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The heat of vaporization of water is one of the highest known.


True
False

Answer:

A.100J

Explanation:

Given parameters:

Force on car = 20N

Distance  = 5m

Unknown:

Work done  = ?

Solution:

Work done is the product of force and distance;

  Work done  = force x distance;

Insert given parameters and solve;

        Work done  = 20 x 5  = 100J

Answer:

The shortest possible distance is  [tex]|s| = 91.9 \ m[/tex]

Explanation:

From the question we are told that

   The mass of the car is   [tex]m = 1800 \ kg[/tex]

    The speed along the horizontal road is  [tex]v_o =u = 18.4 \ m/s[/tex]

     The static friction coefficient is  [tex]\mu_s = 0.188[/tex]

      The kinetic friction coefficient is  [tex]\mu_k = 0.1316[/tex]

Generally the static frictional force acting on the car is  mathematically represented as

          [tex]F_f = m * g * \mu_s[/tex]

Generally the force propelling the car is mathematically represented as

        [tex]F = m * a[/tex]

Here a is the maximum acceleration

at the point which the car stops ,

       [tex]F = F_f[/tex]  

=> [tex]m * g * \mu_s = ma[/tex]

=> [tex]g * \mu_s =a[/tex]

=> [tex]a = 9.8 * 0.188[/tex]

=> [tex]a = 1.8424 \ m/s^2[/tex]

Generally from kinematic equation

    [tex]v^2 = u^2 + 2as[/tex]

Here v  is the final velocity of the car and the value is zero given that the car comes to rest

So

        [tex]0^2 = 18.4^2 + 2* 1.8424 s[/tex]

=>     [tex]s = - \frac{18.4^2}{2 * 1.8424}[/tex]

=>     [tex]|s| = 91.9 \ m[/tex]

Answer:

the line b aka the option d

Explanation:

Explanation:

0.10kg

0.5kg×0.2kg=

0.10

Answer:

I think it's part c . but sorry if its wrong

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. Explanation:

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction

Explanation:

In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Answer:

men

Explanation:

The conservation of momentum P states that the amount of momentum remains constant when there are not external forces.

We don't have external forces, so:

[tex]P_0 = P_1\\m_bv_{0b}+m_pv_{0p}=m_bv_{1b}+m_pv_{1p}\\[/tex]

Where:

Solving for v0b:

[tex]v_{0b} =\dfrac{m_bv_{1b}+m_pv_{1p}- m_pv_{0p}}{m_{b}}\\\\v_{0b} =\dfrac{(7\;kg)(4\;m/s)+(2\;kg)(6\;m/s)- (2\;kg)(0 \;m/s)}{7\;kg}\\v_{0b}=\dfrac{40}{7}\;m/s\\\\\boxed{v_{0b}\approx5.71\;m/s}[/tex]

The original velocity of the ball is 5.71 m/s.

The principle of conservation of momentum: In a closed system, The total momentum before collision is equal to total momentum after collision.

From the principle of conservation of momentum,

MU+mu = MV+mv.................... Equation 1

Where M = mass of the bowling ball, m = mass of the pin, U = initial velocity of the bowling ball, u = initial velocity of the pin, V = final velocity of the bowling ball, v = final velocity of the pin.

From the question,

Given: M = 7 kg, m = 2 kg, u = 0 m/s (at rest), v = 6.0 m/s, V = 4 m/s.

Substitute these values into equation 1 and solve for U

7(U)+2(0) = 7(4)+2(6)

7U = 28+12

7U = 40

U = 40/7

U = 5.71 m/s.

Hence, The original velocity of the ball is 5.71 m/s.

Learn more about velocity here: https://brainly.com/question/6237128

Answer:

Acceleration = 3m/s^2

Vf= 0  Vi =35m/s   t= 13s

Explanation:

[tex]Acceleration = \frac{Change in velocity}{Change in time}\\ = \frac{35m/s}{13s}\\ a = 2.69m/s^2\\ a = 2.7m/s^2\\ a = 3m/s^2[/tex]

Answer:

1080 meters is the answer

Answer:

t = 3.35 s

Explanation:

It is given that,

Mass of a pumpkin, m = 8 kg

It is dropped from a height of 55 m

We need to find the time taken by it to hit the ground.

Initial velocity of the pumpkin, u = 0

Using second equation of motion to find it as follows :

[tex]h=ut+\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2(55)}{9.8}} \\\\t=3.35\ s[/tex]

So, it will take 3.35 seconds to hit the ground.

Answer:

Its A

Explanation:

To reduce the strength of an electromagnet, Juan must  reduced the number of loops in the wire.

The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.

The strength of an induced emf in a given magnetic field is given by;

emf = NBA/t

where;

Decrease in number of turns of the wire, reduces the strength of the magnetic field.

Thus, to reduce the strength of an electromagnet, Juan must  reduced the number of loops in the wire.

Learn more about electromagnet here: https://brainly.com/question/12555869

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Answer:

Answer: C. 3000kg

Explanation:

Hydraulic Jack

It's a device that is used to lift heavy loads by applying force via a hydraulic cylinder.

Since the internal pressure on the liquid of the jack is constant, the following relation applies:

[tex]\displaystyle \frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]

Where

F1  = Force applied in one end of the jack

A1  = Area of the cylinder of the same end

F2  = Force applied in the other end of the jack

A2  = Area of the cylinder of the other end

If we assume the force is being applied on side 1, then the force on side 2 is calculated by solving for F2:

[tex]\displaystyle F_2=\frac{F_1.A_2}{A_1}[/tex]

We have F1=1000N, A1= 48~cm^2, A2= 1440~cm^2, thus:

[tex]\displaystyle F_2=\frac{1000.1440}{48}[/tex]

[tex]F_2 = 30000 ~N[/tex]

Since we need to know the mass that can be lifted by that force, we use the formula:

W = m.g

Where W is the weight of the mass and g= 10~m/s^2. Since the weight is equal to the force exerted by the jack:

[tex]\displaystyle m=\frac{W}{g}=\frac{30000}{10}[/tex]

m = 3000 Kg

Answer: C. 3000kg

Answer:

The force needed to launch the projectile is 150000 N.

Explanation:  

We can find the force using the following equation:

[tex] F = ma [/tex]

Where:

m: is the mass = 15 kg

a: is the acceleration

First, we need to find the acceleration of the projectile:

[tex] v_{f}^{2} = v_{0}^{2} + 2ax [/tex]                          

Where:

[tex]v_{f}[/tex]: is the final speed

[tex]v_{0}[/tex]: is the initial speed = 0

x: is the distance = 2 m

The final speed is:

[tex]v_{f} = \frac{1 km}{5 s}*\frac{1000 m}{1 km} = 200 m/s[/tex]

Then, the acceleration is:

[tex]a = \frac{v_{f}^{2}}{2x} = \frac{(200 m/s)^{2}}{2*2 m} = 10000 m/s^{2}[/tex]

Finally, the force is:

[tex]F = ma = 15 kg*10000 m/s^{2} = 150000 N[/tex]

Therefore, the force needed to launch the projectile is 150000 N.

I hope it helps you!  

Answer:

It's definitely Nucleus

Hope this Helps!

Answer:

C

Explanation:

Answer:

C

Region B, the corpus callosum, is composed of several lobes while region D, the cerebellum, only has one lobe.

Explanation:

Answer:

b

Explanation:

Answer:

a

Explanation:

because the crest and trough are the same length when together and they squeeze together making the length shorter for higher frequencies and are spaced apart when lower frequencies occur

Answer:

Evidence for continental drift

Wegener knew that fossil plants and animals such as mesosaurs, a freshwater reptile found only South America and Africa during the Permian period, could be found on many continents. He also matched up rocks on either side of the Atlantic Ocean like puzzle pieces.

Explanation:

Answer:

Explanation:

The car will fall with acceleration due to gravity which is equal to 9.8 m /s²

For downward fall ,

initial velocity u = o

acceleration due to gravity = g = 9.8 m /s

final velocity v = ?

displacement h = 5.2 m

v² = u² + 2 gh

v² = 0 + 2 x 9.8 x 5.2

= 101.92

v = 10.1 m /s

Answer:

Explanation:

19116 being the distance from the centre of the earth to the point you want to check in metres. So after all that you get G = 1.0888m/second squared. Hope that helps you/ you should be able to pop in any height you want.

plz mark as brainliest

Answer:

c = 894.90 m/s

Explanation:

Given data:

Frequency of wave = 471 Hz

Wavelength of wave = 1.9 m

Speed of wave = ?

Solution:

Formula:

Speed of wave = frequency × wavelength

c = f×λ

c = 471 Hz × 1.9 m

  Hz = s⁻¹

c = 471s⁻¹ × 1.9 m

c = 894.90 m/s

The speed of wave is 894.90 m/s.

Answer:

c

Explanation:

c. the ability to do work or to produce heat

Answer:

I think it's false

Explanation:

clouds also help regulate the Earth's energy balance by reflecting and scattering solar radiation and by absorbing the Earth's infrared radiation.

Answer:

false

Explanation:

Answer:

9 - 10N to the left

10 - There is no change on the object

Explanation:

Can I have brainliest answer pls?

Mass if a substance is the product of its volume and density. The mass of gold of 0.02 m³ with a density of 19300 kg/m³ is 386 kg.

Density of a substance is the measure of its mass per unit volume. Thus, it says how much denser the object is in a given volume. Density of a substance is dependent on its bond type, temperature and pressure beside the volume and mass.

Volume can be defined as the space occupied by the substance. Larger the volume , less dense the substance is. However as the mass increases volume also increases.

Mass of an object is the product of its volume and density.

Given the volume of gold = 0.02 m³

density = 19300 kg/m³.

mass = volume ×  density

         = 0.02 m³ × 19300 kg/m³

         = 386 kg

Therefore, the mass of gold is 386 Kg.

To find more on gold, refer here:

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Answer:

The potential is  [tex]V_A = 9600 \ V[/tex]

Explanation:

From the question we are told that  

   The  magnitude of the charge is  [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]

   The position of the charge is  [tex]x = + 3.0 \ m[/tex]

   The magnitude of the second charge is  [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]

   The position is  [tex]y_1 = - 1.0 \ m[/tex]

     The position of point A is  [tex]y_2 = + 4.0 \ m[/tex]  

Generally the electric potential  at A due to the first charge is mathematically represented as

         [tex]V_a = \frac{k * q_1 }{r_1 }[/tex]

Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]

        [tex]r_1[/tex]  is the distance between first charge and a which is mathematically represented as

         [tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]

=>      [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]    

=>      [tex]r_1 = 5 \ m[/tex]    

So

           [tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]

      [tex]V_a = 7200 \ V[/tex]

Generally the electric potential  at A due to the second charge is mathematically represented as

         [tex]V_b = \frac{k * q_2 }{r_2 }[/tex]

Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]

        [tex]r_2[/tex]  is the distance between second charge and a which is mathematically represented as

         [tex]r_2 = y_2 - y[/tex]

=>      [tex]r _2 = 4.0 - (-1.0)[/tex]    

=>      [tex]r = 5 \ m[/tex]    

So

           [tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]

      [tex]V_a = -3600 \ V[/tex]

So the net potential difference at point A  due to the charges is mathematically represented as

       [tex]V_n = V_a + V_b[/tex]

=>     [tex]V_n = 7200 - 3600[/tex]

=>     [tex]V_n = 3600 V[/tex]

Generally the net potential difference at the origin due to both charges is mathematically represented as

     [tex]V_N = V_c + V_d[/tex]

Here  

      [tex]V_c = \frac{k * q_1 }{x}[/tex]

=>   [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]

=>   [tex]V_c = 12000 V[/tex]

and

              [tex]V_d= \frac{k * q_2 }{y}[/tex]

=>   [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]

=>   [tex]V_c =- 18000 V[/tex]

Generally the net potential difference at the origin is  

       [tex]V_N = 12000 - 18000[/tex]

=>     [tex]V_N = -6000[/tex]

Generally the potential difference at A relative to zero at the origin is mathematically evaluated as

         [tex]V_A = V_n - V_N[/tex]

=>      [tex]V_A = 3600 - (-6000)[/tex]

=>      [tex]V_A = 9600 \ V[/tex]