Please help!!! I will mark brainliest

Answer:

84in^2

Step-by-step explanation:

area = l*w

12*7=84

Answer:

[tex] {2x}^{2} + 12x + 8 \\ = {x}^{2} + 6x + 4 \\ = {x}^{2} + 6x + {( \frac{6}{2}) }^{2} + 4 - {( \frac{6}{2} )}^{2} \\ = ( {x}^{2} + 6x + {3}^{2} ) + ( - 5) \\ = {(x + 3)}^{2} - 5[/tex]

Answer:

(1/2)x + $5 (Answer A)

Step-by-step explanation:

Two points on the line representing the cost are (8, $9) and (12, $11).

The change in x is 4 (minutes); this is the 'run.'  The change in y is $2 (this is the 'rise').  Thus, the slope of this line is m = rise / run = $2/(4 min), or 1/2 dollar per min.

Applying the slope-intercept formula y = mx + b, we get:

$9 = (1/2)(8) + b, and from this we see that b must be $5.

Then the correct equation is y = (1/2)x + $5.

Answer:

The temperature was -8.5

Step-by-step explanation:

Subtraction

Answer:

the term arc is used for a portion of a circle along its circumference. The size of the arc is usually given by the size of the angle subtended by the arc at the center or the length of the arc. The angle subtended at the center is also known as the angle measure of an arc or informally the arc measure.

Step-by-step explanation:

Answer:

A) 64°

Step-by-step explanation:

By intersecting secants theorem:

[tex] m\angle ACB = \frac{1}{2} (m\widehat {AS} - m\widehat {BD}) [/tex]

[tex] 35\degree = \frac{1}{2} (134\degree - m\widehat {BD}) [/tex]

[tex] 70\degree =134\degree - m\widehat {BD} [/tex]

[tex] m\widehat {BD} =134\degree - 70\degree[/tex]

[tex] m\widehat {BD} =64\degree[/tex]

Answer: 39.79

Step-by-step explanation:

126/360 (2pi14)

Each of the cuboidal blocks B and D has a volume of 24 cubic units. As a result, choice D is the right response.

What is the formula to find the volume of a cuboidal block?

The formula to find the volume of a cuboidal block is l×b×h.

The dimensions of cuboidal block A are length=6 units, breadth=2 units and height=1 units

Now, the volume of a cuboidal block A=6×2×1=12 cubic units.

The dimensions of cuboidal block B are length=4 units, breadth=2 units and height=3 units

Now, the volume of a cuboidal block B=4×2×3=24 cubic units.

The dimensions of cuboidal block C are length=5 units, breadth=3 units and height=3 units

Now, the volume of a cuboidal block C=5×3×3=45 cubic units.

The dimensions of cuboidal block D are length=6 units, breadth=2 units and height=2 units

Now, the volume of a cuboidal block D=6×2×2=24 cubic units.

The volume of cuboidal blocks B and D is 24 cubic units each. Therefore, option D is the correct answer.

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Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

[tex]V = \pi r^{2}h[/tex]               *Plug in numbers*

[tex](3.14)(2.5)^{2}(7)[/tex]         *Square 2.5*

[tex](3.14)(6.25)(7)[/tex]        *Solve*

≈ [tex]137.375in^{3}[/tex]

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(2.5)^{3}[/tex]         *Cube 2.5*

[tex]\frac{\frac{4}{3}(3.14)(15.625)}{2}[/tex]         *Divide by 2 and Solve*

≈ [tex]32.7083 in^{3}[/tex]

Add both volumes

[tex]137.375 + 32.7083[/tex] ≈ [tex]170.083in^{3}[/tex]

2.

Cylinder:

[tex]V = \pi r^{2}h[/tex]         *Plug in numbers*

[tex]\pi (3)^{2}(10)[/tex]            *Square 3*

[tex]\pi (9)(10)[/tex]             *Multiply*

[tex]90\pi[/tex]

Sphere:

[tex]V = \frac{4}{3}[/tex] π [tex]r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (3)^{3}[/tex]                   *Cube 3*

[tex]\frac{4}{3} \pi (27)[/tex]                   *Multiply*

[tex]36\pi[/tex]

Add both Volumes to get total

[tex]90\pi + 36\pi = 126in^{3}[/tex]

3.

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(3)^{3}[/tex]            *Cube 3*

[tex]\frac{4}{3} (3.14)(27)[/tex]            *Multiply*

[tex]113.04m^{3}[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]             *Plug in numbers*

[tex]\frac{(3.14)(2)^{2}(5)}{3}[/tex]           *Square 2*

[tex]\frac{(3.14)(4)(5)}{3}[/tex]             *Solve*

[tex]20.93m^{3}[/tex]

Subtract the volumes to get the volume of the blue area

[tex]113.04 - 20.93 = 92.106m^{3}[/tex]

4.

Sphere:

[tex]V = \frac{4}{3} \pi r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (8)^{3}[/tex]                 *Cube 8*

[tex]\\\frac{4}{3}\pi (512)[/tex]               *Multiply*

[tex]\\\\\pi (682.6)[/tex]              *Solve*

[tex]2133.66in^{3}[/tex]           *Divide by 2 since it's a hemisphere*

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (8)^{2}(20)}{3}[/tex]              *Square 8*

[tex]\frac{\pi (64)(20)}{3}[/tex]              *Multiply and Divide*

[tex]1340.41 in^{3}[/tex]

Add both volumes

[tex]1072.33 + 1340.41 = 2412.74in^{3}[/tex]

5.

Cylinder:

[tex]V = \pi r^{2}h[/tex]            *Plug in numbers*

[tex]\pi (6)^{2}(16)[/tex]              *Square 6*

[tex]\pi (36)(16)[/tex]             *Multiply*

[tex]576\pi[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (6)^{2}3}{3}[/tex]                  *Square 6*

[tex]36\pi[/tex]

Add both volumes

[tex]576\pi + 36\pi = 612\pi m^{3}[/tex]

Alternative: *Multiply π*

[tex]1922m^{3}[/tex]

Answer:

1) 175 [tex]in^2[/tex]

2) 1st option

3) 92 [tex]m^2[/tex]

4) 2412 [tex]in^3\\[/tex]

5) 2nd option

Step-by-step explanation:

[tex]1)\ A = D * Pi = 5 * 3.14 = 15.7\\[/tex]

[tex]2)\ V_{1} = 15.7 * 7 = 109.9[/tex]

[tex]3)\ V_{2} = 4Pi*\frac{R^3}{3} = 12.56*\frac{15.625}{3} = 65.41(6)[/tex]

[tex]4)\ V_1 + V_2 = 65.4 + 109.9 = 175.3[/tex] which is close to 175

[tex]1)\ A = Pi * R^2 = 3.14 * (\frac{6}{2})^2 = 3.14 * 3^2 = 28.26\\[/tex]

[tex]2)\ V_1 = A * h = 28.26 * 10 = 282.6[/tex]

[tex]3)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * (\frac{6}{2})^3 = 113.04[/tex]

[tex]4)\ V_1 + V_2 = 282.6 + 113 = 395.6[/tex] which is very close to 396

[tex]5)\ 396 = 126 * pi[/tex]

[tex]1) V_1 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 2^2 * 5 = 20.9(3)[/tex] =

[tex]2)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * 3^3 = 113.04\\[/tex]

[tex]3)\ V_2 - V_1 = 113.04 - 20.93 = 92.14[/tex] which is very close to 92

[tex]1)\ V_1 = \frac{\frac{4}{3} * Pi * R^3}{2} = \frac{\frac{4}{3} * 3.14 * 512}{2} = 1,071.786\\[/tex]

[tex]2)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 64 * 20 = 1,339.733[/tex]

[tex]3)\ V_1 + V_2 = 1072 + 1340 = 2,411 = 2412[/tex]

[tex]1)\ A = Pi * R^2 = 36*Pi\\[/tex]

[tex]2)\ V_1 = 36*Pi * 16 = 576 * Pi\\[/tex]

[tex]3)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * Pi * 36 * 3 = 36 * Pi[/tex]

[tex]4) V_1 + V_2 = 576Pi + 36Pi = 612Pi[/tex]

Answer:

0.13 cm ( as question was posted)

13 cm ( if width was in centimeters)

Step-by-step explanation:

a = lw

4.5m = 450cm

Plug in the knowns

58.5 = l(450)

Divide both sides by 450

0.13 = l

length is 0.13 cm

----------------------------

I did the qustion as you posted it.

If you intended 4.5 centimeters instead of 4.5 meters then

58.5 = l(4.5)

divide both sides by 4.5

l = 13 cm

Answer:

9miles

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

x = 292.2 pounds (£)

Step-by-step explanation:

Write and solve an equation of ratios:

 € 1        £0.72

--------- = ----------

€410         x

Cross-multiplying, we get:

x = 292.2 pounds (£)

Answer:

B

Step-by-step explanation:

The circumference of a circle can be described as the linear distance round the circle

The circumference of a circle = 2πr or πD

π = 3.14

r = radius

d = diameter

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

π  = circumference / 2r or circumference / D

37.68 / 12

Answer:

8x+14

Step-by-step explanation:

x=16

Step-by-step explanation:

A straight angle is 180°

you get 180°- 62°=a

then You add up a and 46=b

lastly we know that a triangle's angle is 180° so we get 180°- b

tYou should try it yourself

Answer:

-7k + 14

Step-by-step explanation:

(k² - 7k + 2) - (k² - 12)

k² - 7k + 2 - k² + 12

k² - k² - 7k + 2 + 12

-7k + 14

Answer:

The range is 24

The Q1 is 53

The Q3 is 69

The IQR is 16

Step-by-step explanation:

Answer:

can you put that in a paragraph

Step-by-step explanation:

Answer:

Step-by-step explanation:

Remark

You are trying to find one of the legs of a right triangle. All you need is the Pythagorean Theorem.

Formula

x^2 + y^2 = c^2

Givens

x = ?

y = 0.9

c = 1.5

Solution

x^2 + 0.9^2 = 1.5^2

x^2 + 0.81 = 2.25         Subtract 0.81 from both sides

x^2 = 2.25 - 0.81

x^2 = 1.44                     Take the square root of both sides

sqrt(x^2) = sqrt(1.44)

x = 1.2  

Answer:

Mean: 8 and MAD: 1.2

Step-by-step explanation:

Given a data with :

Mean = 20 ; mean absolute deviation (MAD) = 3.1

DATA with a low mean and variability Than The above from the options given :

The most appropriate option is : Mean: 8 and MAD: 1.2 ; because both values of the mean and mean absolute deviation are lesser than the value given.

Answer:

5^5+4/5^6

5^9/5^6

5^9-6

5^3

125

Step-by-step explanation:

Firstly the powers of 4 adds up

Then net power is formed by (9-6) ie 3

Lastly 5^3 is result which is 125

Answer:

I'm already past this but the answer is 21

Answer: 38.5%

Step-by-step explanation:

it decreased by 38.5%

formula for it is (value 2 - value 1)/value 1 * 100 = so (800-1300)/1300*100 = -500/1300*100 = -0.384615 * 100 = -38.4615 = -38.5 (round off) = 38.5 decrease

71

Step-by-step explanation:

that it is not 0 because i am a teacher mrs.brainly so there is the thing

Answer:

just add all the numbers

Step-by-step explanation:

please follow me,

follow you back...

Answer:

The answers is 17.2 miles

Step-by-step explanation:

Answer:

120

Step-by-step explanation: