Answer:
about 5.1 units
Step-by-step explanation:
to find the length between two points you can use the pythaogorean theorem
5^2 + 1^2 = c^2
25 + 1 = c^2
26 = c^2
c is about 5.09901
rounding to the nearest tenth we get 5.1
Find an equation of the plane through (-1,4,-3) and perpendicular to the line x-2=t , y+3=t , z=-t
Answer:
x + y -z = 6
Step-by-step explanation:
The equation of the line can be rewritten as ...
(x, y, z) = (2, -3, 0) +t(1, 1, -1)
The direction vector of the line tells you the coefficients of the variables in the equation of the plane. The constant in that plane equation will be the value required to make it pass through the given point.
x + y - z = (-1) +(4) -(-3)
x + y - z = 6 . . . . equation of the plane
This is Functions and Statistics Class:
[tex] \sqrt[6]{x} . \sqrt[4]{ {y}^{3} } \\ = {x}^{ \frac{1}{6} } . {y}^{ \frac{3}{4} } \\ = {x}^{ - 6} . {y}^{ \frac{3}{4} } [/tex]
Hope you could get an idea from here.
Doubt clarification - use comment section.
18) Jacob is trying to decide whether to attend akeshore University or Bayside University. He
likes both schools equally, and both schools sent him letters of acceptance. Recently
Lakeshore University raised its tuition by 6%. Which statement is most reasonable in this
situation?
a) Jacob should attend Bayside University since it will be less expensive.
b) Jacob should gather more information about tuition before making a decision.
c) Jacob should not worry about a 6% tuition increase since this is a small percent.
Answer: B
Step-by-step explanation: Jacob doesn't know either colleges' actual price. Bayside could still be equal to or more expensive than Lakeshore.
Which of the following graphs is described by the function given below?
y = 2x2 + 6x + 3
5
101
10
10
-20
20
- 10
10
-10
20-
101
A.
B.
C.
D.
A. Graph A
B. Graph B
O C. Graph C
D. Graph D
Answer:
Which of the following graphs is described by the function given below?
y = 2x2 + 6x + 3
-A. Graph A
The function y = 2x^2 + 6x + 3 is a quadratic function that has a vertex of (-1.5,-1.5)
How to determine the graph of the function?The equation of the function is given as:
y = 2x^2 + 6x + 3
Differentiate
y' = 4x + 6
Set to 0
4x + 6 = 0
This gives
4x = -6
Divide by 4
x = -1.5
Substitute x = -1.5 in y = 2x^2 + 6x + 3
y = 2(-1.5)^2 + 6(-1.5) + 3
Evaluate
y = -1.5
This means that the function y = 2x^2 + 6x + 3 has a vertex of (-1.5,-1.5)
See attachment for the graph of y = 2x^2 + 6x + 3
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What does the transformation f(x)↦f(x+5)–1 do to the graph of f(x)?
Answer:
Every f(x) shall decrease to 5 times the previous value.
Seven less than one-fourth of a number is 2. What is the number?
Based on the equation given, it can be deduced that the value of the number will be 36.
Let the number be represented by x
Therefore, seven less than one-fourth of a number will be:
=(1/4 × x) - 7
= 0.25x - 7
Now, seven less than one-fourth of a number is 2 will be written as:
0.25x - 7 = 2
0.25x = 2 + 7
0.25x = 9
x = 9/0.25
x = 36
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What is the constant of proportionality in this table?
XY
48
5 10
6 12
10 20
Answer:
2
Ok lets start off with your 3 numbers
First do 10 / 5 = 2
Then do 12 / 6 = 2
After that do 20 / 10 = 2
now you see you that its all equivalent to 2 that's your answer!
Which fractions are equivalent to the fraction below? Check all that apply.
3/4 ??
Answer:
hi there !
The answer is "30/40"
because by dividing each nominator and denominator by "10" it gives 3/4
Question 1
A number, w, is located to the left of 5 on the number line.
Which inequality represents this situation?
A
W> 5
B
w < 5
с
w > -5
D
w < -5
I need help plz.....
Answer:
(c) y^2/16 -(x -7)^2/9 = 1
Step-by-step explanation:
The center, focus, and vertex are on a vertical line, so the hyperbola opens in the direction of the y-axis. The y-term will have the positive coefficient.
The vertex-center distance in the y-direction is 4, so the denominator of the y-term is 4^2 = 16. The denominator of the x-term is 5^2 -16 = 9, where 5 is the center-focus distance.
The equation is ...
y^2/16 -(x -7)^2/9 = 1
Domain and Range from this functions
F(x)= (1/4x-1)^3 +2
Answer:
Domain:(−∞,2)∪(2,∞),{x|x≠2}
Range:(−∞,0)∪(0,∞),{y|y≠0}
Plsssssssssssssssssss
Answer:
18.6cm
Step-by-step explanation:
there is a theorem that states that the midsegment of a triangle (midpoint to midpoint, in this case X and Y) is half of the base (in this case BC)
when applied to the triangle shown:
XY= 1/2 BC
substitute to get
XY=1/2*6.4
XY=3.2
perimeter of BCYX
=XY+YC+CB+BX
=3.2+4+6.4+5
=18.6cm
hope this helps
Help help help help please business
Answer:
x = 35°
Step-by-step explanation:
These are corresponding angles. When a transversal crosses 2 parallel lines, 4 angles are created at each intersection, and each pair of corresponding angles between those are congruent.
These angles are congruent, so you can set them equal to each other:
[tex]2x+20=3x-15[/tex]
Then, just solve for x:
[tex]20=x-15\\35=x\\x=35[/tex]
You can check that by plugging it back into both:
[tex]2x+20=3x-15\\2(35)+20=3(35)-15\\70+20=105-15\\90=90[/tex]
Answer:
x = 35
Step-by-step explanation:
The angles shown are corresponding angles
Corresponding angles are congruent ( equal to each other )
This means that 2x + 20 should equal 3x - 15
Note that we've just created an equation that we can use to solve for x
We know use that equation to solve for x
2x + 20 = 3x - 15
add 15 to both sides
2x + 35 = 3x
subtract 2x from both sides
35 = x
And we are done!
HELP THIS IS MY 2ND ATTEMPT
Answer:
8 1/10
Step-by-step explanation:
mark brainliest if correct
electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density
can you give explanation too
The charge of the electrons is [tex]8.02 \times 10^{-19} \ C[/tex].
The given parameters:
Number of revolution of the electron, N = 1.4 x 10⁶ rev per secFlux density, B = 10⁻⁵ TMass of electron, m = 9.11 x 10⁻³¹ kgThe angular speed of the electron is calculated as follows;
[tex]\omega = 2\pi N\\\\\omega = 2\pi \ \frac{rad}{1 \ rev} \times 1.4 \times 10^6 \ rev/s\\\\\omega = 8.798 \times 10^6 \ rad/s[/tex]
The charge of the electrons is calculated as follows;
[tex]F_c= m\omega ^2 r\\\\F_{B}= qvB = q\omega r B \\\\F_c = F_B\\\\m\omega ^2 r = q\omega r B \\\\q = \frac{m\omega ^2 r}{\omega r B} \\\\q = \frac{m \omega }{B} \\\\q = \frac{9.11 \times 10^{-31} \times 8.798 \times 10^6}{10^{-5}} \\\\q = 8.02 \times 10^{-19} \ C[/tex]
The charge of the electrons is [tex]8.02 \times 10^{-19} \ C[/tex].
The complete question here:
Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density 10⁻⁵ T. What will be the value of charge of the electron?
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Given a conditional statement p → q, find the inverse of its inverse, the inverse of its converse, and the inverse of its contrapositive.
The inverse of an implication p ⇒ q is ¬p ⇒ ¬q.
The converse of p ⇒ q is q ⇒ p.
The contrapositive of p ⇒ q is ¬q ⇒ ¬p.
Then
• the inverse of the inverse of p ⇒ q is p ⇒ q
• the inverse of the the converse of p ⇒ q is ¬q ⇒ ¬p
• the inverse of the contrapositive of p ⇒ q is q ⇒ p
help I have no clue what I'm doING
Answer:
3.0
4.5
6.0
7.5
Step-by-step explanation:
it rains at the rate of 1.5cm per hour
In two hours, the amount will be; 1.5 × 2
= 3cm
in the three hours, the amount will be 1.5×3
=4.5cm
in four hours, the amount will be; 1.5×4
=6cm
in five hours, the amount will be; 1.5×5
=7.5cm
The number sentence 4 × 6 = 6×4 is an example of what property?
Answer:
communtitve property of multiplication
Susanna walked 2/7 of a mile in two over five of an hour what is a unit rate in miles per hour
Answer:
speed = distance/ time so:
(2/7) / (2/5) = (2/7) x (5/2) = 10/14 = 5/7 mph
5/7 = 0.71 miles per hour if you need decimal formatStep-by-step explanation:
Step-by-step explanation:
2/7 miles in 2/5 hours.
to bring this to x miles / 1 hour, we must find the factor for 2/5 to turn into 1.
2/5 × f = 1
f = 5/2
in order to keep the value of the original ratio, we now need to multiply also 2/7 by the same factor (5/2).
2/7 × 5/2 = 10/14 = 5/7
so, the unit rate is 5/7 miles / hour.
which is very slow walking.
The length of a slide on a swing set is 10 ft. The
distance from the base of the ladder to the base of the slide
is 2 ft more than the height of the ladder. Find the height of
the ladder.
Answer:
6cm
Step-by-step explanation:
let height of ladder be x
so if height of ladder is x then the distance from the base of the ladder to the base of the slide is x+2
Assuming this is a right angle triangle, the slide is the longest lenght (c)
so
x²+(x+2)²=10²
x²+x²+4x+4=100
2x²+4x+4=100
2x²+4x+4-100=0
2x²+4x-96=0
2(x²+2x-48)=0
x²+2x-48=0 -- Factor
(x+8)(x-6)=0
x=-8 and x=6
since height cannot be a negative number
height of ladder is 6 cm
The base length is 8 feet. Then the height of the triangle will be 6 feet.
What is a Pythagoras theorem?The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.
The Pythagoras theorem formula is given as
H² = P² + B²
The length of a slide on a swing set is 10 ft.
The distance from the base of the ladder to the base of the slide is 2 ft more than the height of the ladder.
Let x be the length of the height of the triangle. Then the base of the triangle will be (x + 2).
10² = (x + 2)² + x²
100 = x² + 4x + 4 + x²
96 = 2x² + 4x
48 = x² + 2x
0 = x² + 2x - 48
0 = (x - 6)(x + 8)
x = 6, -8
Then the base length is 6 ft. Then the height of the triangle will be
B = x + 2
B = 6 + 2
B = 8 ft
More about the Pythagoras theorem link is given below.
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write 321.51 as word form
Answer:
three hundred twenty one and fifty one hundredths
List the first 5 multiples and find ALL the factors of 16.
Multiples:
Factors:
Answer:
Multiples: 16, 32, 48, 64, 80 Factors: 1, 2, 4, 8 and 16
Step-by-step explanation:
hope this helped :3
Travel back in time to the year 2008, when text messages were charged per text. Some carriers charged $59 for a basic text package of 200 texts and 20 cents per text after that. Today, most packages include unlimited text and data but cost closer to $100 a month.
Write and solve an equation to determine the range of text messages you can send with the 2008 plan without spending more than $100.
If you have a phone, look at your data summary. Is this range your average daily number, weekly number, or monthly number of texts? Determine how much you would have paid for the month if you had the 2008 text plan? Write this as an equation and solve It.
80 POINTS!!!!
Answer:
You can send 405 texts in 2008 without going over 100$
Step-by-step explanation:
Equation for 2008:
59$ for 200 texts + .20 dollars per text after that < or = $100
So minus $59 dollars
.20 * (number of txts) < 100 - 59
.20 * (number of txts) < 41
divide both sides by .2
number of txts < or = 205
so therefore you can send exactly 405 texts without going over $100
Then to find how much you would pay plug into this equation
If total number of texts is lower than 200 texts, then you would be paying $59, but if it is more then plug into the following equation
(Total number of texts - 200) * .20 + 59 = Total $ spent for a 2008 text plan per month.
The total number of texts that can be sent is 405 texts in 2008 without going over 100$. The amount will be $99.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
The equation for 2008:
59$ for 200 texts + 0.20 dollars per text after that < or = $100 and minus $59 dollars
0.20 x (number of texts) < 100 - 59
0.20 x (number of texts) < 41
Divide both sides by 0.2
number of texts < or = 205
405 texts can be sent without going over $100
If the total number of texts is lower than 200 texts, then you would be paying $59, but if it is more then plug into the following equation
(Total number of texts - 200) x 0.20 + 59 = Total $ spent for a 2008 text plan per month.
( 405 - 200 ) x 0.2 + 59 = $99
Therefore, the total number of texts that can be sent is 405 texts in 2008 without going over 100$. The amount will be $99.
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Answer to the question below please.
Answer:
The choice 3;
[tex]x = 15 \: \: \: \\ y = 17[/tex]
Step-by-step explanation:
[tex]m < 2 = m < 4[/tex]
Opposite;
[tex]7x + 7 = 112 \\ 7x = 112 - 7 \\ 7x = 105 \\ \\ x = \frac{105}{7} \\ \\ x = 15[/tex]
____o__o___
[tex]m < 3 + m < 4 = 180 \\ 4y + 112 = 180 \\ 4y = 180 - 112 \\ 4y = 68 \\ \\ y = \frac{68}{4} \\ \\ y = 17[/tex]
Help help help math math math
Answer:
180 - 17 - 14 =149
180 - 149 = 31*
Step-by-step explanation:
Answer: 180 - 17 - 14 =149180 - 149 = 31*
Step-by-step explanation: it’s right
Kaitlyn drove 360 miles in 9 hours. If she continues driving at the same speed, how far will she have driven in 11 hours?
Answer:
440 miles
Step-by-step explanation:
First, you need to calculate the number of miles per hour. To do this, take the total number of miles traveled and divide it by the number of hours it took. 360/9=40. This means Kaitlyn drove at 40 miles per hour. Then, we need to multiply 40 by 11 to figure out the number of miles she drove in 11 hours because her speed stayed the same. 40*11=440. This means Kaitlyn will have driven 440 miles in 11 hours.
Hope this helps! :)
Raven can walk 2 2/5 miles in 3/5 hour. At this rate, how far can she walk in 1 hour? You might want to change 2 2/5 to an improper fraction in order to make the math easier for you to do.
The distance traveled by Raven in 1 hour at the given rate is 4.0 miles.
The given parameters:
Distance traveled by Raven = 2 2/5 milesTime of motion, t = 3/5 hourThe speed of Raven motion is calculated as follows;
[tex]V = \frac{Distance}{Time} \\\\V = Distance\ \times \ \frac{1}{Time} \\\\V = 2\frac{2}{5} \ miles \ \ \times \ \ \frac{1}{3/5 \ hr} \\\\V = \frac{12}{5} \ miles \ \ \times \ \ \frac{5}{3 hr} \\\\V = 4 \ mph[/tex]
The distance traveled by Raven in 1 hour at the given rate is calculated as follows;
[tex]D = 4 \times 1\\\\D = 4 \ miles[/tex]
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Find the 60" term of the following arithmetic sequence.
6, 13, 20, 27,
..
[tex]\text{First term, a =6}\\\\\text{Common difference, d = 13 -6 = 7}\\\\\text{Nth term} = a+(n-1)d = 6 +(n-1)7 = 6+7n-7 = 7n-1\\\\\text{60th term} = 7(60) -1 = 419[/tex]
Liz has 72 stamps in her stamp collection. Risa, who just started her collection, has 9 stamps. Liz’s collection is how many times larger than Risa’s? Choose the answer that has the correct equation AND the correct solution to the equation.
9x = 72; x = 8 times as many stamps
9 + x = 72; x = 63 times as many stamps
9x = 72; x = 7 times as many stamps
72x = 9; x = 8 times as many stamps
Answer:
9x = 72; x = 8 times as many stamps
Step-by-step explanation:
Answer:
9×=72;×=8 times as many stamps
3a+2x-3y=15
Solve for a.
Then Solve put the value for a =
a+7÷10
subtract 2 from both sides
3a - 3y = 15 - 2x
factor out the common term 3
3 (a-y) = 15 - 2x
divide both sides by 3
a - y = 15 - 2x/3
add y to both sides
a = 15-2x/3 + y
then solve put the value for a =
15-2x/3 + y + 7 ÷10
simplify using the common denominator
10(15-2x)+7*3/30
simplify 7 * 3 to 21
10(15-2x)+21/30
expand
150-20x+21/30
simplify 150-20x+21 to -20x + 171
-20x+171/30
Answer: -20x+171/30
[tex]\huge\bf Question:– [/tex]
[tex]\sf \longmapsto \: 3a+2x−3y=15[/tex]
[tex] \bf \huge \: To \: Find:–[/tex]
[tex] \boxed{\bf \: Value\: of \: A}[/tex]
[tex]\huge\bf Solution:–[/tex]
[tex]\sf \longmapsto \: 3a+2x−3y=15[/tex]
[tex]\boxed{ \bf \: Add -2x \: to \: both \: sides}[/tex]
[tex]\sf \longmapsto \: 3a+2x−3y+−2x=15+−2x[/tex]
[tex]\sf \longmapsto \: 3a−3y=−2x+15[/tex]
[tex]\boxed{ \bf \: Add \: 3y \: to \: both \: sides}[/tex]
[tex]\sf \longmapsto \: 3a−3y+3y=−2x+15+3y[/tex]
[tex]\sf \longmapsto \: 3a=−2x+3y+15[/tex]
[tex] \boxed{\bf \: \: Divide \: both \: sides \: by \: 3}[/tex]
[tex]\sf \longmapsto \: \dfrac{3a}{3} = \dfrac{−2x+3y+15}{3} [/tex]
[tex] \boxed{\bf \: Cross \: Multiply}[/tex]
[tex]\boxed{\sf \longmapsto \: a = \dfrac{ - 2}{3} x + y + 5}[/tex]
______________________________________
[tex]\bf \: Put\:The\: Value[/tex]
[tex] \sf \longmapsto \: \dfrac{−2x+3y+15}{3} +7÷10[/tex]
[tex] \boxed{\bf \: Distribute}[/tex]
[tex]\sf \longmapsto \: \dfrac{ - 2}{3} x+y+5+ \dfrac{7}{10} [/tex]
[tex] \boxed{\bf \: Combine \: Like \: terms}[/tex]
[tex]\sf \longmapsto \: \bigg( \dfrac{ - 2}{3} x\bigg) + y +\bigg( 5 + \dfrac{7}{10} \bigg)[/tex]
[tex]\sf \longmapsto \: \dfrac{ - 2}{3} x + y + \dfrac{57}{10} [/tex]
______________________________________
[tex]\boxed{\bf The Answer\: is:–}[/tex]
[tex]\boxed{{\underline{\bf\dfrac{ - 2}{3} x + y + \dfrac{57}{10}} }}[/tex]