Please help guys thank u

Answer:

Mean = 3x

Step-by-step explanation:

Mean = [tex]\frac{SumOfObservations}{No. OfObservations}[/tex]

Mean = [tex]\frac{x+2x+3x+4x+5x}{5}[/tex]

Mean = [tex]\frac{15x}{5}[/tex]

Mean = 3x

The mean, also known as the average of x, 2x, 3x, 4x, and 5x is 3x as per the concept of Simplifying.

To find the mean of x, 2x, 3x, 4x, and 5x, we need to add up all the values and divide by the total number of values.

In this case, we have five values.

Mean = (x + 2x + 3x + 4x + 5x) / 5

Simplifying the numerator:

Mean = (15x) / 5

Mean = 3x

Therefore, the mean of x, 2x, 3x, 4x, and 5x is 3x.

The mean, also known as the average, represents the central tendency of a set of values. In this case, the mean is 3x, which indicates that on average, the values x, 2x, 3x, 4x, and 5x are three times the value of x.

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Answer:

x = 20

Step-by-step explanation:

The three angles form a straight line so they add to 180 degrees

x+ 100 +3x = 180

Combine like terms

100+4x= 180

Subtract 100 from each side

100+4x-100= 180-100

4x= 80

Divide each side by 4

4x/4 = 80/4

x = 20

Answer:

[tex]x = 20 \: \: degrees[/tex]

Step-by-step explanation:

Angles in a straight line = 180 degrees

[tex]x + 3x + 100 = 180 \\ 4x + 100 = 180 \\ 4x = 180 - 100 \\ 4x = 80 \\ \frac{4x}{4} = \frac{80}{4} \\ x = 20 \: \: degrees[/tex]

hope this helps

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Answer:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1} =\frac{0-800}{400-0}= -2[/tex]

And then we can find the y intercept using one point for example (0,800) and we have:

[tex] 800= -2*0+ b[/tex]

[tex] b= 800[/tex]

And our model would be:

[tex] y = -2x +800[/tex]

And the x intercept would be if y=0 then

[tex] 0 =-2x +800[/tex]

[tex] x =400[/tex]

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

We have the following points given:

(0, 800) and (400, 0)

If we want to find the x intercept and y intercept we need to remember that we need to set a linear model given by:

[tex] y=mx +b[/tex]

Where

[tex] m=\frac{y_2 -y_1}{x_2 -x_1} =\frac{0-800}{400-0}= -2[/tex]

And then we can find the y intercept using one point for example (0,800) and we have:

[tex] 800= -2*0+ b[/tex]

[tex] b= 800[/tex]

And our model would be:

[tex] y = -2x +800[/tex]

And the x intercept would be if y=0 then

[tex] 0 =-2x +800[/tex]

[tex] x =400[/tex]

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Answer:

And then we can find the y intercept using one point for example (0,800) and we have:

And our model would be:

And the x intercept would be if y=0 then

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

We have the following points given:

(0, 800) and (400, 0)

If we want to find the x intercept and y intercept we need to remember that we need to set a linear model given by:

Where

And then we can find the y intercept using one point for example (0,800) and we have:

And our model would be:

And the x intercept would be if y=0 then

x intercept =400 represent the value of x when y =0

y intercept = 800 represent the value of y when x =0

Step-by-step explanation:

Answer:

The question is not clear.

Step-by-step explanation:

Normally it helps to rewrite 8 as

8 = 2 * 2 * 2 = 2³

However the question is not clear.

There are no following expressions given...

By 2X^2 +8,

do you mean 2*x² + 8, or do you mean 2*x^(2 + 8)

or did you perhaps mean 2^(x+8)

Next time, please add a picture.

Answer:

(2x-4i)(x+2i)

Answer:

A) 1500 girls

B) 25% are men

Step-by-step explanation:

I hope this helps

Answer:

7. [tex]x \leq 5[/tex]

8. [tex]x\geq 4[/tex]

9. x < 5

10. x < -7

11.  x < 45

12. [tex]x\geq -10[/tex]

13. x < -7

14. x < 45

15. [tex]x\leq 50[/tex]

16. [tex]w\geq 16[/tex]

18. q > 4

Step-by-step explanation:

Answer:

The probability that at least one of the children get the disease from their mother is 0.7125.

Step-by-step explanation:

We are given that a human gene carries a certain disease from the mother to the child with a probability rate of 34%.

Suppose a female carrier of the gene has three children. Assume that the infections of the three children are independent of one another.

Let Probability that children get the disease from their mother = P(A) = 0.34

SO, Complement of the event "At least one of the children get the disease from their mother"= P(A') = 1 - P(A)

where A' = event that children do not get the disease from mother.

So, P(A') = 1 - P(A) = 1 - 0.34 = 0.66

Now, probability that at least one of the children get the disease from their mother = 1 - Probability that none of the three children get disease from their mother

                     = 1 - P(X = 0)

                     = 1 - (0.66 [tex]\times[/tex] 0.66 [tex]\times[/tex] 0.66)

                     = 1 - 0.2875 = 0.7125

[tex]the \: answer \: is \: 7 \: square \: units \\ please \: see \: the \: attached \: picture \: for \: full \: solution \\ hope \: it \: helps[/tex]

Answer:

w || n and n ⊥ m

Step-by-step explanation:

To find out which statement is true, recall the following:

1. 2 lines are said to be parallel to each other if they do not intersect at any given point and are of the same distant apart. Parallel is denoted by ||

2. 2 lines are said to be perpendicular if both lines intersect at a right angle. It is denoted by ⊥

==>From the diagram given, we can see that w and n are of the same distant apart and they do not intersect at any given point.

Also, we can see that n and m intersect at point X to at right angle.

Therefore, we can conclude that w || n and n ⊥ m

Answer:

Step-by-step explanation:

If half of the wine barrels are infected, it means that the proportion of infected wine is 0.5

We would set up the hypothesis test.

For the null hypothesis,

p = 0.5

For the alternative hypothesis,

p < 0.5

Considering the population proportion, probability of success, p = 0.5

q = probability of failure = 1 - p

q = 1 - 0.5 = 0.5

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 28

n = number of samples = 80

P = 28/80 = 0.35

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.35 - 0.5)/√(0.5 × 0.5)/80 = - 2.68

From the normal distribution table, the area below the test z score in the left tail 0.0037

Therefore,

p value = 0.0037

Assuming a significance level of 0.05, therefore,

Since alpha, 0.05 > than the p value, 0.0037, then we would reject the null hypothesis.

Answer:

Step-by-step explanation:

1) Vertical stretch is accomplished by multiplying the function value by the stretch factor. When |x| is stretched by a factor of 2, the stretched function is ...

  g(x) = 2|x|

__

2) Reflection over the x-axis means each y-value is replaced by its opposite. This is accomplished by multiplying the function value by -1.

  g(x) = -2|x|

__

3) As you know from when you plot a point on a graph, shifting it down 3 units subtracts 3 from the y-value.

  g(x) = -2|x| -3

__

4) A right-shift by k units means the argument of the function is replaced by x-k. We want a right shift of 1 unit, so ...

  g(x) = -2|x -1| -3

Answer:

11.42 boxes

Step-by-step explanation:

For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.

After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:

[tex]E_2 = (\frac{4}{5})^{-1} = 1.25[/tex]

For the next unique toy, there is now a 3 in 5 chance of getting it:

[tex]E_3 = (\frac{3}{5})^{-1} = 1.67[/tex]

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

[tex]E_4 = (\frac{2}{5})^{-1} = 2.5[/tex]

Finally, there is a 1 in 5 chance to get the last unique toy:

[tex]E_5 = (\frac{1}{5})^{-1} = 5[/tex]

The expected number of boxes to obtain a full set is:

[tex]E=E_1+E_2+E_3+E_4+E_5\\E=1+1.25+1.67+2.5+5\\E=11.42\ boxes[/tex]

Answer:

[tex]t=\frac{4.5-4}{\frac{2.680}{\sqrt{10}}}=0.59[/tex]  

The degrees of freedom are given by:

[tex] df =n-1= 12-1=11[/tex]

And the p value would be:

[tex]p_v =2*P(t_{11}>0.59)=0.567[/tex]  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean area is not significantly different from 4

Step-by-step explanation:

We have the following data given:

4, 4, 3, 2, 6, 8, 7, 1,9, 3, 1, and 6

The sample mean and deviation from these data are:

[tex]\bar X=4.5[/tex] represent the sample mean  

[tex]s=2.680[/tex] represent the sample deviation

[tex]n=10[/tex] sample size  

[tex]\mu_o =4[/tex] represent the value to verify

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic

[tex]p_v[/tex] represent the p value

Hypothesis to verify

We want to verify if the true mean is equal to 4, the system of hypothesis would be:  

Null hypothesis:[tex]\mu =4[/tex]  

Alternative hypothesis:[tex]\mu \neq 4[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

Replacing the the info we got:

[tex]t=\frac{4.5-4}{\frac{2.680}{\sqrt{10}}}=0.59[/tex]  

The degrees of freedom are given by:

[tex] df =n-1= 12-1=11[/tex]

And the p value would be:

[tex]p_v =2*P(t_{11}>0.59)=0.567[/tex]  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean area is not significantly different from 4

Refer to the provided image.

A triangle with one of its angles to be 90°. That is if a triangle has one right angle then the triangle is a right-angled triangle.

A right-angled triangle's hypotenuse is the longest side. It's the side that's on the opposite side of the right angle.

A leg of a right-angled triangle is the side that is adjacent to the right angle.

The height of the right-angled triangle when the hypotenuse is considered as the base is called the Altitude of the right-angled triangle.

Considering the definitions above label the figure accordingly.

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Answer:

A = 1168.67 cm²

Step-by-step explanation:

[tex]A=2\pi rh+2\pi r^{2}[/tex]           Use this equation to find the surface area

[tex]A=2\pi (6)(25)+2\pi (6)^{2}[/tex]  Multiply    

[tex]A=2\pi (150)+2\pi (36)[/tex]     Multiply

A = 942.48 + 226.19     Add

A = 1168.67 cm²

Answer:

1169.14cm2

Step-by-step explanation:

The surface area is that area which you can feel. Now there are two circles one at the top and one at the bottom.

These areas are expressed as;

π×r2 { remember area of a circle}.

Therefore for the two areas we have twice the area of once since they are the same. Hence we have:

2×π×r2.

Secondly, there is still another area we haven't talked about yet. It's the area you feel at the side and this area curls into a circular fashion.

Now let's assume the two circles are the top and bottom are knocked off , we would have a shape that looks like a rectangle.

Now area of a rectangle is the multiplication of both sides. In this case the side would be the height,h and the circumference of the circle since the rectangle forms into a circle when she try to join both edges together.

Hence the area of this Shape would be;

2πr{circumference} × h=2πrh

Hence the total surface area would be;

2πr2 + 2πrh.

Substituting the giving values we have;

Note: to obtain raduis,r ; we divide the diameter by 2.

2 × 22/7 × 6^2 + 2 × 22/7 × 6× 25

2×22/7(36+150)

44/7(186)= 8184/7

=1169.1429cm2

=1169.14cm2{ to 2 decimal place}

Options:

(A)x = StartFraction 6 over 4 EndFraction

(B)x = Negative StartFraction 6 over 4 EndFraction

(C)x minus one-fourth = negative StartFraction 5 over 4 EndFraction

(D)x = negative three-halves

(E)x = negative three-fourths

Answer:

(B)x = Negative StartFraction 6 over 4 EndFraction

[tex]-\dfrac{6}{4}[/tex]

(D)x = negative three-halves

[tex]-\dfrac{3}{2}[/tex]

Step-by-step explanation:

We want to determine which fraction is equivalent to

[tex]\dfrac{1}{4}+x=-\dfrac{5}{4}\\$First, we collect like terms$\\x=-\dfrac{5}{4}-\dfrac{1}{4} \\\\=\dfrac{-5-1}{4}\\=-\dfrac{6}{4}\\x=-\dfrac{6}{4}[/tex]

This value of x is the result in Option B.

Reducing [tex]-\dfrac{6}{4}[/tex] to its lowest form:

[tex]-\dfrac{6}{4}=-\dfrac{3}{2}[/tex] which is Option D.

Therefore, the correct options are: B and D

Answer:

252

Step-by-step explanation:

The order of the books isn't important, so we'll use combinations.

The number of ways to choose 5 books from 10 is:

₁₀C₅ = 10! / (5! (10 − 5)!)

₁₀C₅ = 10! / (5! 5!)

₁₀C₅ = 10×9×8×7×6 / (5×4×3×2×1)

₁₀C₅ = 252

Answer:

Maximum speed of bird A is [tex]192\,\,\frac{mi}{h}[/tex]

Maximum speed of bird B is [tex]32\,\,\frac{mi}{h}[/tex]

Step-by-step explanation:

This is a problem with two unknowns: Max speed of bird A (we name that "A"), and max speed of bird B (we call that "B"). Now we can create two equations with these two unknowns, based on the info provided:

Equation 1): based on the phrase "bird A can travel six times as fast as bird B" we write:

[tex]A=6\,*\, B\\A=6B[/tex]

Equation 2): based on the phrase; "the total speeds for these two birds is 224 miles per hour​", we write:

[tex]A+B=224\,\,\frac{mi}{h}[/tex]

Now, we use the first equation to substitute A in the second equation, ad then solve for the unknown B:

[tex]A+B=224\,\,\frac{mi}{h}\\(6B)+B=224\,\,\frac{mi}{h}\\7B=224\,\,\frac{mi}{h}\\B=\frac{224}{7} \,\,\frac{mi}{h}\\B=32\,\,\frac{mi}{h}[/tex]

Now we can solve for the other unknown "A" using the substitution equation and the value of B we just found:

[tex]A=6B\\A=6\,(32\,\,\frac{mi}{h})\\A=192\,\,\frac{mi}{h}[/tex]

Answer:

B and A

Step-by-step explanation:

So based on the facts given, we know that b and a both have the same abasolute value. It does not matter whether a or b is negative or positive.

Answer:

[tex]508.68[/tex] [tex]in^{2}[/tex]

Step-by-step explanation:

[tex]\pi r^{2} (1/2)[/tex]

[tex](3.14)(18^{2})(1/2)[/tex]

[tex]12717/25 = 508.68[/tex]

Answer:one lakh....

Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thnk me...

Answer:

1 Lakh = 100 Thousands

Step-by-step explanation:

Answer:

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 9 - 1 = 8

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.8595

The margin of error is:

M = T*s = 1.8595*2.7 = 5

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams

The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.

The 90​% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.

Answer:

The probability that the next customer will request mid-grade gas and fill the tank is 0.1800

Step-by-step explanation:

In order to calculate the probability that the next customer will request mid-grade gas and fill the tank we would have to make the following calculation:

probability that the next customer will request mid-grade gas and fill the tank= percentage of the people using mid-grade gas* percentage of the people using mid-grade gas that fill their tanks

probability that the next customer will request mid-grade gas and fill the tank=  30%*60%

probability that the next customer will request mid-grade gas and fill the tank= 0.1800

The probability that the next customer will request mid-grade gas and fill the tank is 0.1800

Answer:

62/7

Step-by-step explanation:

The budget illustrates ratios and proportions.

The maximum amount to spend on food each day is $8

The given parameters are:

[tex]\mathbf{Budget = \$62}[/tex]

[tex]\mathbf{Days = 7}[/tex]

So, the daily budget is:

[tex]\mathbf{Daily = \frac{Budget}{Days}}[/tex]

So, we have:

[tex]\mathbf{Daily = \frac{\$62}{7}}[/tex]

[tex]\mathbf{Daily = \$8.85714285714}[/tex]

Remove decimal parts (do not approximate)

[tex]\mathbf{Daily = \$8}[/tex]

Hence, the maximum to spend each day is $8

Read more about ratios and proportions at:

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Answer:

Hello!

Step-by-step explanation:

To find the area of a triangle, multiply the base by the height, and then divide by 2. The division by 2 comes from the fact that a parallelogram can be divided into 2 triangles. For example, in the diagram to the left, the area of each triangle is equal to one-half the area of the parallelogram.

So,you have to multiply.

Hope this helps.

Answer:

option 2

Step-by-step explanation:

4^2=16/8=2.  4^2=16/16=1.  2-1=1

Solution,

Radius=2 m

Area =pi r^2

= 3.142*(2)^2

=12.568 m^2

hope it helps

Good luck on your assignment

Answer:

Option (2). None

Step-by-step explanation:

A quadrilateral ABCD has been given with a property,

m∠7 = m∠4

Option (1). AB║ DC

For AB║DC, angle 7 and angle 3 should measure the same.

(By the property of alternate angles)

Therefore, by the given property we can not deduce AB║DC.

Option (3). AD║BC

For AD║BC, angle 7 and angle 3 must be equal in measure.

(By the property of alternate angles)

Therefore, by the given property we can not deduce AD║DC

Option (2). None will be the answer.

Answer:

Step-by-step explanation:

The objective is to  Show that if the set of images {T(v1)......T(vp)} is linearly dependent, then {v1......vp} is linearly dependent.

Given that:

[tex]\mathbf{[T(v_1) +T(v_2) ...T(v_p)]}[/tex] is linearly dependent set

Thus; there exists scalars [tex]\mathbf{k_1 , k_2 ... k_p}[/tex] ; ( read as "such that")  [tex]\mathbf{k_1 T(v_1) +k_2T(v_2) ...k_pT(v_p)=0}[/tex]

[tex]\mathbf{= T(k_1 v_1 +k_2v_2 ...k_pv_p)=0}[/tex]

T = 0                                  (for the fact that T is linear transformation)

[tex]\mathbf{k_1 v_1 +k_2v_2 ...k_pv_p=0}[/tex]     (due to T is one-one)

NOTE: Not all Ki's are zero;

Thus;

[tex]\mathbf{[v_1,v_2 ...v_p] }[/tex]  is linearly dependent

It negation also illustrates that :

If [tex]\mathbf{[v_1,v_2 ...v_p]}[/tex] is also linearly independent then [tex]\mathbf{[T(v_1),T(v_2) ...T(v_p)]}[/tex] is also linearly independent.