Please help & solve for x thank you!

Answer:

-4 < n ≤5

Step-by-step explanation:

The lower limit is -4.  It has an open circle, so there is no equal sign

-4 < n

The upper limit is 5.  It is a closed circle so there is an equals sign

-4 < n ≤5

Answer:

1.-13.2

2.6485

Step-by-step explanation:

Answer:

0.5 ㏑ | 1-2x | +c

Step-by-step explanation:

Formula:  ∫ 1/ax+b dx = 1/a ln Iax+bI +c

Answer:

  19 cups

Step-by-step explanation:

Let c represent the number of cups of tea. The total cost will be ...

  10c +3(45) ≤ 332

  10c ≤ 197 . . . . . . . . . . . subtract 135

  c ≤ 19.7

Bidula can buy up to 19 cups of tea with ₹332.

Answer:

It has to be an isosceles because it has 2 congruent sides (and angles) in the same relative position. The two congruent angles both measure 30 degrees each; the total of degrees in any triangle is always 180. So, the other side has an angle measure of 120 degrees, which is more than 90. Therefore, it is

an obtuse isosceles

Answer:

9×y

Step-by-step explanation:

the

answer

of

the

given

is 9y

Answer:

Step-by-step explanation:

The area A of a rectangle is given by the formula, A=lw , where l is the length and w is the width.

so

8 * 15 = 120sq. units

TICKET MONEY for age 16 and over,

155-49 =106

1 person pays £18.60

106 = 106 × £18.60

=£1,971.6

TICKET MONEY for under 16

1 person pays £12.80

49 people =49 × £12.80

= £627.2

TOTAL NUMBER OF TICKETS

£ 1,971.6 + £6272.2

= £2,598.8

The scale Trent used for his elementary school which has a school yard of 85

meters wide in real life and 102 millimetre wide in drawing  is 51 : 42500

Firstly, let's do the conversion of the units

1 meters = 1000 millimetres

85 meters = ?

cross multiply

length in millimetres = 85 × 1000 = 85000 millimetres

Since the schoolyard width is 85000 millimetres in real life but it's 102 millimetres wide in drawing , the scale will be as follows:

= 102 / 85000

= 51 / 42500

Therefore, the scale is as follows:

51 : 42500

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A scale is chosen to plot the large graphs on smaller paper representing each unit by a supposed unit.

1.2 mm is used to represent 1 meter.

In the scale given the 102 mm is drawn to represent 85 meters.

So dividing the graph line with the original length the scale Trent has used can be found.

102/85= 1.2

This shows that 1.2 mm is used to represent 1 meter.

Multiplying 85 with 1.2 gives 102 .

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The equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)

Let l be the original length of the pool.

Since the length of the pool is increased by 3.7 m, the new length L = l + 3.7.

Also, the area of the pool A = 205.85 square meter and it is a rectangle with width, W = 11.6 meters,

So, A = LW

Substituting the values of the variables into the equation, we have

A = LW

205.85 = (l + 3.7)11.6

So, the equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)

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Answer:

Step-by-step explanation

205.85=11.6(l+3.7)

Answer:

My man Zachary is right!

Step-by-step explanation:

The rule is so very simple!

Whenever a negative, anywhere in the equation multiples to another negative, it is always a positive!

Whenever a positive number multiples to a negative number anywhere in the equation, it is always a negative number!

So Negative*Negative is Positive (-10 x -10 = 100)

And Positive*Negative is always negative (-10 x 10 = -100)

And we both know that Positive times positive is positive. (10 x 10 = 100)

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

[tex](7 + 17 - 14 - 8)q = 14[/tex]

[tex](24 - 22)q = 14[/tex]

[tex]2q = 14[/tex]

Divide both sides by 2

[tex] \frac{2q}{2} = \frac{14}{2} \\ [/tex]

[tex]q = 7[/tex]

There u go...

Have a great day ❤

The confidence interval is between (48.2%, 57.7%)

Using the proportion formula expressed as:

[tex]CI=p\pm z\cdot \sqrt{\frac{p(1-p)}{n} }[/tex]

Get the proportion:

p = 320/600 = 0.53

[tex]z=\frac{x- \mu}{\sigma}[/tex]

[tex]z = \frac{320-240}{47}\\z=\frac{80}{47}\\z= 1.70[/tex]

Substitute into the formula to get the confidence interval to have:

[tex]CI=0.53\pm 1.7\cdot \sqrt{\frac{0.47}{600}}\\CI = 0.53\pm 0.04757\\CI = (0.53-0.04757, 0.53+0.04757)\\CI = (0.482, 0.577)[/tex]

Hence the confidence interval is between (48.2%, 57.7%)

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Answer:

The answer is 2

Step-by-step explanation:

-2, -1, 0, 1, 2, 3, 4, 5, 6

If you remove the first 4 and the last 4 numbers you are left with 2 which is also the median / middle value. Therefore, the temperature is 2.

Answer:

69

Step-by-step explanation:

8's     8's+5                 11's     11's+3

8         13                    11          14

16        21                   22         25

24       29                  33          36

32       37                  44          47

40       45                  55          58

48        53                  66         69

56        61                   

64        69

Answer:

160000

Step-by-step explanation:

Answer:

So first you can find a common denominator to make this equation solvable

in this case 4 is the common denominator

2/4+y=5 1/4

Now subtract to isolate the variable (y)

4 3/4 =y

Answer:

145% increase

Step-by-step explanation:

343 - 140 = 203

203/140 = 1.45

1.45 x 100 = 145

Using the principle of expected value and discrete probability distribution, the missing values are :

The Expected value, E(X) is defined thus :

The cummulative sum of the probability is 1 :

Hence, we have ;

2** + ** + 0.40 + 0.13 + 0.02 = 1

3** + 0.55 = 1

3** = 1 - 0.55

3** = 0.45

** = 0.45 / 3

** = 0.15

Hence,

* = 2(0.15)

* = 0.30

To find *** :

E(X) = (0 × 0.30) + (1 × 0.15) + (*** × 0.40) + (4 × 0.13) + (5 × 0.02)

12.77 = 0 + 0.15 + 0.40*** + 0.52 + 0.10

12.77 = 0.77 + 0.40***

12.77 - 0.77 = 0.40***

12.00 = 0.40***

*** = 12.00/0.40

*** = 30

B.)

P(1 ≤ Y ≤ 4) = P(y = 1) + P(y = 4)

P(1 ≤ Y ≤ 4) = 0.15 + 0.13 = 0.28

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Answer:

RS = XY

Step-by-step explanation:

Corresponding sides will be equal. So

RS = XY

Answer:

2³

Step-by-step explanation:

2×2×2=8

so √8 = 2³

Hope this helps you

Answer:

66 cars

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

14-70=56

Step-by-step explanation:

its subtraction so you just need 70 and take away 14.

reasoning being that theyre all still cars no matter the color and you just need to take away 14 from 70, leaving you with 56.

Answer:

AB = 23.6

BC = 18.5

CD = 23.6

DA = 18.5

Step-by-step explanation:

4.

Both sets of opposite sides are parallel, so this is a parallelogram.

In parallelogram ABCD:

AB≅CD

AD≅BC

Knowing that, you can write 2 equations with the given information:

[tex]2a-20.4=a+1.6\\a-3.5=18.5[/tex]

You can solve whichever one you want, but I'll do both to be sure.

[tex]2a-20.4=a+1.6\\2a=a+1.6+20.4\\2a-a=1.6+20.4\\a=22[/tex]

Now for the second one:

[tex]a-3.5=18.5\\a=18.5+3.5\\a=22[/tex]

a = 22, so now you can solve for the side lengths.

[tex]2(22)-20.4=23.6\\22-3.5=18.5\\22+1.6=23.6\\18.5=18.5[/tex]

Answer: 2, D

Step-by-step explanation: f=-2, so 4x-2 would give -8 add 10 would give 2 as it is for the negative

Answer:

hey you can use scan and search

Answer:

I got : 0.42264973

Step-by-step explanation:

1/ -√3 + 1

-√3 = -1.73 ( 2 decimal place )

1/ -1.73 + 1

and found the answer

Step-by-step explanation:

x1, x2, x3, x4, x5

(x1 + x2 + x3 + x4 + x5)/5 = 4

x5 - x1 = 6

x3 = 3

2 appears more often than any other number (at least twice), otherwise there would have been multiple modes.

x1 + x2 + x3 + x4 + x5 = 4×5 = 20

x3 = 3

x1 + x2 + 3 + x4 + x5 = 20

x1 + x2 + x4 + x5 = 17

x5 = x1 + 6

x1 + x2 + x4 + x1 + 6 = 17

2×x1 + x2 + x4 = 11

since we did not have the number 2 yet (and we made x5 the harvest number, which has to be larger than 2), and it has to appear at least twice.

so, two numbers out of x1, x2, x3 must be 2. not all three of them can be 2, because 2×2 + 2 + 2 = 8 and not 11 as the last equation demands.

we have therefore 2 different solutions, as either

x1 and x2, or x2 and x4 can be 2.

x1 and x4 is the same solution per the last equation as x1 and x2 (as the variables are interchangeable for the number assignment, only x1 is different, because it has an additional factor in the last equation).

solution 1 (x1 and x2 are 2) :

2×2 + 2 + x4 = 11

4 + 2 + x4 = 11

6 + x4 = 11

x4 = 5

so,

x1 = 2,

x2 = 2,

x3 = 3

x4 = 5

x5 = x1 + 6 = 2 + 6 = 8

solution 2 (x2 and x4 are 2) :

2×x1 + 2 + 2 = 11

2×x1 + 4 = 11

2×x1 = 7

x1 = 7/2

so,

x1 = 7/2

x2 = 2

x3 = 3

x4 = 2

x5 = x1 + 6 = 7/2 + 12/2 = 19/2

m = (Y2 - Y1)/(X2 - X1)

m = (-5 - 3)/(-3 - 1)

m = -8/-4

m = 2