please help 100 points if correct ! :)
please actually answer
Instructions
Part 1: Celebration!
Think of an activity that you enjoy or are interested in. Some examples are reading, swimming, or leveling up your gaming character. Use your activity to work through the following problems:

Create a scenario that leads to an inequality of the form ax + b > c. You can use any of the inequality symbols (>, ≥, <, ≤) in your inequality. For this step, just write the word problem.


Write the inequality and show all work to solve the inequality.


Graph the solution to your inequality on a number line.


Explain what your solution means in the context of the problem.

Answers

Answer 1

Well for the activity we can do a game.

In a game you start with 50 coins and everytime you kill a monster "x" you get 2 more coins.You need 100 coins to level up.

We can make the following inequality,

2x + 50 ≥ 100

So to find x we single it out,

2x + 50 ≥ 100

-50 to both sides

2x ≥ 50

Divide 2 by both sides

x ≥ 25

For the number line look at the image below ↓

The solution in the number line is the number of monsters killed in order to level up.

Hope this helps :)

Please Help 100 Points If Correct ! :)please Actually AnswerInstructionsPart 1: Celebration!Think Of

Related Questions

simplifica: 49/90, se puede????

Answers

Answer:

49/90 is simplified

Step-by-step explanation:

Answer:

Step-by-step explanation:

49/90

? of 72 = 45 (answer in fraction)

Answers

Answer:

5/8

Step-by-step explanation:

72 = 16/10 of 45

45 = 10/16 = 5/8 of 72

In a game the average score was 60 time score was 5/2 of the average what was Tim’s score?

Answers

Answer:

in my own reasoning not sure if I am correct

Step-by-step explanation:

first it said Tim score was 5/2 of the of the average score

and the average score is 60

so that will be 5/2 × 60 which is

= 150

Represent 1/3 and 5/2 on the same number line.

Answers

Step-by-step explanation:

1/3 and 5/2 can be shown as:

1/3= 3/6 5/2= 15/6

points with 1/6 interval on the number line:

0, 1/6, 2/6, 3/6, 4/6, ..., 15/6

assume the graph of a function of the form y=asin(k(x+b)) is given below. which of the following are possible values for a, k, and b?

Answers

Answer:

C

Step-by-step explanation:

Okay, here we have the equation of the sine wave as;

y = asin(k(x + b))

By definition a represents the amplitude

k represents the frequency

b represents the horizontal shift or phase shift

Now let’s take a look at the graph.

By definition, the amplitude is the distance from crest to trough. It is the maximum displacement

From this particular graph, amplitude is 4

K is the frequency and this is 1/period

The period ;

Firstly we find the distance between two nodes here and that is 1/2 from the graph (3/4 to 1/4)

F = 1/T = 1/1/2 = 1/0.5 = 2

b is pi/4 ( phase is positive as it is increasing rightwards)

So the correct option here is C

Answer: it is

a=4, k=2, and b= pi/4

Step-by-step explanation:

got it right on A P E X

Pleas answer this is in two minutes

Answers

Answer:

b

Step-by-step explanation:

not a because equilateral would be all equal

scalene is all different

Answer:

scalene

Step-by-step explanation:

because all  sides are different.

The police department uses a formula to determine the speed at which a car was going when the driver applied the breaks, by measuring the distance of the skid marks.The equation d=0.03r^2+r models the distance, d, in feet, r miles per hour (r is the speed of the car) Factor the equation. d=?

Answers

Answer:

0.03 feet

Step-by-step explanation:

d = 0.03r² + r

When d = 0: 0.03r² + r = 0

r(0.03r + 1) = 0

∴ r = 0

When r = 0: d = 0.03 feet


Which expression is equivalent to

Answers

Answer:

Option 2) [tex]x^{\frac{1}{8}}y^8[/tex]

Step-by-step explanation:

=> [tex](x^{\frac{1}{4} } y ^{16} )^\frac{1}{2}[/tex]

=> [tex]x^{\frac{1}{4} * \frac{1}{2} } * y ^{16*\frac{1}{2} }[/tex]

=> [tex]x^{\frac{1}{8}}y^8[/tex]

What is the 5th equivalent fraction to 1/11 ?

Answers

Answer: 5/55

Step-by-step explanation:

1/11 x 5 = 5/55

So, the fifth equivalent fraction to 1/11 is 5/55.

The 5th equivalent fraction should be [tex]5\div 55[/tex]

Calculation of the equivalent fraction:

Since the fraction is [tex]1\div 11[/tex]

So here the 5th equivalent should be

[tex]= 1\div 11 \times 5\div 5[/tex]

= [tex]5\div 55[/tex]

Here 5 represent the numerator and 55 represent the denominator.

Therefore, we can concluded that The 5th equivalent fraction should be [tex]5\div 55[/tex]

Learn more about fraction here: https://brainly.com/question/1786648

A company rounds its losses to the nearest dollar. The error on each loss is independently and uniformly distributed on [–0.5, 0.5]. If the company rounds 2000 such claims, find the 95th percentile for the sum of the rounding errors.

Answers

Answer:

the 95th percentile for the sum of the rounding errors is 21.236

Step-by-step explanation:

Let consider X to be the rounding errors

Then; [tex]X \sim U (a,b)[/tex]

where;

a = -0.5 and b = 0.5

Also;

Since The error on each loss is independently and uniformly distributed

Then;

[tex]\sum X _1 \sim N ( n \mu , n \sigma^2)[/tex]

where;

n = 2000

Mean [tex]\mu = \dfrac{a+b}{2}[/tex]

[tex]\mu = \dfrac{-0.5+0.5}{2}[/tex]

[tex]\mu =0[/tex]

[tex]\sigma^2 = \dfrac{(b-a)^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{(0.5-(-0.5))^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{(0.5+0.5)^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{(1.0)^2}{12}[/tex]

[tex]\sigma^2 = \dfrac{1}{12}[/tex]

Recall:

[tex]\sum X _1 \sim N ( n \mu , n \sigma^2)[/tex]

[tex]n\mu = 2000 \times 0 = 0[/tex]

[tex]n \sigma^2 = 2000 \times \dfrac{1}{12} = \dfrac{2000}{12}[/tex]

For 95th percentile or below

[tex]P(\overline X < 95}) = P(\dfrac{\overline X - \mu }{\sqrt{{n \sigma^2}}}< \dfrac{P_{95}- 0 } {\sqrt{\dfrac{2000}{12}}}) =0.95[/tex]

[tex]P(Z< \dfrac{P_{95} } {\sqrt{\dfrac{2000}{12}}}) = 0.95[/tex]

[tex]P(Z< \dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}}) = 0.95[/tex]

[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} =1- 0.95[/tex]

[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} = 0.05[/tex]

From Normal table; Z >   1.645 = 0.05

[tex]\dfrac{P_{95}\sqrt{12} } {\sqrt{{2000}}} =1.645[/tex]

[tex]{P_{95}\sqrt{12} } = 1.645 \times {\sqrt{{2000}}}[/tex]

[tex]{P_{95} = \dfrac{1.645 \times {\sqrt{{2000}}} }{\sqrt{12} } }[/tex]

[tex]\mathbf{P_{95} = 21.236}[/tex]

the 95th percentile for the sum of the rounding errors is 21.236

how to find the angel in trigonometry when all the lengths of the right angled triangle already given.

Answers

Answer:

The three trigonometric ratios can be used to calculate the size of an angle in a right-angled triangle

Use rule ; SOHCAHTOA .Where sin x = opp/hyp

cos x = adj/hyp

tan x= opp/adj

Substitute the given values for the three sides

into any of the above rules

[tex]example = Hyp = 2\\opp = 1\\sin- x = 1/2\\x = sin^{-1} 1/2\\x = 30[/tex]

Step-by-step explanation:

I Hope It Helps :)

Which of the following investments could be represented by the function A = 250(1 + 0.08/12)12 × 4?

Answers

hello,

the first term is 250 so this is the initial invested amount

[tex](1+\dfrac{0.08}{12})^{12}=(1+\dfrac{8\%}{12})^{12}[/tex]

is to compute 8% annual interest compounded monthly (there are 12 months in a year)

and then multiply by 4 means that it is computed for 4 years so

finally the answer is

$250 is invested at 8% annual interest compounded monthly for 4 years

hope this helps

Which equation could be used to find the length of the hypotenuse?
А
С
5 cm
С
B
8 cm

Answers

Answer:

The first option (5^2 + 8^2 = c^2).

Step-by-step explanation:

According to the Pythagorean Theorem, a^2 + b^2 = c^2.

If a is 5 cm, and b is 8 cm, you would have the following equation...

5^2 + 8^2 = c^2.

That matches with the first option.

Hope this helps!

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