Products are the species present on the right side of a chemical equation.
Therefore, the reactant in Reaction B is [tex]H_{2}O_{2}[/tex]. As 2 is coefficient of [tex]H_{2}O_{2}[/tex] so, 2 molecules are present on the reactant side of the equation.
The the products in Reaction B are [tex]H_{2}O[/tex] and [tex]O_{2}[/tex]. The coefficient of [tex]H_{2}O[/tex] is 2 and coefficient of [tex]O_{2}[/tex] is 1. Hence, there are total (2 + 1) equals to 3 molecules present on the product side of the equation.
Thus, we can conclude that:
The reactant in Reaction B is [tex]H_{2}O_{2}[/tex].
The products in Reaction B are [tex]H_{2}O[/tex] and [tex]O_{2}[/tex].
There are 2 molecules present on the reactant side of the equation.
There are 3 molecules present on the product side of the equation.
When writing the formulas for a compound that contains a polyatomic ion, ... ?
Answer:
The cation is written first in the name; the anion is written second in the name. Rule 2. When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.
When writing the formula of a compound that contains polyatomic ion, the metal is written first followed by the central atom in the ion and then other atoms that surround the central atom.
A poly atomic ion refers to an ion that comprises of more than one atom. Such ions are common in chemistry. Examples of polyatomic ions include; PO4^3-, BH4^- etc.
When writing the formula of a compound that contains a polyatomic ion, the metal is written first then the central atom in the ion follows before other atoms that surround the central atom in the ion.
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Help asap plzzzz 30 points
A chemistry teacher provides students with the amount of potassium hydroxide they need in solution form. The teacher makes the solution by dissolving 42.1 g KOH into 3.0 L of solution.
Each lab group needs 0.023 mol of KOH for their experiment. How many milliliters of the solution does each group need to provide enough dissolved moles?
mL of solution
Answer:
Do you need your 0.00 2 oz
Explanation:
Because that is the right answer
For the enough dissolving of given moles each group will need to provide 92mL of solution.
How we determine Molarity for further calculation?Molarity can be calculated as: M = n/V mol/L where,
V = volume = 3L (given)
n = no. of moles, which can be calculated as:
n = W/M, where
W = given mass = 42.1g (given)
M = molar mass = 56.1g/mol (known)
First of all we have to calculate molarity to determine the volume of solution of each groups. By putting value of n in the 1st equation, molarity can be calculated as follow:
M = 42.1 / 56.1 × 3 = 0.250 mol/L
Now in the question it is given that each group have KOH solution of 0.023 moles. So, we can calculate the volume by using the 1st equation:
M = n/V
0.250 = 0.023/V
V = 0.023mol / 0.250mol per L = 0.092L = 92mL.
Hence, 92mL of the solution will each group need to provide enough dissolved moles
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Please help!!
All fake answers get reported immediately. Yes, I am a girl -_-
Answer:
1.)C₃H₈O
2)OH
3.)1-propanol
1.) C4H8O
2.) C2H6O or CH3CH2OH
3.)Ethanol
Explanation:
Hope this help
What is the correct unit for M1 and M2?
Answer:
M1 and M2 are the masses of two. objects exerting the force on each other, and R is the distance. between their centers.
Explanation:
M1 and M2 are the masses of two. objects exerting the force on each other, and R is the distance. between their centers.
How does velocity affect the movement of an object?
Answer:
when the velocity is at a higher *rate of speed*, the faster the object will move!
Explanation:
Which results in a chemical change?
A. A teacher feels a rough cloth
B. A student colors a blue paper
C. A student smells a flower
D. A teacher lights a candle
Answer:
D. I am pretty sure
Explanation:
:))))))
Answer:
D. A teacher lights a candle
Explanation:
Which radioisotope is naturally occurring?
Answer:
[tex]\frac{131}{53} I[/tex]
Explanation:
A naturally occurring element is an element that is not produced in a nuclear reaction.
Most of the trans-uranium elements are not natural, they are all synthetic elements which are produced as a result of nuclear reactions. They are unknown in nature.
Apart from [tex]\frac{131}{53} I[/tex], all other radioisotopes listed among the options are not natural elements.They are products of nuclear reactions.
CH3OH is an example of a ____ hydrocarbon.
a.
complete
b.
substituted
c.
functional
d.
synthetic
Answer:
functional
Explanation:
c is correct
Which formula represents an isomer of this compound?
Answer:
Explanation:
I can’t explain but this is the answer LOL