please help me I'd appreciate it so much!! (no links)
Which of the following pairs of triangles can be proven similar through SAS similarity? Question options: A) image B) image C) image D) image

Answer:

THE OTHER ANSWER IS WRONG

Step-by-step explanation:

90=20+6x-2

92=20+6x

72=6x

12=x

Hope this helps!

Answer:

C. <3, E. <1

Step-by-step explanation:

A triangle has 3 vertices, so it has exactly 3 interior angles, one at each vertex.

A triangle has 2 exterior angles at each vertex, so a triangle has 6 exterior angles. Each exterior angle is adjacent to an interior angle. The interior angles that are not adjacent to an exterior angle are that exterior angle's remote interior angles.

<6 is an exterior angle of the triangle. <5 is the other exterior angle at that vertex. <2 is an interior angle of the triangle and is adjacent to <6, so <2 is not a remote interior angle to <6.

The other two interior angles of the triangle are <1 and <3.

<1 and <3 are interior angles that are not adjacent to <6, so they are the remote interior angles to <6.

Answer: <1, <3

Answer

Equation : x + 1 + 3x = 7

Miles Lissette biked : 3/2 miles

Step-by-step explanation:

Step 1: Determine the total number of miles biked.

From my understanding. 7 miles is the total number of miles biked by both.

Step 2: Assume the values

Miles Lissette biked = x

Miles Shane biked = 1 + 3x

Step 3: Add miles biked by Lissette and Shane which will be equal to total miles.

Equation for miles Lissette biked: x + 1 + 3x = 7

4x + 1 = 7

x = 6/4

Step 4: Simplify

x = 6/4

x = 3/2

Therefore, the equation for miles Lissette biked is x + 1 + 3x = 7 and Lissete biked for 3/2 miles.

Hope it helped if yes mark me BRAINLIEST

Tysmm

Answer:

7 = 3x - 1

Step-by-step explanation:

Miles Shane biked = y

Miles Lissette biked = x

The equation is

(x ⋅  3) - 1 = y

And we know y = 7, so

(x ⋅  3) - 1 = 7

3x - 1 = 7

Step-by-step explanation:

here ,

length = 8m

height=4m

Rate of plastering 4 walls = 15/m^2

Cost of plastering 4 wall = Rs 1560

Area of floor = Cost of plastering / Rate of plastering

= 1560/15

= 104

again,

Area of four wall = 2h(l+b)

or, 104= 2×4(8+b)

or, 104 =8(8+b)

or, 104/8=8+ b

or,13 - 8= b

or, b= 5

again,

Area of floor= l×b

= 8×5

= 40

again,

Rate of carpeting the floor= 300/ m^2

Area of floor = 40 m^2

cost of carpeting=Rate × Area

= 300×40

= 12000

Answer:

[tex]\huge\boxed{Option \ C}[/tex]

Step-by-step explanation:

∠CAD is the central angle and ∠CBD is the inscribed/circumference angle which means that

∠CAD = 2(∠CBD)

So, If ∠CBD = 55° then ∠CAD = 110°

Hello, because of the geometric sequence we can say that:

[tex]\alpha = \dfrac{b}{a}=\dfrac{c}{b}\\\\\dfrac{c}{a}=\dfrac{c*b}{a*b}=\dfrac{c}{b}\dfrac{b}{a}=\alpha^2\\\\\text{So the equation becomes.}\\\\ax^2+bx+c=0<=>x^2+\dfrac{b}{a}x+\dfrac{c}{a}=0\\\\<=>x^2+\alpha x+ \alpha^2=0\\\\\Delta=b^2-4ac = \alpha^2-4\alpha^2=-3\alpha^2 < 0[/tex]

So there is no real root, so the function does not cut the x axis.

Thank you

For the given quadratic function, the x-axis is not cut by the function because there is no true root.

To determine values for various parameters, quadratic functions are employed in a variety of scientific and engineering disciplines. A parabola is used to graphically illustrate them. The orientation of the curve is defined by the highest degree factor.

As per provided data in question,

α = b/a = c/b

c/a = (c × b)/(a × b) = (c/b) (b/a) = α²

For the equation,

ax² + bx + c = 0

x² + b/a(x) + c/a = 0

⇒ x² + ax + α² =0

Δ = b² - 4 ac = α² - 4α²

Δ = -3α² < 0, which means that no real root is there.

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Answer:

17) #1 = 5

#2 = 49

18) Median= 50.5

Range = 88

Step-by-step explanation:

17) #1 - There are 5 3’s on the leaf side.

#2 - The number that is shown the most times is 49

18) There are 30 numbers in the stem and leaf plot, so the median falls between numbers 15 and 16.  In this plot, those numbers are 50 and 51.  So the median is 50.5.

The data ranges from 10 to 98.  98-10=88

Answer:

[tex]\huge\boxed{9}[/tex]

Step-by-step explanation:

[tex]\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}[/tex]

Rule of exponents [tex]a^0 = 1[/tex] , [tex]1/a^m = a^{-m}[/tex]

=> [tex]\sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}[/tex]

=> [tex]\sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}[/tex]

Combining same bases

=> [tex]\sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}[/tex]

When bases are same , powers are to be added

=> [tex]\sf 2 ^{-16-12+28} * 3^{10-8}[/tex]

=> [tex]\sf 2^{-28+28} * 3^2[/tex]

=> [tex]\sf 2^0 * 3^2[/tex]

=> [tex]\sf 3^2[/tex]

=> 9

[tex]35pq^2=5\cdot7\cdot p\cdot q^2\\-14pq^2=-1 \cdot 2\cdot 7\cdot p \cdot q^2\\-21p^2q^3=-1\cdot 3\cdot 7\cdot p^2 \cdot q^3\\\\\text{hcf}(35pq^2,-14pq^2,-21p^2q^3)=7\cdot p \cdot q^2=7pq^2[/tex]

Answer:

Step-by-step explanation:

Given the expression [tex]sin^{-1} 1/2[/tex], the following steps must be taken to evaluate the expression.

[tex]Let\ y = sin^{-1}1/2[/tex]

[tex]y = sin^{-1} 0.5[/tex]

From the calculator, the value of y wil give;

[tex]y = 30\\\\y = 30.00 (to\ the \ nearest \ hundredth)[/tex]

Hence [tex]sin^{-1} 0.5 = 30.00[/tex].

Answer:

Step-by-step explanation:

The answer is 0.52

Hope that helped

Answer:

6.3294✖️10^7

Step-by-step explanation:

To find the statdard form, you place the decimal after the largest unit, int his case 6.

Then you write down all the numbers except for "0".

This becomes:

6.3294

Then, you add the multiplying sign, and count how many digits are there after 6, and in this case, there are 7, so you add the power "7" after 10.

6.3294✖️10^7

Hope this helped!

Have a nice day:)

Answer:

Step-by-step explanation:

The standard from of equation of a line written in slope-intercept format is expressed as y = mx+c where c is the slope of the line and c is the y-intercept.

Given the equation of the line x+3y = 10, to get the slope of the line, we need write he equation in standard from first by making y the subject of the formula as shown;

[tex]x+3y = 10\\\\subtract\ x \ from \ both \ sides\\\\x+3y-x = 10 -x\\\\3y = -x+10\\\\Divide \ through\ by \ 3\\\\\frac{3y}{3} = -\frac{x}{3} +\frac{10}{3} \\\\[/tex]

[tex]y = -\frac{1}{3}(x) +\frac{10}{3} \\[/tex]

Comparing the resulting equation with y = mx+c, the slope 'm' of the equation is -1/3

The slope of the line is -1/3.

the correct option is D.

To find the slope of the line given by the equation x + 3y = 10, we need to rewrite it in slope-intercept form, which is y = mx + b, where m represents the slope.

Let's rearrange the equation to solve for y:

x + 3y = 10

3y = -x + 10

y = (-1/3)x + 10/3

Comparing this equation to the slope-intercept form, we can see that the coefficient of x (-1/3) represents the slope.

Therefore, the slope of the line is -1/3.

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Answer:

Bridget's first fish =f = 5 ounces

Bridget's dad first fish weighs 17 ounces

Step-by-step explanation:

Bridget went fishing with her dad. Bridget caught the first fish of the day, and it weighed f ounces. That day, she caught four more fish. One was 2 times the weight of the first fish, another was 2 more than 3 times the weight of the first fish, the next was 1/2 the weight of the first fish, and the last was 3/5 the weight of the first fish. Bridget’s dad caught four fish. The first fish he caught weighed 2 more than 3 times the weight of the first fish caught that day. One fish weighed 4/5 the weight of the first fish caught that day, one weighed 4 more than 2 times the weight of the first fish caught that day, and the last weighed 1/2 the weight of the first fish caught that day. If all the fish Bridget caught have the same total weight as all the fish her dad caught, then the first fish Bridget caught weighed___ ounces and the first fish her dad caught___ weighed ounces.

Solution:

Bridget's fishes:

f ounces

2f ounces

3f+2 ounces

1/2f ounces

3/5f ounces

Total= f +2f + (3f+2) + 1/2f +3/5f

=3f + 3f + 2 + 5f+6f/10

=6f + 2 + 11f/10

=60f+11f/10 +2

=71/10f +2

Bridget's dad fishes

3f+2

4/5f

2f+4

1/2f

Total =(3f+2) + (2f+4) + 4/5f +1/2f

=3f+2+2f+4 + 8f+5f/10

=5f + 6 + 13/10f

= 50f+13f/10 + 6

=63/10f +6

Equate the total weight

71/10f +2=63/10f +6

Collect like terms

71/10f - 63/10f =6-2

71f-63f/10 = 4

8f/10=4

Cross product

8f=40

Divide both sides by 8

f=5

Bridget's first fish =f = 5 ounces

Bridget's dad first fish = 3f +2

=3(5)+2

=15+2

=17 ounces

Bridget's dad first fish weighs 17 ounces

Answer:

[tex]3 {x}^{2} - 16x + 16 \\ 3 {x}^{2} - 12x - 4x + 16 \\ 3x(x - 4) - 4(x - 4) \\ (3x - 4)(x - 4)[/tex]

Step-by-step explanation:

I hope it helped U

stay safe stay happy

Answer:

The correct statment is B.

Step-by-step explanation:

A. is not correct:  y = 2.4(30) - 1.8 does not equal 70...

B. Is correct because the slope is 2.4 From the equation

C. is not correct because the points have no 2.4 (maybe 2.2)? difference.

D. is not correct. the correlation isn't positive.

Answer:

Step-by-step explanation:

please refer to the picture above

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

V(t) = 14,000(0.89)^t  

Step-by-step explanation:

Present value of the Dodge Challenger = $14,000

Present percentage value = 100%

Depreciation value = 11%

Number of years = t

Future value = V(t)

V(t) = Present value of the Dodge Challenger(Present percentage value - Depreciation value)^t

= 14,000(100% - 11%)^t

= 14,000(89%)^t

= 14,000(0.89)^t

V(t) = 14,000(0.89)^t

Answer:

468

Step-by-step explanation:

The equation is: 51x² + y + 3​

Let's first find x.  It says x= 3, so let's subsitute that in.

51(3)² + y + 3​

3² is 9 because 3 times 3 is 9, which means:

51(9) + y + 3​.  

It is 51 times 9 and not 519 because x was supposed to be squared by itself and 51 was next to it.  When a number is close to another number, especially with parentheses, it wants you to multiply the two together.  

For example: 3(3) is 9 and 4(5) is 20.

Now that we found x, let's get y.  The problem states that y= 6...let's subsitute that in.  

51(9) + 6 + 3​.  

Now that we got all the variables out of the way, we can simplify!

51 times 9= 459

459+6+3 is the same thing as 459+9, since 6+3= 9.

459+15= 468  :)

Answer:

√134

Step-by-step explanation:

Solve for the top line first,

√(5²+3²)

= √34

then for the dotted line,

√(10²+(√34)²)

= √134

Answer:

b1 = 0, b2 = 0

EXPLICACION

A = 12 b1 + b2 h

A - 12 b1 - b2 h = 0

b2!=0, h = -(12 b1)/b2

Answer:

Perimeter = 8x - 12

Step-by-step explanation:

The perimeter of a square is:

p = 4(side length)

on this case:

p = 4(2x-3)

p = 4*2x + 4*-3

p = 8x - 12

Answer:

[tex] 6\sqrt{6} [/tex]

Step-by-step explanation:

[tex] \sqrt{12}\sqrt{18} = [/tex]

[tex] = \sqrt{12 \cdot 18} [/tex]

[tex] = \sqrt{4 \cdot 3 \cdot 9 \cdot 2} [/tex]

[tex] = \sqrt{36 \cdot 6} [/tex]

[tex] = \sqrt{36}\sqrt{6} [/tex]

[tex] = 6\sqrt{6} [/tex]

Following are the step by step solutions to the given expression:

Given:

[tex]\to \sqrt{12} \times \sqrt{18} \sqrt{30}[/tex]

To find:

solve=?

Solution:

[tex]\to \sqrt{12} \times \sqrt{18} \sqrt{30}[/tex]

[tex]\to \sqrt{2\times 2 \times 3} \times \sqrt{2\times 3 \times 3} \sqrt{2 \times 3 \times 5} \\\\ [/tex]

[tex]\to 2\sqrt{3} \times 3\sqrt{2} \sqrt{2 \times 3 \times 5} \\\\ \to 6\times \sqrt{3} \times \sqrt{2} \sqrt{2\times 3 \times 5} \\\\ \to 6\times \sqrt{3} \times \sqrt{2} \times \sqrt{2}\times \sqrt{3} \times \sqrt{5} \\\\ \to 6 \times 3 \times 2 \times \sqrt{5} \\\\ \to 36 \sqrt{5}[/tex]

Therefore, the final answer is "[tex]36\sqrt{5}[/tex]"

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Answer: Choice B)

The relation is a function because there are no vertical lines that can be drawn on the graph that pass through more than one point.

This graph passes the vertical line test. Any input (x) leads to one and only one output (y). An example of a graph failing the vertical line test would be a graph that is a sideways parabola.

Answer:

1.

= Here,

Narasimha invest = 120,000

Madhu 135,000

pavan =

Answer:

[tex]\large \boxed{4}[/tex]

Step-by-step explanation:

[tex]\sf The \ sum \ of \ -5, \ -10, \ and \ -9 \ is \ divided \\ by \ the \ product \ or \ multiplication \ of \ 2 \ and -3.[/tex]

[tex]\displaystyle \frac{-5+-10+-9}{2 \times -3}[/tex]

[tex]\displaystyle \frac{-24}{-6}[/tex]

[tex]=4[/tex]

Answer:

4

Step-by-step explanation:

-5+(-10)+(-9)/2*(-3)

=-5-10-9/-6

=-24/-6

=4

Answer:

20.78feet

Step-by-step explanation:

The question made us to understand that the man is standing and also there is angle of elevation, then we need to draw a right triangle having a base equal to 36 feet with an angle from the base to the top of the pole which is 30 degrees.

tan= opposite side / adjacent side

Let height of the pole =h

Tan(30)= h/36

But tan 30degree= 1/√3

h= 36 × 1/√3

h= 20.78feet

Therefore, the height of the pole= 20.78feet

CHECK THE ATTACHMENT FOR DETAILED FIGURE

Answer:

B. 12\sqrt{3} ft

Step-by-step explanation:

Answer:

x=2

Step-by-step explanation:

3(x + 2) = 12

Distribute

3x+6 = 12

Subtract 6 from each sdie

3x+6-6 = 12-6

3x = 6

Divide by 3

3x/3 = 6/2

x=2

━━━━━━━☆☆━━━━━━━

▹ Answer

x = 2

▹ Step-by-Step Explanation

3(x + 2) = 12

Distribute:

3x + 6 = 12

Subtract 6 from each side:

6 - 6 = 0

12 - 6 = 6

Rewrite:

3x = 6

Divide each side by 3:

3/3 = x

6/3 = 2

x = 2

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Step-by-step explanation:

Disclaimer: When writing this on the paper use the theta symbol, I'm using x since I'm on mobile.

2.

i).

[tex] \sin(x) \tan(x) \sec(x) = \tan {}^{2} (x) [/tex]

[tex] \sin(x) \sec(x) \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \sin(x) \frac{1}{ \cos(x) } \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \frac{ \sin(x) }{ \cos(x) } \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \tan( x) ) \tan(x) = \tan {}^{2} (x) [/tex]

[tex] \tan {}^{2} (x) = \tan {}^{2} (x) [/tex]

iii).

[tex] \sec {}^{2} (x) (1 - \sin {}^{2} ( x ) ) = 1[/tex]

[tex] \sec {}^{2} (x) ( \cos {}^{2} (x) ) = 1[/tex]

[tex] \frac{1}{ \cos {}^{2} (x) } \cos {}^{2} (x) = 1[/tex]

[tex]1 = 1[/tex]

v).

[tex] \cot {}^{2} (a) - \cos {}^{2} (a) = \cot {}^{2} (a) \cos {}^{2} (a) [/tex]

[tex] \frac{ \cos{}^{2} (x) }{ \sin {}^{2} (x) ) } - \cos {}^{2} (x) [/tex]

Factor out cosine

[tex] \cos {}^{2} (x) ( \frac{1}{ \sin {}^{2} (x) } - 1) [/tex]

Simplify

[tex] \cos {}^{2} (x) ( \frac{1 - \sin {}^{2} (x) }{ \sin(x) } [/tex]

[tex] \cos {}^{2} (x( \frac{ \cos {}^{2} (x) }{ \sin {}^{2} (x) } ) = [/tex]

[tex]( \cos {}^{2} ( x ) ( \cot {}^{2} (x) )[/tex]