Please help me! I will give brainliest!


1. Imagine 50 people walking in straight lines in a room. What would happen to the number of
collisions they would have with the walls if they moved to a room half the size of the original
room but walked at the same speed?

2. Imagine 50 people walking in straight lines in a room. If those 50 people start running, what needs to happen in order for the number of collisions they would have with the walls of the room to remain the same?

The distance between the balloon and the rock can be found by using Pythagorean theorem: d = 198 .2 m

The motion of the stone is the motion of a projectile, thrown with a horizontal speed of

vx = 15 .0 m/s

and with an initial vertical velocity of

= 20.0 m/s

where we have put a negative sign to indicate that the direction is downward.

h is the initial height

g = -9.81 m/s^2 is the acceleration due to gravity

The stone hits the ground after a time t = 6.00 s, so at this time the vertical position is zero:

y(6.00 s) = 0

Substituting into eq.(1), we can solve to find the initial height of the stone, h: = 296 .m

(b) 176.6 m

The balloon is moving downward with a constant vertical speed of

v x = -20.0 m/s

and substituting t = 6.0 s and h = 296.6 m, we find the height of the balloon when the rock hits the ground:

y(t) = 176.6 m

(c) 198.2 m

In order to find how far is the rock from the balloon when it hits the ground, we need to find the horizontal distance covered by the rock during the time of the fall.

The horizontal speed of the rock is

v x = 15.0 m/s

So the horizontal distance travelled in t = 6.00 s is

d x = 90 m

Considering also that the vertical height of the balloon after t=6.00 s is

d y = 176.6 m

The distance between the balloon and the rock can be found by using Pythagorean theorem:

d = 198 .2 m

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Answer:

The same way Newton’s apple fell from the tree and failed to “fall” back up. The steeper the slope the faster the pull of gravity will act. Assuming you are providing the exact same power to a car an upslope will slow the car and a down slope will speed the car. The greater the slope, the greater effect. Until you reach vertical, you should never operate a vehicle in such a manner.

Explanation:

The acceleration and force of the block is 4 m/s² and 2 N respectively.

Acceleration is a measure of the change in an object's velocity over time. It is defined as the rate at which an object changes its velocity, either in speed or direction. Mathematically, acceleration is calculated as the change in velocity (delta v) divided by the change in time (delta t): a = Δv / Δt. In other words, it is the rate of change of velocity. Acceleration has units of meters per second squared (m/s^2) in the International System of Units (SI).

The acceleration of the block can be calculated using the formula:

a = Δv / t, where Δv is the change in velocity and t is the time interval.

Since the block starts from rest, its initial velocity is 0 m/s, and its final velocity can be calculated as v = a × t = 8 m/s.

So, a = [tex]\frac{v}{t}[/tex] = [tex]\frac{8m/s}{2s}[/tex] = 4 m/s².

The value of F can be calculated using Newton's second law, which states that the net force on an object is equal to its mass times acceleration:

F = ma = 500 g × 4 m/s² = 2 N.

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Lighting uses typically range from 2 to 100 watts (W), depending on size and kind.

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An electric field is an invisible field of force created by the attraction and repulsion of electric charges (the cause of electric flow) and is measured in volts per meter (V/m). With increasing distance from the field source, the electric field's intensity decreases.

Electrostatic forces are attractive or repulsive forces between particles that have already been created by their respective electric charges. The electrical force between stationary charged substances is generally known as the electrostatic force.

An electric field is an area around a charged object where the electric force of the object acts on other charged objects. Electric fields weaken the further they are from the charge. The electric field is invisible.

You see, electrically charged particles like protons and electrons actually have invisible force fields around them.

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The angular separation between the central maximum and the first-order maximum is equal to 1.22 radians.

This is the angle between the two points on the wavefront that have the same intensity of the wave, and is determined by the wavelength of the wave and the distance between the two points.

The angular separation is an important factor in understanding the behavior of a wave, as it affects the intensity of the wave at different points.

Additionally, the angular separation between two points on the wavefront can provide insight into the wavelength of the wave, as longer wavelengths yield larger angular separations.

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When there is the proper symmetry, Gauss's law can be used to quickly determine the electric field.One of these scenarios is not the case of an electric dipole.

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Work is done: a) by the gas on the piston.

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The wavelength of the standing wave will be 1.2 m if a cable is stretched between two posts 3.00 m apart. the speed of waves on this cable is 96.0 m/s, and the tension in the cable is 175 n. if a standing wave on this cable has five antinodes.

Length, l = 2 m

speed of waves, v = 96 m

Tension, T = 175 N

Antinodes, n = 5 means 5th harmonic

We know that,

l = nλ/2

or λ = 2l/n = 2x3/5 = 1.2 m

Therefore, the wavelength of the standing wave will be 1.2 m if a cable is stretched between two posts 3.00 m apart. the speed of waves on this cable is 96.0 m/s, and the tension in the cable is 175 n. if a standing wave on this cable has five antinodes.

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The wavelength of waves whose frequency of waves from a radio station is 15 megacycles per second is 20m

Given the frequency of radio waves (f) = 15 megacycles per second

The number of complete wave cycles that pass a location in a unit of time is the definition of frequency. The SI frequency unit is called a Hertz (Hz). A sinusoidal wave's frequency is defined as the total number of full oscillations that every wave constituent performs in a unit of time.

Let the wavelength = ∧

The speed of light waves (v) = 3 x 10^8m/s

We know that frequency = velocity/wavelength

Then f = v/∧ such that ∧ = v/f

∧ = 3 x 10^8/15 x 10^6 = 20m

Hence the wavelength of radio waves = 20m

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No, the glancing incident or near normal incidence does not result in a higher percentage of reflected light.

The percentage of reflected light is determined by the reflectivity of the surface and the angle of incidence. If the angle of incidence is closer to normal, then the reflected light will be more concentrated and will have a higher intensity, but the percentage of reflected light will remain the same.

The term "incidence" describes the emergence of new cases of illness or damage within a community within a predetermined time frame.

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The maximum mass of a polar bear can sit on the floor before sinking is 3075 kg.

The mass of an object is constant and does not change with location, unlike weight which does change depending on the gravitational pull of the planet.

Mass can be determined by measuring the gravitational force on an object using a device called a balance or scale. The International System of Units (SI) unit of mass is the kilogram (kg)

The maximum mass of a polar bear that can sit on the ice floe before it sinks is determined by the buoyancy force. The buoyancy force is equal to the weight of the water that the ice floe displaces, which is equal to the volume of the ice floe multiplied by the density of seawater.

The volume of the ice floe is 3m2 * 1m = 3 m3.

The buoyancy force is 3m3 * 1025 kg/m3 = 3075 kg.

The mass of the polar bear that can sit on the ice floe before it sinks is equal to the buoyancy force. So the maximum mass of a polar bear that can sit on the ice floe before sinking is 3075 kg.

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The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 3.958e-9 N. The distance at which the 60.6 kg mass experiences a net force of zero is infinitely remote.

The universal gravitational constant, denoted as G, is a physical constant that is used to describe the strength of the gravitational force between two objects. Its value is approximately 6.672 x 10^-11 Nm^2/kg^2. This constant is used in the equation for the force of gravity, which is F = G(m1m2)/r^2, where m1 and m2 are the masses of the two objects, and r is the distance between them. The constant is considered to be a fundamental constant of nature and is used in many fields of physics, including cosmology and celestial mechanics.

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Answer: plants have internal and external structures that support growth and reproduction Examples of internal structures are the xylem and phloem Examples of external structures are the roots and stems. All of these structures provide plants with nutrients and food

Explanation: BRAIN

The accelaration of the boat, given the speed of the boat and the time taken to reach the speed, is 0.2 m / s².

Acceleration can be found by dividing the change in the speed of an object by the time it takes.

The change in speed is:

= 8 m / s - 2 m / s

= 6 m /s

The change in time is:

= 1 / 2 x 60 seconds per minute

= 30 seconds

The acceleration is:

= 6 / 30

= 0.2 m / s²

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Answer:

0.2

Explanation:

Acceleration = change in velocity / time = (8 m/s – 2 m/s) / 30s = 0.2 m/s2

Answer:

Unlike charges attract

Explanation:

the force between unlike charges is strong,and the closer the charges are the stronger the electrostatic force between them

A magnetic field is a field that explains how magnetism affects an item in space.

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Answer:

lab report is attached

Explanation:

In this physics demonstration, the ball that is dropped vertically and the one that is launched horizontally will both make contact with the ground at distinct times. The ball that falls vertically will first hit the ground.

This is because the force of gravity acts downward on both balls, causing them to accelerate toward the ground. However, the horizontally launched ball experiences the launch force as well, giving it an initial horizontal velocity. The ball's rate of descent to the ground is slowed by this horizontal velocity, resulting in a longer time spent on the ground.

On the other hand, the vertically dropped ball only experiences the force of gravity because it has no initial horizontal velocity. This indicates that it descends straight down at a steady rate and reaches the ground earlier than the horizontally launched ball.

The rate at which an object's position changes over time is measured by its velocity. It has magnitude and direction because it is a vector quantity. Meters per second (m/s) is the International System of Units (SI) standard for measuring velocity.

Mathematically, velocity can be represented as:

v = x/t, where x is the object's change in position (or displacement), t is the change in time, and v is the velocity.

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The additional mass should be distributed as 2.75g, 0.25g, and 3 gm at vertices V1, V2, and V3 respectively, to move the center of mass of the plate at (2, 2).

The center of mass (x, y) of a triangular plate with vertices V1=(0,1), V2=(8,1), and V3=(2,4) can be calculated by taking the average of the x and y coordinates of the vertices.

x = (0 + 8 + 2)/3 = 10/3

Similarly y = 6/3 = 2

So, the center of mass of the plate is (4, 2).

New center of the mass is (2, 2)

w1 + w2 + w3 = 6 g ....eqn(1)

Mass of the plate, m = 3 g

To distribute an additional mass of 6 g at the three vertices of the plate to move the balance point of the plate to (2,2), we need to determine the masses w1, w2, and w3 that need to be added at each vertex.

The formula for finding the center of mass of a system of point masses is:

x = (w1 × x1 + w2 × x2 + w3 × x3 + m × 10/3)/(m + w1 + w2 + w3)

y = (w1 × y1 + w2 × y2 + w3 × y3 + m × 2)/(m + w1 + w2 + w3)

2 = (w1 × 0 + w2 × 8 + w3 × 2 + 3 × 10/3)/(3 + 6)

18 = 8w2 + 2w3 + 10

8 = 8w2 + 2w3....eqn(2)

Similarly

2 = (w1 × 1 + w2 × 1 + w3 × 4 + 3 × 2)/(3+6)

18-6 = w1 + w2 + 4w3

12 = w1 + w2 + 4w3 ...... eqn(3)

On solving three equations

6 = w1 + w2 + w3

8 = 8w2 + 2w3

12 = w1 + w2 + 4w3

We get

w1 = 2.75 g

w2 = 0.25 g

w3 = 3 g

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--The given question is incomplete, the complete question is:

"A thin triangular plate of uniform density and thickness has vertices V1=(0,1), V2=(8,1), and V3=(2,4), and the mass of the plate is 3 g.

Determine how to distribute an additional mass of 6g at the three vertices of the place to move the balance point of the plate to (2,2). Hint: Let w1,w2,w3 denote the masses added to the three vertices so that w1+w2+w3= 6."--

The equator is characterized by relatively  low atmospheric pressure aloft.

The equator is a large circle that circles the planet Earth, being in a plane perpendicular to the axis of the planet and being equally spaced from geographic poles.

The geographic Equator, also known as the terrestrial Equator, is the imaginary line on the surface of the Earth from which latitude is calculated; it is the line at 0° latitude. It separates Earth into the Northern and Southern hemispheres.

Equatorial regions are hotter, which causes the air above to expand, lose density, and ascend. At this latitude, this results in a low pressure band.

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Delivery method for their speech is True.

The context of the speaking event can greatly affect the audience's expectations for the delivery of a speech. For example, in a formal setting such as a business conference, the audience may expect a more professional and formal delivery, with the use of slides or visual aids and a well-structured speech. In contrast, at a casual event such as a family gathering, the audience may expect a more relaxed and conversational delivery, with less emphasis on visual aids and a more informal structure. Additionally, the topic of the speech, the background of the audience and the purpose of the speech can also affect the audience's expectations. Therefore, a speaker should be aware of the context of the event, and adjust their delivery method accordingly.

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The velocity will be 0 m/s. We calculated it as shown below.

It is the directional speed of a moving object, as measured by a specific unit of time and viewed from a particular vantage point, that is called velocity. Vectorial velocity describes the displacement that an object or particle experiences with respect to time. It is accepted that the metre per second (m/s) is the unit of magnitude of velocity (also called speed). As well as meters per second (m/s), centimeters per second can also be used to express magnitude.

Velocity = [tex]\frac{Displacement}{Time}[/tex]

= 0/ 35

= 0 m/s

So , The velocity will be 0 m/s.

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The maximal static friction force (F) between surfaces in contact prior to motion starting is divided by the normal force (N) to determine the coefficient of static friction. Solving yields a value of 1.08 m/s2.

The maximal static friction force (F) between surfaces in contact prior to motion starting is divided by the normal force (N) to determine the coefficient of static friction.

Static friction's highest value is F s = _s mg.

where _s is the static friction coefficient

50kg is the box's weight in meters.

Gravitational acceleration is equal to 9.81 m/s2.

F s = 0.5×50×9.81 =245 N

The object must be in motion because the applied force exceeds the static friction's maximum value, F s.

As a result, kinetic friction rather than static friction must be considered.

by the equilibrium state

ma = F k m g

where F = 250 N, k = kinetic friction coefficient = 0.4, and m = 50 Kg

a = box's acceleration

50a = 250-0.4×50×9.81

Solving yields a value of 1.08 m/s2.

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According to its definition, the net force is the total of all the forces operating on an object.So, 108.46 N force is exerted on the ball.

According to its definition, the net force is the total of all the forces operating on an object.

Mass can be propelled forward by net force.In motion or at rest, another force exerts its influence on the body.When a system contains a sizable number of forces, the term "net force" is employed.

It is given that,

Initial velocity of the baseball, u = 0

The baseball's final speed was 97 mph, or 43.36 m/s.

Mass of baseball, m = 0.15 kg

Distance, s = 1.3 m

(a) Let a be the acceleration of the baseball. Use third equation of motion as :

a = 43.36 /2*1.3

a = 723.11 m/s

Force is given by :

F = m a

F = 0.15 * 723.11= 108.46 N

So, 108.46 N force is exerted on the ball.

(b) The pitcher would need to increase the force so as to alter the required force to reach the same speed if the mass of the ball is decreased.

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A large air mass moving over flat land from a desert to an ocean is a true statement.

The temperature, humidity, and pressure of the air mass, as well as the temperature, humidity, and pressure of the water beneath it, are the data

Scientists need to know to assist them to estimate the possibility of precipitation as the air mass travels closer to the ocean.

Being a warm front, the precipitation is expected to contain a few scattered clouds. This is due to the fact that the air mass of the desert is passing over an ocean, which implies that a heated, dry air mass is passing over a cold air mass.

Therefore, it is a true statement.

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The correct option is (b) i.e. optical system. It is made up of a laser, optical filters, light-collecting optics, and beam-shaping components.

A scanner assembly, as it relates to digital imaging and document scanning, typically consists of a laser, optical filters, light-collecting optics, and beam-shaping devices. The laser is used to project a precise, concentrated beam of light onto the surface of the plate or document being scanned. Optical filters are used to control the wavelength and intensity of the light being used. Light-collecting optics, such as lenses, are used to focus the beam of light onto the plate or document. Finally, beam-shaping devices, such as mirrors or prisms, are used to guide the beam of light as it scans across the plate or document. The scanner assembly is designed to move the beam of light back and forth across the plate in a controlled manner, capturing an image of the plate or document as it does so.

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Question - The part of the reader that consists of a laser, optical filters, light-collecting optics, and beam-shaping devices that is designed to project and guide a precisely controlled laser beam back and forth across the plate as the plate moves through the scan area is the

a) photodetector

b) optical system

c) drive mechanism

d) photostimulable luminescence

If it starts from rest can travel 1000m, in a straight path, and again it has to come to rest at the end of  1000m, then minimum 70s will be taken.

According to the question, the car starts off at a stop, travels up to a top speed of 20 m/s, and then comes to a stop. This implies that the vehicle must have first reached its maximum speed before braking to a stop.

Let, [tex]T_1[/tex] and [tex]T_2[/tex] be the time for acceleration (attaining maximum velocity) and deceleration (come to the rest) respectively.

Then,

[tex]T_1[/tex] = (Maximum velocity - initial velocity) / acceleration

⇒ [tex]T_1=\frac{20-0}{1}=20sec[/tex]

Then, distance travelled in time [tex]T_1[/tex],

⇒ [tex]S_1=UT_1+\frac{1}{2}aT_1^2[/tex]

⇒ [tex]S_1=0+\frac{1}{2}*1*20^{2}[/tex]

⇒ [tex]S_1= 200m[/tex]

Similarly,

⇒ [tex]T_2=\frac{0-20}{-1}=20sec[/tex]

⇒ [tex]S_2=UT_2+\frac{1}{2}aT_ 2^2[/tex]

⇒ [tex]S_2=(20*20)-(\frac{1}{2}*1*20^2)[/tex]

⇒ [tex]S_2=400-200=200m[/tex]

∴ Distance travelled at uniform velocity is

⇒ [tex]S = 1000-(S_1+S_2)[/tex]

⇒ [tex]S=1000-(200+200)=1000-400=600m[/tex]

This 600m is travelled at a speed of 20m/s.

and time of travel for constant velocity is

⇒ [tex]T_3=\frac{S}{V}[/tex]

⇒ [tex]T_3=\frac{600}{20}=30sec[/tex]

Hence, total time for travel

⇒ [tex]T=T_1+T_2+T_3=(20+20+30)sec=70sec[/tex]

On a V-T graph, it can be displayed here(See picture).

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The magnitude of charge q3 is 3*10^4 N/C and it has a positive sign.

To find the magnitude and sign of the additional charge q3 needed to make the total electric field at point A equal to zero, we can use the principle of superposition of electric fields. This principle states that the total electric field at any point in space is the vector sum of the electric fields due to each individual charge.

We can start by calculating the electric field due to each of the two point charges q1 and q2 at point A, which is located at the origin. The electric field due to a point charge q at a distance r from it is given by the equation:

E = k*q/r^2

Where k is the Coulomb constant and q is the charge.

For q1, the electric field at point A is:

E1 = kq1/(16m)^2 = 910^9 * 810^-9 / 256 = 310^4 N/C

For q2, the electric field at point A is:

E2 = kq2/(9m)^2 = 910^9 * 610^-9 / 81 = 610^4 N/C

Since q2 is on the negative x-axis, the electric field is pointing in the negative x direction.

Now we can calculate the total electric field at point A by adding these two fields vectorially.

E = E1 + E2 = 310^4 N/C - 610^4 N/C = -3*10^4 N/C

The total electric field at point A is pointing in the negative x direction.

To make the total electric field equal to zero, we need to add an additional charge q3 at point B that has the same magnitude as the total electric field but pointing in the opposite direction. The magnitude of q3 is -3*10^4 N/C, and since it is pointing in the positive x-direction, the sign of q3 is positive.

So, the magnitude of q3 is 3*10^4 N/C and it has a positive sign.

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To determine the charge, we can use the equation for the electric field due to a point charge:

E = k * q / r^2

Where E is the electric field, k is the Coulomb constant (8.98755 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the point charge.

We can rearrange this equation to solve for q:

q = E * r^2 / k

Plugging in the given values:

q = (68.3 N/C) * (28.8 m)^2 / (8.98755 x 10^9 Nm^2/C^2)

q = (68.3 N/C) * (826.24 m^2) / (8.98755 x 10^9 Nm^2/C^2)

q = (68.3 N/C) * (826.24 m^2/C^2)

q = (68.3 N/C) * (826.24 / 8.98755 x 10^9) C

q = (68.3 N/C) * (9.26 x 10^-9) C

q = 6.36 x 10^-7 C

The charge is approximately 6.36 x 10^-7 Coulombs.

The speed of the car truck combination is calculated to be 0.667 m/s and it is a type of inelastic collision.

Mass of the car m₁ = 700 kg

Velocity of the car u₁ = 20 m/s

Mass of the stationary truck m₂ = 1400 kg

Velocity of the stationary truck u₂ = 0

The momentum before collision is, m₁ u₁ = 700× 20 = 1400 kg m/s

As, we know from the principle of conservation of linear momentum,

momentum before the collision of trucks is equal to momentum after the collision of trucks.

The momentum after the collision is (m₁ + m₂) vf = 1400 kg m/s

(700 + 1400) vf = 1400

2100 vf = 1400

vf = 0.667 m/s

Now, let us compare kinetic energies before and after collision.

Kinetic energy before collision = 1/2 m₁ u₁² = 1/2 × 700× 20² = 14×10⁴ kg m/s

Kinetic energy after collision =1/2 (m₁+m₂) vf₂ = 1/2(700 + 1400) 0.667² = 467.13 kg m/s

As kinetic energy is not conserved, the type of collision is said to be an inelastic collision.

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