Please give a step by step explanation: 30 points up for grabs.

Please Give A Step By Step Explanation: 30 Points Up For Grabs.

Answers

Answer 1

Answer:

Honestly, I don't know ¯\_(ツ)_/¯

Explanation:


Related Questions

A truck travels on a straight road at a velocity of 17 meters per second. Over 20

seconds, it accelerates uniformly to 27 meters per second. What distance did the truck

travel during this acceleration?

Answers

Answer:

Distance, S = 440 meters.

Explanation:

Given the following data;

Initial velocity, u = 17m/s

Time, t = 20 seconds

Final velocity, v = 27m/s

To find the distance;

First of all, we would determine the acceleration of the truck.

Acceleration = (v-u)/t

Substituting the given values into the equation, we have;

Acceleration = (27 - 17)/20

Acceleration = 10/20

Acceleration = 0.5m/s²

Now, we would use the second equation of motion to find the distance traveled.

S = ut + ½at²

S = 17*20 + ½*0.5*20²

S = 340 + 0.25*400

S = 340 + 100

S = 440m

The equations of motion can be used to obtain the distance covered as 440 m.

We have to use of the equations that are used for uniformly accelerated motion in solving the problem. The chosen equation must be;

v^2 = u^2 + 2as and v = u + at

v = final velocity

u = initial velocity

a = acceleration

s = distance

To obtain the acceleration;

27 = 17 + 20(a)

27 - 17 = 20a

a = 0.5 ms-2

Now, to obtain the distance;

v^2 = u^2 + 2as

v^2 - u^2/as = s

s = (27)^2 - (17)^2/2(0.5)

s = 440 m

Learn more about the acceleration: https://brainly.com/question/12134554

One reason why it’s often easy to miss an action-reaction pair is because of the ________ of one of the objects.

Answers

Answer:

an action-reaction pair is because one of the objects is often much more massive and appears to remain motionless when a force acts on it. It has so much inertia, or tendency to remain at rest, that it hardly

define stress engineering science​

Answers

Answer:

Stress, in physical sciences and engineering, force per unit area within materials that arises from externally applied forces, uneven heating, or permanent deformation and that permits an accurate description and prediction of elastic, plastic, and fluid behaviour.

I hope it's helpful!

A car travels 100 km due East in 2 hours. It then travels 50 km South in 1 hour. What is its average velocity?

Answers

The average velocity of the car is 37.27 km/h.

The given parameters;

Initial displacement of the car, x = 100 kmTime of motion, t = 2 hoursFinal displacement of the car, y = 50 kmtime of motion, t = 1 hour

The average velocity of the car is calculated as follows;

[tex]average \ velocity = \frac{Total \ displacement}{Total \ time}[/tex]

The total displacement of the car is calculated as follows;

[tex]d = \sqrt{x^2 + y^2} \\\\d = \sqrt{100^2 \ + \ 50^2} \\\\d = 111.803 \ km[/tex]

The average velocity of the car is calculated as follows;

[tex]v = \frac{111.803}{3} \\\\v = 37.27 \ km/h[/tex]

Learn more about average velocity here: https://brainly.com/question/6504879

Two insulated wires, each 2.64 m long, are taped together to form a two-wire unit that is 2.64 m long. One wire carries a current of 7.68 A; the other carries a smaller current I in the opposite direction. The two wire unit is placed at an angle of 65.0o relative to a magnetic field whose magnitude is 0.59 T. The magnitude of the net magnetic force experienced by the two-wire unit is 4.11 N. What is the current I

Answers

Answer:

[tex]4.77\ \text{A}[/tex]

Explanation:

F = Magnetic force = 4.11 N

[tex]I_n[/tex] = Net current

[tex]I_2[/tex] = Current in one of the wires = 7.68 A

B = Magnetic field = 0.59 T

[tex]\theta[/tex] = Angle between current and magnetic field = [tex]65^{\circ}[/tex]

[tex]l[/tex] = Length of wires = 2.64 m

[tex]I[/tex] = Current in the other wire

Magnetic force is given by

[tex]F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}[/tex]

Net current is given by

[tex]I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}[/tex]

The current I is [tex]4.77\ \text{A}[/tex].

A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.

Answers

Time needed = t = 20.83 s

Further explanation

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.

Answers

Time needed = t = 20.83 s

Further explanation

Given

car speed = 85 km/h

truck speed = 73 km/h

Required

the time it takes for the car to reach the truck

Solution

When the car reaches the truck, the distance between them will be the same

x car - 250 m = x truck

General formula for distance (d) :

d = v.t

So the equation becomes :

85t-250 = 73t

12t=250

t = 20.83 s

a ball is thrown upward with a beginning speed of 40m/s. The graph below shows how the speed of the ball changes until it reaches its maximum height.

use the graph to find
a) the time when the ball reaches its maximum height
b) the acceleration of the ball
c) the maximum height the ball went​

Answers

Answer:

a) 4.0816s

b) -9.8 ms^-1

c) 81.63265m

Fred's lightbulb is 45% efficient, and Fran's is 75% efficient. If they both use the same amount of electric energy, which produces more light energy? ​

Answers

Answer:

Frank's 75% efficient light bulb will shine brighter.

Explanation:

The brightness of a bulb is gotten from the power equation;

P = I²R

The more the power rating in watts, the more the brightness.

Now, if they both use the same amount of energy but yet have different efficiency, it means we will just multiply the efficiency by the power.

Thus, 75% efficiency will yield more power than a 45% efficient one.

Therefore, Frank's light bulb will shine brighter.

Connective Tissue in a tendon is

Answers


Overview. A tendon is a fibrous connective tissue which attaches muscle to bone. Tendons may also attach muscles to structures such as the eyeball. A tendon serves to move the bone or structure.

The surface area of a postage

stamp is 0.00600 m^2, and the air

exerts 1.00 atm of pressure on it.

How much force does it exert on

the stamp?

(Hint: The standard unit for

pressure is Pa.)

(Unit = N)

Answers

Answer:

Force = 607.95 Newton

Explanation:

Given the following data;

Area = 0.00600 m^2

Pressure = 1 atm to Pascal = 101325 Pa

To find the force;

Pressure = Force/area

Force = pressure * area

Substituting into the equation, we have;

Force = 101325 * 0.00600

Force = 607.95 Newton.

Therefore, the amount of force exerted by the air on the stamp is 607.95 Newton.

Choose the words that make each statement correct.
(i) After being released from rest in a uniform electric field, a pro- ton will move [(a) in the same direction as; (b) opposite the direction of] the electric field to regions of [(c) higher; (d) lower] electric potential.
(ii) After being released from rest in a uniform electric field, an electron will move [(e) in the same direction as; (f) opposite the direction of] the electric field to regions of [(g) higher; (h) lower] electric potential.

Answers

Answer:

i). (a) in the same direction as , (d) lower

ii). (f) opposite the direction of, (g) higher

Explanation:

An proton may be defined as a sub atomic particle and it has a positive electrical charge. Its mass is slightly less than that of a neutron. When a proton is placed in an electrical field that is uniformly charged, it is at rest. When the proton first moves out from rest from the uniform electric field, it will move in a direction which is same as that of the electric field and it will move to a region of higher potential.

An electron is defined as the subatomic particle having negative electric charge. When an electron is released form rest from an uniform electric field, it will move in the opposite direction of the uniform electric field and will move to the region of lower electric potential.

The "problem of perception" is best characterized as?

Answers

Answer:

making sense of a 3-d world from 2-d data

Explanation:

Jshshshsshhsbxbxbxbxbdbdbd

What fitness component is plank exercises?

Answers

Answer:

The plank (also called a front hold, hover, or abdominal bridge) is an isometric core strength exercise that involves maintaining a position similar to a push-up for the maximum possible time.

Explanation:

please mark me has brainllest

Carousel conveyors are used for storage and order picking for small parts. The conveyorsrotate clockwise or counterclockwise, as necessary, to position storage bins at the storageand retrieval point. The conveyors are closely spaced, such that the operators travel timebetween conveyors is negligible. The conveyor rotation time for each item equals 1 minute;the time required for the operator to retrieve an item after the conveyor stops rotatingequals 0.25 minute. How many carousel conveyors can one operator tend without creatingidle time on the part of the conveyors

Answers

Answer:

the number of carousel conveyors that an operator can operate without any idle time is 5

Explanation:

Given the data in the question;

first we express the equation for number of carousel conveyors that can be operated by an operator;

n' = [tex]\frac{(a + t)}{( a + b)}[/tex]

where a is the concurrent activity time ( 0.25 minute )

b is the independent operator activity time

t is the independent machine activity time( 1 )

Now independent activity time is zero as the operator is not performing any inspection or packaging tasks.

So time taken for the operator to retrieve the finished item at the end of the process is the concurrent activity and independent machine activity time, the conveyor rotation time of each item

so

we substitute

0.25min for a, 1 for t and 0min for b

n' = [tex]\frac{(0.25min + 1min)}{( 0.25min+ 0 min)}[/tex]

n' = 1.25 min / 0.25

n' - 5

Therefore, the number of carousel conveyors that an operator can operate without any idle time is 5

Using the graph, when (in seconds) would you expect the object to have the highest velocity? Explain your answer.

Answers

Answer:

blue

Explanation:

nswer the following about two objects, A and B, whose motion produced ihe following ... "A" starts with a greater (t) position. Since they ... since you are moving away from the origin

At what speed, in m/s, would a moving clock lose 1.3ns in 1.0 day according to experimenters on the ground?

Answers

Answer:

v=0.14c

Explanation:

A plastic rod 1.6 m long is rubbed all over with wool, and acquires a charge of -9e-08 coulombs. We choose the center of the rod to be the origin of our coordinate system, with the x-axis extending to the right, the y-axis extending up, and the z-axis out of the page. In order to calculate the electric field at location A = < 0.7, 0, 0 > m, we divide the rod into 8 pieces, and approximate each piece as a point charge located at the center of the piece.

Answers

Solution :

Length of the plastic rod , L = 1.6 m

Total charge on the plastic rod , Q = [tex]$-9 \times 10^{-8}$[/tex] C

The rod is divided into 8 pieces.

a). The length of the 8 pieces is , [tex]$l=\frac{L}{8}$[/tex]

                                                         [tex]$=\frac{1.6}{8}$[/tex]

                                                         = 0.2 m

b). Location of the center of the piece number 5 is given as : 0 m, -0.09375 m, 0 m.

c). The charge q on the piece number 5 is given as

[tex]$q=\frac{Q}{L}\times l$[/tex]

[tex]$q=\frac{-9 \times 10^{-8}}{1.6}\times0.2$[/tex]

 = [tex]$-1.125 \times 10^{-8}$[/tex] C

d). WE approximate that piece 5 as a point charge and we need to find out the field at point A(0.7 m, 0, 0) only due to the charge.

We know,  the Coulombs force constant, k = [tex]$8.99 \times 10^9 \ N.m^2/C^2$[/tex]

So the X component of the electric field at the point A  is given as

[tex]$E_x = 8.99 \times 10^9 \times 1 \times 10^{-8} \ \cos \frac{187.628}{0.70625}$[/tex]

     = -126.15 N/C

The Y component of the electric field at the point A is

[tex]$E_y = 8.99 \times 10^9 \times 1 \times 10^{-8} \ \sin \frac{187.628}{0.70625}$[/tex]

    = -16.93 N/C

Now since the rod and the point A is in the x - y plane, the z component of the field at point A due to the piece 5 will be zero.

∴ [tex]$E_z=0$[/tex]

Thus, [tex]$E= <-126.15,-16.93,0>$[/tex]

A bird lands on a bird feeder which is connected to a spring. The mass of the bird is exactly the same as the mass of the bird feeder. How does the added mass affect the period of oscillation of the bird feeder?

Answers

Answer:

The added mass will mean a longer period of oscillation.

Explanation:

The period of oscillation here is given by the formula;

T = 2π√(m/k)

Where m is mass and k is spring constant

From the equation of oscillation period above, it's obvious that when we increase the mass, the oscillation period will also increase.

Thus, the added mass will mean a longer period of oscillation.

A train 350 m long is moving on a straight track with a speed of 84.1 km/h. The engineer applies the brakes at a crossing, and later the last car passes the crossing with a speed of 15.8 km/h. Assuming constant acceleration, determine how long the train blocked the crossing. Disregard the width of the crossing.

Answers

Answer:

t = 25.0 s

Explanation:

Assuming that the engineer applies the brakes just over the crossing, the train moves exactly 350 m at a constant acceleration, with a final speed (when the last car of the train leaves the crossing) of 15.8km/h.Since we know the initial and final speeds, and the horizontal distance traveled (the length of the train) we can use the following kinematic equation to get the acceleration:

       [tex]v_{f}^{2} - v_{o}^{2} = 2*a* \Delta x (1)[/tex]

Since we need to find the time in seconds, it is advisable to convert vf and  vo to m/s first, as follows:

       [tex]v_{o} = 84.1 km/h*\frac{1h}{3600s} *\frac{1000m}{1km} = 23.4 m/s (2)[/tex]

      [tex]v_{f} = 15.8 km/h*\frac{1h}{3600s} *\frac{1000m}{1km} = 4.4 m/s (3)[/tex]

Replacing (2) and (3) in (1), since Δx =350m, we can solving for a:

       [tex]a = \frac{(4.4m/s)^{2} - (23.4m/s)^{2}}{2*350m} = -0.76 m/s2 (4)[/tex]

In order to get the time, we can simply use the definition of acceleration, and rearrange terms:

       [tex]t =\frac{v_{f}-v_{o}}{a} = \frac{(4.4m/s)-(23.4m/s)}{-0.76m/s2} = 25.0 s (5)[/tex]

Emma is working in a shoe test lab measuring the coefficient of friction for tennis shoes on a variety of surfaces. The shoes are pushed against the surface with a force of 400 N, and a sample of the surface material is then pulled out from under the shoe by a machine. The machine pulls with a force of 300 N before the material begins to slide. When the material is sliding, the machine has to pull with a force of only 200 N to keep the material moving.
a. What is the coefficient of static friction between the shoe and the material?
b. What is the coefficient of dynamic friction between the shoe and the material?
c. Draw a Free Body Diagram for the above.

Answers

Answer:

Explanation:

Force of friction = μ N , where μ is coefficient of friction , N is normal force on the body .

a )

Given,

Normal force N = 400 N

Force of friction = 300 N

μ = coefficient of static friction = ?

Putting the values ,

300 = 400 μ

μ = .75

b )

Normal force N = 400 N

Force of friction = 200 N

μ = coefficient of kinetic  friction = ?

Putting the values ,

200 = 400 μ

μ = .50

c ) see attached file .

A baseball player hits a 0.15 kg 0.15kg0, point, 15, start text, k, g, end text baseball that is initially at rest, changing its momentum by 11 kg ⋅ m s 11 s kg⋅m ​ 11, start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, end fraction.

Answers

Answer:

73.3m/s

Explanation:

We can find the velocity of the player.

Momentum = mass * velocity

Given

Mass = 0.15kg

Momentum = 11kgm/s

Get the velocity

Velocity = Momentum/Mass

Velocity = 11/0.15

Velocity = 73.3m/s

Hence the velocity of the player is 73.3m/s

A simple pendulum of length 5.5 m makes 10.0 complete swings in 25 s what is the acceleration due to gravity at the location of the pendulum ?

Answers

Answer:

The acceleration due to gravity at the location of the pendulum is 34.74 m/s².

Explanation:

Given that,

The length of a simple pendulum, l = 5.5 m

It makes 10.0 complete swings in 25 s.

Frequency of pendulum,

[tex]f=\dfrac{10}{25}\\\\f=0.4\ Hz[/tex]

The time period of a simple pendulum is given by :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

Frequency,

[tex]f=\dfrac{1}{T}\\\\f=\dfrac{1}{2\pi \sqrt{\dfrac{l}{g}} }\\\\f=\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}[/tex]

g is the acceleration due to gravity at the location where the pendulum is placed. So,

[tex]f^2=\dfrac{g}{4\pi^2l}\\\\g=f^2\times 4\pi^2l\\\\g=0.4^2\times 4\pi^2\times 5.5\\\\g=34.74\ m/s^2[/tex]

So, the acceleration due to gravity at the location of the pendulum is 34.74 m/s².

According to Coulomb's Law, if the distance between two charged particles is doubled, the electric force will be _________. *

Answers

Answer: reduced by 1/4

Explanation:

The force will be reduced by 1/4. Try plugging in 2r, then squaring it. You will get 4r^2, which is essentially dividing the force by 4

A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log floating by. Always with the same engine throttle setting, the boater continues to travel upstream for another 1.45 km, which takes her 69.1 min. She then turns the boat around and returns downstream to her starting point, which she reaches at the same time as the same log does. How much time does the boater spend traveling back downstream

Answers

Answer:

 t ’= [tex]\frac{1450}{0.6499 + 2 v_r}[/tex],  v_r = 1 m/s       t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

        v_b - v_r = d / t

By the time the boat goes down the river

        v_b + v_r = d '/ t'

let's subtract the equations

       2 v_r = d ’/ t’ - d / t

       d ’/ t’ = 2v_r + d / t

       [tex]t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }[/tex]

In the exercise they tell us

         d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

         d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

      t ’= [tex]\frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \ + 2 \ v_r}[/tex]

      t ’= [tex]\frac{1450}{0.6499 + 2 v_r}[/tex]

In order to complete the calculation, we must assume a river speed

          v_r = 1 m / s

       

let's calculate

      t ’= [tex]\frac{ 1450}{ 0.6499 + 2 \ 1}[/tex]

      t ’= 547.19 s

Elizabeth has always believed that people's thoughts can help heal them. She wants to help people use positive thinking to positively affect their
illnesses. What type of psychology would be MOST appropriate for Elizabeth to study?

Answers

Answer: Family

Explanation:

What is the maximum height achieved if a 0.400 kg mass is thrown straight upward with an initial speed of 40.0 m⋅s−1? Ignore the effect of air resistance

Answers

The maximum height : 81.63 m

Further explanation

Given

0.4 kg mass

vo = initial speed = 40 m/s

Required

the maximum height

Solution

We can use the law of conservation energy(ME=PE+KE) or use parabolic motion

For parabolic motion :

h max = (vo²sin²θ)/2g

θ = 90°(straight upward)

Input the value :

h max = (40²sin²90°)/2 x 9.8

h max = 81.63 m

A friend comments to you that there was a beautiful, thin sliver of a Moon visible in the early morning just before sunrise. Which phase of the Moon would this be, and in what direction would you look to see the Moon (in the southern sky, on the eastern horizon, on the western horizon, high in the sky, etc.)?

Answers

Answer: Waning Crescent

Explanation:

Choose the best explanation from among the following:_________.
1. Charge is conserved, and therefore the mass of the object will remain the same.
2. A positive charge increases an object's mass; a negative charge decreases its mass.
3. To give the object a negative charge we must give it more electrons, and this will increase its mass.

Answers

Answer: 3. To give the object a negative charge we must give it more electrons, and this will increase its mass.

Explanation:

Suppose we have an object and we negatively charge it.

Then we are "adding" N electrons to the object.

Remember that the mass of an electron is:

m = 9.11*10^(-31) kg

Then if we add N electrons to an object of mass M, the new mass of the object will be:

Mass = M + N*9.11*10^(-31) kg

So we will have an (almost negligible) increase of the mass of the object.

(Something similar can happen if the object is positively charged, where we remove electrons, then the mass of the object decreases)

Then the correct option is:

3. To give the object a negative charge we must give it more electrons, and this will increase its mass.

What is the mass of an object if it is moving at a speed of 10 m/s and has 400 J of kinetic energy?

Answers

Answers:

8 kg

Explanation:

Kinetic Energy = (mass × velocity × velocity) ÷ 2

We know that Kinetic Energy = 400 J and velocity = 10 m/s.

KE = (m × v × v) ÷ 2

400 J = (m × 10 m/s × 10 m/s) ÷ 2

400 J = m × 50 m^2/s^2

To find the mass you will divide 400 J and 50 m^2/s^2.

m = 8 kg

You can also check it if it gives you 400 J.

KE = (m × v × v) ÷ 2

KE = (8 kg × 10 m/s × 10 m/s) ÷ 2

KE = 400 J

So this means that the mass is 8 kg. I know that it is a bit confusing, but when you do J (joules) ÷ m^2/s^2 = kg (kilograms). Hope this helps, thank you !!

Other Questions
A model release can be either oral or written down. True False Exposing the Lunacy of the Lunar Effect1The sight of a full moon riding high in the sky on a cloudless night brings to mind beauty, the harvest, and poetic thoughts, but it also reminds us of legends of strange things that happen during a full moon. Some people believe that the full moon affects humans and animals. Temporary insanity, violence, car accidents, animal bites, and births all increase when the moon is full or do they? While belief in the lunar effect is widespread, there is little evidence to suggest it is a real phenomenon.2One argument commonly put forth in favor of the lunar effect is that tides are higher when the moon is full. The human body is mostly water. If the moon can affect an entire ocean, surely it affects us too. This line of thinking is problematic for several reasons. First, the water of the ocean is not confined within a small space in the same way that the water inside the human body is. Second, the gravitational pull the moon exerts on any objects here on Earth is actually very weak. Finally, the highest tides occur not only during the full moon, but also the new moon. If the lunar effect is real, then it should logically also be observable during the new moon.3The results of some studies have suggested that animals are more aggressive (and more likely to bite) during a full moon, and that the number of births also peaks around this time, but they are the exception. As shown in the table below, many other investigations have failed to find any correlation between these events.image 06cd8839cecf44d0beeca5ea88fc28c64It is true that the full moon can interfere with sleep, but this was mainly a problem before artificial lighting. There is no mystery here. People tend to sleep best when it is dark. A full moon makes for a brighter night, so people dont sleep as well. A streetlight shining into someones bedroom window would likely produce exactly the same result. 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Select ALL that apply.A The sight of a full moon riding high in the sky on a cloudless night brings to mind beauty, the harvest, and poetic thoughts, but it also reminds us of legends of strange things that happen during a full moon.B If the lunar effect is real, then it should logically also be observable during the new moon.C The results of some studies have suggested that animals are more aggressive (and more likely to bite) during a full moon, and that the number of births also peaks around this time, but they are the exception.D A streetlight shining into someones bedroom window would likely produce exactly the same result.E The other beliefs about the lunar effect are largely based on isolated incidents, anecdotes, and fictional films and television programs. Aaron went to watch The Avengers at the movie theater. He noticed that 60% of the movie extras during one of the scenes were teachers from his school. He recognized 24 teachers from his school. How many movie extras were there all together? Marty's class collected $34.00 in a school-wide penny collection contest. If Tommy's class added $3.00 to the amount theycollected, x, and then multiplied the sum by 2, they would have the same amount of money as Marty's class.2(x + $3.00)= $34.00How much money did Tommy's class collect? .$20.00OB.$17.00O C. $3.00OD.$14.00 what is 6 more than -3 in integers help please i need the answers asap What's the infinitive of visto and what's the infinitive? match each u.s. political idea to document it was borrowed from 1 Yvonne is saving money for college, and currently has $1200 in a savings account. She plans to deposit $30 each week from her part-time job and then deposit birthday money from her Aunt Marlene ($40 each birthday). Her goal is to have saved $6,000 by the time she graduates from high school in three years. 1. Write a function that models Yvonne's savings. 2. Simplify your function. 3. Use your function to create a graph of Yvonne's savings.(input your function in your calculator and take a screenshot) Which system of inequalities does the graph represent? Which test point satisfies both of the inequalities in that system?The graph represents the system of inequalities .The test point satisfies both of the inequalities in the system represented by the graph. Find each slope and y-intercept. Then graph each equation. Susan incorrectly factored the expression below. 12a 15b + 6 3 (4a + 5b + 3) HELP PLEASEEA baker uses 63 cups of flour and 72 cups of water for a recipe. The flour to water ratio is 63:72 how much water does the baker need if he uses only 7 cups of flour? What's 4 x 90 divided by 3 x 7? 1. Which layer of the atmosphere has: a. the most water vapor? b. the lowest pressure? 2. What remains the same in different layers of the atmosphere? 3. Scientists have divided the earth's atmosphere into different layers. What property of the atmosphere do you think these divisions are based on? 4. You collected data on four layers of the atmosphere. The atmos- phere merges into outer space in an extremely thin upper layer known as the exosphere. Which of the five layers of the atmos- phere do people live in? -5.6 > X + 3.6I need help with my edgeunity If c=10\pic=10, what does 10 represent? Transversal relations helpppppppppppppppppppppppp the graph represents the x^2+y^2=8. Use the graph to answer questions 6,7,8.6. look at the graph of the equation x^2+y^2=8. give its domaim and range7. use algebraic means to show that x^2+y^2=8 is not a function. Explain your process.8. is there any value(s) of the domain of x^2+y^2=8 that passes the verticle line test? if so, name the value(s) and state whether or not the existence of this value makes this relation a function. You can use Desmos to help you explore this idea, if needed.