Please help me. Please!!
What expression is equivalent to -6(-2/3+2x)
a. - 4 - 12x
b. - 4 + 2x
c. 4 - 12x
d.4 + 12x

The answer has one solution:

_______________________________

       →  x = 6 ; y = 7 ;  or, write as:  [6, 7].

_______________________________

Step-by-step explanation:

_______________________________

Given:

y = x + 1;

y = 2x – 5 ;

_______________________________

2x  – 5 = x + 1  ;  Solve for "x" ;

Subtract "x" ; and Subtract "1" ; from Each Side of the equation:

   2x  – x  – 5  – 1 = x  – x  +  1  –  1 ;

to get:  

   x   –  6  =  0  ;

Now, add "6" to Each Side of the equation;

       to isolate "x" on one side of the equation;

        and to solve for "x" :

    x   –  6   +  6 =  0  +  6  ;

to get:

       x  =  6 .

_______________________________

Now, let us solve for "y" ;  

We are given:  

  y =  x + 1  ;

Substitute our solved value for "x" ; which is:  "6" ; for "x" ; into this given equation; to obtain the value for "y" :

 y =  x + 1 ;

    =  6 + 1 ;

 y =  7 .

_______________________________

Let us check our answers by plugging the values for "x" and "y" ;

("6" ; and "7"; respectively);  into the second given equation; to see if these values for "x" and "y" ; hold true:

  Given:  y = 2x –  5 ;

        →  7 =? 2(6) –  5 ??  ;

        →  7 =? 2(6) –  5 ??  ;        

        →  7 =?  12   –  5 ??  ;

        →  7 =?   7 ?? ;

        →  Yes!

_______________________________

The answer has one solution:

       →  x = 6 ; y = 7 ;  or, write as:  [6, 7].

_______________________________

Hope this is helpful!  Best wishes!

_______________________________

Answer:

[tex]z=\frac{404-409}{\frac{24}{\sqrt{42}}}=-1.35[/tex]  

The p value for this case is given by:

[tex]p_v =P(z<-1.35)=0.0885[/tex]  

For this case the p value is higher than the significance level given so we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean is significantly less than 409

Step-by-step explanation:

Information given

[tex]\bar X=404[/tex] represent the sample mean

[tex]\sigma=24[/tex] represent the population standard deviation

[tex]n=42[/tex] sample size  

[tex]\mu_o =409[/tex] represent the value to verify

[tex]\alpha=0.01[/tex] represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to verify if the true mean is less than 409, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \geq 409[/tex]  

Alternative hypothesis:[tex]\mu < 409[/tex]  

The statistic for this case is given by:

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)  

Replacing the info we got:

[tex]z=\frac{404-409}{\frac{24}{\sqrt{42}}}=-1.35[/tex]  

The p value for this case is given by:

[tex]p_v =P(z<-1.35)=0.0885[/tex]  

For this case the p value is higher than the significance level given so we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean is significantly less than 409

Answer:

[tex]t=\frac{10.8-11}{\frac{1.5}{\sqrt{9}}}=-0.4[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=9-1=8[/tex]  

And the p value would be given by:

[tex]p_v =P(t_{(8)}<-0.4)=0.350[/tex]  

Since the p value is higher than the the significance level of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from the traditional methods.

Step-by-step explanation:

Assuming this first part of the problem obtained from the web: "Using traditional methods, it takes 11.0 hours to receive a basic driving license. A new license training method using Computer Aided Instruction (CAI) has been proposed"

Information given

[tex]\bar X=10.8[/tex] represent the mean height for the sample  

[tex]s=1.5[/tex] represent the sample standard deviation

[tex]n=9[/tex] sample size  

[tex]\mu_o =11[/tex] represent the value that we want to test

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic  

[tex]p_v[/tex] represent the p value

Hypothesis to test

We want to check if the true mean for this case is equal to 11 or not, the system of hypothesis would be:  

Null hypothesis:[tex]\mu = 11[/tex]  

Alternative hypothesis:[tex]\mu \neq 11[/tex]  

The statistic would be given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex]  (1)  

Replacing the info given we got:

[tex]t=\frac{10.8-11}{\frac{1.5}{\sqrt{9}}}=-0.4[/tex]    

The degrees of freedom are given by:

[tex]df=n-1=9-1=8[/tex]  

And the p value would be given by:

[tex]p_v =P(t_{(8)}<-0.4)=0.350[/tex]  

Since the p value is higher than the the significance level of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from the traditional methods.

Answer:

x = 1/5

Step-by-step explanation:

Step 1: Add 9 to both sides

80x = 16

Step 2: Divide both sides by 80

x = 16/80

Step 3: Simplify by dividing top and bottom by 16

x = 1/5

And we have our final answer!

Answer:

x = 1/5

Step-by-step explanation:

80x - 9 = 7​

Add 9 into both sides.

80x = 7 + 9

80x = 16

Divide 80 into both sides.

x = 16/80

Simplify.

x = 1/5

Answer:

Volume: 3x2x4=24 so the volume is 24 Meter3

Surface area:

52 Square meter

Answer:

  6 to the power of 1/6

Step-by-step explanation:

In general, a root is the same as a fractional power. That is, ...

  [tex]\sqrt[n]{x}=x^{\frac{1}{n}}[/tex]

So, the square root of a cube root is ...

  (6^(1/3))^(1/2)

According to the rules of exponents, a power of a power is ...

  (a^b)^c = a^(bc)

so, the above root of a root is ...

  (6^(1/3))^(1/2) = 6^((1/3)(1/2)) = 6^(1/6)

The square root of the cube root of 6 is 6 to the power of 1/6.

Answer:

A) 6^1/6 or 6 to the power of 1 sixth

Answer:

A. The E(Y) is 0.80

B. The expected amount of the surcharges is $165

Step-by-step explanation:

A. In order to calculate the E(Y), we would have to calculate the following formula:

E(Y)=∑yp(y)

E(Y)=(0*0.5)+(1*0.25)+(2*0.20)+(3*0.05)

E(Y)=0+0.25+0.40+0.15

E(Y)=0.80

B. In order to calculate the expected amount of the surcharges we would have to calculate the following formula:

E($110Y∧2)=110E(Y∧2)

=110∑y∧2p(y)

=110((0∧2*0.5)+(1∧2*0.25)+(2∧2*0.20)+(3∧2*0.05))

110(0+0.25+0.80+0.45)

=$165

Answer:

(a) 125

[tex](b) \dfrac{1}{125}[/tex]

[tex](c) \dfrac{124}{125}[/tex]

Step-by-step explanation:

We are given that access code consists of 3 digits.

Each digit can be any digit through 1 to 5 and can be repeated.

Now, this problem is equivalent to the problem that we have to find:

The number of 3 digit numbers that can be formed using the digits 1 to 5 with repetition allowed.

(a) We have 3 places here, unit's, ten's and hundred's places respectively and  each of the 3 places have 5 possibilities (any digit allowed with repetition).

So, total number of access codes possible:

[tex]5\times 5 \times 5 = 125[/tex]

(b) Suppose, an access code is randomly selected, what is the probability that it will be correct.

Formula for probability of an event E can be observed as:

[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}[/tex]

Here, only 1 code is correct, so

Number of favorable cases = 1

Total number of cases = 125

So, required probability:

[tex]P(E) = \dfrac{1}{125}[/tex]

(c) Probability of not selecting the correct access code on first time:

[tex]P(\overline E) = 1-P(E)\\\Rightarrow P(\overline E) = 1-\dfrac{1}{125}\\\Rightarrow P(\overline E) = \dfrac{125-1}{125}\\\Rightarrow P(\overline E) = \dfrac{124}{125}[/tex]

So, the answers are:

(a) 125

[tex](b) \dfrac{1}{125}[/tex]

[tex](c) \dfrac{124}{125}[/tex]

Answer:

B) 92.03 < μ < 97.97

99% confidence interval for the mean score of all students.

92.03 < μ < 97.97

Step-by-step explanation:

Step(i):-

Given sample mean (x⁻) = 95

standard deviation of the sample (s) = 6.6

Random sample size 'n' = 30

99% confidence interval for the mean score of all students.

[tex]((x^{-} - Z_{0.01} \frac{S}{\sqrt{n} } , (x^{-} + Z_{0.01} \frac{S}{\sqrt{n} })[/tex]

step(ii):-

Degrees of freedom

ν =   n-1 = 30-1 =29

[tex]t_{0.01} = 2.462[/tex]

99% confidence interval for the mean score of all students.

[tex]((95 - 2.462 \frac{6.6}{\sqrt{30} } , 95 + 2.462\frac{6.6}{\sqrt{30} } )[/tex]

( 95 - 2.966 , 95 + 2.966)

(92.03 , 97.97)

Final answer:-

99% confidence interval for the mean score of all students.

92.03 < μ < 97.97

Answer:

  73.4%

Step-by-step explanation:

The ratio of acid to mixture volume is ...

  (0.62·175 +1.00·75)/(175 +75) = 183.5/250 = 0.734 = 73.4%

73.4% of the resulting mixture is acid.

Answer:

5.12 x 10¹¹ bit

Step-by-step explanation:

1GB = 8 x 10⁹ bits

so 64gb = 64 x 8 x 10⁹

= 512 x 10⁹

= 5.12 x 10¹¹ bits

scientific notation = 5.12 x 10¹¹ bits

standard Notation = 512 ,000,000,000 bits.

Answer:

The answer is "[tex]\bold{\frac{32}{3}}\\[/tex]"

Step-by-step explanation:

The rectangle should also be symmetrical to it because of the symmetry to the y-axis  The pole of the y-axis.  Its lower two vertices are (-x,0). it means that  

and (-x,0), and (x,0). Therefore the base measurement of the rectangle is 2x. The top vertices on the parabola are as follows:  

The calculation of the height of the rectangle also is clearly 16-x^2, (-x,16,-x^2) and (x,16,-x^2).  

The area of the rectangle:

[tex]A(x)=(2x)(16-x^2)\\\\A(x)=32x-2x^3[/tex]

The local extremes of this function are where the first derivative is 0:

[tex]A'(x)=32-6x^2\\\\32-6x^2=0\\\\x= \pm\sqrt{\frac{32}{6}}\\\\x= \pm\frac{4\sqrt{3}}{3}\\\\[/tex]

Simply ignore the negative root because we need a positive length calculation

It wants a maximum, this we want to see if the second derivative's profit at the end is negative.

[tex]A''\frac{4\sqrt{3}}{3} = -12\frac{4\sqrt{3}}{3}<0\\\\2.\frac{4\sqrt{3}}{3}= \frac{8\sqrt{3}}{3}\\\\\vertical \ dimension\\\\16-(\frac{4\sqrt{3}}{3})^2= \frac{32}{3}[/tex]

Question:

You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on constructing a confidence interval; however, you are not sure how many citizens should be included in the sample. If you want your sample estimate to be within 5 years of the actual mean with a confidence level of 97% , how many citizens should be included in your sample? Assume that the standard deviation of the ages of all the citizens in this community is 18 years.

Answer:

61.03

Step-by-step explanation:

Given:

Standard deviation = 18

Sample estimate = 5

Confidence level = 97%

Required:

Find sample size, n.

First find the Z value. Using zscore table

Z-value at a confidence level of 97% = 2.17

To find the sample size, use the formula below:

[tex] n = (Z * \frac{\sigma}{E})^2[/tex]

[tex] n = ( 2.17 * \frac{18}{5})^2 [/tex]

[tex] n = (2.17 * 3.6)^2 [/tex]

[tex] n = (7.812)^2 [/tex]

[tex] n = 61.03 [/tex]

Sample size = 61.03

Answer:

2

Step-by-step explanation:

Since there are four negative signs, we have -1 multiplying each other 4 times,  multiplying by positive 2. This is then 1 * 2, which is 2.

Answer:

+2

Step-by-step explanation:

=> -(-(-(-2))))

=> -(-(+2))

=> -(-2)

=> +2

Answer:

  50 in²

Step-by-step explanation:

If we assume that 5 inch and 15 inch are the base dimensions, the area formula tells us the area is ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(5 in +15 in)(5 in) = 50 in²

The area of the trapezoid is 50 square inches.

Answer:

$300

Step-by-step explanation:

Let [tex]x[/tex] be the original price.

[tex]x \times (1-0.04)=288[/tex]

[tex]0.96x=288[/tex]

[tex]x=\frac{288}{0.96}[/tex]

[tex]x=300[/tex]

Answer:

$300

Step-by-step explanation:

If it was a 4% reduction then we get:

[tex]x*0.96=288\\[/tex]

Divide both sides by 0.96

[tex]x=300[/tex]

The original suit price was $300

Answer:

[tex]\boxed{\sf \ \ \ 49a^8b^6c^2 \ \ \ }[/tex]

Step-by-step explanation:

Hello,

[tex](-7a^4b^3c)^2=(-1)^27^2a^{4*2}b^{3*2}c^2=49a^8b^6c^2[/tex]

as

[tex](-1)^2=1[/tex]

Answer:

it’s C

Step-by-step explanation:

No, the vertices of the image and pre-image do not correspond

No, the vertices of the image and pre-image do not correspond, Micaela tried to rotate the square 180° about the origin. Hence, option C is correct.

A figure can be rotated by 90 degrees clockwise by rotating each vertex of the figure 90 degrees clockwise about the origin.

Let's take the vertices of a square with points at (+1,+1), (-1,+1), (-1,-1), and (+1,-1), centered at the origin, can be found in the following positions after rotation:

Micaela's rotation must be accurate if it led to the same points. Her rotation is incorrect if the points are different, though.

It is impossible to tell if Micaela's rotation is accurate without more details or a diagram.

Thus, option C is correct.

For more information about rotation about the origin, click here:

https://brainly.com/question/30198965

#SPJ7

Answer:

-3

Step-by-step explanation:

every sequence goes down by -3

Answer:

take away 3. the common difference is 3

Step-by-step explanation:

take away 3

Answer:

80-119 ⇒ 5

Because

80-99 ⇒ 3

100-119 ⇒ 2

So 2+3 = 5

Answer:

80-119: 5

Step-by-step explanation:

If you just added up, you can find all the values.

Answer:

________________________

Answer:8.2 x 10^5

Step-by-step explanation:

Answer:

Store A

Step-by-step explanation:

So. What we are going to want to do here is start off by having two stores obviously. And we have the sales that they have. If the discount is 20% rhat means the new price will be 80% of 250. So we take 250 x .8 = 200

If the discount is 25%, that means the new price will be 75% of what it was before hand. So we take 280 x .75 = 210. So the better price is at Store a

Answer:

The return on assets in this business for Macrosoft is

ROA = 10.50%

Step-by-step explanation:

Return on Equity:

ROE represents how much a firm is generating profits by using the shareholder's money.

ROE is calculated as

[tex]$ {ROE = \frac{Annual \:\: net\: \: income}{Average \:\: shareholder's \:\: equity} $[/tex]​  ​

Return on Assets:

ROA represents how much a firm is generating profits for every dollar of its assets.

ROA is calculated as

[tex]$ {ROA = \frac{Annual \:\: net\: \: income}{Total \:\: assests} $[/tex]​  ​ ​

What is the return on assets in this business if Macrosoft has no debt?

Debt plays an important role in the calculations of return on assets.

We know that

Assets = Liabilities + Equity

Since the Macrosoft has no debt, its return on assets will be same as return on equity.

Assets = Equity

ROA = ROE

ROA = 10.50%

Answer:

[tex] \frac{1}{2} [/tex]

Step-by-step explanation:

[tex]scale \: factor = \frac{5}{10} = \frac{1}{2} \\ [/tex]

Answer:

  193.77 < p < 1806.23

Step-by-step explanation:

You want R(p) > 2,100,000, so ...

  -6p^2 +12000p > 2100000

  p^2 -2000p < -350000 . . . . divide by -6

Adding (2000/2)^2 = 1000000 will "complete the square".

  p^2 -2000p +1000000 < 650000 . . . . complete the square

  (p -1000)^2 < 650000

  -√650000 < p -1000 < √650000 . . . . take the square root

  1000 -806.23 < p < 1000 +806.23 . . . .add 1000

  193.77 < p < 1806.23 . . . . range of prices for desired revenue

Answer: b

Explanation:

The -2 outside of the parentheses means it’s at y=-2 and the -4 inside the parentheses means it’s at x= 4 because it’s always the opposite

Answer:

17x +7y

Step-by-step explanation:

8x + 10y + 9x - 3y

Combine like terms

8x+ 9x          + 10y - 3y

17x                   +7y

8x+9x are like terms    and 10y -3y are like terms

Answer:

17x + 7y

Step-by-step explanation:

8x + 10y + 9x - 3y

Rearrange.

8x + 9x + 10y - 3y

Factor out x and y.

x (8 + 9) + y (10 - 3)

Add or subtract.

x (17) + y (7)

17x + 7y