Please help me. Anyone who gives ridiculous answers for points will be reported.

Answer:

DNS

Explanation:

Hope this helps

Answer:

The answer is interpret Proof is down below

Explanation:

Here is the proooooooffffffff i made a 90 but this one was right

Secondary sources interpret information gathered from primary sources.

A secondary source is known to be made up of discussion that is often based on a primary information source.

Hence, the feature of secondary sources are known to give some kind of interpretation to all the information that has been gathered from other primary sources.

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Answer:

4

Explanation:

Input/output, datapath, control, and memory

There wrong its C bold it.

:)))))

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.

It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.

It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.

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Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

              //print the header

              System.out.println("**************************************");

              System.out.println("*                                    *");

              System.out.println("*                                    *");

              System.out.println("*   Gas-N-Clean Service Station      *");

              System.out.println("*                                    *");

              System.out.println("*   March 2, 2004                    *");

              System.out.println("*                                    *");

              System.out.println("**************************************");

               //set the constant values for gasoline

               final double REGULAR_GASOLINE = 2.89;

               final double PLUS_GASOLINE = 3.09;

               final double SUPER_GASOLINE = 3.39;

              // initialize the variables as 0

              double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;

               Scanner input = new Scanner(System.in);

               //ask the user to enter the gallons, gas type and car wash choice

               System.out.print("Enter number of gallons ");

               double gasolinePurchase = input.nextDouble();

               System.out.print("Enter gas type (R, P, S, or N) ");

               char gasType = input.next().charAt(0);

               System.out.print("Enter Y or N for car wash ");

               char carWashChoice = input.next().charAt(0);

               //check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value

              if(gasType == 'R')

                  gasolinePrice = REGULAR_GASOLINE;

              else if(gasType == 'P')

                  gasolinePrice = PLUS_GASOLINE;

              else if(gasType == 'S')

                  gasolinePrice = SUPER_GASOLINE;

                //calculate the gasolineCost

                gasolineCost = gasolinePurchase * gasolinePrice;

               //check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00

               if(carWashChoice == 'Y'){    

                   if(gasolineCost >= 10)

                       carWashCost = 1.25;

                   else

                       carWashCost = 3.00;

               }

              //calculate the total cost, add gasolineCost and carWashCost

              totalCost = gasolineCost + carWashCost;

               //print the values in required format

              System.out.println("Amount Gasoline purchases " + gasolinePurchase);

              System.out.println("Gallons Price per gallons $ " + gasolinePrice);

              System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);

              System.out.println("Car wash cost $ " + carWashCost);

              System.out.printf("Total due $ %.2f\n", totalCost);

               System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");

}  

}

Explanation:

*The code is in Java.

Please see the comments in the code for explanation

import java.util.Scanner;

public class JoggerPro {

   public static void main(String[] args) {

       String days[] = {"Monday?", "Tuesday?", "Wednesday?", "Thursday?","Friday?","Saturday?","Sunday?"};

       System.out.println("Welcome to JoggerPro!");

       Scanner myObj = new Scanner(System.in);

       System.out.println("Do you want to continue?");

       String answer = myObj.nextLine();

       if (answer.toLowerCase().equals("y")){

           double totalMiles = 0;

           for (int i =0; i < 7; i++){

               System.out.println(" ");

               System.out.println("How many miles did you jog on " + days[i]);

               double miles = myObj.nextDouble();

               totalMiles += miles;

           }

           double average = totalMiles / 7;

           System.out.println(" ");

           System.out.println("You ran a total of " + totalMiles+ " for the week.");

           System.out.println(" ");

           System.out.println("The average mileage is " + average);

       }

   }

}

I'm pretty sure this is what you're looking for. I hope this helps!

Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

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The one that is not a period of the Middle Ages is the High Middle Ages. The correct option is c.

The Middle Ages, which roughly correspond to the years 500 to 1400–1500 BCE, is the term used to describe this time of European history. The phrase was initially used by academics in the 15th century to refer to the time frame between their own era and the dissolution of the Western Roman Empire.

The period between the fall of Imperial Rome and the start of Early Modern Europe is referred to as the “Middle Ages” for this reason. The reason the Middle Ages are known as the Dark Ages is that life was hard and brief in Europe, and contrasted with the orderliness of classical antiquity.

The time period in European history from roughly 500 AD to 1500 AD. This time period's early years are commonly referred to as the Dark Ages.

Therefore, the correct option is c, High Middle Ages.

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Answer:

import random

decisions = int(input("How many decisions: "))

for i in range(decisions):

   number = random.randint(0, 1)

   if number == 0:

       print("heads")

   else:

       print("tails")

Explanation:

*The code is in Python.

import the random to be able to generate random numbers

Ask the user to enter the number of decisions

Create a for loop that iterates number of decisions times. For each round; generate a number between 0 and 1 using the randint() method. Check the number. If it is equal to 0, print "heads". Otherwise, print "tails"

Answer:

Search

Explanation:

Because you are searching up a specific recording using keywords.

I hope this helps

Answer:

Filter

Explanation:

I got it correct for a quiz.

Answer:

Written in Python

numVal = int(input("Input: "))

for i in range(numVal,0,-1):

    print(i)

print("Ready!")

Explanation:

This line prompts user for numVal

numVal = int(input("Input: "))

This line iterates from numVal to 1

for i in range(numVal,0,-1):

This line prints digits in descending order

    print(i)

This line prints the string "Ready!"

print("Ready!")

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is an online decision support system. Because the decision support systems process the data, evaluate and predict the decision, and helps the decision-makers,  and offer real-time information immediately in making the decision in an organization. So the correct answer to this question is the decision supports system.

Why other options are not correct

Because the transaction processing system can only process the transaction and have not the capability to make the decision for the future. Office support processing system support office work, while the batch processing system process the task into the batch without user involvement.   however, online executive processing does not make decisions and offer timely information to decision-makers in an organization.

Answer: the answer is A.

Explanation: He has to listen to what the people tell him and think about the information he has and make a choice on what to reply with.

This is python code.

In python, you are supposed to put a colon at the end of while loops. This code does not have a colon after the while loop, therefore, you need to add a colon to the end of the statement.

The error to be fixed in the while loop is to add a colon at the end of the while statements.

x = 1

while (x<26)

     print(x)

     x = x + 1

This is the right code;

x = 1

while(x < 26):

   print(x)

   x = x + 1

The actual code , the while statement is missing a colon at the end of it.

The code is written in python. In python while or for loops statements always ends with a colon.

In the error code, there was no colon at the end of the while loop.

The right codes which I have written will print the value 1 to 25.

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Answer:

i choose choice D

Explanation:

reason as to my answer public keys are simply input keys used to encrypt data into either a computer or any electrical device as private keys are out put used to either erase or edit

Answer:

Press and hold the power button for up to 10 seconds, until your Mac turns off. If that doesn't work, try using a cellular device to contact Apple Support.

Explanation:

If that also doesn't work try click the following keys altogether:

(press Command-Control-Eject on your keyboard)

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

This makes the laptop (macOS) instruct to restart immediately.

Hopefully this helps! If you need any additional help, feel free and don't hesitate to comment here or private message me!. Have a nice day/night! :))))

Another Tip:

(Press the shift, control, and option keys at the same time. While you are pressing those keys, also hold the power button along with that.)

(For at least 10 seconds)

Answer:

Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.

Explanation:

Answer:

The equivalent if statements is:

ranforce = randi([0, 12]);

if (ranforce == 0)

     disp('There is no wind')

else  if(ranforce>0 && ranforce <7)

     disp('There is a breeze')

else  if(ranforce>6 && ranforce <10)

     disp('This is a gale')

else  if(ranforce>9 && ranforce <12)

     disp('It is a storm')

else  if(ranforce==12)

     disp('Hello, Hurricane!')

end

Explanation:

The solution is straight forward.

All you need to do is to replace the case statements with corresponding if or else if statements as shown in the answer section

Answer:

270 nsec

Explanation:

Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.

Formula to calculate the delay of a ripple-carry adder is;

  = 2( n + 1 ) x D

delay in a full-adder = 150 nsec.

number of full-adders = number of ripple-carry bits = 8

 = 2 ( 8 + 1 ) x 150

 = 18 x 150

 = 270 nsec

Answer:

The corrected program is:

import java.util.Scanner;

public class LabProgram{

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int qtr, dime, nickel, penny;

double dollars;

System.out.print("Quarters: ");

qtr =scnr.nextInt();

System.out.print("Dimes: ");

dime = scnr.nextInt();

System.out.print("Nickel: ");

nickel = scnr.nextInt();

System.out.print("Penny: ");

penny = scnr.nextInt();

dollars = qtr * 0.25 + dime * 0.1 + nickel * 0.05 + penny * 0.01;

System.out.printf("Amount: $%.2f\n", dollars);

System.out.print((dollars * 100)+" cents");

}

}

Explanation:

I've added the full program as an attachment where I used comments as explanation

Answer:

the clock rate of the first machine need to be 1.7 GHz

Explanation:

Given:

CPI of A = 1.9

CPI of B = 1.1

machine, B executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz

To find:

In order for the two machines to have the same performance, what does the clock rate of the first machine need to be

Solution:

CPU execution time = Instruction Count * Cycles per Instruction/ clock rate

CPU execution time = (IC * CPI) / clock rate

(IC * CPI) (A) / clock rate(A) =  (IC * CPI)B / clock rate(B)

(IC * 1.9) (A) / clock rate(A) = (IC * (1.1 * (1.0 - 0.20)))(B) / 800 * 10⁶ (B)

Notice that 0.20 is basically from 20% less instructions

(IC * 1.9)  / clock rate = (IC * (1.1 * (1.0 - 0.20))) / 800 * 10⁶

(IC * 1.9)  / clock rate =  (IC*(1.1 * ( 0.8))/800 * 10⁶

(IC * 1.9)  / clock rate =  (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) / (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) (800 * 10⁶) /  (IC * 0.88)

clock rate (A) = 1.9(800)(1000000)  / 0.88

clock rate (A) =  (1.9)(800000000)  / 0.88

clock rate (A) = 1520000000  / 0.88

clock rate (A) = 1727272727.272727

clock rate (A) = 1.7 GHz

Answer:

umm that is a todler song

Explanation:

umm that is a todler song that they sing to them when there crying

A country, called Simpleland, has a language with a small vocabulary of just “the”, “on”, “and”, “go”, “round”, “bus”, and “wheels”. As per the given scenario, the vector of counts will be 2111211. The correct option is C.

C++ has a built-in function that counts the length of the vector. Size is the function's name ().

It returns the size or total number of elements of the vector that was utilized to create it. There is no need for debate.

The number of observations (rows) includes deleted observations as well. In an SAS data collection, there can be a maximum of 2 63-1 observations, or roughly 9.2 quintillion observations. For the majority of users, going above that limit is quite rare.

The vector of counts in the above scenario will be 2111211.

Thus, the correct option is C.

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Answer:

And what??????????????

Answer:

false

Explanation:

1 MB = 0.001 GB

In python:

print(steps_walked / 2000)

Answer:

Yes

Explanation:

Online privacy is a controversial topic due to the fact that it's a very hard thing to navigate. Some websites use cookies that are used to store your data so in a way there taking your privacy away which is controversial because of the way they use the information. Some websites store it for use of ads while others sell it. This issue is applicable to me and my peers because of the way we use technology. It can be used to steal my information about where I live and what I look up online. Also, the information stored could have my credit or debit card credentials. This issue should be a federal and nationwide issue because this is an everyday occurrence and leaves tons of people in crushing   debt every year.

Answer:

speed and storage

Explanation:

The pros and cons of both are mainly in regards to speed and storage. Due to linked lists elements being connected to one another it requires that each previous element be accessed in order to arrive at a specific element. This makes it much slower than an array-based implementation where any element can be quickly accessed easily due to it having a specific location. This brings us to the other aspect which is memory. Since Arrays are saved as a single block, where each element has a specific location this takes much more space in the RAM as opposed to a linked implementation which is stored randomly and as indexes of the array itself.

Array Implementation:

Linked Implementation

Answer:

C and G

Explanation:

In C language, the asterisks, ' * ', and the ampersand, ' & ', are used to create pointers and references to pointers respectively. The asterisks are used with unique identifiers to declare a pointer to a variable location in memory, while the ampersand is always placed before a variable name as an r_value to the pointer declared.

Answer:

Follows are the code to this question:

def weeklypay(hour_rate,hour ):#defining a method weeklypay that accepts two parameters

   pay=hour_rate* hour#defining variable pay that calculate payable amount

   return pay#return pay value

hour_rate=float(input("Enter your hour rate $: "))#defining variable hour_rate that accepts rate vlue

hour=int(input("Enter total hours: "))#defining hour variable that accepts hour value

print('The total amount you will get $: ',weeklypay(hour_rate,hour))#call method and print return value

Output:

Enter your hour rate $: 300

Enter total hours: 3

The total amount you will get $:  900.0

Explanation:

In the above-given code, a method "weeklypay" is declared, which holds two value "hour_rate and hour" in its parameter, inside a method a "pay" variable is declared, that calculate the total payable amount of the given inputs and return its value.

In the next step, the above variable is used to input the value from the user-end and uses the print method to call the "weeklypay" method and print its return value.