✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h
95/ 3,6 ≈ 26,4 m/s
Ec = ½ m x V²
With Ec in J; m in kg; and V in m/s
Ec = ½ 1750 x 26,4² Ec ≈ 610 000 J✔ Knowing that the car has a p power of 215,000 W, so :
T = E/P
T = 610 000/215 000 T ≈ 2.8 s The car takes 2.8 s to reach 95 km/h QUESTION②)N = 2,8/6,5 x 100 = 43.07
The car efficiency is 43 %Why does time seem to flow only in one direction?
Answer:
Time seem to flow only in one direction because if it started to go in backward direction that would break the second law of thermodynamics. We do not find time to be moving in any direction because time is not an object that can move nor is it a force that can move any object.
What is the angle of deviation in a plane mirror at normal incidence?
Answer:
The deviation of a mirror is equal to twice the angle of incidence.The total angle between the straight-line path and the reflected ray is twice the angle of incidence. This is called the deviation of the light and measures the angle at which the light has strayed from its initial straight-line path.
HOPE IT HELPS :)
PLEASE MARK IT THE BRAINLIEST!
Complete all four parts. 15 points. Will give brainliest! Show work!
Answer:
A. 5.08 secs.
B. 10.16 secs.
C. 126.50 m.
D. 373.36 m
Explanation:
Data obtained from the question include the following:
Initial velocity (u) = 65 m/s
Angle of projection θ = 50°
A. Determination of the time taken to reach the peak.
Initial velocity (u) = 65 m/s
Angle of projection θ = 50°
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =.?
t = u•Sine θ/g
t = (65 × Sine 50) /9.8
t = 5.08 secs.
B. Determination of the total time spent by the ball in air.
Time (t) taken to reach the peak = 5.08 secs.
Total time (T) spent by the ball in air =?
T = 2t
T = 2 × 5.08
T = 10.16 secs
Therefore, the total time spent by the ball in air is 10.16 secs.
C. Determination of the maximum height.
Initial velocity (u) = 65 m/s
Angle of projection θ = 50°
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (H) =..?
H = u²•Sine² θ / 2g
H = 65² × (Sine 50)² / 2 × 9.8
H = 4225 × (Sine 50)² /19.6
H = 126.50 m
Therefore, the maximum height reached by the ball is 126.50 m.
D. Determination of the horizontal distance travelled by the ball.
Initial velocity (u) = 65 m/s
Angle of projection θ = 50°
Acceleration due to gravity (g) = 9.8 m/s²
Horizontal distance (R) =..?
R = u²•Sine 2θ / g
R = 65² × Sine (2×30) / 9.8
R = (4225 × Sine 60) / 9.8
R = 373.36 m
Therefore, the horizontal distance travelled by the ball is 373.36 m
To get an idea how big a farad is, suppose you want to make a 1.0-F air-filled parallel-plate capacitor for a circuit you are building. To make it a reasonable size, suppose you limit the plate area to 1.4 cm2 .
Part A
What would the gap have to be between the plates?
Express your answer using two significant figures and include the appropriate units.
Part B
Is this practically achievable?
Is this practically achievable?
a. yes
b. no
Answer:
The gap between the plates will be 1.2 x 10^-15 m
No, this is not practically achievable.
Explanation:
Capacitance = 1.0 F
area of plate = 1.4 cm^2 = 1.4/10000 m^2 = m^2
distance = ?
We use the equation
[tex]C[/tex] = [tex]\frac{A}{d}[/tex]*ε
C is the capacitance
where A is the area
d is the distance of separation of plates
ε is the permeability of free space = 8.854×10^-12 F⋅m−1
substituting values, we have
1 = [tex]\frac{0.00014}{d}[/tex]* 8.854×10^-12
distance between plates = 1.2 x 10^-15 m
This is not practically achievable in real life
Fill in the blanks in the following statements:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_____light years.
3. The more distant a star, the_____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is_____.
5. The closest stars have parallaxes smaller than______arcsecond.
6. The first successful measurements of stellar parallax were made by______in year______for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is______times______then star Bob.
Answer:
Explanation:
1. A parsec is defined as the distance from the Sun which would result in a parallax of_TWO____ arcsecond as seen from Earth when observed 6 months apart.
2. One parsecs is about_3.3____light years
3. The more distant a star, the_LESS ____its parallax.
4. The statement "we can measure stellar parallax for most stars in our galaxy" is__TRUE .___.
5. The closest stars have parallaxes smaller than_.002 _____arcsecond.
6. The first successful measurements of stellar parallax were made by_Friedrich Bessel_____in year_1838_____for the star named.
7. Star Fred has parallax four times greater than star Bob. Star Fred is__4____times_nearer_____than star Bob.
the velocity is always _____ to the line of a circle
Answer:
The velocity is always tangent to the line of a circle .
Explanation:
When an object moves in a circular path, its motion is called the circular motion. The speed of the object is constant at each and every point in such motion while the velocity changes due to change in direction.
In a circular motion, the direction of velocity is always tangent to the circle. At each and every point, its direction is found tangentially.
You are playing a violin, where the fundamental frequency of one of the strings is 440 Hz, as you are standing in front of the opening of a long tube that is closed at the other end. As you play, you notice that the first time you hear an echo from the tube is when the sound from the 440 Hz string is in its fourth harmonic. Assuming you are playing this string on earth, what must be the length of the tube? What is the next higher harmonic number for the same string on the violin when you hear the next higher harmonic echo from the tube?
Answer:
a) L = 440 cm
Explanation:
In the open tube on one side and cowbell on the other, we have a maximum in the open part and a node in the closed part, therefore the resonance frequencies are
λ₁ = 4L fundamental
λ₃ = 4L / 3 third harmonic
λ₅ = 4L / 5 five harmonic
The violin string is a fixed cure in its two extracts, so both are nodes, their length from resonance wave are
λ₁ = 2L fundamental
λ₂ = 2L / 2 second harmonic
λ₃ = 2L / 3 third harmonic
λ₄= 2L / 4 fourth harmonic
They indicate that resonance occurs in the fourth harmonic, let's look for the frequency
v =λ f
for the fundamental
v = λ₀ f₀
V = 2L f₀
for the fourth harmonica
v = λ₄ f ’
v = L / 2 f'
2L f₀ = L / 2 f ’
f ’= 4 f₀
f ’= 4 440
f ’= 1760 Hz
for this frequency it has the resonance with the tube
f ’= 4L
L = f ’/ 4
L = 1760/4
L = 440 cm
b) let's find the frequency of the next harmonic in the tube
λ₃ = 4L / 3
λ₃ = 4 400/3
λ₃ = 586.6 cm
v = λf
f = v / λlam₃
f₃3 = 340 / 586.6
f3 = 0.579
as the minimum frequency on the violin is 440 Beam there is no way to reach this value, therefore there are no higher resonances
A projectile is fired from a height of 80 M above sea level, horizontally with a speed of 360 M / S, calculate: The time it takes for the projectile to reach the water. The Horizontal scope. The height that remains to descend after 2 seconds of being launched.
Answer:
(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.
Explanation:
The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:
[tex]x = x_{o}+v_{o,x} \cdot t[/tex]
[tex]y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex]
Where:
[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial horizontal and vertical position of the projectile, measured in meters.
[tex]v_{o,x}[/tex], [tex]v_{o,y}[/tex] - Initial horizontal and vertical speed of the projectile, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]x[/tex], [tex]y[/tex] - Current horizontal and vertical position of the projectile, measured in meters.
Given that [tex]x_{o} = 0\,m[/tex], [tex]y_{o} = 80\,m[/tex], [tex]v_{o,x} = 360\,\frac{m}{s}[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the kinematic equations are, respectively:
[tex]x = 360\cdot t[/tex]
[tex]y = 80-4.094\cdot t^{2}[/tex]
(a) If [tex]y = 0\,m[/tex], the time taken for the projectile to reach the water is:
[tex]80 - 4.094\cdot t^{2} = 0[/tex]
[tex]t = \sqrt{\frac{80}{4.094} }\,s[/tex]
[tex]t \approx 4.420\,s[/tex]
The projectile takes approximately 4.420 seconds to reach the water.
(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If [tex]t \approx 4.420\,s[/tex], the horizontal scope of the projectile is:
[tex]x = 360\cdot (4.420)[/tex]
[tex]x = 1591.2\,m[/tex]
The horizontal scope of the projectile is 1591.2 meters.
(c) If [tex]t = 2\,s[/tex], the height that remains to descend is:
[tex]y = 80-4.094\cdot (2)^{2}[/tex]
[tex]y = 63.624\,m[/tex]
The remaining height to descend after 2 seconds of being launched is 63.624 meters.
When the current in a toroidal solenoid is changing at a rate of 0.0260 A/s, the magnitude of the induced emf is 12.2 mV. When the current equals 1.40 A, the average flux through each turn of the solenoid is 0.00308 Wb. How many turns does the solenoid have?
Answer:
The solenoid has 213 turns.
Explanation:
The number of the solenoid's turns (N) can be found as follows:
[tex] N = \frac{L*I}{\phi_{B}} [/tex] (1)
Where:
L: is the self-inductance of the solenoid
I: is the current = 1.40 A
[tex]\phi_{B}[/tex]: is the magnetic flux = 0.00308 Wb
The self-inductance of the solenoid (L) is:
[tex] L = \frac{|\epsilon|}{|dI/dt|} [/tex] (2)
Where:
ε: is the induced emf = 12.2x10⁻³ V
dI/dt: is the rate changing of the current = 0.0260 A/s
By entering equation (2) into (1) we can find the number of turns:
[tex] N = \frac{|\epsilon|*I}{\phi_{B}|dI/dt|} = \frac{12.2 \cdot 10^{-3} V*1.40 A}{0.00308 Wb*0.0260 A/s} = 213 [/tex]
Therefore, the solenoid has 213 turns.
I hope it helps you!
Help!
6. Assume a position vs time graph displays a horizontal line, what does this represent?
A. Constant Velocity
B. 0 Acceleration
if it is horizontal line, that means position is same but time is increasing.
velocity=0 . particle is not even moving
Which of the following best represents a double replacement reaction?
A. AB → A + B
B. A + B → AB
C. A + BC → AC + B
D. AC + BD → AD + BC
Answer:
D. AC+BD -> AD +BC
Explanation:
I got it right
A double displacement reaction is also called the double replacement reaction or double decomposition reaction. Here AC + BD → AD + BC is a double displacement reaction. The correct option is D.
What is double displacement reaction?A double displacement reaction is defined as a chemical reaction in which the positive and negative ions of two ionic compounds exchange their places to form two new compounds. The general form of a double displacement reaction is given as:
AC + BD → AD + BC
Here 'A' and 'B' are positively charged cations, whereas 'C' and 'D' are negatively charged anions. The double displacement reactions generally occur between the substances in an aqueous solution. In order for a reaction to occur, one of the products is usually a solid precipitate, a gas or a molecular compound like water.
Thus the correct option is D.
To know more about double replacement reaction, visit;
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what is the formula for velovity?
Answer:
if it's velocity u talking of.....
Explanation:
then it's displacement/ time
Mustang Sally just finished restoring her 1965 Ford Mustang car. To save money, she did not get a new battery. When she tries to start the car, she discovers that the battery is dead (an insufficient or zero voltage difference across the battery terminals) and so she will need a jump start. Here is how she accomplishes the jump start:
Explanation:
To jump start she needs
1. Jumper cables
2. Power source/jump box/ portable batteries.
The positive end of the jump cable will be connected to terminal of the car battery and the jump box, likewise the negative terminal to complete the circuit for a successful jump start to be accomplished
Given a volume of 1000. сm of an ideal gas at 300. K, what volume would it occupy at a temperature of 600. K?
Answer:
2000 cm³
Explanation:
Assuming the pressure is constant:
V / T = V / T
1000 cm³ / 300 K = V / 600 K
V = 2000 cm³
Letícia leaves the grocery store and walks 150.0 m to the parking lot. Then, she turns 90° to the right and walks an additional 70.0 m to her car. What is the magnitude of the displacement of her car from the grocery store exit?
Answer:
165.529454
Explanation:
According to the Pythagorean Theorem for calculating the lengths of a right angle triangle's sides, a^2 + b+2 = c^2, where c is the longest side (and the side opposing the right angle). So in your case it would be 150*150 + 70*70 = 27400. And √ 27400 is your answer.
4.
An "extreme" pogo stick utilizes a spring whose uncompressed length is 46 cm and whose force constant is 1.4 x 104 N/m. A 60-kg person is jumping on the pogo stick,
compressing the spring to a length of only 5.0 cm at the bottom of their jump. Which is the upward acceleration of the person at the moment the spring reaches its greatest
compression at the bottom of their jump?
6 m 2
Answer:
a = 85.9 m / s²
Explanation:
For this exercise we can use Newton's second law in the most compressed part
F - W = m a
force is the spring elastic force
F = - k Δx
k Δx - m g = m a
a = k/m Δx - g
Δx = x₀ -[tex]x_{f}[/tex]
ΔX = 46 - 5 = 41cm (1m / 100cm) = 0.41 m
let's calculate
a = 1.4 10⁴/60 0.41 - 9.8
a = 85.9 m / s²
A body moves in a straight line. At time, it's acceleration is given by a = 12t + 1. When t =0, the velocity of the body v is 2 metres per second and its displacement from the origin s is 0.
1. Express v and s in terms of t.
2. Determine velocity and displacement of the body after 3 seconds.
Answer:
v = 6t² + t + 2, s = 2t³ + ½ t² + 2t
59 m/s, 64.5 m
Explanation:
a = 12t + 1
v = ∫ a dt
v = 6t² + t + C
At t = 0, v = 2.
2 = 6(0)² + (0) + C
2 = C
Therefore, v = 6t² + t + 2.
s = ∫ v dt
s = 2t³ + ½ t² + 2t + C
At t = 0, s = 0.
0 = 2(0)³ + ½ (0)² + 2(0) + C
0 = C
Therefore, s = 2t³ + ½ t² + 2t.
At t = 3:
v = 6(3)² + (3) + 2 = 59
s = 2(3)³ + ½ (3)² + 2(3) = 64.5
define the term 'one solar mass.'
Answer:
the mass of one sun
Explanation:
its really heavy
Which statement best describes the difference between how lenses and
mirrors interact with light?
A. Lenses bring light to a point; mirrors do not.
B. Lenses form images by reflecting light; mirrors do not.
C. Lenses spread light apart; mirrors do not.
D. Lenses form images by refracting light; mirrors do not.
Answer:D
Explanation:
Apex
How do you find time with current and charge
[tex]\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Current Electricity .
Since we know that, Current is Charge per unit time.
so we get as,
Q = I*t
here, Q = charge, I = current, t = time.
Increase in Space Suit Pressure 0.0/3.0 points (graded) If the pressure in a space suit increases, how will each of the following be affected? Flexilibity will: Increase Decrease Stay the same unanswered The required pre-breathe time will: Increase Decrease Stay the same unanswered The mass of the suit will: Increase Decrease Stay the same
Answer:
Flexibility Increases
Pre-breathe time decreases
Mass of suit decreases.
Explanation:
Spacesuits are designed for space shuttles when a person goes to explore the galaxy. The spacesuits shuttle era are pressurized at 4.3 pounds per inch. The gas in the suit is 100% of oxygen and there is more oxygen to breathe when the altitude of 10,000 is reached. This will decrease the breathing time and mass of suit.
An alternating source drives a series RLC circuit with an emf amplitude of 6.34 V, at a phase angle of +32.6°. When the potential difference across the capacitor reaches its maximum positive value of +5.08 V, what is the potential difference across the inductor (sign included)?
Answer:
V=-8.35v
Explanation:
Pls see attached file
A 1,383 kg purple car is driving southbound on a road and collides with a 1,827 kg orange car, that was traveling 31.87 m/s eastbound. The two cars collide and stick, sliding 14.54 meters before coming to rest. What was the initial velocity of the two-car system just after the collision? Take the coefficient of friction to be 0.463, and the acceleration due to gravity to be 9.8 m/s2. Answer to two decimal places.
Answer:
Explanation:
We shall apply work energy theorem to calculate the initial velocity just after the collision .
Their kinetic energy will be equal to work done by friction .
force of friction = μ mg , where μ is coefficient of friction , m is total mass and g is acceleration due to gravity
force = .463 x 3210 x 9.8
= 14565.05 N
work done = force x displacement
= 14565.05 x 14.54 = 211775.88 J
now applying work energy theorem
1/2 m v² = 211775.88 , m is composite mass , v is velocity just after the collision
.5 x 3210 x v² = 211775.88
v² = 131.94
v 11.48 m /s
Ionizing radiation is radiation of sufficient energy to produce charged atoms. All of these describe ionizing radiation. is radiation of sufficient energy to produce ions. is radiation of sufficient energy to remove electrons from atoms.
Answer:
Is radiation of sufficient energy to produce ions.
Is radiation of sufficient energy to remove electrons from atoms.
Explanation:
Ionization radiation is a radiation that travels at a high speed, and possesses sufficient speed to knock electrons off of an atom or a molecule, ionizing the atom. Ionization radiation can be made of travelling subatomic particles, or an electromagnetic wave with high energy, usually the types found at the end of the electromagnetic spectrum. Some subatomic particles that produce ionization are alpha particle, beta particles, and neutron. The electromagnetic waves with ionization abilities includes Gamma rays. -rays, and high energy ultraviolet rays.
1. A note has a wavelength of 0.77955 m. If the speed of sound is 343.00 m/s, what pitch is this note? 2. A note has a wavelength of 0.52028 m. If the speed of sound is 343.00 m/s, what pitch is this note? please no funny answers
Answer:
1.) 440 Hz
2.) 659.3 Hz
Explanation:
1.) Given parameters are:
wavelength = 0.77955 m.
speed of sound = 343.00 m/s
Frequency = speed/ wavelength
Substitute speed and wavelength into the formula
Frequency = 343/ 0.77955
Frequency = 439.99
Frequency = 440 Hz approximately
2.) The parameters given are:
wavelength = 0.52028 m.
speed of sound = 343.00 m/s
Using the same formula
Frequency = speed/wavelength
Substitute all the parameters into the formula
Frequency = 343 / 0.52028
Frequency = 659.3 Hz approximately
The pitch of a note depends on the frequency of the sound waves.
The pitch of a sound increases as the frequency of the sound waves increases.
Answer:
1.) 440 Hz
2.) 659.3 Hz
Explanation:
1.) Given parameters are:
wavelength = 0.77955 m.
speed of sound = 343.00 m/s
Frequency = speed/ wavelength
Substitute speed and wavelength into the formula
Frequency = 343/ 0.77955
Frequency = 439.99
Frequency = 440 Hz approximately
2.) The parameters given are:
wavelength = 0.52028 m.
speed of sound = 343.00 m/s
Using the same formula
Frequency = speed/wavelength
Substitute all the parameters into the formula
Frequency = 343 / 0.52028
Frequency = 659.3 Hz approximately
The pitch of a note depends on the frequency of the sound waves.
The pitch of a sound increases as the frequency of the sound waves increases.
A charged particle with charge of 2 (uC) and mass 10-20 (kg) is traveling with velocity of 108 (m/s) in space. The charge reaches to a region in space with magnetic field of 0.05 (T) and experience a force of 8 (N) exerted by the magnetic field.
A- What is the angle between velocity of particle and magnetic field direction?
B- What is acceleration of charged particle while experiencing the force?
Answer:
Explanation:
A ) Let the angle be θ between magnetic field and velocity of charged particle
Force created on charged particle F
= Bqv sinθ, B is magnetic field , q is charge , v is velocity of charged particle
F = .05 x 2 x 10⁻⁶ x 10⁸ x sinθ
8 = 10 sinθ
sinθ = .8
θ = 53°.
B )
acceleration = force / mass
= 8 / 10⁻²⁰
= 8 x 10²⁰ m / s²
a physical quantity Z is given by z=ad/g .calculte the relatibe error in z
Answer:
e_{r} = Δa /a + Δd /Δ d + Δg / g
Explanation:
The error or uncertainty of a quantity is given by several factors, the most direct error is the absolute one that is given by the appreciation of the instruments, when some quantities obtained by a mathematical formula we must know how each error is programmed in the total error, we can see this with the relative error
the calculated quantity is Z
its relative error is
[tex]e_{r}[/tex] = ΔZ/Z = 1/Z (dZ /da Δa + dZ /dd Δd + dZ /dg Δg)
e_{r} = 1 / Z (d /g Δa + a /g Δd + ad !1/g²! Δg)
e_{r} = Δa /a + Δd /Δ d + Δg / g
notice that we take the worst case.
The measured quantities have absolute errors Da, Dd, Dg
20 m
A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity components are Vox = 310 m's and Vov = 26 m s The
projectile reaches maximum height at point P. then it falls and strikes the ground at point Q which is 20 m below the launch point. What is the horizontal
distance that the projectile travels (labeled x in the diagram)?
O 1.3 km
700 m
O 32 km
O 870 m
O 1.9 km
Answer:
1.9 km
Explanation:
The equation for vertical motion is ...
h(t) = -4.9t^2 +26t +20
This will have a zero near t = 5.988 seconds.*
The horizontal distance traveled in that time is ...
(310 m/s)(5.988 s) ≈ 1856 m ≈ 1.9 km
_____
* The root of a quadratic can be found numerous ways. We choose the quick and easy: let a graphing calculator show it to you.
A diver releases an air bubble of volume 3.0 cm3 from a depth of 18 m below the surface of a lake, where the temperature is 9.0 ∘C. Part A What is the volume of the bubble when it reaches just below the surface of the lake, where the temperature is 22 ∘C?
Answer:
Explanation:
We shall apply gas law formula to get the solution .
P₁ V₁ / T₁ = P₂ V₂ / T₂
P₁ = 10⁵ + 18 x 10³ x 9.8 where 10⁵ Pa is atmospheric pressure at surface
= 1.764 x 10⁵ + 10⁵
= 2.764 x 10⁵
2.764 x 10⁵ x 3 / ( 273 + 9 ) = 10⁵ x V₂ / ( 273 + 22 )
V₂ = 8.67 cm³
Two students are trying to measure how high a ball bounces when it is dropped from different heights. They dropped a ball from P and it bounced up till Q. They now have to record two measurements as shown below. Which measurements should they take?A.A B.B C.C D.D
Answer:
A.A
Explanation:
The balls usually bounce 60% of the original height because it stores 60% of the energy it had before the bounce. When a ball is dropped from a great height it has kinetic energy before it hits the ground which is the result of the bounce of ball. The size of ball does matter in this case, Large balls will bounce higher.