Answer: A The energy and intensity of X-rays can be controlled.|
Explanation:
Calculate the wavelength of an orange light wave with a frequency of 5.085 x 10^14 Hz. The speed of light is 3.0 x 10^8 m/s.
^ meaning a power
Answer:
5.9 x 10⁻⁷m
Explanation:
Given parameters:
Frequency = 5.085 x 10¹⁴Hz
Speed of light = 3.0 x 10⁸m/s
Unknown:
Wavelength of the orange light = ?
Solution:
The wavelength can be derived using the expression below;
wavelength = [tex]\frac{v}{f}[/tex]
v is the speed of light
f is the frequency
wavelength = [tex]\frac{3 x 10^{8} }{5.085 x 10^{14} }[/tex] = 5.9 x 10⁻⁷m
How much work is needed to move an object 20 meters with 40 newtons of force?
a) 800 J
b) 850 N
c) 875 W
d) 825 m
Answer:
a) 800 J
Explanation:
Work is said to be done when a force induces movement over a distance in an object. The amount of work done (W) is calculated by multiplying the force by the distance traveled.
That is;
W = F × d
Where;
W = work done (J or N/m)
F = force (N)
d = distance (m)
In the information given in this question, F = 40N, d = 20m
Hence,
Work done = 40N × 20m
Work done = 800N/m or 800 J
What provides The energy needed to fill the water cycle
Answer:
The water cycles energy source comes from the sun
Explanation:
The sun's solar energy helps evaporate water from several bodies of water which causes the process of transportation
Is this statement true or false?
Line spacing refers to the amount of space between each line in a paragraph.
true
false
Answer:
True
Explanation:
I just took the test and got 100
Differentiate between
joule and watt
What happens to thermal energy when Kinetic energy is Increased/Decreased?
Answer:If kinetic energy increases, so does the thermal energy, and vice versa.
Please brainliest!
What part of an experiment contains the data tables and graphs
?
Answer: Review your data. ...
Calculate an average for the different trials of your experiment, if appropriate.
Make sure to clearly label all tables and graphs. ...
Place your independent variable on the x-axis of your graph and the dependent variable on the y-axis.
Hope this helps!!
The section of a longitudinal wave in which the particles are densely packed together
giving an area of high pressure is known as the
Answer:
compressions or refractions
Explanation:
The energy transferred between objects in contact as of temperature difference is called what?
Answer:
Heat
Explanation:
Answer:
Heat conduction, also called diffusion, is the direct microscopic exchange of kinetic energy of particles through the boundary between two systems.
Explanation:
what is the mass of a vehicle that has 50,000 N and 25M/S/S
Answer:
F = 1250000 N
Explanation:
If you have 50,000 S, by 25 M. It would be calculated to 1,250,000 N.
Will mark the brainliest
A nail of mass ,7.0g is held horizontally and is hit by a hammer of mass 0.25kg moving at 10ms −1. The hammer remains in contact with the nail during and after the blow.
If velocity of nail and hammer immediately after the blow is 9.7ms-1 Calculate the impulse transferred to the nail
Answer:
The impulse transferred to the nail is 0.01 kg*m/s.
Explanation:
The impulse (J) transferred to the nail can be found using the following equation:
[tex] J = \Delta p = p_{f} - p_{i} [/tex]
Where:
[tex]p_{f}[/tex]: is the final momentum
[tex]p_{i}[/tex]: is the initial momentum
The initial momentum is given by:
[tex] p_{i} = m_{1}v_{1_{i}} + m_{2}v_{2_{i}} [/tex]
Where 1 is for the hammer and 2 is for the nail.
Since the hammer is moving down (in the negative direction):
[tex]v_{1_{i}} = -10 m/s [/tex]
And because the nail is not moving:
[tex]v_{2_{i}}= 0[/tex]
[tex] p_{i} = m_{1}v_{1_{i}} = 0.25 kg*(-10 m/s) = -2.5 kg*m/s [/tex]
Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:
[tex] p_{f} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} [/tex]
Since the hammer and the nail are moving in the negative direction:
[tex]v_{1_{f}}[/tex] = [tex]v_{2_{f}}[/tex] = -9.7 m/s
[tex] p_{f} = -9.7 m/s(7 \cdot 10^{-3} kg + 0.25 kg) = -2.49 kg*m/s [/tex]
Finally, the impulse is:
[tex] J = p_{f} - p_{i} = - 2.49 kg*m/s + 2.50 kg*m/s = 0.01 kg*m/s [/tex]
Therefore, the impulse transferred to the nail is 0.01 kg*m/s.
I hope it helps you!
An iron bal of mass 20kg is rolling on a flat surface. On applying force, the velocity change from 17ms to 27m/s in 5s. Calculate the magnitude of the force. (Ans:40N)
Answer:
40 N
Explanation:
We first need to calculate the acceleration of the tron ball.
Since acceleration, a = (v - u)/t where u = initial velocity of iron ball = 17m/s, v = final velocity of iron ball = 27m/s and t = time taken for the change in velocity = 5 s.
So, a = (v - u)/t
= (27 m/s - 17 m/s)/5 s
= 10 m/s ÷ 5 s
= 2 m/s²
We know force on iron ball, F = ma where m = mass of iron ball = 20 kg and a = acceleration = 2 m/s²
So, F = ma
= 20 kg × 2 m/s²
= 40 kgm/s²
= 40 N
So, the magnitude of the force on the iron ball is 40 N.
Kiana is wearing a black shirt and shiny necklace. While she is outside at recess her shirt absorbs the light waves and gets very hot in the sun, but her necklace reflects the light waves and small circles of light are seen around the yard. What explains why the light waves behaved differently on her shirt than they did on her necklace?
Answer:
Black bodies are good absorber of light waves from the sun, while shining surfaces are good reflector of the light waves.
Explanation:
Generally, a black surface or material tends to absorb light waves while under the sun, while a shiny surface is a good reflector of the waves. This is because the black material is a good absorber, and also a good emitter.
The shiny necklace can only absorb little light waves from the sun, thus it reflects most of the light waves. The reflection is the reason for the small circles of light seen around the yard.
However, when in a cool environment the black shirt would cools faster (good emitter) than the shiny necklace.
A net impulse delivered to an object always causes a change in the object's
what? A. Energy B. Momentum C. Speed D. mass
Answer:
momentum
Explanation:
The net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.
The given problem is based on the concept of net impulse. The magnitude of force acting on any object for very short interval of time is known as impulse. In the given problem, the transfer of impulse can be explained by the impulse - momentum theorem.
As per the impulse-momentum theorem, "The magnitude of force applied for a very short interval of time is equal to the change in linear momentum , such that the magnitude of force is known as impulse. Ans the expression is,[tex]F \times t = \Delta P\\\\I= \Delta P[/tex]
Here, I is the impulse.
Thus, we can conclude that the net impulse delivered to an object always causes a change in the object's momentum. Hence, option (B) is correct.
Learn more about the impulse-momentum theorem here:
https://brainly.com/question/24744548
A car weighing 12,000 N is parked on a 36° slope. The car starts to roll down the hill. What is the acceleration of the car?
Given that,
Weight of a car, W = 12,000 N
It is parked on a 36° slope.
To find,
The acceleration of the car.
Solution,
Let m be the mass of the car. Using formula for weight of an object.
W = mg
[tex]m=\dfrac{12000}{9.8}\\\\=1224.48\ kg[/tex]
Let a be the acceleration of the car. Using second law of motion as follows :
[tex]a=\dfrac{F_{\text{parallel}}}{m}\\\\=\dfrac{F\sin\theta}{m}\\\\=\dfrac{12000\times \sin(36)}{1224.48}\\\\=5.76\ m/s^2[/tex]
So, the acceleration of the car is [tex]5.76\ m/s^2[/tex].
Help please.
How long is between each phase of the moon?
Answer:
The Moon actually takes 27.3 days to complete a single orbit around the earth. The Moon takes 29.5 days to complete one phase cycle.
Hope it helps!
The velocity of a 48.0 g shell leaving a 2.95 kg rifle is 391. m/s. What is the recoil velocity of the rifle?
Hi there!
[tex]\large\boxed{ -6.36m/s}[/tex]
Use the equation:
[tex]v_{2} = -\frac{m_{1}}{m_{2}} v_{1}[/tex]
Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:
v2 = ?
m1 = 0.048 kg (converted)
m2 = 2.95
v1 = 391
[tex]v_{2} = -\frac{0.048}{2.95} *391[/tex]
[tex]v_{2} = -6.36m/s[/tex]
if 1 m = 100 cm , then how many cm^2 are there in a m^2 ?? please hel[p
Answer:if 1 m = 100 cm then there should be 200 cm in m^2
Explanation:
Changes of state occur when there is a change in:
Thermal energy
Electromagnetic energy
Chemical energy
Electrical energy
interior crocodile alligator i drive a chevrolet movie theater
Answer:
nah bro tesla
Explanation:
plz help will give brainlest! if you cant help, well, merry christmas!
Fossils are found in:
sedimentary rock
metamorphic rock
sedimentary and metamorphic rock
sedimentary and igneous rock
most fossils are found in sedimentary rocks
Answer:
Sedimentary rock.
Explanation:
A girl throws a 2 kg rock with a net force of 6 N. What is the acceleration of the rock?
8 m/s2
0.33 m/s
2 3 m/s2
12 m/s2
Answer:
3 m/s2
Explanation:
Took the test
28) What is the net force on this box? *
A- 10 N to the left
B- 10 N to the right
C- 60 N to the left
D- 50 N to the right
Answer:
C- 60 N to the left
Explanation:
there is a 60n arrow to the left of the box
What would be the acceleration of an object with a mass of 5,000 g when hit with a force of 55 N?
Answer:
11 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass in kg
From the question
5000 g = 5 kg
We have
[tex]a = \frac{55}{5} \\ [/tex]
We have the final answer as
11 m/s²Hope this helps you
Look at the picture
Answer:
Your answer is d
Explanation:
1.)A tank travels at a rate of 10.0 km/hr for 12.00 minutes, then at 15.0 km/hr for 8.00
minutes, then turns 180 degrees at 20.0 km/hr for 12.00 minutes. What is the total
distance covered in km by the tank? What is the average speed for the complete trip in
m/s? What is the change of position of the tank? What is its average velocity?
Given
Equation
Find
Diagram
12.00 min = 0.2 hr
8.00 min = 0.15 hr
Total distance:
(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) + (20.0 km/hr) (0.2 hr)
= 8.25 km
Average speed:
(10.0 km/hr + 15.0 km/hr + 20.0 km/hr) / 3
= 15 km/hr
Change in position:
(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) - (20.0 km/hr) (0.2 hr)
= 0.25 km
Average velocity:
(10.0 km/hr + 15.0 km/hr - 20.0 km/hr) / 3
≈ 1.67 m/s
Name and briefly describe the 10 “world climates” or biomes
These are Some climates
Tropical.
Dry.
Temperate.
Continental.
Polar.
And these are some biomes
aquatic, grassland, forest, desert, and tundra,
A 0.50-kilogram frog is at rest on a rock next to a pond. The frog leaps pushing off of the rock with an acceleration of 5.0 m/s2. What is the magnitude of the net force exerted on the frog as it leaps? a)2.5 N b)1.5 N c)1.0 N d)2.0 N
Given that,
Mass of a frog, m = 0.5 kg
The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².
To find,
The magnitude of the net force exerted on the frog as it leaps.
Solution,
Let the net force exerted on the frog is given by the formula as follows :
F = ma
Putting the values of m and a to find F as follows :
F = 0.5 kg × 5 m/s²
F = 2.5 N
So, the magnitude of net force is 2.5 N.
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
Given the data in the question;
Mass of frog; [tex]m = 0.5kg[/tex]Acceleration; [tex]a = 5.0m/s^2[/tex]Force Exerted; [tex]F = ?[/tex]
To determine the magnitude of the net force exerted on the frog as it leaps, we the expression from the Newton's Second law of motion:
[tex]F = m * a[/tex]
Where m is mass and a is acceleration
We substitute our given values into the equation
[tex]F = 0.5kg * 5.0m/s^2\\\\F = 2.5kgm/s^2\\\\F= 2.5N[/tex]
The magnitude of the net force exerted on the frog as it leaps is 2.5 Newtons.
Hence, Option a) 2.5N is the correct answer.
Learn more on Newton's Second law of motion here: https://brainly.com/question/19473547
Two carts connected by a 0.25 m spring hit a wall, compressing the spring to 0.1 m. The spring constant k is 100 N m . What is the elastic potential energy stored from the spring's compression?
Given that,
Initial position of the spring, x₁ = 0.25 m
Final position of the spring, x₂ = 0.1 m
The spring constant of the spring, k = 100 N/m
To find,
The elastic potential energy stored from the spring's compression.
Solution,
The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :
[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]
So, the required energy is 2.62 J.
Answer:
1.125 J
Explanation:
The correct answer is 1.125 J
2. A person lifts 200kg seven times over the course of 11.8s. If they displaced the weight 2.2m up each time, how much power did the person deliver?
Answer:
The person delivered a power of 2,558 Watt
Explanation:
Work and Power
Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.
Being the force vector and the displacement vector, the work is calculated as:
[tex]W=\vec F\cdot \vec s[/tex]
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy transferred per unit of time. In the SI, the unit of power is the watt, equivalent to one joule per second.
The power can be calculated as:
[tex]\displaystyle P=\frac {W}{t}[/tex]
Where W is the work and t is the time.
If the person lifts a mass of m=200 Kg, then exerts a force equal to its weight:
F = m.g = 200*9.8 = 1,960
F = 1,960 N
The work done when lifting the weight 7 times by a distance of s=2.2 m is:
W = 7*1,960*2.2=30,184
W = 30,184 J
Finally, the power delivered in t=11.8 seconds is:
[tex]\displaystyle P=\frac {30,184}{11.8}[/tex]
P = 2,558 Watt
The person delivered a power of 2,558 Watt