Physics College

PLEASE HELP I need help bad
66. Which of the following results of correlational
studies implies that environment contributes to
the determination of IQ?
(A) Correlations are higher for identical twins
than for fraternal twins.
(B) Correlations are higher for children and their
biological parents than for children and their
adoptive parents.
(C) Correlations are higher for parents and their
children than for husbands and wives.
(D) Correlations for two children in the same
family are lower when one of the children is
adopted than when both are the biological
offspring of the parents.
(E) Correlations for children and their adoptive
parents are statistically significant and
positive.

Answers

Answer 1

i think the answer is B.

i believe this because the child’s brain development is proven to have changed based off separation from their biological parents, presenting a change in their environment

i hope this helps ! ♡

Answer 2

Correlational study involves a non-experimental study of the relationship between two variables using statistical study in the evaluation of our result.

The association between environment and IQ in the options given is best identified by the statistical significance shown in the association between children and their adoptive parent.

Correlational study involves the establishment of statistical pattern or trend using methods such as Analysis of variance. Statistical evaluation is key in establishing the outcome of a correlational study or evaluation. Since the method by which the correlation between the variables in the other options aren't stated, the best option is E.

Therefore, correlation between adoptive parent and children showing positive statistical significance implies a correlational study.

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Related Questions

A car comes to a stop six seconds after the driver applies the brakes. While the brakes are on, the following velocities are recorded:
Time since brakes applied (sec) 0 2 4 6
Velocity (ft/s) 87 44 16 0
Give lower and upper estimates (using all of the available data) for the distance the car traveled after the brakes were applied.

Answers

Answer:

Explanation:

deceleration during first 2 s = (87 - 44) / 2 =21.5 m /s²

deceleration during next 2 s = (44 - 16) / 2 =14 m /s²

deceleration during last  2 s = (16 - 0) / 2 = 8  m /s²

If we assume the acceleration to be uniform during 3 readings

distance travelled during first 2 s

v² - u² = 2 a s

87² - 44² = 2 x 21.5 x s

s = 7569 - 1936 / 43

= 176 m

distance travelled during next 2 s

44² - 16² = 2 x 14 x s

s =  1936 - 256  / 28

= 60 m

distance travelled during last 2 s

16² - 0² = 2 x 8 x s

s =   256  / 16

= 16 m

Total distance travelled = 176 + 60 + 16 = 252 m

If we assume the acceleration as non- uniform , we first calculate average acceleration as follows .

average acceleration = (87 - 0)/ 6 = 14.5 m /s²

v² - u² = 2 a s

87² - 0² = 2 x 14.5 x s

s = 7569  / 29

= 261  m

Hence lower estimate of distance travelled = 252 m ; upper estimate of distance travelled = 261 m .

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