please help me! im confused ​

Answer:

B.  [tex]x = -4\,\lor \,x = -1[/tex]

Step-by-step explanation:

Let [tex]\sqrt{-4-5\cdot x} = x[/tex], we solve for [tex]x[/tex] by algebraic means.

1) [tex]\sqrt{-4-5\cdot x} = x[/tex] Given

2) [tex]-4-5\cdot x = x^{2}[/tex] Definition of power/Symmetry of equality

3) [tex]x^{2}+5\cdot x + 4 = 0[/tex] Compatibility with addition/Commutative and associative properties/Existence of additive inverse/Modulative property

4) [tex](x+4)\cdot (x+1) = 0[/tex]         [tex]x^{2}+(a+b)\cdot x +a\cdot b = (x + a)\cdot (x+b)[/tex]

5) [tex]x = -4\,\lor \,x = -1[/tex] Result

Hence, the correct answer is B.

Answer:

y=-2x+5

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

Answer:

I dont know what sin is

Step-by-step explanation:

Answer:

B is the answer.

Step-by-step explanation:

took test. 100% sure.

Answer:

Step-by-step explanation:

bbbbbbbbbbbbb

Answer:

y=0.5x-3

Step-by-step explanation:

m=(-12+14)/(-18+22)=0.5

y+14=0.5(x+22)

y=0.5x-3

Answer:

[tex]\frac{10\sqrt{6} }{3}[/tex] and [tex]\frac{11\sqrt{3} }{3}[/tex]

Step-by-step explanation:

(a)

A = [tex]\frac{1}{2}[/tex] × 4[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]

   = 2[tex]\sqrt{2}[/tex] × [tex]\frac{5}{\sqrt{3} }[/tex]

   = [tex]\frac{10\sqrt{2} }{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator

= [tex]\frac{10\sqrt{6} }{3}[/tex] units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4[tex]\sqrt{2}[/tex] )² + ([tex]\frac{5}{\sqrt{3} }[/tex] )²

    = 32 + [tex]\frac{25}{3}[/tex]

    = [tex]\frac{96}{3}[/tex] + [tex]\frac{25}{3}[/tex]

    = [tex]\frac{121}{3}[/tex] ( take the square root of both sides )

h = [tex]\sqrt{\frac{121}{3} }[/tex] = [tex]\frac{11}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ← rationalise the denominator

h = [tex]\frac{11\sqrt{3} }{3}[/tex]

Answer:

24-18=6+6+12

hope this helps you!!

Step-by-step explanation:

Answer:

Answering so you can give other person branliest

Answer:

so simple pls follow up..

Inbox me

Answer:

This is a reduction dilation :)

Step-by-step explanation:

Answer:

18t-72

Step-by-step explanation:

Answer:

0 = -16t² + 3200 → 16t²= 3200 → t² = 200 → t = 10√2 s ≈ 14 s

The time taken by the skydiver to reach the ground is 14.1 second.

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

Given that, the height of a skydiver jumping out of an airplane is given by n = -16t² + 3200.

Here, n=0

-16t² + 3200=0

-16t²=-3200

t²=200

t=√200

t=14.14

t=14.1 second

Therefore, the time taken by the skydiver to reach the ground is 14.1 second.

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Answer:

1152

Step-by-step explanation:

Complete Question:

g(x), represents transformations on the parent function of [tex]y = (\frac{1}{2})^x[/tex].

Write the equation for g (x ) with the following transformations:

Reflect over y-axis, and shift right 7

Answer:

[tex]g(x) = (\frac{1}{2})^{-x-7}[/tex]

Step-by-step explanation:

Given

[tex]y = (\frac{1}{2})^x[/tex]

Represent the function as:

[tex]f(x) = (\frac{1}{2})^x[/tex]

Taking the transformations, one after the other:

Reflect over the y-axis.

This is represented by the rule: (x,y) ==> (-x,y)

So, we have:

[tex]f'(x) = (\frac{1}{2})^{-x}[/tex]

Shift right 7 units

This is represented by (x,y) = (x - b, y)

Where b represents the number of units

So, we have:

[tex]f'(x-7) = (\frac{1}{2})^{-x-7}[/tex]

Hence:

[tex]g(x) = (\frac{1}{2})^{-x-7}[/tex]

Answer:

arc XY = 46°

Step-by-step explanation:

the arc of an inscribed angle is equal to 2 x the inscribed angle

mXY

Answer:

B) ΔGRS ≈ ΔART by SAS Similarity

Step-by-step explanation:

Answer:

22,000

Step-by-step explanation:

c=2πr

2(3.14)3500

Answer:

11) 75.2

12) 44.2

Step-by-step explanation:

angles formed by intersecting lines tangent to a circle are the same length.

11)

Perimeter = 2(5) + 2(12) + 2(11.4) + 2(9.2) = 75.2

12)

Perimeter = 2(4) + 2(8) + 2(5.3) + 2(4.8) = 44.2

Answer:

[tex]\frac{2x+y}{w}[/tex]

Answer:

6-12.

Step-by-step explanation:

Between 6 to 12 two numbers must the third side of the card fall.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that Sarah is creating a triangular birthday card for her teacher.

Thus in order to glue lace around the outside of the card, Sarah needs to know the length of each side.

It should be known that two of the sides measure 4 inches and 9 inches.

Therefore, in between 6 to 12 the third number must be lie.

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Answer:

64*x^-6

Step-by-step explanation:

Simplify Using Laws of Exponent (4x^-2)^3

Given data

(4x^-2)^3

Let us open the bracket

=4^3*x^-2*3

=64*x^-6

=64x^-6

Hence the equivalent is

64*x^-6

Answer:

Triangular prism

Step-by-step explanation:

A triangular prism has 9 edges, 6 vertices and 5 faces. I don't think there is any other shape which fits 9 edges and 6 faces.

Answer:

7.0

Step-by-step explanation:

Right angled triangle. To find the hypotenuse, use Pythagorean theorem.

Hypotenuse² =  base² + altitude²

                      = 6.5² + 2.7²

                      = 42.25 + 7.29

                     = 49.54

hypotenuse = √49.54 = 7.04 = 7

Step-by-step explanation:

by using Pythagoras law

h²=p²+b²

missing angle =h let

h²=(2.7)²+(6.5)²

h=√(49.50)=7.03=7

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. [tex]\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}[/tex] Therefore, because sin is y/r, r = [tex]\sqrt{5}[/tex] and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = [tex]\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}[/tex]

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = [tex]4\sqrt{2}[/tex]. Now, to find csc, we have to do r/y.

csc = [tex]\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}[/tex]

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = [tex]\sqrt{7/16}[/tex] = [tex]\frac{\sqrt{7}}{4}[/tex]

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -[tex]\sqrt{7/9} = \frac{-\sqrt{7}}{3}[/tex]

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = [tex](\frac{-\sqrt{6}}{2})^{2}[/tex]

1 + cot^2 = 6/4

cot^2 = 2/4

cot = [tex]\frac{\sqrt{2}}{2}[/tex]

tan = [tex]\sqrt{2}[/tex]

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

[tex](\frac{2}{\sqrt{2}})^2[/tex] + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -[tex]\sqrt{3}[/tex]

cos = [tex]\frac{-\sqrt{3}}{3}[/tex]

Hope this helps!! :)

Answer:

sin(θ)=√7/4

tan(θ)= - √7/3

Step-by-step explanation:

c^2= √(4^2-(-3^2))

c^2= √(16-9)

c^2= √7

sin(θ)= opp/hyp=√7/4

tan(θ)= (opp )/adj= - √7/3

Answer:

x = 22

Step-by-step explanation:

19+23=2X-2

42 = 2x - 2

-2x = -2 - 42

-2x = -44

x = 22

hope this helps

Answer: $117,000

Step-by-step explanation:

The maximum that Arianna may borrow is 2.5 times her annual income.

First step therefore, would be to calculate her annual income:

= 900 * 52 weeks

= $46,800

She may borrow 2.5 times this:

= 46,800 * 2.5

= $117,000

Answer:

When x=2

Step-by-step explanation:

Well in the first one it tells you that 2x is 90.

In the second it's y=40x+10

So you plug 2 in as the x.

y=40(2)+10

y=80+10

y=90

Hope this helps

Answer:

Step-by-step explanation:

Answer:

T<-2, -7> (x, y)

Step-by-step explanation:

A coordinate system in geometry is a system that employs one or more integers, or coordinates, to define the position of points. The rule that maps the other vertices of the figure to their images is T<-2, -7> (x, y).

A coordinate system in geometry is a system that employs one or more integers, or coordinates, to define the position of points or other geometric components on a manifold such as Euclidean space.

Given that Sanjay determined that one vertex of a figure was mapped to its image by translating the point 2 units left and 7 units down.

In order to translate coordinates, 2 units left we need to subtract 2 units from the x-coordinate of the point, while to translate the point 7 units down we need to subtract 7 from the y-coordinate of the point.

Therefore, the rule that maps the other vertices of the figure to their images is,

(x₁, y₁) = (x-2, y-7), ot it can bse written as T<-2, -7> (x, y),

where x₁ and y₁ are the coordinates of the point after translation.

Hence, the rule that maps the other vertices of the figure to their images is T<-2, -7> (x, y).

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