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magnets attract everything with metal inside of it

Answer: magnets attract everything with metal inside of it

Explanation:

Answer:

A-10

Explanation:

In the SI, designations of multiples and subdivision of any unit may be arrived at by combining with the name of the unit the prefixes deka, hecto, and kilo meaning, respectively, 10, 100, and 1000, and deci, centi, and milli, meaning, respectively, one-tenth, one-hundredth, and one-thousandth.

IM NOT SURE PO

To find the force,

 ⇒ must know the force's formula ⇒ F = MA

Let's consider the information given:

Let's solve:

  [tex]F=MA=0.025kg*5m/s^2=0.125N[/tex]

Thus the force is 0.125N

Answer: 0.125N

Hope that helps!

If Kelli and Jarvis maintain a forward force of 524 N for 1.44 seconds on a 158-kg piano, the acceleration will be 0.671 m/s² and the final velocity will be 0.966 m/s.

Kelli and Jarvis exert a force of 524 N on a 158- kg (m) piano.

The friction force, which opposes this force, is 418 N.

The net force (F) is the difference between both forces.

F = 524 N - 418 N = 106 N

We can calculate the acceleration (a) of the piano using Newton's second law of motion.

Newton's second law of motion states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force and inversely proportional to the mass of the object.

a = F/m = 106 N/158kg = 0.671 m/s²

The piano start from rest (u = 0 m/s) and moves with an acceleration of 0.671 m/s² for 1.44 s.

We can calculate its final velocity (v) using the following kinematic equation.

v = u + a × t

v = 0 m/s + 0.671 m/s² × 1.44 s = 0.966 m/s

If Kelli and Jarvis maintain a forward force of 524 N for 1.44 seconds on a 158-kg piano, the acceleration will be 0.671 m/s² and the final velocity will be 0.966 m/s.

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Answer:

1. the nail which is kept immersed in Sodium Chloride solution

2.

Explanation:

The amount of alcohol contained in each of the listed beverages can be compared as follows; 1/2 oz of 80 proof liquor > 5 oz of wine (12% alcohol) > 12 oz of wine cooler (5%alcohol) = 12 oz of beer  (5%alcohol) .

A drink that contains alcohol must be an intoxicating beverage. The extent of intoxication of an alcoholic beverage depends on the amount of alcohol that the beverage contains. There are various types of alcoholic beverages as listed in the question.

The amount of alcohol contained in each of the listed beverages can be compared as follows; 1/2 oz of 80 proof liquor > 5 oz of wine (12% alcohol) > 12 oz of wine cooler (5%alcohol) = 12 oz of beer  (5%alcohol) .

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Why does cold soda taste great but warm soda taste flat ?

Answer

When a carbonated drink is at room temperature, it is less fizzy and taste flat. Cool it down and it will taste better because the drink is designed to be drank at a lower temperature for optimal fizz and taste.

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Answer:

SORRY IM LATE! at least i saw it.

Explanation:

Kingdom is Eucaryota

domain is eucarya

Answer:

About 0.53 g of carbon dioxide needs to be added.

Explanation:

Recall the ideal gas law:

[tex]\displaystyle PV = n RT[/tex]

To determine the amount of carbon dioxide we need, we need to solve for n:

[tex]\displaystyle n = \frac{PV}{RT}[/tex]

Recall that P, V, and T are in atm, L, and K, respectively. R is the universal gas constant.

Convert all values into the correct units:

Volume:

[tex]\displaystyle 250\text{ mL } \cdot \frac{1 \text{ L}}{1000 \text{ mL}} = 0.25 \text{ L}[/tex]

Temperature:

[tex]\displaystyle \begin{aligned} K & =( ^\circ C) + 273.15 \\ \\ & = (-24) + (273.15) \\ \\ & = 249 \text{ K}\end{aligned}[/tex]

And pressure:

[tex]\displaystyle 95 \text{ kPa} \cdot \frac{1.00 \text{ atm}}{101.3 \text{ kPa}} = 0.94 \text{ atm}[/tex]

Substitute and evaluate:

[tex]\displaystyle\begin{aligned} n & = \frac{\left(0.94 \text{ atm}\right)\left(0.25 \text{ L}\right)}{\left(\dfrac{0.08206 \text{ L-atm}}{\text{mol-K}}\right)\left(249\text{ K}\right)} \\ \\ & = 0.012 \text{ mol CO$_2$}\end{aligned}[/tex]

Convert moles to grams:

[tex]\displaystyle 0.012 \text{ mol CO$_2$} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} = 0.53 \text{ g CO$_2$}[/tex]

In conclusion, about 0.53 g of carbon dioxide needs to be added.

Answer:

Any substance that cannot be decomposed into simpler substances by ordinary chemical processes.

Another definition:

An element is the simplest pure substance which can neither be split nor built up from other simpler substances by chemical reaction

We can extract 3×3 power 3 from glucose molecules

Answer:

In the Lewis structure for IF5 you'll need to put a total of 12 valence electrons on the Iodine atom in order to draw the Lewis structure. Remember that Iodine (I) can hold more than eight valence electrons. For the IF5 Lewis structure, calculate the total number of valence electrons for the IF5 molecule

Explanation:

I be knowing hope this helps

Answer:

valence electrons get closer but rest of them are remain same

A graduated cylinder

_________________

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A wave with a smaller wavelength has UV radiation energy than one with a larger wavelength.

Uses of UV Rays

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Explanation:

P1. V1/T1 = P2. V2/T2

Apply this

since here, P1 = P2

100 ml / 300 = V2/ 200

==> 100*200/300 = V2

===> V2 = 66.66 ml

The mass percentage of sugar in the sweet tea is 10%

From the question,

We are to determine the mass percentage of sugar in the sweet tea

[tex]Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{Mass\ of\ sugar\ in\ the\ solution}{Mass\ of\ the\ solution} \times 100\%[/tex]

Mass of sugar in the solution = 20 g

Mass of the solution = 20g + 180g = 200g

[tex]Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{20}{200} \times 100\%[/tex]

[tex]Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{20}{2} \%[/tex]

∴ Mass percentage of sugar in the sweet tea = 10%

Hence, the mass percentage of sugar in the sweet tea is 10%

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Answer:

Pulley

Explanation:

You can't the piano up the stairs, you need to something to bring it up

Answer: Dinitrogen Monoxide ( also called nitrous oxide )

is an inorganic ( not made from living matter) compound with the chemical formula of N2O.

Explanation:

Read above

The part of the chemical reaction that is the Brønsted-Lowry base is BrO.

Bronsted-Lowry definition of a base and acid is as follows:

According to this question, the following chemical reaction is given:

BrO + H2CO3 → HCO3 + BrOH

In the above reaction, BrO is the compound that accepts the hydrogen ion (H+) to become BrOH, hence, BrO is the Bronsted-Lowry base.

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Br and As:

Bromine is more reactive as reactivity increases on moving from left to right in p-block

Answer:

Proteins

Explanation:

Their Function Formation Encoded in mRNA into polypeptide chains of amino acids that produces protein

The ribosome of plant cells are sites for the synthesis of proteins. The correct option is (d).

Ribosomes are organelles that take part in the synthesis of proteins. The prokaryotic cell's ribosomes are smaller than the eukaryotic cell's ribosomes.

Currently, ribosomal RNA is a component of the cell's ribosome or protein-building machinery. The process of making proteins, or translation, is carried out by ribosomes.

The ribosome, which translates the genetic code generated in mRNA into an amino acid sequence, is universally responsible for protein synthesis. The two ribosomal subunits, small and big, come together to form the full ribosome, which is used to produce proteins.

Therefore, the correct option is (d) proteins.

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#SPJ2

Using thermodynamics

[tex]\\ \sf\longmapsto Q=mc∆T[/tex]

[tex]\\ \sf\longmapsto Q=0.015(328)(4184)[/tex]

[tex]\\ \sf\longmapsto Q=20585.28J[/tex]

The enthalpy of this reaction is -296. 8 kJ/mol.

The equation of the reaction is;

S(s) + O2(g) -----> SO2(g)

Recall that the enthalpy of the reaction can be obtained from the formula;

ΔHrxn = ΔHf(products) - ΔHf(reactants)

We know that;

ΔHf S(s) = 0 KJ/mol

ΔHf O2(g) =  0 KJ/mol

ΔHf SO2(g) = -296. 8 kJ/mol

Hence;

ΔHrxn =  -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]

ΔHrxn = -296. 8 kJ/mol

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The total heat required to convert the ice to steam is 155,000 J.

The given parameters:

The heat required to raise the temperature to 0⁰C is calculated as;

[tex]Q = mc\Delta t\\\\Q_1 = 50 \times 4.184 \times (0 - (-10))\\\\Q_1 = 2092 \ J[/tex]

The  heat required to melt the ice is calculated as follows;

[tex]Q_2 = mL_f\\\\Q_2 = 50 \times 333.55 \\\\Q_2 = 16,677.5 \ J[/tex]

The heat raise the temperature to 100⁰C is calculated as;

[tex]Q_3 = 50 \times 4.184 \times (100 - 0)\\\\Q_3 = 20,920 \ J[/tex]

The  heat required to boil the water is calculated as follows;

[tex]Q_4 = mL_v\\\\Q_4 = 50 \times 2230\\\\4_4 = 111,500 \ J[/tex]

The heat raise the temperature to 120⁰C is calculated as;

[tex]Q_5 = 50 \times 4.184 \times (120 - 100)\\\\Q_5 = 4,184 \ J[/tex]

The total heat required is calculated as follows;

[tex]Q_t = Q_1 + Q_2 + Q_3 + Q_4 + Q _5 \\\\Q_t = 2092 + 16,677.5 + 20,920 + 111,500 + 4,184\\\\Q_t = 155,373.5 \ J\\\\Q_t \approx 155,000 \ J[/tex]

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