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compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 1 C, and at a distance of 1 m from each other.

Answer:

alright i responded

Explanation:

you didnt say i had to answer

Answer:

Miles is the distance unit. Hours is the time unit.

Explanation:

Answer:

0.5m/s2

..............

Answer:

1) The velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Explanation:

1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:

Position

[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]

[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)

Velocity

[tex]v = v_{o}-g\cdot t[/tex] (2)

Where:

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.

[tex]v[/tex] - Final velocity of the ball, measured in meters per second.

From (1), we get the time when the ball returns to the thrower's hand:

[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]

[tex]t = \frac{2\cdot v_{o}}{g}[/tex]

And then we apply this result in (2):

[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]

[tex]v = -v_{o}[/tex] (3)

Then, the velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:

[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)

If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:

[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]

The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Answer:

Mass, m = 32 kg

Explanation:

Given that,

Force, F = 2000 N

The change in velocity, (v-u) = 50 m/s

Time, t = 0.8 s

We need to find the mass of the ball. The net force acting on an object is given by :

F = ma

Where a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{(v-u)}\\\\m=\dfrac{2000\times 0.8}{50}\\\\m=32\ kg[/tex]

So, the mass of the ball is 32 kg.

Answer:

its 120 C

Explanation:

its 120 C

The voltage drop across the 10.0 Ω resistor is c)120V

Voltage drop is the decrease of electrical potential along the path of a current flowing in an electrical circuit.

since , all three resistors 10Ω , 20 Ω and 30Ω are in series combination

this implies that voltage drop across each resistor will be same as the total voltage drop in the circuit because in parallel combination voltage remain same in the circuit buy current get divided in each branch  

hence , the voltage drop across the 10.0 Ω resistor = 120 V

  correct answer c) 120 V

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Answer:

60 km per hour

Explanation:

if you drive for 30 min and go 30km then if you drive for 60 min(1hr) then you would have driven 60km.

Answer:

60

Explanation:

hope this helps

Answer:

800 kg

Explanation:

I just did it :)

Answer:

A compound is a substance that consists of two or more elements in a unique composition. The smallest particle of a compound is called a molecule. Chemical bonds hold together the atoms of molecules

Answer:

Uniform Speed: A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. Variable Speed: A body is said to be moving with variable speed if it covers unequal distances in equal intervals of time.

Explanation:

I got it from google

Answer:

Speed is a measure of how fast an object is moving at a given instant of time. It is a scalar quantity. Its unit is m/s. For a body covering equal distances in equal time intervals, the speed is called uniform speed.

Explanation:

Answer:

E

Explanation:

Elaphants and noodles+ramen and sushi

A. 30 m/s . . . speed

B. 30 m to the East  . . . displacement

C. 30 m/s to the East  . . . velocity

D. 30 m . . . distance

Use the definition of average acceleration:

a = ∆v / t

If v is the starting speed, then ∆v = 0 - v, so solve for v :

-6.42 m/s² = (0 - v) / (2.85 s)

v = (6.42 m/s²) (2.85 s)

v ≈ 18.3 m/s

Answer:

Yes

Explanation:

Its a good game.

Answer:

oof

Explanation:

Answer:

The distance is 45m. (s)

Acceleration is 9.8 m/s^2 (acceleration due to gravity). (a)

We have to find the time (t)

By the 3rd equation of motion,

s = ut + 1/2 at^2 (here u is the initial velocity of the ball)

Since the initial velocity was 0 m/s, the formula becomes s = 1/2 at^2.

(substituting the values in the formula)

45 = 1/2 x 9.8 x t^2

45 = 9.8/2 x t^2

45 = 4.9 x t^2 (9.8/2 = 4.9)

(divide 4.9 on both sides)

45/4.9 = 4.9 x t^2 / 4.9

9.1836 = t^2

3.030 = t

So it takes approximately 3 seconds for the ball to reach the surface of the earth (neglecting air resistance). You can try the same with 50 m .

The velocity of the ball the moment it hits the ground is equal to 31.3 m/s.

Equation of motion has established a relation between the velocity of the body and acceleration of the body when the body is moving with uniform acceleration along a straight line. The distance traveled in a specific time has expressed a set of equations termed equations of motion.

The first equation of motion can be expressed as follows:

v = u + at

The second equation of motion can be expressed as follows:

S= ut + (1/2)at²

Where u is the initial velocity of a body, v is the final velocity, S is the distance, a is the acceleration and t is the time.

Given, the distance traveled by the ball, S = 50 m

and, the initial velocity of the ball, u = 0 as ball is at rest initially.

From the second equation of motion, find the value of 't':

50 = (0) t + (1/2)× (9.8) ×(t²)

t = 3.19 sec

Now from the first equation of motion, find the value of the final velocity of the ball:

v = (0) + (9.8) (3.19)

v = 31.3 m/s

Therefore, the ball hits the ground with a velocity of 31/3 m/s.

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Answer:

0.138889 m/s2

Explanation:

The average acceleration of the vehicle would be 0.139 meters/second².

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem a truck accelerates from 25 kilometers/hour to 45  kilometers/hour in 40 seconds.

Let us first convert the velocities from kilometers/hour to meters/seconds

25 kilometers/hour ⇒ 25×1000/3600

                                    = 6.94 meters/seconds

45 kilometers/seconds =  45×1000/3600

                                       = 12.5 meters/seconds

acceleration = change in the velocity/time

                     =(12.5 -6.94)/40

                     =0.139 meters/second²

Thus, the acceleration of the truck would be 0.139 meters/second²

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In physics, the triangle symbol (∆) typically represents a change or difference in a particular quantity.



A triangle is often used to denote the difference between two values of a variable. For example, if we have two values of time, t1 and t2, the change or difference in time can be represented as Δt = t2 - t1, where Δt is the triangle symbol indicating the change in time. Similarly, it can be used to represent differences in other physical quantities such as displacement (∆x), velocity (∆v), or temperature (∆T). The triangle symbol (∆) is a shorthand notation commonly used in physics to indicate changes or differences.

In terms of change in displacement, the triangle symbol (∆) represents the difference between two positions or locations. It indicates the change in the object's position from an initial point to a final point.

For example, if an object initially starts at position x1 and then moves to position x2, the change in displacement (∆x) can be calculated as ∆x = x2 - x1. Here, ∆x represents the difference or change in the object's displacement.

The magnitude of ∆x gives the overall distance traveled by the object, and its sign indicates the direction of the displacement. A positive ∆x signifies a displacement in the positive direction (e.g., to the right or upward), while a negative ∆x represents a displacement in the negative direction (e.g., to the left or downward).

Therefore, The triangle symbol (∆) is commonly used in physics equations to denote changes or differences in various quantities, including displacement, velocity, time, and more. It helps us analyze and quantify the differences between two values of a physical quantity.

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Answer: velocity

Explanation: v/t

The answer is option c - It will divide in half to form two new cells..

Explanation:

The sentence that best describes what happened during cell growth is ;

( D ) It will become larger by taking in nutrients

As the yeast cells begin to grow ( i.e. cell growth ), they will require more nutrients and as they take in the necessary nutrients they will gradually increase in size ( becoming larger ) which is a vital sign of cell growth and development, which will be seen in the yeast cells as they undergo cell growth.

The production of offsprings with a mate does not describe an activity that occurs in cell growth.  

Hence we can conclude that The sentence that best describes what happened during cell growth is, It will become larger by taking in nutrients.

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Answer:

The force to get the plane moving, and to balance the friction so it does not stop, is provided by the propeller. However, the wheels provide the acceleration of the car.

Explanation:

energy drinks

sitting

watching TV

Answer:

use natural lights

turn off electrical appliances..if not in use

check your wires every next Month

Answer:

11 times the weight of Philip.

Explanation:

From the question given above, the following data were obtained:

Weight of Melissa (i.e cow) = 0.65 tons

Weight of Philip (i.e rabbit) = 192 ounces

Next, we shall express the weight of Philip (i.e the rabbit) in tons. This can be obtained as follow:

1 ounce = 3.125×10¯⁵ ton

Therefore,

192 ounce = 192 ounce × 3.125×10¯⁵ ton / 1 ounce

192 ounce = 0.06 ton

Thus, the weight of Philip (i.e the rabbit) in ton is 0.06 ton.

Next, we shall determine the ratio of the weight of Melissa (i.e the cow) to the weight of Philip (i.e the rabbit). This can be obtained as follow:

Weight of Melissa (i.e cow) = 0.65 ton

Weight of Philip (i.e rabbit) = 0.06 ton

Melissa /Philip = 0.65/0.06

Melissa /Philip = 11

Melissa = 11 × Phillip

Thus, it will take 11 times the weight of Philip to weigh as much as Melissa.

The genetic material of an offspring of sexually reproducing organisms is best described as genes from both parents in unique combinations.

SEXUAL REPRODUCTION:

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Answer:D

Explanation:AP3X

The statement describes the interaction between the permanent magnets and the electromagnet in an electric motor is option D.

A substance which is negative charged at one end and positive charged at another end creating the magnetic field around it.

A bar is a magnet which can attract the particle which are charged. It has two poles North and South.

The permanent magnet create magnetic field very strong. The electromagnet is find in the electric motor. In the motor, loop made up of conductor is rotated by the effect of magnetic field of permanent magnet.

Thus, the correct option is D.

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Answer:

The resultant displacement of the airplane in 4 hours is 212.8 km.

Explanation:

The components of the airplane's velocity and wind's velocity are:

Airplane:

[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]

[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]

Wind:

[tex] v_{w_{x}} = 0 [/tex]

[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]

Now, to know the new velocity of the airplane we to find the result vector:

[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]

[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]  

Now, the magnitude of the new speed of the airplane is:

[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]

Finally, after 4 hours the resultant displacement of the airplane is:

[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]

Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.

I hope it helps you!                                        

Answer:

Road A = 8 meters Wet

Road B = 2 meters Muddy

Road C = 12 meters Dry

Explanation:

Answer:

053.

Explanation:

Given that the radius of curvature of the path, R = 75 m.

Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]

The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v  on curved path having radiusR

Ris[tex]F_c = mv^2/R[/tex]

Gravitational force, [tex]F_g[/tex] = mg.

Let tha angle of superelevation is [tex]\theta.[/tex]

As the car does not skid even with zero friction, so

[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]

[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]

On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]  

As [tex]v_2[/tex] = 118 m/s is greater than   v_so the car tends to skid in upper direction and the frictional

force,f, will acts is downward direction.

As there is no skidding, so

[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]

[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]

where [tex]f= \mu N.[/tex]

[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]

Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.

[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]

From equation (ii)

[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]

[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]

[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]

[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]

[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]

=0.53

Hence, the minimum coefficient of friction is 0.53.