Please help I don't understand this

49627/28000 or you can use the decimal 1.77

Step-by-step explanation:

28x=49.627

divide both sides by 28

bro what angle I don't see one here so how we are able to solve this problem

1)f(×)=3*=f(×)=×-1 0 1=0.23

Answer: -c= 157+X^2

Step-by-step explanation:

Answer:i would say C ADHAKFFA

Step-by-step explanation:

Answer:

m = 0

Step-by-step explanation:

Hope this helps:)

Answer:

Static Public Member Functions ... Get FWORD from string (Big Endian 16-bit signed integer). ... (62x88 mm ; 2.44x3.46 in); B9 (44x62 mm ; 1.73x2.44 in); B10 (31x44 mm ; 1.22x1.73 in) ...

Answer:

V = (4.2)(7.5)·w

if w = 2 then V = 63 ft³

Step-by-step explanation:

V = l·w·h

V = (4.2)(7.5)(2)

V = 63

Answer:

a) 8,000!/(8000 - 4)! ways

b) 15,000,000 + 7998!/(7998 - 2)! ways

c) 5,000 + 7,999!/(7,999- 3)! ways

d) 3,000 + 7,999!/(7,999- 3)! ways

Step-by-step explanation:

The number of students at Rackham Graduate School = 8,000 students

The number of PhD students = 5,000

The number of masters students = 3,000

The number of student members of the Rackham Student Government Executive Board = 4 students

a) The number of ways there are to choose the Exec Board from all Rackham students = The number of ways to choose 4 students from 8,000 = 8,000!/(8000 - 4)!

b) The number of ways of having one Master student in the board = 3,000 ways

The number of ways of having one PhD student in the board after selecting a masters student = 5,000 ways

The number of ways of selecting the remaining 2 members =

7998!/(7998 - 2)!

The total number of ways of selecting at least one masters and one PhD in the board is therefore equal to 5,000 × 3,000 + 7998!/(7998 - 2)! ways

c) The number of ways of choosing the VP position as PhD = 5,000 ways

The number of ways of choosing the other three members = 7,999!/(8000 - 3)!

Therefore, the total number of ways = 5,000 + 7,999!/(7,999- 3)! ways

d) The number of ways of choosing a masters student as the VP position = 3,000 ways

The number of ways of choosing the other three members = 7,999!/(8000 - 3)!

Therefore, the total number of ways = 3,000 + 7,999!/(7,999- 3)! ways

Answer:

4/12+3/12=7/12

Step-by-step explanation:

just took the quiz

Answer:

1) You can rely solely on your brakes because when doing so the car will just travel 250ft from the point you hit your brakes till the point the car stopped completely, leaving you 50ft away from the cow.

2) See attached picture.

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in [tex]ft/s^{2}[/tex]

3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) [tex]j(t)=\left \{ {{95t-9t^{2}; 0\le t<5.28s} \atop {250.69; 5.28s\leq t \leq 10s}} \right.[/tex]

[tex]j'(t)=\left \{ {{95-18t; 0\leq t<5.28s} \atop {0 ; 5.28s\leq t \leq 10s}} \right.[/tex]

(see attached picture for graph)

Step-by-step explanation:

1) In this part of the problem we need to find the time when the speed of the car is 0. Gets to a complete stop. For this we will need to take the derivative of the position function so we get:

[tex]j(t)=95t-9t^2[/tex]

[tex]j'(t)=95-18t[/tex]

and we set the first derivative equal to zero so we get:

95-18t=0

and solve for t

-18t=-95

[tex]t=\frac{95}{18}[/tex]

t=5.28s

so now we calculate the position of the car after 5.28 seconds, so we get:

[tex]j(5.28)=95(5.28)-9(5.28)^{2}[/tex]

[tex]j(5.28)=250.69ft[/tex]

so we have that the car will stop 250.69ft after he hit the brakes, so there will be about 50ft between the car and the cow when the car stops completely, so he can rely just on the breaks.

2) For answer 2 I take the second derivative of the function so I get:

[tex]j(t)=95t-9t^{2}[/tex]

[tex]j'(t)=95-18t[/tex]

j"(t)=-18

and then we graph them. (See attached picture)

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in [tex]ft/s^{2}[/tex]

3)  yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) [tex]j(t)=\left \{ {{95t-9t^{2}; 0\le t<5.28s} \atop {250.69; 5.28s\leq t \leq 10s}} \right.[/tex]

[tex]j'(t)=\left \{ {{95-18t; 0\leq t<5.28s} \atop {0 ; 5.28s\leq t \leq 10s}} \right.[/tex]

(see attached picture for graph)

Answer:

there in not enough information in your question to get an answer

Answer:

Part 1: Jeff Part 2: 130

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

2 x (25 + 10) = 2 x 35 = 70

Answer:

B) 2

Step-by-step explanation:

6/3 = 2

3/3 = 1

6÷3 = 2

Hopefully this helps :3 Sorry if wrong :( Plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3

-Bee~

Answer:

It's B

Step-by-step explanation:

Answer:

B is a functional answer

Answer:

-8k + 24

Step-by-step explanation:

Is your expression.

Answer:

B

Step-by-step explanation:

If you plug in the answers for guess and repeat this one works.

The correct statement is Sarah must sell between 40 and 50 springtime bouquets true if Sarah needs to make a profit of at least $9,000.

Given that,

Sarah owns a flower shop and can model the profits from selling springtime bouquets using this equation,

Where b is the number of springtime bouquets, [tex]P = -5b^2 + 450b - 1,000[/tex].

We have to determine,

Which statement is true if Sarah needs to make a profit of at least $9,000.

According to the question,

Sarah owns a flower shop and can model the profits from selling springtime bouquets using this equation,

[tex]P = -5b^2 + 450b - 1,000[/tex]

Divide the equation by -5,

[tex]P = -5b^2 + 450b - 1,000\\\\P = -b^2 + 90b - 200[/tex]

Factorize the equation for the value of profit,

[tex]b^2 - 90b +200 = 0\\\\b^2 -50b -40b +200= 0\\\\b ( b-50) - 40(b-50) = 0 \\\\(b-50) (b-40) = 0 \\\\b- 50 = 0, \ b = 50\\\\b - 40 = 0, \ b = 40[/tex]

Hence, Sarah must sell between 40 and 50 springtime bouquets.

To know more about Quadratic equations click the link given below.

https://brainly.com/question/22364785

Answer:

C. -2

Step-by-step explanation:

All parallel lines have the same slope

Answer:

Step-by-step explanation:

Answer:

5.573.75

Step-by-step explanation:

because math

Answer:

15x = 60

Step-by-step explanation:

Hi,

We know he bought 15 shirts for an x amount of dollars, so 15 times however much they cost is 15x and the total is 60.

hope this helps :)

Answer:

60

Step-by-step explanation:

Please refer to the attachment

9514 1404 393

Answer:

  x = 62

Step-by-step explanation:

The angle marked x° is shown as the complement of the angle marked 28°. This means ...

  x = 90 -28 = 62

Answer:

B is correct hope this helps

Answer:

?

Step-by-step explanation:

Answer: lesser x = 1/5 greater x = 4

Step-by-step explanation:

Answer:

A) The multiplier for this situation is 0.02.

B) The cost in 4 years will be $ 33,555.39.

C) 31,000 x 1.02 ^ N = X

Step-by-step explanation:

Since in 2012 the average cost for a new midsized car was about $ 31,000, and new car prices tend to go up about 2% every year, to determine what is the multiplier for this situation, what will the cost be in 4 years if this trend continues and to write an equation to calculate the cost in n years the following calculations must be performed:

A)

31,000 x 2/100 = X

31,000 x 0.02 = X

Thus, the multiplier for this situation is 0.02.

B)

31,000 x 1.02 ^ 4 = X

33,555.39 = X

Thus, the cost in 4 years will be $ 33,555.39.

C)

31,000 x 1.02 ^ N = X

Here, N represents the number of years over which the price increase will be calculated, and X represents the price after that number of years.